UPSC Insta–DART (Daily Aptitude and Reasoning Test) 7 Aug 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question What is the HCF of 2334 and 2532 ? a) 2^53^3 b) 2^33^4 c) 2^33^2 d) 2^53^4 Correct Answer: (c) HCF is 2332 Incorrect Answer: (c) HCF is 2332
#### 1. Question
What is the HCF of 2334 and 2532 ?
• a) 2^5*3^3
• b) 2^3*3^4
• c) 2^3*3^2
• d) 2^5*3^4
Answer: (c) HCF is 23*32
Answer: (c) HCF is 23*32
• Question 2 of 5 2. Question When 13511 13903 and 14589 are divided by the greatest number ‘n’ the remainder in each case is ‘m’ the value of (n+ m) is. a) 183 b) 182 c) 181 d) 179 Correct Answer: (a) Explanation: The greatest number that divides the three numbers leaving the some remainder is HCF of the positive difference of three numbers 13903-13511=392 14589-13903=686 14589-13511=1078 HCF of 392, 686, 1078 is 98 Remainder by dividing any of three numbers by 98 we get remainder as 85 ,m=98 ,n=85 (m+ n)=183 Incorrect Answer: (a) Explanation: The greatest number that divides the three numbers leaving the some remainder is HCF of the positive difference of three numbers 13903-13511=392 14589-13903=686 14589-13511=1078 HCF of 392, 686, 1078 is 98 Remainder by dividing any of three numbers by 98 we get remainder as 85 ,m=98 ,n=85 (m+ n)=183
#### 2. Question
When 13511 13903 and 14589 are divided by the greatest number ‘n’ the remainder in each case is ‘m’ the value of (n+ m) is.
Answer: (a)
Explanation:
The greatest number that divides the three numbers leaving the some remainder is HCF of the positive difference of three numbers
13903-13511=392
14589-13903=686
14589-13511=1078
HCF of 392, 686, 1078 is 98
Remainder by dividing any of three numbers by 98 we get remainder as 85
(m+ n)=183
Answer: (a)
Explanation:
The greatest number that divides the three numbers leaving the some remainder is HCF of the positive difference of three numbers
13903-13511=392
14589-13903=686
14589-13511=1078
HCF of 392, 686, 1078 is 98
Remainder by dividing any of three numbers by 98 we get remainder as 85
(m+ n)=183
• Question 3 of 5 3. Question The sum of 2 numbers is 135 and their HCF is 9. How many such pairs of numbers can be formed ? a) 2 b) 5 c) 4 d) 6 Correct Answer: (c) 4 Explanation: Let the numbers be 9a and 9b 9a+9b=135 9(a+ b)=135 (a+ b) =15 (1,14), (2,13), (4,11), (7,8) Four pairs of co-prime are possible. Incorrect Answer: (c) 4 Explanation: Let the numbers be 9a and 9b 9a+9b=135 9(a+ b)=135 (a+ b) =15 (1,14), (2,13), (4,11), (7,8) Four pairs of co-prime are possible.
#### 3. Question
The sum of 2 numbers is 135 and their HCF is 9. How many such pairs of numbers can be formed ?
Answer: (c) 4
Explanation:
Let the numbers be 9a and 9b
9(a+ b)=135
(a+ b) =15
(1,14), (2,13), (4,11), (7,8)
Four pairs of co-prime are possible.
Answer: (c) 4
Explanation:
Let the numbers be 9a and 9b
9(a+ b)=135
(a+ b) =15
(1,14), (2,13), (4,11), (7,8)
Four pairs of co-prime are possible.
• Question 4 of 5 4. Question Three numbers are in the ratio 3:4:5 and their LCM is 4200 their HCF is a) 60 b) 20 c) 70 d) 15 Correct Answer: (c) 70 Explanation: Numbers be 3x4x5x=60x 60x=4200 X=70 HCF=70 Incorrect Answer: (c) 70 Explanation: Numbers be 3x4x5x=60x 60x=4200 X=70 HCF=70
#### 4. Question
Three numbers are in the ratio 3:4:5 and their LCM is 4200 their HCF is
Answer: (c) 70
Explanation:
Numbers be 3x4x5x=60x
Answer: (c) 70
Explanation:
Numbers be 3x4x5x=60x
• Question 5 of 5 5. Question The product of two numbers is 6845. If the HCF of the numbers is 37, then the greater number is, a) 111 b) 37 c) 48 d) 185 Correct Answer: (d) 185 Explanation: The numbers are 37x and 37y 37x37y=6845 ,xy=6845/3737 =5 (1,5) co-prime 371 and 375 are the numbers Greater number is 185 Incorrect Answer: (d) 185 Explanation: The numbers are 37x and 37y 37x37y=6845 ,xy=6845/3737 =5 (1,5) co-prime 371 and 375 are the numbers Greater number is 185
#### 5. Question
The product of two numbers is 6845. If the HCF of the numbers is 37, then the greater number is,
Answer: (d) 185
Explanation:
The numbers are 37x and 37y
37x*37y=6845
,xy=6845/37*37 =5
(1,5) co-prime
371 and 375 are the numbers
Greater number is 185
Answer: (d) 185
Explanation:
The numbers are 37x and 37y
37x*37y=6845
,xy=6845/37*37 =5
(1,5) co-prime
371 and 375 are the numbers
Greater number is 185
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