UPSC Insta–DART (Daily Aptitude and Reasoning Test) 3 Mar 2026

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question “Amit” and “Bhavya” can finish a task in 12 days and 20 days, respectively. They start together. After some days, “Amit” leaves and “Charu,” who can finish the task alone in 15 days, joins. Two days before completion, Charu leaves. If Amit and Charu worked for the same number of days, how much of the work was completed by Bhavya? (a) 9/25 (b) 23/50 (c) 11/30 (d) 2/5 Correct Answer: (b) Amit’s rate = 1/12, Bhavya’s rate = 1/20, Charu’s rate = 1/15 (work/day). Let x = days Amit worked = days Charu worked. Since Charu left 2 days before completion, total time T = (x by Amit) + (full T by Bhavya) + (x by Charu) with Charu’s last day at T − 2 ⇒ T = 2x + 2. Work equation: x/12 + T/20 + x/15 = 1. Substitute T = 2x + 2: x/12 + (2x + 2)/20 + x/15 = 1. Multiply by LCM 60: 5x + 3(2x + 2) + 4x = 60 ⇒ 5x + 6x + 6 + 4x = 60 ⇒ 15x + 6 = 60 ⇒ x = 54/15 = 3.6. Then T = 2x + 2 = 9.2 days. Bhavya’s work = T × (1/20) = 9.2/20 = 23/50. Hence, 23/50. Incorrect Answer: (b) Amit’s rate = 1/12, Bhavya’s rate = 1/20, Charu’s rate = 1/15 (work/day). Let x = days Amit worked = days Charu worked. Since Charu left 2 days before completion, total time T = (x by Amit) + (full T by Bhavya) + (x by Charu) with Charu’s last day at T − 2 ⇒ T = 2x + 2. Work equation: x/12 + T/20 + x/15 = 1. Substitute T = 2x + 2: x/12 + (2x + 2)/20 + x/15 = 1. Multiply by LCM 60: 5x + 3(2x + 2) + 4x = 60 ⇒ 5x + 6x + 6 + 4x = 60 ⇒ 15x + 6 = 60 ⇒ x = 54/15 = 3.6. Then T = 2x + 2 = 9.2 days. Bhavya’s work = T × (1/20) = 9.2/20 = 23/50. Hence, 23/50.

#### 1. Question

“Amit” and “Bhavya” can finish a task in 12 days and 20 days, respectively. They start together. After some days, “Amit” leaves and “Charu,” who can finish the task alone in 15 days, joins. Two days before completion, Charu leaves. If Amit and Charu worked for the same number of days, how much of the work was completed by Bhavya?

Answer: (b)

Amit’s rate = 1/12, Bhavya’s rate = 1/20, Charu’s rate = 1/15 (work/day). Let x = days Amit worked = days Charu worked.

Since Charu left 2 days before completion, total time T = (x by Amit) + (full T by Bhavya) + (x by Charu) with Charu’s last day at T − 2 ⇒ T = 2x + 2. Work equation: x/12 + T/20 + x/15 = 1.

Substitute T = 2x + 2: x/12 + (2x + 2)/20 + x/15 = 1. Multiply by LCM 60: 5x + 3(2x + 2) + 4x = 60 ⇒ 5x + 6x + 6 + 4x = 60 ⇒ 15x + 6 = 60 ⇒ x = 54/15 = 3.6. Then T = 2x + 2 = 9.2 days. Bhavya’s work = T × (1/20) = 9.2/20 = 23/50.

Hence, 23/50.

Answer: (b)

Amit’s rate = 1/12, Bhavya’s rate = 1/20, Charu’s rate = 1/15 (work/day). Let x = days Amit worked = days Charu worked.

Since Charu left 2 days before completion, total time T = (x by Amit) + (full T by Bhavya) + (x by Charu) with Charu’s last day at T − 2 ⇒ T = 2x + 2. Work equation: x/12 + T/20 + x/15 = 1.

Hence, 23/50.

• Question 2 of 5 2. Question Daily wages of a man and a woman are in the ratio 4 : 3., 15 men and 10 women can earn ₹13,500 in 5 days. How much will 10 men and 15 women earn in 10 days? (a) ₹25,500 (b) ₹18,500 (c) ₹19,000 (d) ₹21,000 Correct Incorrect

#### 2. Question

Daily wages of a man and a woman are in the ratio 4 : 3., 15 men and 10 women can earn ₹13,500 in 5 days. How much will 10 men and 15 women earn in 10 days?

• (a) ₹25,500

• (b) ₹18,500

• (c) ₹19,000

• (d) ₹21,000

• Question 3 of 5 3. Question X and Y together undertake to complete a work for ₹6,000. X alone can complete the work in 10 days and Y alone in 12 days. With the help of Z, they finish the work in 4 days. What is the share of Z? (a) ₹1,200 (b) ₹1,600 (c) ₹1,800 (d) ₹2,000 Correct Incorrect

#### 3. Question

X and Y together undertake to complete a work for ₹6,000. X alone can complete the work in 10 days and Y alone in 12 days. With the help of Z, they finish the work in 4 days. What is the share of Z?

• (a) ₹1,200

• (b) ₹1,600

• (c) ₹1,800

• (d) ₹2,000

• Question 4 of 5 4. Question A, B, and C can complete a work in 6 days, 8 days, and 12 days respectively. They work together and complete the work. If the total wage is ₹1,350 and it is distributed in proportion to their work efficiency, how much more does A receive than C? (a) ₹150 (b) ₹225 (c) ₹300 (d) ₹450 Correct Incorrect

#### 4. Question

A, B, and C can complete a work in 6 days, 8 days, and 12 days respectively. They work together and complete the work. If the total wage is ₹1,350 and it is distributed in proportion to their work efficiency, how much more does A receive than C?

• Question 5 of 5 5. Question A and B together complete a work in 8 days. With the help of C, they complete it in 4 days. The ratio of efficiency of A and B is 2 : 1. If C completes the work alone in (R + 10) days, find in how many days B alone can complete the work? (a) R + 30 (b) R + 24 (c) R + 20 (d) R + 28 Correct Answer: (b) Solution [A + B] one day’s work = 1/8. [A + B + C] one day’s work = 1/4. So C’s one day’s work = 1/4 – 1/8 = 1/8. Hence C alone finishes in 8 days. 8 = R + 10 ⇒ R = –2 (valid as an algebraic placeholder). Ratio A : B = 2 : 1 ⇒ A = 2k, B = k. Then 2k + k = 1/8 ⇒ 3k = 1/8 ⇒ k = 1/24. So B alone takes 24 days. That equals R + 24. Answer: (b) Solution [A + B] one day’s work = 1/8. [A + B + C] one day’s work = 1/4. So C’s one day’s work = 1/4 – 1/8 = 1/8. Hence C alone finishes in 8 days. 8 = R + 10 ⇒ R = –2 (valid as an algebraic placeholder). Ratio A : B = 2 : 1 ⇒ A = 2k, B = k. Then 2k + k = 1/8 ⇒ 3k = 1/8 ⇒ k = 1/24. So B alone takes 24 days. That equals R + 24. Incorrect Answer: (b) Solution [A + B] one day’s work = 1/8. [A + B + C] one day’s work = 1/4. So C’s one day’s work = 1/4 – 1/8 = 1/8. Hence C alone finishes in 8 days. 8 = R + 10 ⇒ R = –2 (valid as an algebraic placeholder). Ratio A : B = 2 : 1 ⇒ A = 2k, B = k. Then 2k + k = 1/8 ⇒ 3k = 1/8 ⇒ k = 1/24. So B alone takes 24 days. That equals R + 24.

#### 5. Question

A and B together complete a work in 8 days. With the help of C, they complete it in 4 days. The ratio of efficiency of A and B is 2 : 1. If C completes the work alone in (R + 10) days, find in how many days B alone can complete the work?

• (a) R + 30

• (b) R + 24

• (c) R + 20

• (d) R + 28

Answer: (b) Solution [A + B] one day’s work = 1/8. [A + B + C] one day’s work = 1/4. So C’s one day’s work = 1/4 – 1/8 = 1/8. Hence C alone finishes in 8 days. 8 = R + 10 ⇒ R = –2 (valid as an algebraic placeholder). Ratio A : B = 2 : 1 ⇒ A = 2k, B = k. Then 2k + k = 1/8 ⇒ 3k = 1/8 ⇒ k = 1/24. So B alone takes 24 days. That equals R + 24.

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