UPSC Insta–DART (Daily Aptitude and Reasoning Test) 30 Sep 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Akshay drove his car at a speed 40 km/h. After 30 minutes, Anup started chasing him at a speed of 60 km/h (through the same route). Find how much distance Anup will have to cover to chase down Akshay. a) 45 km b) 50 km c) 40 km d) 60 km Correct Answer: Option (d) Explanation: Speed of Akshay= 40 km/h. Speed of Anup = 60 km/h. Their relative speed = 60 – 40 (they are moving in the same direction) = 20 km/h. Distance travelled by Akshay in 30 minutes (1/2 hour) = 40×1/2 (distance =speed×time) = 20 km. So the time taken by Anup to meet Akshay = Distance/Relative speed = 20/20 = 1 h. Hence, the distance Anup need to cover = speed of Anup × time needed = 60×1 = 60 km. Incorrect Answer: Option (d) Explanation: Speed of Akshay= 40 km/h. Speed of Anup = 60 km/h. Their relative speed = 60 – 40 (they are moving in the same direction) = 20 km/h. Distance travelled by Akshay in 30 minutes (1/2 hour) = 40×1/2 (distance =speed×time) = 20 km. So the time taken by Anup to meet Akshay = Distance/Relative speed = 20/20 = 1 h. Hence, the distance Anup need to cover = speed of Anup × time needed = 60×1 = 60 km.
#### 1. Question
Akshay drove his car at a speed 40 km/h. After 30 minutes, Anup started chasing him at a speed of 60 km/h (through the same route). Find how much distance Anup will have to cover to chase down Akshay.
Answer: Option (d)
Explanation:
Speed of Akshay= 40 km/h.
Speed of Anup = 60 km/h.
Their relative speed = 60 – 40 (they are moving in the same direction) = 20 km/h.
Distance travelled by Akshay in 30 minutes (1/2 hour)
= 40×1/2 (distance =speed×time) = 20 km.
So the time taken by Anup to meet Akshay
= Distance/Relative speed
= 20/20 = 1 h.
Hence, the distance Anup need to cover
= speed of Anup × time needed
= 60×1 = 60 km.
Answer: Option (d)
Explanation:
Speed of Akshay= 40 km/h.
Speed of Anup = 60 km/h.
Their relative speed = 60 – 40 (they are moving in the same direction) = 20 km/h.
Distance travelled by Akshay in 30 minutes (1/2 hour)
= 40×1/2 (distance =speed×time) = 20 km.
So the time taken by Anup to meet Akshay
= Distance/Relative speed
= 20/20 = 1 h.
Hence, the distance Anup need to cover
= speed of Anup × time needed
= 60×1 = 60 km.
• Question 2 of 5 2. Question Quantity I – A train running at the speed of 72 km/hr passed a man in 14 sec and a platform in 32 sec. Find the length of platform ? Quantity II – A train moves at the speed of 108 km/hr, passes a platform and a bridge in 15 sec and 18 sec respectively. If the length of platform is 50% of length of bridge, then find the length of train. a) Quantity I > Quantity II b) Quantity I < Quantity II c) Quantity I = Quantity II d) Quantity I ≤ Quantity II Correct Answer: Option (c) Explanation: Quantity I – Let length of train be L meter ATQ— Speed = 72 × 5/18 = 20 m/sec 20 = L/14 L = 280 meter Let length of platform be P meter 20 = (P+280)/32 P = 640 – 280 P = 360 meter Quantity II – Let’s length of train is X meter and length of bridge and platform are 2L and L meter respectively Speed of train = 108 × 5/18 = 30m/s When train passed the bridge Distance covered = X + 2L X + 2L = 540 …(i) When train passes the platform Distance covered = X + L X + L = 450 …(ii) From (i) and (ii) L = 90 meter X = 360 meter So, Quantity I = Quantity II Hence, option (c) is the correct answer. Incorrect Answer: Option (c) Explanation: Quantity I – Let length of train be L meter ATQ— Speed = 72 × 5/18 = 20 m/sec 20 = L/14 L = 280 meter Let length of platform be P meter 20 = (P+280)/32 P = 640 – 280 P = 360 meter Quantity II – Let’s length of train is X meter and length of bridge and platform are 2L and L meter respectively Speed of train = 108 × 5/18 = 30m/s When train passed the bridge Distance covered = X + 2L X + 2L = 540 …(i) When train passes the platform Distance covered = X + L X + L = 450 …(ii) From (i) and (ii) L = 90 meter X = 360 meter So, Quantity I = Quantity II Hence, option (c) is the correct answer.
#### 2. Question
Quantity I – A train running at the speed of 72 km/hr passed a man in 14 sec and a platform in 32 sec. Find the length of platform ?
Quantity II – A train moves at the speed of 108 km/hr, passes a platform and a bridge in 15 sec and 18 sec respectively. If the length of platform is 50% of length of bridge, then find the length of train.
• a) Quantity I > Quantity II
• b) Quantity I < Quantity II
• c) Quantity I = Quantity II
• d) Quantity I ≤ Quantity II
Answer: Option (c)
Explanation:
Quantity I – Let length of train be L meter
Speed = 72 × 5/18 = 20 m/sec
L = 280 meter
Let length of platform be P meter
20 = (P+280)/32
P = 640 – 280
P = 360 meter
Quantity II – Let’s length of train is X meter and length of bridge
and platform are 2L and L meter respectively
Speed of train = 108 × 5/18 = 30m/s
When train passed the bridge
Distance covered = X + 2L
X + 2L = 540 …(i)
When train passes the platform
Distance covered = X + L
X + L = 450 …(ii)
From (i) and (ii)
L = 90 meter
X = 360 meter
So, Quantity I = Quantity II Hence, option (c) is the correct answer.
Answer: Option (c)
Explanation:
Quantity I – Let length of train be L meter
Speed = 72 × 5/18 = 20 m/sec
L = 280 meter
Let length of platform be P meter
20 = (P+280)/32
P = 640 – 280
P = 360 meter
Quantity II – Let’s length of train is X meter and length of bridge
and platform are 2L and L meter respectively
Speed of train = 108 × 5/18 = 30m/s
When train passed the bridge
Distance covered = X + 2L
X + 2L = 540 …(i)
When train passes the platform
Distance covered = X + L
X + L = 450 …(ii)
From (i) and (ii)
L = 90 meter
X = 360 meter
So, Quantity I = Quantity II Hence, option (c) is the correct answer.
• Question 3 of 5 3. Question An express train travels at an average speed of 80 km/hr. Starting from its source station, it stops for 3 minutes after travelling every 45 km before reaching its destination. If the distance between source to destination is 720 km, then which of the following can be concluded? a) Without any stoppages, the train would take less than 6 hrs. to travel 720 kms. b) With stoppages the train takes 6 hrs. to travel 720 kms. c) There are 16 stoppages between source and destination. d) There are 15 stoppages between source and destination. Correct Answer: Option (d) Explanation: The average speed of train is 80 km/hr. and distance is 720 km. Train stops for 3 minutes after every 45 km. Let the time taken by train be t hours. According to the question, we have Time (t) = Distance (d)/ Speed (s) ⇒ t = 720/80 ⇒ t = 9 hr. Without stoppages, the train would take 9 hrs. to travel 720 kms. Thus, option (a) is incorrect. Number of stops in 720 km = (720/45) – 1 = 16 – 1 = 15 Hence, there are 15 stoppages between source and destination. Thus, option (d) is correct. Total time wasted in stoppages after every 45 km = 15 × 3 = 45 mins. ∴ Total time to cover 720 km = 9 hours + 45 minutes = 9 hrs. 45 mins. So, with stoppages the train takes 9 hrs. 45 mins. to travel 720 kms. Thus, option (b) is incorrect. Hence, option (d) is the correct answer. Incorrect Answer: Option (d) Explanation: The average speed of train is 80 km/hr. and distance is 720 km. Train stops for 3 minutes after every 45 km. Let the time taken by train be t hours. According to the question, we have Time (t) = Distance (d)/ Speed (s) ⇒ t = 720/80 ⇒ t = 9 hr. Without stoppages, the train would take 9 hrs. to travel 720 kms. Thus, option (a) is incorrect. Number of stops in 720 km = (720/45) – 1 = 16 – 1 = 15 Hence, there are 15 stoppages between source and destination. Thus, option (d) is correct. Total time wasted in stoppages after every 45 km = 15 × 3 = 45 mins. ∴ Total time to cover 720 km = 9 hours + 45 minutes = 9 hrs. 45 mins. So, with stoppages the train takes 9 hrs. 45 mins. to travel 720 kms. Thus, option (b) is incorrect. Hence, option (d) is the correct answer.
#### 3. Question
An express train travels at an average speed of 80 km/hr. Starting from its source station, it stops for 3 minutes after travelling every 45 km before reaching its destination. If the distance between source to destination is 720 km, then which of the following can be concluded?
• a) Without any stoppages, the train would take less than 6 hrs. to travel 720 kms.
• b) With stoppages the train takes 6 hrs. to travel 720 kms.
• c) There are 16 stoppages between source and destination.
• d) There are 15 stoppages between source and destination.
Answer: Option (d)
Explanation:
The average speed of train is 80 km/hr. and distance is 720 km.
Train stops for 3 minutes after every 45 km.
Let the time taken by train be t hours.
According to the question, we have Time (t) = Distance (d)/ Speed (s)
⇒ t = 720/80
⇒ t = 9 hr.
Without stoppages, the train would take 9 hrs. to travel 720 kms. Thus, option (a) is incorrect.
Number of stops in 720 km = (720/45) – 1 = 16 – 1 = 15
Hence, there are 15 stoppages between source and destination. Thus, option (d) is correct.
Total time wasted in stoppages after every 45 km = 15 × 3 = 45 mins.
∴ Total time to cover 720 km = 9 hours + 45 minutes = 9 hrs. 45 mins.
So, with stoppages the train takes 9 hrs. 45 mins. to travel 720 kms. Thus, option (b) is incorrect. Hence, option (d) is the correct answer.
Answer: Option (d)
Explanation:
The average speed of train is 80 km/hr. and distance is 720 km.
Train stops for 3 minutes after every 45 km.
Let the time taken by train be t hours.
According to the question, we have Time (t) = Distance (d)/ Speed (s)
⇒ t = 720/80
⇒ t = 9 hr.
Without stoppages, the train would take 9 hrs. to travel 720 kms. Thus, option (a) is incorrect.
Number of stops in 720 km = (720/45) – 1 = 16 – 1 = 15
Hence, there are 15 stoppages between source and destination. Thus, option (d) is correct.
Total time wasted in stoppages after every 45 km = 15 × 3 = 45 mins.
∴ Total time to cover 720 km = 9 hours + 45 minutes = 9 hrs. 45 mins.
So, with stoppages the train takes 9 hrs. 45 mins. to travel 720 kms. Thus, option (b) is incorrect. Hence, option (d) is the correct answer.
• Question 4 of 5 4. Question There are two Pipes, A and B can fill a container in 8 and 12 hours respectively. And another Pipe C can empty in 6 hours. If all the three pipes are opened together, then the container will be filled in. a) 12 hours b) 15 hours c) 20 hours c) 20 hours Correct Answer: Option (d) Explanation: Pipe A = 8 hours (fill) Pipe B = 12 hours (fill) Pipe C = 6 hours (empty) Lcm = 24 Units fill/empty Pipe A = 3 units (fill) Pipe B = 2 units (fill) Pipe C = 4 units (empty) Together = 5–4 = 1 unit (fill) Time = 24/1 = 24 hours Incorrect Answer: Option (d) Explanation: Pipe A = 8 hours (fill) Pipe B = 12 hours (fill) Pipe C = 6 hours (empty) Lcm = 24 Units fill/empty Pipe A = 3 units (fill) Pipe B = 2 units (fill) Pipe C = 4 units (empty) Together = 5–4 = 1 unit (fill) Time = 24/1 = 24 hours
#### 4. Question
There are two Pipes, A and B can fill a container in 8 and 12 hours respectively. And another Pipe C can empty in 6 hours. If all the three pipes are opened together, then the container will be filled in.
• a) 12 hours
• b) 15 hours
• c) 20 hours
• c) 20 hours
Answer: Option (d)
Explanation:
Pipe A = 8 hours (fill)
Pipe B = 12 hours (fill)
Pipe C = 6 hours (empty)
Lcm = 24 Units fill/empty Pipe A = 3 units (fill)
Pipe B = 2 units (fill)
Pipe C = 4 units (empty)
Together = 5–4 = 1 unit (fill)
Time = 24/1 = 24 hours
Answer: Option (d)
Explanation:
Pipe A = 8 hours (fill)
Pipe B = 12 hours (fill)
Pipe C = 6 hours (empty)
Lcm = 24 Units fill/empty Pipe A = 3 units (fill)
Pipe B = 2 units (fill)
Pipe C = 4 units (empty)
Together = 5–4 = 1 unit (fill)
Time = 24/1 = 24 hours
• Question 5 of 5 5. Question A cistern has three pipes P, Q, R; Pipe P and Q can fill it in 5 and 6 hr respectively; and pipe R can empty it in 2 hr. If these pipes are opened in order at 7a.m, at 8 a.m. and 9 a.m., then at what time will the cistern be emptied? a) 12 : 45 am b) 1 : 15 p.m c) 1 : 45 p.m d) 2 : 15 p.m Correct Answer: Option (b) Explanation: Pipe P = 5 hours (fill) Pipe Q = 6 hours (fill) Pipe R = 2 hours (empty) LCM = 30 units Units per hour Pipe P = 6 (fill) Pipe Q = 5 (fill) Pipe R = 15 hours (empty) Together = 15–11 = 4 units Pipe P fill = 6×2 = 12 units Pipe Q fill = 5×1 = 5 units Total units fill till 9 a.m. = 12+5 = 17 Together they empty 5 units per hour. Time to empty = 17/4 = 4 hours 15 min Empty at 1:15p.m. Incorrect Answer: Option (b) Explanation: Pipe P = 5 hours (fill) Pipe Q = 6 hours (fill) Pipe R = 2 hours (empty) LCM = 30 units Units per hour Pipe P = 6 (fill) Pipe Q = 5 (fill) Pipe R = 15 hours (empty) Together = 15–11 = 4 units Pipe P fill = 6×2 = 12 units Pipe Q fill = 5×1 = 5 units Total units fill till 9 a.m. = 12+5 = 17 Together they empty 5 units per hour. Time to empty = 17/4 = 4 hours 15 min Empty at 1:15p.m.
#### 5. Question
A cistern has three pipes P, Q, R; Pipe P and Q can fill it in 5 and 6 hr respectively; and pipe R can empty it in 2 hr. If these pipes are opened in order at 7a.m, at 8 a.m. and 9 a.m., then at what time will the cistern be emptied?
• a) 12 : 45 am
• b) 1 : 15 p.m
• c) 1 : 45 p.m
• d) 2 : 15 p.m
Answer: Option (b)
Explanation:
Pipe P = 5 hours (fill)
Pipe Q = 6 hours (fill)
Pipe R = 2 hours (empty)
LCM = 30 units Units per hour
Pipe P = 6 (fill)
Pipe Q = 5 (fill)
Pipe R = 15 hours (empty)
Together = 15–11 = 4 units
Pipe P fill = 6×2 = 12 units
Pipe Q fill = 5×1 = 5 units
Total units fill till 9 a.m. = 12+5 = 17
Together they empty 5 units per hour.
Time to empty = 17/4 = 4 hours 15 min
Empty at 1:15p.m.
Answer: Option (b)
Explanation:
Pipe P = 5 hours (fill)
Pipe Q = 6 hours (fill)
Pipe R = 2 hours (empty)
LCM = 30 units Units per hour
Pipe P = 6 (fill)
Pipe Q = 5 (fill)
Pipe R = 15 hours (empty)
Together = 15–11 = 4 units
Pipe P fill = 6×2 = 12 units
Pipe Q fill = 5×1 = 5 units
Total units fill till 9 a.m. = 12+5 = 17
Together they empty 5 units per hour.
Time to empty = 17/4 = 4 hours 15 min
Empty at 1:15p.m.
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