UPSC Insta–DART (Daily Aptitude and Reasoning Test) 6 Nov 2024

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

#### Quiz-summary

0 of 5 questions completed

Questions:

#### Information

Best of Luck! 🙂

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

0 of 5 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

#### Categories

• Not categorized 0%

• Question 1 of 5 1. Question If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 141 km downstream. a) 3hrs b) 4hrs c) 5 hrs d) 2 hrs Correct Answer: A Explanation: Speed of Upstream =u-v Speed of Downstream = u+v u-v+u+v=82 2u=82 u=41km/hr. 41 – v = 105/3 = 35 v = 6 km/hr then, u + v= 141/t 41 + 6 = 141/t t = 141/47 = 3 hrs. Incorrect Answer: A Explanation: Speed of Upstream =u-v Speed of Downstream = u+v u-v+u+v=82 2u=82 u=41km/hr. 41 – v = 105/3 = 35 v = 6 km/hr then, u + v= 141/t 41 + 6 = 141/t t = 141/47 = 3 hrs.

#### 1. Question

If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 141 km downstream.

Answer: A Explanation: Speed of Upstream =u-v Speed of Downstream = u+v u-v+u+v=82 2u=82 u=41km/hr. 41 – v = 105/3 = 35 v = 6 km/hr then, u + v= 141/t 41 + 6 = 141/t t = 141/47 = 3 hrs.

• Question 2 of 5 2. Question ‘L’ meters of long train cross a 480 m long tunnel in 40 sec running at the speed of 108 kmph. If train cross a man running in opposite direction in 8 sec, find speed of man (in km/hour). a) 118 km/hr b) 98 km/hr c) 100 km/hr d) 108 km/hr Correct Answer: D Explanation: speed of train=1085/18=30 sec ATQ, L+480/40=30 sec L=1200-480=720 let, the speed of man=’x’ sec 720/30+x=12 x=30m/sec sped of main =3018/5=108 km/hr Incorrect Answer: D Explanation: speed of train=1085/18=30 sec ATQ, L+480/40=30 sec L=1200-480=720 let, the speed of man=’x’ sec 720/30+x=12 x=30m/sec sped of main =3018/5=108 km/hr

#### 2. Question

‘L’ meters of long train cross a 480 m long tunnel in 40 sec running at the speed of 108 kmph. If train cross a man running in opposite direction in 8 sec, find speed of man (in km/hour).

• a) 118 km/hr

• b) 98 km/hr

• c) 100 km/hr

• d) 108 km/hr

Answer: D Explanation:

speed of train=1085/18=30 sec ATQ, L+480/40=30 sec L=1200-480=720 let, the speed of man=’x’ sec 720/30+x=12 x=30m/sec sped of main =3018/5=108 km/hr

Answer: D Explanation:

speed of train=1085/18=30 sec ATQ, L+480/40=30 sec L=1200-480=720 let, the speed of man=’x’ sec 720/30+x=12 x=30m/sec sped of main =3018/5=108 km/hr

• Question 3 of 5 3. Question A train can cross a tunnel of length 360m in 15sec, while a pole in 3 sec. In what time the train can cross a platform of length of 210 m. a) 20 sec b) 10 sec c) 15 sec d) 5 sec Correct Answer: B Explanation: let length of train be x meters (x+360)/15=x/3 15x=3x+1080 x=90 meters speed of train=90+360/15=450/15=30 m/sec required time=90+210/30=10 sec Incorrect Answer: B Explanation: let length of train be x meters (x+360)/15=x/3 15x=3x+1080 x=90 meters speed of train=90+360/15=450/15=30 m/sec required time=90+210/30=10 sec

#### 3. Question

A train can cross a tunnel of length 360m in 15sec, while a pole in 3 sec. In what time the train can cross a platform of length of 210 m.

Answer: B Explanation:

let length of train be x meters (x+360)/15=x/3 15x=3x+1080 x=90 meters speed of train=90+360/15=450/15=30 m/sec required time=90+210/30=10 sec

Answer: B Explanation:

let length of train be x meters (x+360)/15=x/3 15x=3x+1080 x=90 meters speed of train=90+360/15=450/15=30 m/sec required time=90+210/30=10 sec

• Question 4 of 5 4. Question Shivani can row a boat at 10 kmph in still water. If the speed of the stream is 6 kmph, the time taken to row a distance of 80 km down the stream is ? a) 8 hrs b) 9 hrs c) 5 hrs d) 7 hrs Correct Answer: C Explanation: Speed in still water, ½ (a+b) = 10 km/hr a+b = 20 km/hr…………….(1) speed of the stream, ½ (x-y) = 6km/hr x-y = 12 km/hr …………….(2) (1)+(2 ) we get 2x = 32 x= 16 km/hr speed downstream =distance traveled / time taken time taken = 80/16 = 5 hours Incorrect Answer: C Explanation: Speed in still water, ½ (a+b) = 10 km/hr a+b = 20 km/hr…………….(1) speed of the stream, ½ (x-y) = 6km/hr x-y = 12 km/hr …………….(2) (1)+(2 ) we get 2x = 32 x= 16 km/hr speed downstream =distance traveled / time taken time taken = 80/16 = 5 hours

#### 4. Question

Shivani can row a boat at 10 kmph in still water. If the speed of the stream is 6 kmph, the time taken to row a distance of 80 km down the stream is ?

Answer: C Explanation:

Speed in still water, ½ (a+b) = 10 km/hr a+b = 20 km/hr…………….(1) speed of the stream, ½ (x-y) = 6km/hr x-y = 12 km/hr …………….(2) (1)+(2 ) we get 2x = 32 x= 16 km/hr speed downstream =distance traveled / time taken time taken = 80/16 = 5 hours

Answer: C Explanation:

• Question 5 of 5 5. Question Srikant can row 9 (1/3) kmph in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. What is speed of current ? a) 4 (2/3) km/hr b) 5 (3/4) km/hr c) 6 (3/4) km/hr d) 8 (2/3) km/hr Correct Answer: A Explanation: Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (x+y) = 28/3 km/hr =½ (x+3x) = 28/3 2x = 28/3 = x = 28/ 2 x 3 = 14/3 km/hr rate upstream = 14/3 km/hr and rate downstream = 14/3 x 3 = 14 km/hr speed of the current = ½ (x-x) = ½ (14 – 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr Incorrect Answer: A Explanation: Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (x+y) = 28/3 km/hr =½ (x+3x) = 28/3 2x = 28/3 = x = 28/ 2 x 3 = 14/3 km/hr rate upstream = 14/3 km/hr and rate downstream = 14/3 x 3 = 14 km/hr speed of the current = ½ (x-x) = ½ (14 – 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr

#### 5. Question

Srikant can row 9 (1/3) kmph in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. What is speed of current ?

• a) 4 (2/3) km/hr

• b) 5 (3/4) km/hr

• c) 6 (3/4) km/hr

• d) 8 (2/3) km/hr

Answer: A Explanation:

Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (x+y) = 28/3 km/hr =½ (x+3x) = 28/3 2x = 28/3 = x = 28/ 2 x 3 = 14/3 km/hr rate upstream = 14/3 km/hr and rate downstream = 14/3 x 3 = 14 km/hr speed of the current = ½ (x-x) = ½ (14 – 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr

Answer: A Explanation:

• Official Facebook Page HERE

• Follow our Twitter Account HERE