UPSC Insta–DART (Daily Aptitude and Reasoning Test) 30 Aug 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question In a party Sathish mixed two type of liquid in a glass, type A liquid contains 35% of juice and type B liquid contains 40% of juice. Sathish takes 12ml from type A liquid and 8ml from type B liquid, then find percentage of juice in the glass? a) 32% b) 74% c) 50% d) 35% Correct Answer: (b) 74% Explanation: Let’s total quantity of glass=10ml So, juice from type A liquid=12ml 35/100=4.2ml Juice from type B liquid=8ml 40/100=3.2ml Total juice=(4.2+3.2)=7.4ml Required %=7.4 100/10=74% Incorrect Answer: (b) 74% Explanation: Let’s total quantity of glass=10ml So, juice from type A liquid=12ml 35/100=4.2ml Juice from type B liquid=8ml 40/100=3.2ml Total juice=(4.2+3.2)=7.4ml Required %=7.4 100/10=74%
#### 1. Question
In a party Sathish mixed two type of liquid in a glass, type A liquid contains 35% of juice and type B liquid contains 40% of juice. Sathish takes 12ml from type A liquid and 8ml from type B liquid, then find percentage of juice in the glass?
Answer: (b) 74%
Explanation:
Let’s total quantity of glass=10ml
So, juice from type A liquid=12ml *35/100=4.2ml
Juice from type B liquid=8ml * 40/100=3.2ml
Total juice=(4.2+3.2)=7.4ml
Required %=7.4 *100/10=74%
Answer: (b) 74%
Explanation:
Let’s total quantity of glass=10ml
So, juice from type A liquid=12ml *35/100=4.2ml
Juice from type B liquid=8ml * 40/100=3.2ml
Total juice=(4.2+3.2)=7.4ml
Required %=7.4 *100/10=74%
• Question 2 of 5 2. Question The expenditure and income of a person are in the ratio of 5:8. After some time income of a person is increased by 40% but at the same time his saving is also increased by 3(1/3)%. Find increased or decreased percent in his expenditure. a) 62% b) 60% c) 31% d) 50% Correct Answer: (a) 62% Explanation: Let the income and expenditure of a person is 8x and 5x respectively Savings of a person=8x-5x=3x Income of a person after 40% increase=8x 140/100=11.2x New savings of a person=3x310/300=3.1x New expenditure=11.2x-3.1x=8.1x Required percentage=(8.1x-5x )/5x 100=62% Incorrect Answer: (a) 62% Explanation: Let the income and expenditure of a person is 8x and 5x respectively Savings of a person=8x-5x=3x Income of a person after 40% increase=8x 140/100=11.2x New savings of a person=3x310/300=3.1x New expenditure=11.2x-3.1x=8.1x Required percentage=(8.1x-5x )/5x 100=62%
#### 2. Question
The expenditure and income of a person are in the ratio of 5:8. After some time income of a person is increased by 40% but at the same time his saving is also increased by 3(1/3)%. Find increased or decreased percent in his expenditure.
Answer: (a) 62%
Explanation:
Let the income and expenditure of a person is 8x and 5x respectively
Savings of a person=8x-5x=3x
Income of a person after 40% increase=8x *140/100=11.2x
New savings of a person=3x*310/300=3.1x
New expenditure=11.2x-3.1x=8.1x
Required percentage=(8.1x-5x )/5x *100=62%
Answer: (a) 62%
Explanation:
Let the income and expenditure of a person is 8x and 5x respectively
Savings of a person=8x-5x=3x
Income of a person after 40% increase=8x *140/100=11.2x
New savings of a person=3x*310/300=3.1x
New expenditure=11.2x-3.1x=8.1x
Required percentage=(8.1x-5x )/5x *100=62%
• Question 3 of 5 3. Question In a class 1, total students are 50% more than total students in Class 2, while both class have same number of boys. In class 1 , there are 70% girls. Find percentage of boys in class 2. a) 45% b) 25% c) 50% d) 75% Correct Answer: (a) 45% Explanation: Let students n class 2=x Students in class 1 =x+50x/100=1.5x Girls in class 1=70/100 1.5x=1.05x Boys in class 1=1.5x-1.05x=0.45x=boys in class 2 Required %=0.45/x 100=45% Incorrect Answer: (a) 45% Explanation: Let students n class 2=x Students in class 1 =x+50x/100=1.5x Girls in class 1=70/100 1.5x=1.05x Boys in class 1=1.5x-1.05x=0.45x=boys in class 2 Required %=0.45/x 100=45%
#### 3. Question
In a class 1, total students are 50% more than total students in Class 2, while both class have same number of boys. In class 1 , there are 70% girls. Find percentage of boys in class 2.
Answer: (a) 45%
Explanation:
Let students n class 2=x
Students in class 1 =x+50x/100=1.5x
Girls in class 1=70/100 *1.5x=1.05x
Boys in class 1=1.5x-1.05x=0.45x=boys in class 2
Required %=0.45/x *100=45%
Answer: (a) 45%
Explanation:
Let students n class 2=x
Students in class 1 =x+50x/100=1.5x
Girls in class 1=70/100 *1.5x=1.05x
Boys in class 1=1.5x-1.05x=0.45x=boys in class 2
Required %=0.45/x *100=45%
• Question 4 of 5 4. Question A two digit number get reversed when 1/5th of it is added to it. Find the 80% of that no. a) 36 b) 18 c) 15 d) 26 Correct Answer: (a) 36 Explanation: Let the two digit number be=(10a+b), where a is tens digit and b is unit digit ATQ, (10a+b) + 0.2(10a+b)=(10b+a) 11a=8.8b a/b =4/5 since the no is two digit number . so the only possible no. is 45 and reverse of it is 54 so 80% of that number is 36 Incorrect Answer: (a) 36 Explanation: Let the two digit number be=(10a+b), where a is tens digit and b is unit digit ATQ, (10a+b) + 0.2(10a+b)=(10b+a) 11a=8.8b a/b =4/5 since the no is two digit number . so the only possible no. is 45 and reverse of it is 54 so 80% of that number is 36
#### 4. Question
A two digit number get reversed when 1/5th of it is added to it. Find the 80% of that no.
Answer: (a) 36
Explanation:
Let the two digit number be=(10a+b), where a is tens digit and b is unit digit
(10a+b) + 0.2(10a+b)=(10b+a)
since the no is two digit number . so the only possible no. is 45 and reverse of it is 54
so 80% of that number is 36
Answer: (a) 36
Explanation:
Let the two digit number be=(10a+b), where a is tens digit and b is unit digit
(10a+b) + 0.2(10a+b)=(10b+a)
since the no is two digit number . so the only possible no. is 45 and reverse of it is 54
so 80% of that number is 36
• Question 5 of 5 5. Question When 30% of no. x is subtracted from y. it becomes 620 and when 50% of x is added to y it becomes 1100. Find ratio of y to x. a) 4:3 b) 3:4 c) 2:3 d) 3:2 Correct Answer: (a) 4:3 Explanation: y-0.3x=620——à (1) y+0.5x=1100—à(2) dividing 1 by 2 on solving we get y to x=4:3 Incorrect Answer: (a) 4:3 Explanation: y-0.3x=620——à (1) y+0.5x=1100—à(2) dividing 1 by 2 on solving we get y to x=4:3
#### 5. Question
When 30% of no. x is subtracted from y. it becomes 620 and when 50% of x is added to y it becomes 1100. Find ratio of y to x.
Answer: (a) 4:3
Explanation:
y-0.3x=620——à (1)
y+0.5x=1100—à(2)
dividing 1 by 2
on solving we get
y to x=4:3
Answer: (a) 4:3
Explanation:
y-0.3x=620——à (1)
y+0.5x=1100—à(2)
dividing 1 by 2
on solving we get
y to x=4:3
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