UPSC Insta–DART (Daily Aptitude and Reasoning Test) 7 Oct 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question A thief runs at 9 m/s. A policeman starts chasing him from the same point but 2 minutes later, running at 12 m/s. How long will it take the policeman to catch the thief after starting the chase? (a) 6 min (b) 7 min (c) 8 min (d) 9 min Correct Answer: (a) Solution: In 2 minutes, thief’s head start = 9 × 120 = 1080 m Relative speed = 12 − 9 = 3 m/s Time to catch = 1080 ÷ 3 = 360 s = 6 minutes So, option (a) is correct. Incorrect Answer: (a) Solution: In 2 minutes, thief’s head start = 9 × 120 = 1080 m Relative speed = 12 − 9 = 3 m/s Time to catch = 1080 ÷ 3 = 360 s = 6 minutes So, option (a) is correct.
#### 1. Question
A thief runs at 9 m/s. A policeman starts chasing him from the same point but 2 minutes later, running at 12 m/s. How long will it take the policeman to catch the thief after starting the chase?
Answer: (a)
Solution: In 2 minutes, thief’s head start = 9 × 120 = 1080 m Relative speed = 12 − 9 = 3 m/s Time to catch = 1080 ÷ 3 = 360 s = 6 minutes So, option (a) is correct.
Answer: (a)
Solution: In 2 minutes, thief’s head start = 9 × 120 = 1080 m Relative speed = 12 − 9 = 3 m/s Time to catch = 1080 ÷ 3 = 360 s = 6 minutes So, option (a) is correct.
• Question 2 of 5 2. Question X, Y and Z can complete a work alone in 5, 10 and 20 hours respectively. Only one person works per hour, and no one works two consecutive hours. All are engaged to finish the work. What is the minimum time required? (a) 6 hrs 15 min (b) 6 hrs 30 min (c) 7 hrs (d) 7 hrs 15 min Correct Answer: (a) Solution: Total work = LCM(5, 10, 20) = 20 units Efficiency: X = 4 units/hr, Y = 2 units/hr, Z = 1 unit/hr Strategy: alternate X and Y. Hour 1: X → 4 Hour 2: Y → 2, total 6 Hour 3: X → 4, total 10 Hour 4: Y → 2, total 12 Hour 5: X → 4, total 16 Hour 6: Y → 2, total 18 Remaining = 2 units. Next turn is X (4/hr). Time = 2/4 hr = 15 min. Total = 6 hrs 15 min. Correct option = (a). Incorrect Answer: (a) Solution: Total work = LCM(5, 10, 20) = 20 units Efficiency: X = 4 units/hr, Y = 2 units/hr, Z = 1 unit/hr Strategy: alternate X and Y. Hour 1: X → 4 Hour 2: Y → 2, total 6 Hour 3: X → 4, total 10 Hour 4: Y → 2, total 12 Hour 5: X → 4, total 16 Hour 6: Y → 2, total 18 Remaining = 2 units. Next turn is X (4/hr). Time = 2/4 hr = 15 min. Total = 6 hrs 15 min. Correct option = (a).
#### 2. Question
X, Y and Z can complete a work alone in 5, 10 and 20 hours respectively. Only one person works per hour, and no one works two consecutive hours. All are engaged to finish the work. What is the minimum time required?
• (a) 6 hrs 15 min
• (b) 6 hrs 30 min
• (d) 7 hrs 15 min
Answer: (a)
Solution: Total work = LCM(5, 10, 20) = 20 units Efficiency: X = 4 units/hr, Y = 2 units/hr, Z = 1 unit/hr
Strategy: alternate X and Y.
Hour 1: X → 4 Hour 2: Y → 2, total 6 Hour 3: X → 4, total 10 Hour 4: Y → 2, total 12 Hour 5: X → 4, total 16 Hour 6: Y → 2, total 18
Remaining = 2 units. Next turn is X (4/hr). Time = 2/4 hr = 15 min.
Total = 6 hrs 15 min. Correct option = (a).
Answer: (a)
Solution: Total work = LCM(5, 10, 20) = 20 units Efficiency: X = 4 units/hr, Y = 2 units/hr, Z = 1 unit/hr
Strategy: alternate X and Y.
Hour 1: X → 4 Hour 2: Y → 2, total 6 Hour 3: X → 4, total 10 Hour 4: Y → 2, total 12 Hour 5: X → 4, total 16 Hour 6: Y → 2, total 18
Remaining = 2 units. Next turn is X (4/hr). Time = 2/4 hr = 15 min.
Total = 6 hrs 15 min. Correct option = (a).
• Question 3 of 5 3. Question Consider the following questions and statements Question: What is the total time required for A and B together to complete a job? Statement I: A alone can complete the job in 15 days, and B alone can complete the job in 20 days. Statement II: A and B together can complete 7/60 of the job in one day. Which of the following is correct with respect to above? (a) If Statement I alone is sufficient. (b) If Statement II alone is sufficient. (c) If both Statements I and II together are required. (d) If both Statements I and II together are not sufficient. Correct Answer: (b) Explanation: From Statement I: Work/day of A = 1/15, B = 1/20. Together = 1/15 + 1/20 = 7/60. So total = 60/7 days. Sufficient. From Statement II: Directly gives daily work = 7/60, so total = 60/7 days. Sufficient. Hence either alone is sufficient, correct option = (b). Incorrect Answer: (b) Explanation: From Statement I: Work/day of A = 1/15, B = 1/20. Together = 1/15 + 1/20 = 7/60. So total = 60/7 days. Sufficient. From Statement II: Directly gives daily work = 7/60, so total = 60/7 days. Sufficient. Hence either alone is sufficient, correct option = (b).
#### 3. Question
Consider the following questions and statements
Question: What is the total time required for A and B together to complete a job?
Statement I: A alone can complete the job in 15 days, and B alone can complete the job in 20 days. Statement II: A and B together can complete 7/60 of the job in one day.
Which of the following is correct with respect to above?
• (a) If Statement I alone is sufficient.
• (b) If Statement II alone is sufficient.
• (c) If both Statements I and II together are required.
• (d) If both Statements I and II together are not sufficient.
Answer: (b)
Explanation: From Statement I: Work/day of A = 1/15, B = 1/20. Together = 1/15 + 1/20 = 7/60. So total = 60/7 days. Sufficient.
From Statement II: Directly gives daily work = 7/60, so total = 60/7 days. Sufficient.
Hence either alone is sufficient, correct option = (b).
Answer: (b)
Explanation: From Statement I: Work/day of A = 1/15, B = 1/20. Together = 1/15 + 1/20 = 7/60. So total = 60/7 days. Sufficient.
From Statement II: Directly gives daily work = 7/60, so total = 60/7 days. Sufficient.
Hence either alone is sufficient, correct option = (b).
• Question 4 of 5 4. Question The number of triangles that can be formed using 12 distinct points on a circle (no three points are collinear) is (a) 220 (b) 230 (c) 240 (d) 250 Correct Answer – A Solution: To form a triangle, we need to choose 3 points out of 12. Number of triangles = 12C3 = (12×11×10)/(3×2×1) = 220. Hence, option (a) 220 is correct. Incorrect Answer – A Solution: To form a triangle, we need to choose 3 points out of 12. Number of triangles = 12C3 = (12×11×10)/(3×2×1) = 220. Hence, option (a) 220 is correct.
#### 4. Question
The number of triangles that can be formed using 12 distinct points on a circle (no three points are collinear) is
Answer – A Solution: To form a triangle, we need to choose 3 points out of 12. Number of triangles = 12C3 = (12×11×10)/(3×2×1) = 220.
Hence, option (a) 220 is correct.
Answer – A Solution: To form a triangle, we need to choose 3 points out of 12. Number of triangles = 12C3 = (12×11×10)/(3×2×1) = 220.
Hence, option (a) 220 is correct.
• Question 5 of 5 5. Question There are 4 horizontal and 6 vertical lines, parallel and equidistant to one another on a board. What is the maximum number of rectangles that can be formed? (a) 72 (b) 84 (c) 90 (d) 96 Correct Answer – C Solution: Given that, There are 4 horizontal and 6 vertical lines, parallel and equidistant. To form a rectangle, choose 2 of the vertical lines and 2 of the horizontal lines. So, 4C2 × 6C2 = 6 × 15 = 90 rectangles. Hence option (c) is correct Incorrect Answer – C Solution: Given that, There are 4 horizontal and 6 vertical lines, parallel and equidistant. To form a rectangle, choose 2 of the vertical lines and 2 of the horizontal lines. So, 4C2 × 6C2 = 6 × 15 = 90 rectangles. Hence option (c) is correct
#### 5. Question
There are 4 horizontal and 6 vertical lines, parallel and equidistant to one another on a board. What is the maximum number of rectangles that can be formed?
Answer – C Solution:
Given that,
There are 4 horizontal and 6 vertical lines, parallel and equidistant.
To form a rectangle, choose 2 of the vertical lines and 2 of the horizontal lines.
4C2 × 6C2 = 6 × 15 = 90 rectangles.
Hence option (c) is correct
Answer – C Solution:
Given that,
There are 4 horizontal and 6 vertical lines, parallel and equidistant.
To form a rectangle, choose 2 of the vertical lines and 2 of the horizontal lines.
4C2 × 6C2 = 6 × 15 = 90 rectangles.
Hence option (c) is correct
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