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UPSC Insta–DART (Daily Aptitude and Reasoning Test) 9 Mar 2026

Kartavya Desk Staff

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question In how many ways can 6 people be seated around a circular table such that two particular people, A and B, always sit next to each other? (a) 24 (b) 48 (c) 120 (d) 240 Correct Incorrect

#### 1. Question

In how many ways can 6 people be seated around a circular table such that two particular people, A and B, always sit next to each other?

• Question 2 of 5 2. Question If the letters of the word CHART” are arranged in all possible ways and listed as in a dictionary, what is the rank of the word “CHART”? (a) 31 (b) 32 (c) 25 (d) 26 Correct Answer: (a) Solution Letters of the word CHART are: C, H, A, R, T. First arrange them in alphabetical order: A, C, H, R, T. Now we count how many words come before “CHART” in dictionary order. First letter is C. Only one letter comes before C, which is A. Fix A in the first position and arrange the remaining 4 letters in all possible ways: 4! = 24 So, 24 words come before those starting with C. Next, fix C and look at the second letter H. Remaining letters are A, H, R, T. Only A comes before H. Fix CA and arrange the remaining 3 letters: 3! = 6 Total so far = 24 + 6 = 30. Now, fix CH and look at the third letter A. Remaining letters are A, R, T. No letter comes before A, so add 0. Next, fix CHA and look at the fourth letter R. Remaining letters are R and T. No letter comes before R, so add 0. Thus, the number of words before “CHART” is 30. Including the word itself, its rank is: 30 + 1 = 31 Incorrect Answer: (a) Solution Letters of the word CHART are: C, H, A, R, T. First arrange them in alphabetical order: A, C, H, R, T. Now we count how many words come before “CHART” in dictionary order. First letter is C. Only one letter comes before C, which is A. Fix A in the first position and arrange the remaining 4 letters in all possible ways: 4! = 24 So, 24 words come before those starting with C. Next, fix C and look at the second letter H. Remaining letters are A, H, R, T. Only A comes before H. Fix CA and arrange the remaining 3 letters: 3! = 6 Total so far = 24 + 6 = 30. Now, fix CH and look at the third letter A. Remaining letters are A, R, T. No letter comes before A, so add 0. Next, fix CHA and look at the fourth letter R. Remaining letters are R and T. No letter comes before R, so add 0. Thus, the number of words before “CHART” is 30. Including the word itself, its rank is: 30 + 1 = 31

#### 2. Question

If the letters of the word CHART” are arranged in all possible ways and listed as in a dictionary, what is the rank of the word “CHART”?

Answer: (a)

Solution

Letters of the word CHART are: C, H, A, R, T. First arrange them in alphabetical order: A, C, H, R, T.

Now we count how many words come before “CHART” in dictionary order.

First letter is C. Only one letter comes before C, which is A. Fix A in the first position and arrange the remaining 4 letters in all possible ways: 4! = 24 So, 24 words come before those starting with C.

Next, fix C and look at the second letter H. Remaining letters are A, H, R, T. Only A comes before H. Fix CA and arrange the remaining 3 letters: 3! = 6

Total so far = 24 + 6 = 30.

Now, fix CH and look at the third letter A. Remaining letters are A, R, T. No letter comes before A, so add 0.

Next, fix CHA and look at the fourth letter R. Remaining letters are R and T. No letter comes before R, so add 0.

Thus, the number of words before “CHART” is 30. Including the word itself, its rank is:

30 + 1 = 31

Answer: (a)

Solution

Letters of the word CHART are: C, H, A, R, T. First arrange them in alphabetical order: A, C, H, R, T.

Now we count how many words come before “CHART” in dictionary order.

First letter is C. Only one letter comes before C, which is A. Fix A in the first position and arrange the remaining 4 letters in all possible ways: 4! = 24 So, 24 words come before those starting with C.

Next, fix C and look at the second letter H. Remaining letters are A, H, R, T. Only A comes before H. Fix CA and arrange the remaining 3 letters: 3! = 6

Total so far = 24 + 6 = 30.

Now, fix CH and look at the third letter A. Remaining letters are A, R, T. No letter comes before A, so add 0.

Next, fix CHA and look at the fourth letter R. Remaining letters are R and T. No letter comes before R, so add 0.

Thus, the number of words before “CHART” is 30. Including the word itself, its rank is:

30 + 1 = 31

• Question 3 of 5 3. Question Consider the following question and statements: Question: In how many ways can n people be seated in a row? Statement I: If two particular people must always sit together, the number of arrangements is 48. Statement II: If the same n people are seated around a circular table, the number of arrangements is 24. Which of the following is correct with respect to above? (a) Statement I alone is sufficient. (b) Statement II alone is sufficient. (c) Both Statements together are sufficient. (d) Each Statement alone is sufficient. Correct Answer: (d) Solution: We need to find: In how many ways can people be seated in a row? That means we need . Using Statement I “If two particular people must always sit together, the number of arrangements is 48.” If people are seated in a row and two fixed people (say A and B) must be together: Treat (A,B) as one block. So we have units to arrange in a row → ways Inside the block, A and B can be arranged in 2 ways (AB or BA) Statement II alone is sufficient. Hence, each statement alone gives , hence row arrangements . Incorrect Answer: (d) Solution: We need to find: In how many ways can people be seated in a row? That means we need . Using Statement I “If two particular people must always sit together, the number of arrangements is 48.” If people are seated in a row and two fixed people (say A and B) must be together: Treat (A,B) as one block. So we have units to arrange in a row → ways Inside the block, A and B can be arranged in 2 ways (AB or BA) Statement II alone is sufficient. Hence, each statement alone gives , hence row arrangements .

#### 3. Question

Consider the following question and statements:

Question: In how many ways can n people be seated in a row?

Statement I: If two particular people must always sit together, the number of arrangements is 48.

Statement II: If the same n people are seated around a circular table, the number of arrangements is 24.

Which of the following is correct with respect to above?

• (a) Statement I alone is sufficient.

• (b) Statement II alone is sufficient.

• (c) Both Statements together are sufficient.

• (d) Each Statement alone is sufficient.

Answer: (d)

Solution:

We need to find: In how many ways can people be seated in a row? That means we need .

Using Statement I

“If two particular people must always sit together, the number of arrangements is 48.”

If people are seated in a row and two fixed people (say A and B) must be together:

Treat (A,B) as one block. So we have units to arrange in a row → ways Inside the block, A and B can be arranged in 2 ways (AB or BA)

Statement II alone is sufficient.

Hence, each statement alone gives , hence row arrangements .

Answer: (d)

Solution:

We need to find: In how many ways can people be seated in a row? That means we need .

Using Statement I

“If two particular people must always sit together, the number of arrangements is 48.”

If people are seated in a row and two fixed people (say A and B) must be together:

Treat (A,B) as one block. So we have units to arrange in a row → ways Inside the block, A and B can be arranged in 2 ways (AB or BA)

Statement II alone is sufficient.

Hence, each statement alone gives , hence row arrangements .

• Question 4 of 5 4. Question In a party, every person shakes hands with every other person exactly once. If the total number of handshakes is 66, and 3 people leave the party early without shaking hands with anyone, how many people were originally at the party? (a) 12 (b) 15 (c) 18 (d) 21 Correct Incorrect

#### 4. Question

In a party, every person shakes hands with every other person exactly once. If the total number of handshakes is 66, and 3 people leave the party early without shaking hands with anyone, how many people were originally at the party?

• Question 5 of 5 5. Question A man has to go from point A to point B in a 4 × 4 grid, moving only Right or Up. However, there is a forbidden point C located exactly at the middle of the grid , through which he cannot pass. How many distinct paths are available from A to B? (a) 26 (b) 34 (c) 50 (d) 70 Correct Incorrect

#### 5. Question

A man has to go from point A to point B in a 4 × 4 grid, moving only Right or Up. However, there is a forbidden point C located exactly at the middle of the grid , through which he cannot pass. How many distinct paths are available from A to B?

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