UPSC Insta–DART (Daily Aptitude and Reasoning Test) 9 Oct 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Based on the above passage, the following assumptions have been made: Markets alone cannot guarantee equitable outcomes without regulatory intervention. State regulation and market mechanisms must coexist to balance efficiency with social justice. Select the correct answer using the code given below: (a) 1 only (b) 2 only (c) Both 1 and 2 (d) Neither 1 nor 2 Correct Solution: (c) Explanation: • Statement 1 is valid: The passage highlights how markets fail to address inequality, public goods, and sustainability. • Statement 2 is valid: The concluding line explicitly notes the tension between market faith and regulatory need, implying coexistence is necessary. Thus, both assumptions logically follow, making (c) correct. Incorrect Solution: (c) Explanation: • Statement 1 is valid: The passage highlights how markets fail to address inequality, public goods, and sustainability. • Statement 2 is valid: The concluding line explicitly notes the tension between market faith and regulatory need, implying coexistence is necessary. Thus, both assumptions logically follow, making (c) correct.
#### 1. Question
Based on the above passage, the following assumptions have been made:
• Markets alone cannot guarantee equitable outcomes without regulatory intervention.
• State regulation and market mechanisms must coexist to balance efficiency with social justice.
Select the correct answer using the code given below:
• (a) 1 only
• (b) 2 only
• (c) Both 1 and 2
• (d) Neither 1 nor 2
Solution: (c)
Explanation: • Statement 1 is valid: The passage highlights how markets fail to address inequality, public goods, and sustainability. • Statement 2 is valid: The concluding line explicitly notes the tension between market faith and regulatory need, implying coexistence is necessary. Thus, both assumptions logically follow, making (c) correct.
Solution: (c)
Explanation: • Statement 1 is valid: The passage highlights how markets fail to address inequality, public goods, and sustainability. • Statement 2 is valid: The concluding line explicitly notes the tension between market faith and regulatory need, implying coexistence is necessary. Thus, both assumptions logically follow, making (c) correct.
• Question 2 of 5 2. Question If 12 men and 16 boys can finish a work in 5 days, while 25 men and 50 boys can finish it in 2 days, then the time taken by 15 men and 20 boys will be: (a) 3 days (b) 4 days (c) 5 days (d) 6 days Correct Answer – B Solution: Given that, Let 1 man’s 1-day work = mmm and 1 boy’s 1-day work = bbb. (12m + 16b) × 5 = 1 ⇒ 12m + 16b = 1/5 …(i) (25m + 50b) × 2 = 1 ⇒ 25m + 50b = 1/2 …(ii) From (i): 3m + 4b = 1/20 ⇒ m = 1/60 − (4/3)b Substitute in (ii): 25(1/60 − 4b/3) + 50b = 1/2 5/12 − 100b/3 + 50b = 1/2 ⇒ 5/12 + (−100/3 + 150/3)b = 1/2 ⇒ 5/12 + (50/3)b = 1/2 ⇒ (50/3)b = 1/2 − 5/12 = 1/12 ⇒ b = 1/200 Then 3m + 4(1/200) = 1/20 ⇒ 3m = 1/20 − 1/50 = 3/100 ⇒ m = 1/100 Now, (15m + 20b) = 15/100 + 20/200 = 0.25 = 1/4 Time taken = 1 ÷ (1/4) = 4 days Hence option (b) is correct Incorrect Answer – B Solution: Given that, Let 1 man’s 1-day work = mmm and 1 boy’s 1-day work = bbb. (12m + 16b) × 5 = 1 ⇒ 12m + 16b = 1/5 …(i) (25m + 50b) × 2 = 1 ⇒ 25m + 50b = 1/2 …(ii) From (i): 3m + 4b = 1/20 ⇒ m = 1/60 − (4/3)b Substitute in (ii): 25(1/60 − 4b/3) + 50b = 1/2 5/12 − 100b/3 + 50b = 1/2 ⇒ 5/12 + (−100/3 + 150/3)b = 1/2 ⇒ 5/12 + (50/3)b = 1/2 ⇒ (50/3)b = 1/2 − 5/12 = 1/12 ⇒ b = 1/200 Then 3m + 4(1/200) = 1/20 ⇒ 3m = 1/20 − 1/50 = 3/100 ⇒ m = 1/100 Now, (15m + 20b) = 15/100 + 20/200 = 0.25 = 1/4 Time taken = 1 ÷ (1/4) = 4 days Hence option (b) is correct
#### 2. Question
If 12 men and 16 boys can finish a work in 5 days, while 25 men and 50 boys can finish it in 2 days, then the time taken by 15 men and 20 boys will be:
• (a) 3 days
• (b) 4 days
• (c) 5 days
• (d) 6 days
Answer – B Solution: Given that,
Let 1 man’s 1-day work = mmm and 1 boy’s 1-day work = bbb.
(12m + 16b) × 5 = 1 ⇒ 12m + 16b = 1/5 …(i) (25m + 50b) × 2 = 1 ⇒ 25m + 50b = 1/2 …(ii)
From (i): 3m + 4b = 1/20 ⇒ m = 1/60 − (4/3)b
Substitute in (ii):
25(1/60 − 4b/3) + 50b = 1/2 5/12 − 100b/3 + 50b = 1/2 ⇒ 5/12 + (−100/3 + 150/3)b = 1/2 ⇒ 5/12 + (50/3)b = 1/2 ⇒ (50/3)b = 1/2 − 5/12 = 1/12 ⇒ b = 1/200
Then 3m + 4(1/200) = 1/20 ⇒ 3m = 1/20 − 1/50 = 3/100 ⇒ m = 1/100
Now, (15m + 20b) = 15/100 + 20/200 = 0.25 = 1/4 Time taken = 1 ÷ (1/4) = 4 days
Hence option (b) is correct
Answer – B Solution: Given that,
Let 1 man’s 1-day work = mmm and 1 boy’s 1-day work = bbb.
(12m + 16b) × 5 = 1 ⇒ 12m + 16b = 1/5 …(i) (25m + 50b) × 2 = 1 ⇒ 25m + 50b = 1/2 …(ii)
From (i): 3m + 4b = 1/20 ⇒ m = 1/60 − (4/3)b
Substitute in (ii):
25(1/60 − 4b/3) + 50b = 1/2 5/12 − 100b/3 + 50b = 1/2 ⇒ 5/12 + (−100/3 + 150/3)b = 1/2 ⇒ 5/12 + (50/3)b = 1/2 ⇒ (50/3)b = 1/2 − 5/12 = 1/12 ⇒ b = 1/200
Then 3m + 4(1/200) = 1/20 ⇒ 3m = 1/20 − 1/50 = 3/100 ⇒ m = 1/100
Now, (15m + 20b) = 15/100 + 20/200 = 0.25 = 1/4 Time taken = 1 ÷ (1/4) = 4 days
Hence option (b) is correct
• Question 3 of 5 3. Question 8 men can complete a work in 8 days and 16 boys take 16 days to complete the work. How many days will 4 men and 16 boys take to complete the work? (a) 6 (b) 7 (c) 8 (d) 9 Correct Answer – C Solution: Given, ⇒ 8 men finish in 8 days ⇒ 1 man’s 1-day work = 1/(8×8) = 1/64 ⇒ 16 boys finish in 16 days ⇒ 1 boy’s 1-day work = 1/(16×16) = 1/256 (4 men + 16 boys)’s 1-day work = 4×(1/64) + 16×(1/256) = 1/16 + 1/16 = 1/8 Time taken = 1 ÷ (1/8) = 8 days Hence option (c) 8 is correct Incorrect Answer – C Solution: Given, ⇒ 8 men finish in 8 days ⇒ 1 man’s 1-day work = 1/(8×8) = 1/64 ⇒ 16 boys finish in 16 days ⇒ 1 boy’s 1-day work = 1/(16×16) = 1/256 (4 men + 16 boys)’s 1-day work = 4×(1/64) + 16×(1/256) = 1/16 + 1/16 = 1/8 Time taken = 1 ÷ (1/8) = 8 days Hence option (c) 8 is correct
#### 3. Question
8 men can complete a work in 8 days and 16 boys take 16 days to complete the work. How many days will 4 men and 16 boys take to complete the work?
Answer – C Solution: Given,
⇒ 8 men finish in 8 days ⇒ 1 man’s 1-day work = 1/(8×8) = 1/64 ⇒ 16 boys finish in 16 days ⇒ 1 boy’s 1-day work = 1/(16×16) = 1/256
(4 men + 16 boys)’s 1-day work = 4×(1/64) + 16×(1/256) = 1/16 + 1/16 = 1/8
Time taken = 1 ÷ (1/8) = 8 days
Hence option (c) 8 is correct
Answer – C Solution: Given,
⇒ 8 men finish in 8 days ⇒ 1 man’s 1-day work = 1/(8×8) = 1/64 ⇒ 16 boys finish in 16 days ⇒ 1 boy’s 1-day work = 1/(16×16) = 1/256
(4 men + 16 boys)’s 1-day work = 4×(1/64) + 16×(1/256) = 1/16 + 1/16 = 1/8
Time taken = 1 ÷ (1/8) = 8 days
Hence option (c) 8 is correct
• Question 4 of 5 4. Question A certain number of men can complete a piece of work in 12k days. By what percent should the number of men be increased so that the work can be completed in 9k days? (a) 25% (b) 30% (c) 33⅓% (d) 40% Correct Answer – C Solution: Given that, Work can be completed in 12k days. Let number of men be M1 and M2 Days are D1 = 12k and D2 = 9k M1 × D1 = M2 × D2 M1 × 12k = M2 × 9k M2 = (M1 × 12k)/9k = (4/3)M1 % change = {(4/3)M1 − M1}/M1 × 100 = (1/3) × 100 = 33⅓% Thus 33⅓% more men are required. Hence option (c) is correct Incorrect Answer – C Solution: Given that, Work can be completed in 12k days. Let number of men be M1 and M2 Days are D1 = 12k and D2 = 9k M1 × D1 = M2 × D2 M1 × 12k = M2 × 9k M2 = (M1 × 12k)/9k = (4/3)M1 % change = {(4/3)M1 − M1}/M1 × 100 = (1/3) × 100 = 33⅓% Thus 33⅓% more men are required. Hence option (c) is correct
#### 4. Question
A certain number of men can complete a piece of work in 12k days. By what percent should the number of men be increased so that the work can be completed in 9k days?
Answer – C Solution:
Given that,
Work can be completed in 12k days.
Let number of men be M1 and M2
Days are D1 = 12k and D2 = 9k
M1 × D1 = M2 × D2
M1 × 12k = M2 × 9k
M2 = (M1 × 12k)/9k = (4/3)M1
% change = {(4/3)M1 − M1}/M1 × 100 = (1/3) × 100 = 33⅓%
Thus 33⅓% more men are required.
Hence option (c) is correct
Answer – C Solution:
Given that,
Work can be completed in 12k days.
Let number of men be M1 and M2
Days are D1 = 12k and D2 = 9k
M1 × D1 = M2 × D2
M1 × 12k = M2 × 9k
M2 = (M1 × 12k)/9k = (4/3)M1
% change = {(4/3)M1 − M1}/M1 × 100 = (1/3) × 100 = 33⅓%
Thus 33⅓% more men are required.
Hence option (c) is correct
• Question 5 of 5 5. Question If a runner moves at 12 km/hr instead of 8 km/hr, he would have covered 20 km more. The actual distance covered by him is: (a) 32 km (b) 36 km (c) 40 km (d) 44 km Correct Answer – C Solution: Given that, At 12 km/hr instead of 8 km/hr, extra distance = 20 km. Let the common time be t hours. 12t = 8t + 20 ⇒ 4t = 20 ⇒ t = 5 hours Actual distance = 8 × t = 8 × 5 = 40 km Hence option (c) is correct Incorrect Answer – C Solution: Given that, At 12 km/hr instead of 8 km/hr, extra distance = 20 km. Let the common time be t hours. 12t = 8t + 20 ⇒ 4t = 20 ⇒ t = 5 hours Actual distance = 8 × t = 8 × 5 = 40 km Hence option (c) is correct
#### 5. Question
If a runner moves at 12 km/hr instead of 8 km/hr, he would have covered 20 km more. The actual distance covered by him is:
Answer – C Solution:
Given that,
At 12 km/hr instead of 8 km/hr, extra distance = 20 km.
Let the common time be t hours.
12t = 8t + 20 ⇒ 4t = 20 ⇒ t = 5 hours
Actual distance = 8 × t = 8 × 5 = 40 km
Hence option (c) is correct
Answer – C Solution:
Given that,
At 12 km/hr instead of 8 km/hr, extra distance = 20 km.
Let the common time be t hours.
12t = 8t + 20 ⇒ 4t = 20 ⇒ t = 5 hours
Actual distance = 8 × t = 8 × 5 = 40 km
Hence option (c) is correct
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