UPSC Insta–DART (Daily Aptitude and Reasoning Test) 8 Nov 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
#### Quiz-summary
0 of 5 questions completed
Questions:
#### Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
#### Categories
• Not categorized 0%
• Question 1 of 5 1. Question A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? a) 5:4 b) 8:3 c) 7:6 d) 4:5 Correct Answer: B Solution: Let the man’s rate upstream be x kmph and that downstream be y kmph. Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs. X8 4/5 =4y 44/5x=4y Y=11/5x. Required ratio (y+x)/2=(y-x)/2 16x/10:6x/10 = 8:3 Incorrect Answer: B Solution: Let the man’s rate upstream be x kmph and that downstream be y kmph. Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs. X8 4/5 =4y 44/5x=4y Y=11/5x. Required ratio (y+x)/2=(y-x)/2 16x/10:6x/10 = 8:3
#### 1. Question
A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?
Let the man’s rate upstream be x kmph and that downstream be y kmph.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
X*8 4/5 =4y
Required ratio (y+x)/2=(y-x)/2
16x/10:6x/10 = 8:3
Let the man’s rate upstream be x kmph and that downstream be y kmph.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
X*8 4/5 =4y
Required ratio (y+x)/2=(y-x)/2
16x/10:6x/10 = 8:3
• Question 2 of 5 2. Question At his usual rowing rate, Rahul can travel 12 miles downstream in a certain river in 6 hours less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24-mile round trip, the downstream 12 miles would then take only one hour less than the upstream 12 miles. What is the speed of the current in miles per hour? a) 2 2/3mph b) 2mph c) 1 1/4mph d) 3mph Correct Answer: A Solution: Let the speed of Rahul in still water be x mph and the speed of the current be y mph Then, Speed upstream = (x – y) mph Speed downstream = (x + y) mph Distance = 12 miles Time taken to travel upstream – Time taken to travel downstream = 6 hours 12/(x-y) – 12/(x+y)=6 x2=y2+4y—1 Now he doubles his speed. i.e., his new speed = 2x Now, Speed upstream = (2x – y) mph Speed downstream = (2x + y) mph In this case, Time taken to travel upstream – Time taken to travel downstream = 1 hour 12/(2x-y) – 12/(2x+y) = 1 4×2=y2+24y—2 From 1 and 2 we get 4y+y2=(24y +y2)/4 Y=8/3==> 2 2/3mph Incorrect Answer: A Solution: Let the speed of Rahul in still water be x mph and the speed of the current be y mph Then, Speed upstream = (x – y) mph Speed downstream = (x + y) mph Distance = 12 miles Time taken to travel upstream – Time taken to travel downstream = 6 hours 12/(x-y) – 12/(x+y)=6 x2=y2+4y—1 Now he doubles his speed. i.e., his new speed = 2x Now, Speed upstream = (2x – y) mph Speed downstream = (2x + y) mph In this case, Time taken to travel upstream – Time taken to travel downstream = 1 hour 12/(2x-y) – 12/(2x+y) = 1 4×2=y2+24y—2 From 1 and 2 we get 4y+y2=(24y +y2)/4 Y=8/3==> 2 2/3mph
#### 2. Question
At his usual rowing rate, Rahul can travel 12 miles downstream in a certain river in 6 hours less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24-mile round trip, the downstream 12 miles would then take only one hour less than the upstream 12 miles. What is the speed of the current in miles per hour?
• a) 2 2/3mph
• c) 1 1/4mph
Let the speed of Rahul in still water be x mph
and the speed of the current be y mph
Then, Speed upstream = (x – y) mph
Speed downstream = (x + y) mph
Distance = 12 miles
Time taken to travel upstream – Time taken to travel downstream = 6 hours
12/(x-y) – 12/(x+y)=6
x2=y2+4y—1
Now he doubles his speed. i.e., his new speed = 2x
Now, Speed upstream = (2x – y) mph
Speed downstream = (2x + y) mph
In this case, Time taken to travel upstream – Time taken to travel downstream = 1 hour
12/(2x-y) – 12/(2x+y) = 1
4×2=y2+24y—2
From 1 and 2 we get
4y+y2=(24y +y2)/4
Y=8/3==> 2 2/3mph
Let the speed of Rahul in still water be x mph
and the speed of the current be y mph
Then, Speed upstream = (x – y) mph
Speed downstream = (x + y) mph
Distance = 12 miles
Time taken to travel upstream – Time taken to travel downstream = 6 hours
12/(x-y) – 12/(x+y)=6
x2=y2+4y—1
Now he doubles his speed. i.e., his new speed = 2x
Now, Speed upstream = (2x – y) mph
Speed downstream = (2x + y) mph
In this case, Time taken to travel upstream – Time taken to travel downstream = 1 hour
12/(2x-y) – 12/(2x+y) = 1
4×2=y2+24y—2
From 1 and 2 we get
4y+y2=(24y +y2)/4
Y=8/3==> 2 2/3mph
• Question 3 of 5 3. Question A man rows to a place 60 km distant and come back in 35 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. Find the speed in still water and in stream: a) 1.5, 2 b) 0.5, 2.5 c) 3.5, 0.5 d) 2, 2.5 Correct Answer: C Solution: If he moves 4 km downstream in x hours. Downstream speed=4/x Upstream speed=3/x Then 60/(4/x) + 60/(3/x)=35 60[(3x+4x)/12]=35 607x/12=35 57x=35==> x=1km. Then Downstream speed=4km/hr , Upstream speed=3km/hr U=(4+3)/2=7/2=3.5km/hr V=(4-3)/2=1/2=0.5km/hr Incorrect Answer: C Solution: If he moves 4 km downstream in x hours. Downstream speed=4/x Upstream speed=3/x Then 60/(4/x) + 60/(3/x)=35 60[(3x+4x)/12]=35 607x/12=35 57x=35==> x=1km. Then Downstream speed=4km/hr , Upstream speed=3km/hr U=(4+3)/2=7/2=3.5km/hr V=(4-3)/2=1/2=0.5km/hr
#### 3. Question
A man rows to a place 60 km distant and come back in 35 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. Find the speed in still water and in stream:
• b) 0.5, 2.5
• c) 3.5, 0.5
If he moves 4 km downstream in x hours.
Downstream speed=4/x
Upstream speed=3/x
Then 60/(4/x) + 60/(3/x)=35
60[(3x+4x)/12]=35
60*7x/12=35
5*7x=35==> x=1km.
Then Downstream speed=4km/hr , Upstream speed=3km/hr
U=(4+3)/2=7/2=3.5km/hr
V=(4-3)/2=1/2=0.5km/hr
If he moves 4 km downstream in x hours.
Downstream speed=4/x
Upstream speed=3/x
Then 60/(4/x) + 60/(3/x)=35
60[(3x+4x)/12]=35
60*7x/12=35
5*7x=35==> x=1km.
Then Downstream speed=4km/hr , Upstream speed=3km/hr
U=(4+3)/2=7/2=3.5km/hr
V=(4-3)/2=1/2=0.5km/hr
• Question 4 of 5 4. Question Vinay want to travel to Delhi from Banglore. it’s 600 kilometre. If he opt for train , it takes twelve hour more than the flight. If the speed of the train is doubled ,it takes ten hours less than the flight. what’s the speed of the flight? a) 255 kmph b) 245kmph c) 265 kmph d) 250 kmph Correct Answer: D Solution: Speed of the train = 600 / 12 = 50 km / hr If it speed doubled = 50 x 2 = 100 km/hr So 100 / 10 = 10 times increased. Then original time 12-10 = 2 hrs Therefore speed = 500 / 2 = 250 kmph . Incorrect Answer: D Solution: Speed of the train = 600 / 12 = 50 km / hr If it speed doubled = 50 x 2 = 100 km/hr So 100 / 10 = 10 times increased. Then original time 12-10 = 2 hrs Therefore speed = 500 / 2 = 250 kmph .
#### 4. Question
Vinay want to travel to Delhi from Banglore. it’s 600 kilometre. If he opt for train , it takes twelve hour more than the flight. If the speed of the train is doubled ,it takes ten hours less than the flight. what’s the speed of the flight?
• a) 255 kmph
• b) 245kmph
• c) 265 kmph
• d) 250 kmph
Speed of the train = 600 / 12 = 50 km / hr
If it speed doubled = 50 x 2 = 100 km/hr
So 100 / 10 = 10 times increased.
Then original time 12-10 = 2 hrs
Therefore speed = 500 / 2 = 250 kmph .
Speed of the train = 600 / 12 = 50 km / hr
If it speed doubled = 50 x 2 = 100 km/hr
So 100 / 10 = 10 times increased.
Then original time 12-10 = 2 hrs
Therefore speed = 500 / 2 = 250 kmph .
• Question 5 of 5 5. Question Two trains of equal length, running with the speeds of 40kmph and 60 kmph, take 40 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions ? a) 9 sec b) 8 sec c) 10 sec d) 5 sec Correct Answer: B Solution: Relative Speed = (60 -40) = 20 x 5/18 = 100/18 Time = 40 Distance = 40 x 100/18 = 2000/9 Relative Speed = 60 + 40 = 100 x 5/18 Time = (200018)/(9500) = 8 sec. Incorrect Answer: B Solution: Relative Speed = (60 -40) = 20 x 5/18 = 100/18 Time = 40 Distance = 40 x 100/18 = 2000/9 Relative Speed = 60 + 40 = 100 x 5/18 Time = (200018)/(9500) = 8 sec.
#### 5. Question
Two trains of equal length, running with the speeds of 40kmph and 60 kmph, take 40 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions ?
Relative Speed = (60 -40) = 20 x 5/18 = 100/18
Distance = 40 x 100/18 = 2000/9
Relative Speed = 60 + 40 = 100 x 5/18
Time = (200018)/(9500) = 8 sec.
Relative Speed = (60 -40) = 20 x 5/18 = 100/18
Distance = 40 x 100/18 = 2000/9
Relative Speed = 60 + 40 = 100 x 5/18
Time = (200018)/(9500) = 8 sec.
• Official Facebook Page HERE
• Follow our Twitter Account HERE