UPSC Insta–DART (Daily Aptitude and Reasoning Test) 5 Mar 2026

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question A project requires 120 man-hours to complete. If 6 workers start at 8:00 am, then the team increases to 10 workers at 12:00 pm, and 15 workers from 3:00 pm, at what time will the project be finished? (a) 4:50 pm (b) 6:00 pm (b) 6:00 pm (d) 8:09 pm Correct Answer: (c) Explanation: Total work = 120 man-hours. 8–12 pm: 6 × 4 = 24 man-hours. Remaining = 120 – 24 = 96. 12–3 pm: 10 × 3 = 30 man-hours. Remaining = 96 – 30 = 66. After 3 pm: 15 workers ⇒ 15 man-hours/hour. Time to finish = 66 ÷ 15 = 4.4 hours = 4 hours 24 min. So completion time = 3:00 pm + 4 h 24 min = 7:24 pm. Incorrect Answer: (c) Explanation: Total work = 120 man-hours. 8–12 pm: 6 × 4 = 24 man-hours. Remaining = 120 – 24 = 96. 12–3 pm: 10 × 3 = 30 man-hours. Remaining = 96 – 30 = 66. After 3 pm: 15 workers ⇒ 15 man-hours/hour. Time to finish = 66 ÷ 15 = 4.4 hours = 4 hours 24 min. So completion time = 3:00 pm + 4 h 24 min = 7:24 pm.

#### 1. Question

A project requires 120 man-hours to complete. If 6 workers start at 8:00 am, then the team increases to 10 workers at 12:00 pm, and 15 workers from 3:00 pm, at what time will the project be finished?

• (a) 4:50 pm

• (b) 6:00 pm

• (d) 8:09 pm

Answer: (c)

Explanation: Total work = 120 man-hours. 8–12 pm: 6 × 4 = 24 man-hours. Remaining = 120 – 24 = 96. 12–3 pm: 10 × 3 = 30 man-hours. Remaining = 96 – 30 = 66. After 3 pm: 15 workers ⇒ 15 man-hours/hour. Time to finish = 66 ÷ 15 = 4.4 hours = 4 hours 24 min. So completion time = 3:00 pm + 4 h 24 min = 7:24 pm.

Answer: (c)

• Question 2 of 5 2. Question Aman and Bimal work for a courier company. When Aman delivers alone, he delivers 60 parcels in a hours. When both Aman and Bimal deliver simultaneously at their optimum capacity, they deliver 60 parcels in b hours. How many hours will be taken by Bimal, working alone, in delivering 60 parcels? (a) a/(a + b) (b) b/(a + b) (c) ab/(a + b) (d) ab/(a − b) Correct Answer: (d) Explanation Let 60 be a unit. Aman’s rate = 1/a (unit per hour) Combined rate = 1/b (unit per hour) Bimal’s rate = (combined) − (Aman) = 1/b − 1/a = (a − b)/(ab) (unit per hour) Time for Bimal to deliver 1 unit = 1 ÷ [(a − b)/(ab)] = ab/(a − b) hours. Hence, option (d) is correct. Incorrect Answer: (d) Explanation Let 60 be a unit. Aman’s rate = 1/a (unit per hour) Combined rate = 1/b (unit per hour) Bimal’s rate = (combined) − (Aman) = 1/b − 1/a = (a − b)/(ab) (unit per hour) Time for Bimal to deliver 1 unit = 1 ÷ [(a − b)/(ab)] = ab/(a − b) hours. Hence, option (d) is correct.

#### 2. Question

Aman and Bimal work for a courier company. When Aman delivers alone, he delivers 60 parcels in a hours. When both Aman and Bimal deliver simultaneously at their optimum capacity, they deliver 60 parcels in b hours. How many hours will be taken by Bimal, working alone, in delivering 60 parcels?

• (a) a/(a + b)

• (b) b/(a + b)

• (c) ab/(a + b)

• (d) ab/(a − b)

Answer: (d) Explanation Let 60 be a unit. Aman’s rate = 1/a (unit per hour) Combined rate = 1/b (unit per hour) Bimal’s rate = (combined) − (Aman) = 1/b − 1/a = (a − b)/(ab) (unit per hour) Time for Bimal to deliver 1 unit = 1 ÷ [(a − b)/(ab)] = ab/(a − b) hours. Hence, option (d) is correct.

• Question 3 of 5 3. Question Pipes A and B can fill a tank with water in 36 minutes and 45 minutes, respectively, while pipe C can drain off 56 litres per minute. If all the three pipes are opened together, the tank is filled in 180 minutes. What is the capacity (in litres) of the tank? (a) 960 (b) 1050 (c) 1170 (d) 1260 Correct Capacity of the tank = 1260 litres. Incorrect Capacity of the tank = 1260 litres.

#### 3. Question

Pipes A and B can fill a tank with water in 36 minutes and 45 minutes, respectively, while pipe C can drain off 56 litres per minute. If all the three pipes are opened together, the tank is filled in 180 minutes. What is the capacity (in litres) of the tank?

Capacity of the tank = 1260 litres.

• Question 4 of 5 4. Question A hot water tap can fill a tank in 12 minutes and a cold-water tap can fill the same tank in 18 minutes. Rakesh opens both taps together and after 5 minutes he closes the hot-water tap. Cold water tap will fill the remaining part of the tank in: (a) 5 minutes 12 seconds (b) 5 minutes 30 seconds (c) 5 minutes 36 seconds (d) 5 minutes 45 seconds Correct Answer: B Explanation: Hot water tap fills (1/12) per minute; cold-water tap fills (1/18) per minute. Work done by both pipes in 5 minutes = 5 × [(1/12) + (1/18)] = 5 × [(3 + 2)/36] = 5 × (5/36) = 25/36. Remaining part = 1 − (25/36) = 11/36. Time by cold-water tap = (11/36)/(1/18) = (11/36) × 18 = 11/2 = 5 minutes 30 seconds. Hence, option (b) is correct. Incorrect Answer: B Explanation: Hot water tap fills (1/12) per minute; cold-water tap fills (1/18) per minute. Work done by both pipes in 5 minutes = 5 × [(1/12) + (1/18)] = 5 × [(3 + 2)/36] = 5 × (5/36) = 25/36. Remaining part = 1 − (25/36) = 11/36. Time by cold-water tap = (11/36)/(1/18) = (11/36) × 18 = 11/2 = 5 minutes 30 seconds. Hence, option (b) is correct.

#### 4. Question

A hot water tap can fill a tank in 12 minutes and a cold-water tap can fill the same tank in 18 minutes. Rakesh opens both taps together and after 5 minutes he closes the hot-water tap. Cold water tap will fill the remaining part of the tank in:

• (a) 5 minutes 12 seconds

• (b) 5 minutes 30 seconds

• (c) 5 minutes 36 seconds

• (d) 5 minutes 45 seconds

Answer: B Explanation: Hot water tap fills (1/12) per minute; cold-water tap fills (1/18) per minute. Work done by both pipes in 5 minutes = 5 × [(1/12) + (1/18)] = 5 × [(3 + 2)/36] = 5 × (5/36) = 25/36. Remaining part = 1 − (25/36) = 11/36. Time by cold-water tap = (11/36)/(1/18) = (11/36) × 18 = 11/2 = 5 minutes 30 seconds. Hence, option (b) is correct.

• Question 5 of 5 5. Question Consider the following statements: Statement I: There are 60 three-digit numbers divisible by 15. Statement II: There are 100 three-digit numbers divisible by 5. Which of the statements is/are correct? (a) I only (b) II only (c) Both I and II (d) Neither I nor II Correct Answer: (a) Solution: For Statement I: Smallest 3-digit multiple of 15 = 105, largest = 990. Count = (990 − 105)/15 + 1 = 885/15 + 1 = 59 + 1 = 60 → correct. For Statement II: Smallest 3-digit multiple of 5 = 100, largest = 995. Count = (995 − 100)/5 + 1 = 895/5 + 1 = 179 + 1 = 180 → not 100 → incorrect. Hence, only Statement I is correct. Incorrect Answer: (a) Solution: For Statement I: Smallest 3-digit multiple of 15 = 105, largest = 990. Count = (990 − 105)/15 + 1 = 885/15 + 1 = 59 + 1 = 60 → correct. For Statement II: Smallest 3-digit multiple of 5 = 100, largest = 995. Count = (995 − 100)/5 + 1 = 895/5 + 1 = 179 + 1 = 180 → not 100 → incorrect. Hence, only Statement I is correct.

#### 5. Question

Consider the following statements:

Statement I: There are 60 three-digit numbers divisible by 15. Statement II: There are 100 three-digit numbers divisible by 5. Which of the statements is/are correct?

• (a) I only

• (b) II only

• (c) Both I and II

• (d) Neither I nor II

Answer: (a) Solution: For Statement I: Smallest 3-digit multiple of 15 = 105, largest = 990. Count = (990 − 105)/15 + 1 = 885/15 + 1 = 59 + 1 = 60 → correct. For Statement II: Smallest 3-digit multiple of 5 = 100, largest = 995. Count = (995 − 100)/5 + 1 = 895/5 + 1 = 179 + 1 = 180 → not 100 → incorrect. Hence, only Statement I is correct.

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