UPSC Insta–DART (Daily Aptitude and Reasoning Test) 6 Mar 2026
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question A joint family consists of seven members P, Q, R, S, T, U and V with three females. V is a widow and sister-in-law of U. Q and S are siblings and T is the daughter of Q. R is the cousin of Q. Who is P? Father of Q Husband of V Uncle of R Select the correct answer using the code given below: (a) 1 and 2 only (b) 2 and 3 only (c) 1 and 3 only (d) 1, 2 and 3 Correct Answer: (c) Solution: Given: three females. T is daughter of Q ⇒ T is female. V is widow ⇒ V is female. So one female already fixed as T, one as V. Only one female left among P,Q,R,S,U. V is sister-in-law of U and widow. Most direct: V was wife of U’s brother. So her husband is a brother of U. Now Q and S are siblings. T is daughter of Q. R is cousin of Q ⇒ R is child of Q’s uncle/aunt. Now test statements about P: If P is father of Q ⇒ P is older generation male. Possible. Husband of V ⇒ that would make P the brother of U, but then P must be dead (since V is widow). Not possible if P is among current 7 family members (treated as living members). So statement (2) cannot be true. If P is uncle of R ⇒ since R is cousin of Q, and P is father of Q, P can be uncle of R (R is child of P’s sibling). This is consistent. Thus (1) and (3) are correct, but (2) is not. Hence option (c) 1 and 3 only is correct. Incorrect Answer: (c) Solution: Given: three females. T is daughter of Q ⇒ T is female. V is widow ⇒ V is female. So one female already fixed as T, one as V. Only one female left among P,Q,R,S,U. V is sister-in-law of U and widow. Most direct: V was wife of U’s brother. So her husband is a brother of U. Now Q and S are siblings. T is daughter of Q. R is cousin of Q ⇒ R is child of Q’s uncle/aunt. Now test statements about P: If P is father of Q ⇒ P is older generation male. Possible. Husband of V ⇒ that would make P the brother of U, but then P must be dead (since V is widow). Not possible if P is among current 7 family members (treated as living members). So statement (2) cannot be true. If P is uncle of R ⇒ since R is cousin of Q, and P is father of Q, P can be uncle of R (R is child of P’s sibling). This is consistent. Thus (1) and (3) are correct, but (2) is not. Hence option (c) 1 and 3 only is correct.
#### 1. Question
A joint family consists of seven members P, Q, R, S, T, U and V with three females. V is a widow and sister-in-law of U. Q and S are siblings and T is the daughter of Q. R is the cousin of Q. Who is P?
• Father of Q
• Husband of V
• Uncle of R
Select the correct answer using the code given below:
• (a) 1 and 2 only
• (b) 2 and 3 only
• (c) 1 and 3 only
• (d) 1, 2 and 3
Answer: (c)
Solution: Given: three females.
• T is daughter of Q ⇒ T is female.
• V is widow ⇒ V is female. So one female already fixed as T, one as V. Only one female left among P,Q,R,S,U.
V is sister-in-law of U and widow. Most direct: V was wife of U’s brother. So her husband is a brother of U.
Now Q and S are siblings. T is daughter of Q.
R is cousin of Q ⇒ R is child of Q’s uncle/aunt.
Now test statements about P:
• If P is father of Q ⇒ P is older generation male. Possible.
• Husband of V ⇒ that would make P the brother of U, but then P must be dead (since V is widow). Not possible if P is among current 7 family members (treated as living members). So statement (2) cannot be true.
• If P is uncle of R ⇒ since R is cousin of Q, and P is father of Q, P can be uncle of R (R is child of P’s sibling). This is consistent.
Thus (1) and (3) are correct, but (2) is not.
Hence option (c) 1 and 3 only is correct.
Answer: (c)
Solution: Given: three females.
• T is daughter of Q ⇒ T is female.
• V is widow ⇒ V is female. So one female already fixed as T, one as V. Only one female left among P,Q,R,S,U.
V is sister-in-law of U and widow. Most direct: V was wife of U’s brother. So her husband is a brother of U.
Now Q and S are siblings. T is daughter of Q.
R is cousin of Q ⇒ R is child of Q’s uncle/aunt.
Now test statements about P:
• If P is father of Q ⇒ P is older generation male. Possible.
• Husband of V ⇒ that would make P the brother of U, but then P must be dead (since V is widow). Not possible if P is among current 7 family members (treated as living members). So statement (2) cannot be true.
• If P is uncle of R ⇒ since R is cousin of Q, and P is father of Q, P can be uncle of R (R is child of P’s sibling). This is consistent.
Thus (1) and (3) are correct, but (2) is not.
Hence option (c) 1 and 3 only is correct.
• Question 2 of 5 2. Question Ten persons V, W, X, Y, Z and five others speak in random order. What is the chance that V speaks after W, W after X, X after Y, and Y after Z (i.e., V after W after X after Y after Z)? (a) 1/60 (b) 1/120 (c) 1/24 (d) 1/6 Correct Answer: (b) Solution: Total number of ways = 10! Number of ways to place V, W, X, Y, Z in the given order = ¹⁰C₅ Arrangements of the remaining 5 persons = 5! Favourable ways = ¹⁰C₅ × 5! Required chance = (¹⁰C₅ × 5!) / 10! = 1/5! = 1/120 Hence, option (b) is correct. Incorrect Answer: (b) Solution: Total number of ways = 10! Number of ways to place V, W, X, Y, Z in the given order = ¹⁰C₅ Arrangements of the remaining 5 persons = 5! Favourable ways = ¹⁰C₅ × 5! Required chance = (¹⁰C₅ × 5!) / 10! = 1/5! = 1/120 Hence, option (b) is correct.
#### 2. Question
Ten persons V, W, X, Y, Z and five others speak in random order. What is the chance that V speaks after W, W after X, X after Y, and Y after Z (i.e., V after W after X after Y after Z)?
Answer: (b) Solution: Total number of ways = 10! Number of ways to place V, W, X, Y, Z in the given order = ¹⁰C₅ Arrangements of the remaining 5 persons = 5! Favourable ways = ¹⁰C₅ × 5! Required chance = (¹⁰C₅ × 5!) / 10! = 1/5! = 1/120 Hence, option (b) is correct.
Answer: (b) Solution: Total number of ways = 10! Number of ways to place V, W, X, Y, Z in the given order = ¹⁰C₅ Arrangements of the remaining 5 persons = 5! Favourable ways = ¹⁰C₅ × 5! Required chance = (¹⁰C₅ × 5!) / 10! = 1/5! = 1/120 Hence, option (b) is correct.
• Question 3 of 5 3. Question While writing all the numbers from 500 to 999, how many numbers occur in which the digit at hundred’s place is less than the digit at ten’s place, and the digit at ten’s place is less than the digit at unit’s place? (a) 9 (b) 10 (c) 12 (d) 15 Correct Answer: (b) Solution: Given that, From 500 to 999, we need strictly increasing digits: H < T < U. Now, For each hundred’s digit H, choose two larger digits for (T,U) from {H+1,…,9}. H = 5 → choose two from {6,7,8,9}: 6 ways. H = 6 → from {7,8,9}: 3 ways. H = 7 → from {8,9}: 1 way. H = 8 or 9 → 0 ways. Total = 6 + 3 + 1 = 10. Hence option (b) is correct. Incorrect Answer: (b) Solution: Given that, From 500 to 999, we need strictly increasing digits: H < T < U. Now, For each hundred’s digit H, choose two larger digits for (T,U) from {H+1,…,9}. H = 5 → choose two from {6,7,8,9}: 6 ways. H = 6 → from {7,8,9}: 3 ways. H = 7 → from {8,9}: 1 way. H = 8 or 9 → 0 ways. Total = 6 + 3 + 1 = 10. Hence option (b) is correct.
#### 3. Question
While writing all the numbers from 500 to 999, how many numbers occur in which the digit at hundred’s place is less than the digit at ten’s place, and the digit at ten’s place is less than the digit at unit’s place?
Answer: (b)
Given that,
From 500 to 999, we need strictly increasing digits: H < T < U.
For each hundred’s digit H, choose two larger digits for (T,U) from {H+1,…,9}.
H = 5 → choose two from {6,7,8,9}: 6 ways. H = 6 → from {7,8,9}: 3 ways. H = 7 → from {8,9}: 1 way. H = 8 or 9 → 0 ways.
Total = 6 + 3 + 1 = 10.
Hence option (b) is correct.
Answer: (b)
Given that,
From 500 to 999, we need strictly increasing digits: H < T < U.
For each hundred’s digit H, choose two larger digits for (T,U) from {H+1,…,9}.
H = 5 → choose two from {6,7,8,9}: 6 ways. H = 6 → from {7,8,9}: 3 ways. H = 7 → from {8,9}: 1 way. H = 8 or 9 → 0 ways.
Total = 6 + 3 + 1 = 10.
Hence option (b) is correct.
• Question 4 of 5 4. Question One-half of the employees in a company are permanent. Two-thirds of the employees are graduates. Three-fourths of the employees are below 35 years of age. Which one of the following statements is certainly correct? (a) All permanent employees are graduates. (b) Some employees below 35 years of age are graduates. (c) Only half of the graduates are permanent employees. (d) No employee below 35 years of age is permanent. Correct Answer: (b) Solution: Given: Graduates = 2/3 = 66.67% Below 35 = 3/4 = 75% Sum = 66.67% + 75% = 141.67% > 100% So there must be an overlap between “graduates” and “below 35”. Therefore, some employees below 35 years of age are graduates. Hence option (b) is certainly correct. Incorrect Answer: (b) Solution: Given: Graduates = 2/3 = 66.67% Below 35 = 3/4 = 75% Sum = 66.67% + 75% = 141.67% > 100% So there must be an overlap between “graduates” and “below 35”. Therefore, some employees below 35 years of age are graduates. Hence option (b) is certainly correct.
#### 4. Question
One-half of the employees in a company are permanent. Two-thirds of the employees are graduates. Three-fourths of the employees are below 35 years of age. Which one of the following statements is certainly correct?
• (a) All permanent employees are graduates.
• (b) Some employees below 35 years of age are graduates.
• (c) Only half of the graduates are permanent employees.
• (d) No employee below 35 years of age is permanent.
Answer: (b)
Solution: Given:
• Graduates = 2/3 = 66.67%
• Below 35 = 3/4 = 75%
Sum = 66.67% + 75% = 141.67% > 100% So there must be an overlap between “graduates” and “below 35”.
Therefore, some employees below 35 years of age are graduates. Hence option (b) is certainly correct.
Answer: (b)
Solution: Given:
• Graduates = 2/3 = 66.67%
• Below 35 = 3/4 = 75%
Sum = 66.67% + 75% = 141.67% > 100% So there must be an overlap between “graduates” and “below 35”.
Therefore, some employees below 35 years of age are graduates. Hence option (b) is certainly correct.
• Question 5 of 5 5. Question If to a proper fraction, the numerator is increased and the denominator is decreased by the same positive quantity (> 0) (and the denominator remains positive), the resulting fraction is (a) Always less than the original fraction (b) Always greater than the original fraction (c) Always equal to the original fraction (d) Such that nothing can be claimed definitely Correct Answer: B Solution: Given that, If the numerator is increased and the denominator is decreased by the same positive quantity Considering fraction 5/7, make (+2, −2) = 7/5 7/5 > 5/7 Hence option (b) is correct Incorrect Answer: B Solution: Given that, If the numerator is increased and the denominator is decreased by the same positive quantity Considering fraction 5/7, make (+2, −2) = 7/5 7/5 > 5/7 Hence option (b) is correct
#### 5. Question
If to a proper fraction, the numerator is increased and the denominator is decreased by the same positive quantity (> 0) (and the denominator remains positive), the resulting fraction is
• (a) Always less than the original fraction
• (b) Always greater than the original fraction
• (c) Always equal to the original fraction
• (d) Such that nothing can be claimed definitely
Answer: B
Solution:
Given that,
If the numerator is increased and the denominator is decreased by the same positive quantity
Considering fraction 5/7, make (+2, −2) = 7/5
Hence option (b) is correct
Answer: B
Solution:
Given that,
If the numerator is increased and the denominator is decreased by the same positive quantity
Considering fraction 5/7, make (+2, −2) = 7/5
Hence option (b) is correct
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