UPSC Insta–DART (Daily Aptitude and Reasoning Test) 4 Oct 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question The following questions are accompanied by three statements (I), (II), and (III). You have to determine which statement(s) is/are sufficient /necessary to answer the question. Question: What is distance between A and B? I. Two persons Amit and Abhi started simultaneously from A to B with their speed in ratio 4 : 5. II. Abhi reached one hour earlier than Amit. III. Difference between speed of Amit and Abhi is 20 km/hr. a) Only I and II. b) Only II and III c) I, II and III d) Cannot be answered even including all three statements Correct Answer: Option (c) Explanation: From I, II & III Let speed of Amit and Abhi be 4x and 5x km/hr respectively. 5x – 4x = 20 ∴ x = 20 km/hr Let distance be d km (d/80) – (d/100) = 1 ∴ d = (80×100)/20 = 400km Hence, option (c) is correct answer Incorrect Answer: Option (c) Explanation: From I, II & III Let speed of Amit and Abhi be 4x and 5x km/hr respectively. 5x – 4x = 20 ∴ x = 20 km/hr Let distance be d km (d/80) – (d/100) = 1 ∴ d = (80×100)/20 = 400km Hence, option (c) is correct answer
#### 1. Question
The following questions are accompanied by three statements (I), (II), and (III). You have to determine which statement(s) is/are sufficient /necessary to answer the question.
Question: What is distance between A and B?
I. Two persons Amit and Abhi started simultaneously from A to B with their speed in ratio 4 : 5.
II. Abhi reached one hour earlier than Amit.
III. Difference between speed of Amit and Abhi is 20 km/hr.
• a) Only I and II.
• b) Only II and III
• c) I, II and III
• d) Cannot be answered even including all three statements
Answer: Option (c)
Explanation:
From I, II & III
Let speed of Amit and Abhi be 4x and 5x km/hr respectively.
5x – 4x = 20
∴ x = 20 km/hr
Let distance be d km
(d/80) – (d/100) = 1
∴ d = (80×100)/20 = 400km Hence, option (c) is correct answer
Answer: Option (c)
Explanation:
From I, II & III
Let speed of Amit and Abhi be 4x and 5x km/hr respectively.
5x – 4x = 20
∴ x = 20 km/hr
Let distance be d km
(d/80) – (d/100) = 1
∴ d = (80×100)/20 = 400km Hence, option (c) is correct answer
• Question 2 of 5 2. Question Two trains start at the same time from Bengaluru and Shimoga and proceed towards each other at 70 kmph and 85 kmph respectively. When they meet, it is found that one train has travelled 150 km more than the other. Find the distance between Bengaluru and Shimoga. a) 1550 km b) 1750 km c) 1250 km d) 1600 km Correct Answer: Option (a) Explanation: Let t be the time taken by them to meet. Distance travelled by first train = Speed × Time = 70 × t = 70t Distance travelled by second train = Speed × Time = 85 × t = 85t Now, the difference in the distances travelled by the two trains is 150 kms Therefore, 85t – 70t = 150 or 15t = 150 or t = 10 hr So, Total Distance between Bengaluru and Shimoga = (85 + 70) t = 155 × 10 = 1550 kms Incorrect Answer: Option (a) Explanation: Let t be the time taken by them to meet. Distance travelled by first train = Speed × Time = 70 × t = 70t Distance travelled by second train = Speed × Time = 85 × t = 85t Now, the difference in the distances travelled by the two trains is 150 kms Therefore, 85t – 70t = 150 or 15t = 150 or t = 10 hr So, Total Distance between Bengaluru and Shimoga = (85 + 70) t = 155 × 10 = 1550 kms
#### 2. Question
Two trains start at the same time from Bengaluru and Shimoga and proceed towards each other at 70 kmph and 85 kmph respectively. When they meet, it is found that one train has travelled 150 km more than the other. Find the distance between Bengaluru and Shimoga.
• a) 1550 km
• b) 1750 km
• c) 1250 km
• d) 1600 km
Answer: Option (a)
Explanation:
Let t be the time taken by them to meet.
Distance travelled by first train = Speed × Time = 70 × t = 70t
Distance travelled by second train = Speed × Time = 85 × t = 85t
Now, the difference in the distances travelled by the two trains is 150 kms
Therefore, 85t – 70t = 150
or 15t = 150
or t = 10 hr So, Total Distance between Bengaluru and Shimoga = (85 + 70) t = 155 × 10 = 1550 kms
Answer: Option (a)
Explanation:
Let t be the time taken by them to meet.
Distance travelled by first train = Speed × Time = 70 × t = 70t
Distance travelled by second train = Speed × Time = 85 × t = 85t
Now, the difference in the distances travelled by the two trains is 150 kms
Therefore, 85t – 70t = 150
or 15t = 150
or t = 10 hr So, Total Distance between Bengaluru and Shimoga = (85 + 70) t = 155 × 10 = 1550 kms
• Question 3 of 5 3. Question Mohan travels from Delhi to Agra at an average speed of 75 Km/h covering the distance in 4 hours. While returning, he takes a different route from Agra to Delhi and reaches Delhi after a journey of 4 hours. Which of the following statements is correct? a) The average speed of Mohan while going to Agra is same as the average speed while returning from Agra. b) The average speed of Mohan while going to Agra is greater than the average speed while returning from Agra. c) The average speed of Mohan while going to Agra is less than the average speed while returning from Agra. d) No conclusion can be drawn regarding the average speeds. Correct Answer: Option (d) Explanation: As Mohan takes a different path while returning from Agra, the distance of the new path is not known. Hence, no conclusion regarding the speed can be made. Incorrect Answer: Option (d) Explanation: As Mohan takes a different path while returning from Agra, the distance of the new path is not known. Hence, no conclusion regarding the speed can be made.
#### 3. Question
Mohan travels from Delhi to Agra at an average speed of 75 Km/h covering the distance in 4 hours. While returning, he takes a different route from Agra to Delhi and reaches Delhi after a journey of 4 hours. Which of the following statements is correct?
• a) The average speed of Mohan while going to Agra is same as the average speed while returning from Agra.
• b) The average speed of Mohan while going to Agra is greater than the average speed while returning from Agra.
• c) The average speed of Mohan while going to Agra is less than the average speed while returning from Agra.
• d) No conclusion can be drawn regarding the average speeds.
Answer: Option (d)
Explanation:
As Mohan takes a different path while returning from Agra, the distance of the new path is not known. Hence, no conclusion regarding the speed can be made.
Answer: Option (d)
Explanation:
As Mohan takes a different path while returning from Agra, the distance of the new path is not known. Hence, no conclusion regarding the speed can be made.
• Question 4 of 5 4. Question A water tank is filled in 5 hours by three pipes X, Y and Z the pipe Z is thrice as fast as Y and Y is twice as fast as X. How much time will pipe X alone take to fill the water tank? a) 60 hrs b) 45 hrs c) 40 hrs d) 35 hrs Correct Answer: Option (b) Explanation: A water tank is filled in 5 hours by three pipes X, Y and Z the pipe Z is thrice as fast as Y and Y is twice as fast as X. Now equate both the ratios by making Y equal in both, So, Z : Y : X = 6 : 2 : 1 (this is the ratio of efficiencies of the pipes) If three pipes fill the tank in 5 hours, there fore the total work done is = Time × Total Efficiency of pipes = 5 × (6+2+1) = 45 So X will take time = Work/ X’s Efficiency = 45/1 = 45 hours Incorrect Answer: Option (b) Explanation: A water tank is filled in 5 hours by three pipes X, Y and Z the pipe Z is thrice as fast as Y and Y is twice as fast as X. Now equate both the ratios by making Y equal in both, So, Z : Y : X = 6 : 2 : 1 (this is the ratio of efficiencies of the pipes) If three pipes fill the tank in 5 hours, there fore the total work done is = Time × Total Efficiency of pipes = 5 × (6+2+1) = 45 So X will take time = Work/ X’s Efficiency = 45/1 = 45 hours
#### 4. Question
A water tank is filled in 5 hours by three pipes X, Y and Z the pipe Z is thrice as fast as Y and Y is twice as fast as X. How much time will pipe X alone take to fill the water tank?
Answer: Option (b)
Explanation:
A water tank is filled in 5 hours by three pipes X, Y and Z the pipe Z is thrice as fast as Y and Y is twice as fast as X.
Now equate both the ratios by making Y equal in both,
So, Z : Y : X = 6 : 2 : 1 (this is the ratio of efficiencies of the pipes)
If three pipes fill the tank in 5 hours, there fore the total work done is
= Time × Total Efficiency of pipes
= 5 × (6+2+1) = 45
So X will take time = Work/ X’s Efficiency
= 45/1 = 45 hours
Answer: Option (b)
Explanation:
A water tank is filled in 5 hours by three pipes X, Y and Z the pipe Z is thrice as fast as Y and Y is twice as fast as X.
Now equate both the ratios by making Y equal in both,
So, Z : Y : X = 6 : 2 : 1 (this is the ratio of efficiencies of the pipes)
If three pipes fill the tank in 5 hours, there fore the total work done is
= Time × Total Efficiency of pipes
= 5 × (6+2+1) = 45
So X will take time = Work/ X’s Efficiency
= 45/1 = 45 hours
• Question 5 of 5 5. Question Pipe A is an inlet pipe that can fill an empty cistern in 69 hours. Pipe B can drain the filled cistern in 46 hours. When the cistern was filled the two pipes are opened one at a time for an hour each, starting with Pipe B. how long will it take for the cistern to be empty? a) 11 days 10 hours b) 11 days 7 hours c) 11 days 12 hours d) 1 days 13 hours Correct Answer: Option (b) Explanation: Pipe A can fill cistern in 69 hours. Pipe B can empty cistern in 46 hours. Let’s assume total work = 138 Efficiency of A = 2 Efficiency of B = -3 (Subtraction sign is due to outlet pipe.) For empty the cistern, Alternatively pipe B and A respectively work. So in every 2 hours 1 part of tank is empty out of total 138. Then we can say that for emptying 135 parts, we need 270 hours and last 1 hour B will empty 3 parts. So 270 + 1 = 271 hours If we convert 271 hours in days by dividing 24. Then got 11 days 7 hours. Incorrect Answer: Option (b) Explanation: Pipe A can fill cistern in 69 hours. Pipe B can empty cistern in 46 hours. Let’s assume total work = 138 Efficiency of A = 2 Efficiency of B = -3 (Subtraction sign is due to outlet pipe.) For empty the cistern, Alternatively pipe B and A respectively work. So in every 2 hours 1 part of tank is empty out of total 138. Then we can say that for emptying 135 parts, we need 270 hours and last 1 hour B will empty 3 parts. So 270 + 1 = 271 hours If we convert 271 hours in days by dividing 24. Then got 11 days 7 hours.
#### 5. Question
Pipe A is an inlet pipe that can fill an empty cistern in 69 hours. Pipe B can drain the filled cistern in 46 hours. When the cistern was filled the two pipes are opened one at a time for an hour each, starting with Pipe B. how long will it take for the cistern to be empty?
• a) 11 days 10 hours
• b) 11 days 7 hours
• c) 11 days 12 hours
• d) 1 days 13 hours
Answer: Option (b)
Explanation:
Pipe A can fill cistern in 69 hours.
Pipe B can empty cistern in 46 hours.
Let’s assume total work = 138
Efficiency of A = 2
Efficiency of B = -3 (Subtraction sign is due to outlet pipe.)
For empty the cistern, Alternatively pipe B and A respectively work. So in every 2 hours 1 part of tank is empty out of total 138.
Then we can say that for emptying 135 parts, we need 270 hours and last 1 hour B will empty 3 parts.
So 270 + 1 = 271 hours
If we convert 271 hours in days by dividing 24. Then got 11 days 7 hours.
Answer: Option (b)
Explanation:
Pipe A can fill cistern in 69 hours.
Pipe B can empty cistern in 46 hours.
Let’s assume total work = 138
Efficiency of A = 2
Efficiency of B = -3 (Subtraction sign is due to outlet pipe.)
For empty the cistern, Alternatively pipe B and A respectively work. So in every 2 hours 1 part of tank is empty out of total 138.
Then we can say that for emptying 135 parts, we need 270 hours and last 1 hour B will empty 3 parts.
So 270 + 1 = 271 hours
If we convert 271 hours in days by dividing 24. Then got 11 days 7 hours.
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