UPSC Insta–DART (Daily Aptitude and Reasoning Test) 7 Aug 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question With reference to the above passage, the following assumptions have been made: Hunger persists in India not due to lack of food but due to systemic failures in access and distribution. Addressing malnutrition requires going beyond calorie-based measures and considering broader nutritional needs. Which of the above assumptions is/are valid? (a) I only (b) II only (c) Both I and II (d) Neither I nor II Correct Answer: C Explanation: Assumption I is valid: The passage clearly states that food stocks may exist yet hunger persists due to distribution gaps and exclusion. This directly supports assumption I. Assumption II is valid: The passage criticises calorie sufficiency as inadequate and stresses hidden hunger and micronutrient deficiencies, validating this assumption. Thus, both assumptions follow logically, making option (c) correct. Incorrect Answer: C Explanation: Assumption I is valid: The passage clearly states that food stocks may exist yet hunger persists due to distribution gaps and exclusion. This directly supports assumption I. Assumption II is valid: The passage criticises calorie sufficiency as inadequate and stresses hidden hunger and micronutrient deficiencies, validating this assumption. Thus, both assumptions follow logically, making option (c) correct.
#### 1. Question
With reference to the above passage, the following assumptions have been made:
• Hunger persists in India not due to lack of food but due to systemic failures in access and distribution.
• Addressing malnutrition requires going beyond calorie-based measures and considering broader nutritional needs.
Which of the above assumptions is/are valid?
• (a) I only
• (b) II only
• (c) Both I and II
• (d) Neither I nor II
Answer: C
Explanation:
• Assumption I is valid: The passage clearly states that food stocks may exist yet hunger persists due to distribution gaps and exclusion. This directly supports assumption I.
• Assumption II is valid: The passage criticises calorie sufficiency as inadequate and stresses hidden hunger and micronutrient deficiencies, validating this assumption.
Thus, both assumptions follow logically, making option (c) correct.
Answer: C
Explanation:
• Assumption I is valid: The passage clearly states that food stocks may exist yet hunger persists due to distribution gaps and exclusion. This directly supports assumption I.
• Assumption II is valid: The passage criticises calorie sufficiency as inadequate and stresses hidden hunger and micronutrient deficiencies, validating this assumption.
Thus, both assumptions follow logically, making option (c) correct.
• Question 2 of 5 2. Question Out of the pens manufactured in a factory, 10% are defective. Of the remaining pens, 25% are sold in the domestic market. If 6,750 pens are left for export, what was the total number of pens produced? (a) 9000 (b) 9500 (c) 10,000 (d) 8700 Correct Answer: C Solution: Let total number of pens = x Defective pens = 10% of x = 0.10x Non-defective = 0.90x 25% sold in domestic market → left = 75% of non-defective = 0.75×0.90x=0.675 Given: 0.675x=6750⇒x=6750/0.675=10,0000. Incorrect Answer: C Solution: Let total number of pens = x Defective pens = 10% of x = 0.10x Non-defective = 0.90x 25% sold in domestic market → left = 75% of non-defective = 0.75×0.90x=0.675 Given: 0.675x=6750⇒x=6750/0.675=10,0000.
#### 2. Question
Out of the pens manufactured in a factory, 10% are defective. Of the remaining pens, 25% are sold in the domestic market. If 6,750 pens are left for export, what was the total number of pens produced?
• (c) 10,000
Solution: Let total number of pens = x
• Defective pens = 10% of x = 0.10x
• Non-defective = 0.90x
• 25% sold in domestic market → left = 75% of non-defective = 0.75×0.90x=0.675
0.675x=6750⇒x=6750/0.675=10,0000.
Solution: Let total number of pens = x
• Defective pens = 10% of x = 0.10x
• Non-defective = 0.90x
• 25% sold in domestic market → left = 75% of non-defective = 0.75×0.90x=0.675
0.675x=6750⇒x=6750/0.675=10,0000.
• Question 3 of 5 3. Question Pipe A fills a tank in 10 min, pipe B in 15 min. Both are opened together. After 3 minutes, A is closed. How much more time will B take to fill the tank? (a) 7 minutes 12 seconds (b) 7 minutes 24 seconds (c) 6 minutes 40 seconds (d) 7 minutes 30 seconds Correct Answer: D Solution A: 1/10, B: 1/15 Work in 3 min: 3×(1/10+1/15)=3×(3/30+2/30)=3×5/30=1/2 Remaining = 1 − 1/2 = 1/2 B fills at 1/15 ⇒ Time = (1/2) ÷ (1/15) = 15/2 = 7.5 minutes = 7 min 30 sec Incorrect Answer: D Solution A: 1/10, B: 1/15 Work in 3 min: 3×(1/10+1/15)=3×(3/30+2/30)=3×5/30=1/2 Remaining = 1 − 1/2 = 1/2 B fills at 1/15 ⇒ Time = (1/2) ÷ (1/15) = 15/2 = 7.5 minutes = 7 min 30 sec
#### 3. Question
Pipe A fills a tank in 10 min, pipe B in 15 min. Both are opened together. After 3 minutes, A is closed. How much more time will B take to fill the tank?
• (a) 7 minutes 12 seconds
• (b) 7 minutes 24 seconds
• (c) 6 minutes 40 seconds
• (d) 7 minutes 30 seconds
• A: 1/10, B: 1/15 Work in 3 min:
3×(1/10+1/15)=3×(3/30+2/30)=3×5/30=1/2
Remaining = 1 − 1/2 = 1/2 B fills at 1/15 ⇒ Time = (1/2) ÷ (1/15) = 15/2 = 7.5 minutes = 7 min 30 sec
• A: 1/10, B: 1/15 Work in 3 min:
3×(1/10+1/15)=3×(3/30+2/30)=3×5/30=1/2
Remaining = 1 − 1/2 = 1/2 B fills at 1/15 ⇒ Time = (1/2) ÷ (1/15) = 15/2 = 7.5 minutes = 7 min 30 sec
• Question 4 of 5 4. Question From numbers 1 to 1000, how many are divisible by at least one of 3, 5, or 7? (a) 744 (b) 580 (c) 543 (d) 670 Correct Answer: C Solution: Let N=1000N = 1000N=1000 Let: A = divisible by 3 ⇒ ⌊1000/3⌋=333 B = divisible by 5 ⇒ ⌊1000/5⌋=200 C = divisible by 7 ⇒ ⌊1000/7⌋=142 Now pairwise: A ∩ B = divisible by 15 ⇒ ⌊1000/15⌋=66 A ∩ C = divisible by 21 ⇒ ⌊1000/21⌋=47 B ∩ C = divisible by 35 ⇒ ⌊1000/35⌋=28 Triple overlap: A ∩ B ∩ C = divisible by 105 ⇒ ⌊1000/105⌋=9 Now apply PIE: ∣A∪B∪C∣=333+200+142−(66+47+28)+9=675−141+9=543 Incorrect Answer: C Solution: Let N=1000N = 1000N=1000 Let: A = divisible by 3 ⇒ ⌊1000/3⌋=333 B = divisible by 5 ⇒ ⌊1000/5⌋=200 C = divisible by 7 ⇒ ⌊1000/7⌋=142 Now pairwise: A ∩ B = divisible by 15 ⇒ ⌊1000/15⌋=66 A ∩ C = divisible by 21 ⇒ ⌊1000/21⌋=47 B ∩ C = divisible by 35 ⇒ ⌊1000/35⌋=28 Triple overlap: A ∩ B ∩ C = divisible by 105 ⇒ ⌊1000/105⌋=9 Now apply PIE: ∣A∪B∪C∣=333+200+142−(66+47+28)+9=675−141+9=543
#### 4. Question
From numbers 1 to 1000, how many are divisible by at least one of 3, 5, or 7?
Solution:
Let N=1000N = 1000N=1000
• A = divisible by 3 ⇒ ⌊1000/3⌋=333
• B = divisible by 5 ⇒ ⌊1000/5⌋=200
• C = divisible by 7 ⇒ ⌊1000/7⌋=142
Now pairwise:
• A ∩ B = divisible by 15 ⇒ ⌊1000/15⌋=66
• A ∩ C = divisible by 21 ⇒ ⌊1000/21⌋=47
• B ∩ C = divisible by 35 ⇒ ⌊1000/35⌋=28
Triple overlap:
• A ∩ B ∩ C = divisible by 105 ⇒ ⌊1000/105⌋=9
Now apply PIE:
∣A∪B∪C∣=333+200+142−(66+47+28)+9=675−141+9=543
Solution:
Let N=1000N = 1000N=1000
• A = divisible by 3 ⇒ ⌊1000/3⌋=333
• B = divisible by 5 ⇒ ⌊1000/5⌋=200
• C = divisible by 7 ⇒ ⌊1000/7⌋=142
Now pairwise:
• A ∩ B = divisible by 15 ⇒ ⌊1000/15⌋=66
• A ∩ C = divisible by 21 ⇒ ⌊1000/21⌋=47
• B ∩ C = divisible by 35 ⇒ ⌊1000/35⌋=28
Triple overlap:
• A ∩ B ∩ C = divisible by 105 ⇒ ⌊1000/105⌋=9
Now apply PIE:
∣A∪B∪C∣=333+200+142−(66+47+28)+9=675−141+9=543
• Question 5 of 5 5. Question The sum of the ages of a man and his son is 68 years. Four years ago, the product of their ages was 644. What is the present age of the man? (a) 44 years (b) 48 years (c) 50 years (d) 52 years Correct Answer: C Explanation: Let man’s age = x, then son’s = 68 − x 4 years ago: (x−4)(64−x)=644⇒x=50(x − 4)(64 − x) = 644 ⇒ x = 50(x−4)(64−x)=644⇒x=50 Answer: (c) 50 years Incorrect Answer: C Explanation: Let man’s age = x, then son’s = 68 − x 4 years ago: (x−4)(64−x)=644⇒x=50(x − 4)(64 − x) = 644 ⇒ x = 50(x−4)(64−x)=644⇒x=50 Answer: (c) 50 years
#### 5. Question
The sum of the ages of a man and his son is 68 years. Four years ago, the product of their ages was 644. What is the present age of the man?
• (a) 44 years
• (b) 48 years
• (c) 50 years
• (d) 52 years
Explanation: Let man’s age = x, then son’s = 68 − x 4 years ago: (x−4)(64−x)=644⇒x=50(x − 4)(64 − x) = 644 ⇒ x = 50(x−4)(64−x)=644⇒x=50
Answer: (c) 50 years
Explanation: Let man’s age = x, then son’s = 68 − x 4 years ago: (x−4)(64−x)=644⇒x=50(x − 4)(64 − x) = 644 ⇒ x = 50(x−4)(64−x)=644⇒x=50
Answer: (c) 50 years
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