UPSC Insta–DART (Daily Aptitude and Reasoning Test) 28 Nov 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question Three masons Arav, Bala and Charu are to plaster a long boundary wall. Working independently, they can complete the whole work in 18, 27 and 54 days, respectively. Arav alone works on Monday, Bala alone works on Tuesday, Charu alone works on Wednesday, Arav again on Thursday, and so on (the trio keeps repeating in that order). Consider the statements: (I) The work will be finished on Sunday. (II) The work will be finished in 27 days. Which of the above statement(s) is/are correct? (a) Only (I) (b) Only (II) (c) Both (I) and (II) (d) Neither I nor II Correct Ans: (c) Explanation: Take total work = LCM(18, 27, 54) = 54 units. Daily efficiencies: Arav = 54/18 = 3 units/day, Bala = 54/27 = 2 units/day, Charu = 54/54 = 1 unit/day. A 3‑day block (Mon–Wed) completes 3 + 2 + 1 = 6 units. Total blocks needed = 54/6 = 9 blocks = 27 days. Starting on Monday, day 7 is Sunday, day 14 is Sunday, day 21 is Sunday, day 27 is Sunday. So it finishes on Sunday and in 27 days. Hence, both statements are correct. Incorrect Ans: (c) Explanation: Take total work = LCM(18, 27, 54) = 54 units. Daily efficiencies: Arav = 54/18 = 3 units/day, Bala = 54/27 = 2 units/day, Charu = 54/54 = 1 unit/day. A 3‑day block (Mon–Wed) completes 3 + 2 + 1 = 6 units. Total blocks needed = 54/6 = 9 blocks = 27 days. Starting on Monday, day 7 is Sunday, day 14 is Sunday, day 21 is Sunday, day 27 is Sunday. So it finishes on Sunday and in 27 days. Hence, both statements are correct.

#### 1. Question

Three masons Arav, Bala and Charu are to plaster a long boundary wall. Working independently, they can complete the whole work in 18, 27 and 54 days, respectively. Arav alone works on Monday, Bala alone works on Tuesday, Charu alone works on Wednesday, Arav again on Thursday, and so on (the trio keeps repeating in that order). Consider the statements:

(I) The work will be finished on Sunday. (II) The work will be finished in 27 days.

Which of the above statement(s) is/are correct?

• (a) Only (I)

• (b) Only (II)

• (c) Both (I) and (II)

• (d) Neither I nor II

Ans: (c)

Explanation: Take total work = LCM(18, 27, 54) = 54 units. Daily efficiencies: Arav = 54/18 = 3 units/day, Bala = 54/27 = 2 units/day, Charu = 54/54 = 1 unit/day. A 3‑day block (Mon–Wed) completes 3 + 2 + 1 = 6 units. Total blocks needed = 54/6 = 9 blocks = 27 days. Starting on Monday, day 7 is Sunday, day 14 is Sunday, day 21 is Sunday, day 27 is Sunday. So it finishes on Sunday and in 27 days. Hence, both statements are correct.

Ans: (c)

• Question 2 of 5 2. Question Pipe A can fill a tank in 8 hours, Pipe B can empty it in 12 hours, and Pipe C can fill it in 24 hours. All three are opened together at 10:00 a.m. After some time, Pipe B is closed, and the tank gets completely filled at 8:00 p.m. When was Pipe B closed? (a) 12:00 p.m. (b) 2:00 p.m. (c) 4:00 p.m. (d) 6:00 p.m. Correct Answer: (d) Explanation: A = 8 h (fill), B = 12 h (empty), C = 24 h (fill) LCM = 24 units Efficiency: A = 3 u/hr, B = –2 u/hr, C = 1 u/hr With all three open: net = 3 – 2 + 1 = 2 u/hr After closing B: net = 3 + 1 = 4 u/hr Total time from 10 a.m. to 8 p.m. = 10 hours Let B was open for x hours. Total work = 24 units = (2 × x) + [4 × (10 – x)] ⇒ 24 = 2x + 40 – 4x = 40 – 2x ⇒ 2x = 16 ⇒ x = 8 So B was closed 8 hours after 10 a.m. ⇒ 6:00 p.m. Hence, option (d) is correct. Incorrect Answer: (d) Explanation: A = 8 h (fill), B = 12 h (empty), C = 24 h (fill) LCM = 24 units Efficiency: A = 3 u/hr, B = –2 u/hr, C = 1 u/hr With all three open: net = 3 – 2 + 1 = 2 u/hr After closing B: net = 3 + 1 = 4 u/hr Total time from 10 a.m. to 8 p.m. = 10 hours Let B was open for x hours. Total work = 24 units = (2 × x) + [4 × (10 – x)] ⇒ 24 = 2x + 40 – 4x = 40 – 2x ⇒ 2x = 16 ⇒ x = 8 So B was closed 8 hours after 10 a.m. ⇒ 6:00 p.m. Hence, option (d) is correct.

#### 2. Question

Pipe A can fill a tank in 8 hours, Pipe B can empty it in 12 hours, and Pipe C can fill it in 24 hours. All three are opened together at 10:00 a.m. After some time, Pipe B is closed, and the tank gets completely filled at 8:00 p.m. When was Pipe B closed?

• (a) 12:00 p.m.

• (b) 2:00 p.m.

• (c) 4:00 p.m.

• (d) 6:00 p.m.

Answer: (d) Explanation: A = 8 h (fill), B = 12 h (empty), C = 24 h (fill) LCM = 24 units Efficiency: A = 3 u/hr, B = –2 u/hr, C = 1 u/hr With all three open: net = 3 – 2 + 1 = 2 u/hr After closing B: net = 3 + 1 = 4 u/hr Total time from 10 a.m. to 8 p.m. = 10 hours Let B was open for x hours. Total work = 24 units = (2 × x) + [4 × (10 – x)] ⇒ 24 = 2x + 40 – 4x = 40 – 2x ⇒ 2x = 16 ⇒ x = 8 So B was closed 8 hours after 10 a.m. ⇒ 6:00 p.m. Hence, option (d) is correct.

• Question 3 of 5 3. Question A pack of 52 cards contains four different colors cards each color contains cards numbered from 1 to 13. Cards are drawn randomly from the pack. Consider the following statements: Smallest number of attempts, which will always get full set of atleast one color 49. Smallest number of attempts, which will always get atleast one card of each color is 40. Which of the statements given above is/are correct? (a) I only (b) II only (c) Both I and II (d) Neither I nor II Correct Answer: (c) Solution Statement 1 is correct: For full set of one color we have to take the worst case. Worst case is one card of each color remaining in the pack till the last ie till we withdraw 48 cards. Next card withdraw is bound to fulfill atleast one set of color. So number of attempts is 49. Statement 2 is correct: For getting at least one card of each color, i.e. getting all color cards, the worst case is one color is totally left out until others are drawn, i.e. 13 x 3 i.e. 39 cards are drawn. The next card i.e. 40 th card when we draw, it is bound to give atleast one cards of all color. Hence, option (c) is correct Incorrect Answer: (c) Solution Statement 1 is correct: For full set of one color we have to take the worst case. Worst case is one card of each color remaining in the pack till the last ie till we withdraw 48 cards. Next card withdraw is bound to fulfill atleast one set of color. So number of attempts is 49. Statement 2 is correct: For getting at least one card of each color, i.e. getting all color cards, the worst case is one color is totally left out until others are drawn, i.e. 13 x 3 i.e. 39 cards are drawn. The next card i.e. 40 th card when we draw, it is bound to give atleast one cards of all color. Hence, option (c) is correct

#### 3. Question

A pack of 52 cards contains four different colors cards each color contains cards numbered from 1 to 13. Cards are drawn randomly from the pack. Consider the following statements:

• Smallest number of attempts, which will always get full set of atleast one color 49.

• Smallest number of attempts, which will always get atleast one card of each color is 40.

Which of the statements given above is/are correct?

• (a) I only

• (b) II only

• (c) Both I and II

• (d) Neither I nor II

Answer: (c)

Solution

Statement 1 is correct: For full set of one color we have to take the worst case. Worst case is one card of each color remaining in the pack till the last ie till we withdraw 48 cards. Next card withdraw is bound to fulfill atleast one set of color. So number of attempts is 49.

Statement 2 is correct: For getting at least one card of each color, i.e. getting all color cards, the worst case is one color is totally left out until others are drawn, i.e. 13 x 3 i.e. 39 cards are drawn. The next card i.e. 40 th card when we draw, it is bound to give atleast one cards of all color. Hence, option (c) is correct

Answer: (c)

Solution

• Question 4 of 5 4. Question The average temperature for the first four days of a week was 64°C. The average for the 2nd, 3rd, 4th, and 5th days was 66°C. If the ratio of the temperatures on the 1st and 5th days was 5:6, what was the temperature on the 1st day? (a) 30°C (b) 66°C (c) 55°C (d) 40°C Correct Answer: (d) Explanation: Let temps on 1st to 5th days be A, B, C, D, E. From the question: A + B + C + D = 64 × 4 = 256 B + C + D + E = 66 × 4 = 264 Subtract: → (B + C + D + E) − (A + B + C + D) → E − A = 8 Also, A : E = 5 : 6 ⇒ Let A = 5x, E = 6x So, E − A = x = 8 ⇒ x = 8 ⇒ A = 5x = 40 Incorrect Answer: (d) Explanation: Let temps on 1st to 5th days be A, B, C, D, E. From the question: A + B + C + D = 64 × 4 = 256 B + C + D + E = 66 × 4 = 264 Subtract: → (B + C + D + E) − (A + B + C + D) → E − A = 8 Also, A : E = 5 : 6 ⇒ Let A = 5x, E = 6x So, E − A = x = 8 ⇒ x = 8 ⇒ A = 5x = 40

#### 4. Question

The average temperature for the first four days of a week was 64°C. The average for the 2nd, 3rd, 4th, and 5th days was 66°C. If the ratio of the temperatures on the 1st and 5th days was 5:6, what was the temperature on the 1st day?

Answer: (d)

Explanation:

Let temps on 1st to 5th days be A, B, C, D, E.

From the question:

• A + B + C + D = 64 × 4 = 256

• B + C + D + E = 66 × 4 = 264

Subtract: → (B + C + D + E) − (A + B + C + D) → E − A = 8 Also, A : E = 5 : 6 ⇒ Let A = 5x, E = 6x So, E − A = x = 8 ⇒ x = 8 ⇒ A = 5x = 40

Answer: (d)

Explanation:

Let temps on 1st to 5th days be A, B, C, D, E.

From the question:

• A + B + C + D = 64 × 4 = 256

• B + C + D + E = 66 × 4 = 264

Subtract: → (B + C + D + E) − (A + B + C + D) → E − A = 8 Also, A : E = 5 : 6 ⇒ Let A = 5x, E = 6x So, E − A = x = 8 ⇒ x = 8 ⇒ A = 5x = 40

• Question 5 of 5 5. Question A thief is spotted by a policeman 300 m ahead and runs at 8 m/s. The policeman starts chasing immediately at 12 m/s. After how much time will the policeman catch the thief? (a) 60 s (b) 75 s (c) 80 s (d) 90 s Correct Answer: (b) Solution: Initial gap = 300 m Relative speed = 12 − 8 = 4 m/s Time = 300 ÷ 4 = 75 seconds So, option (b) is correct. Incorrect Answer: (b) Solution: Initial gap = 300 m Relative speed = 12 − 8 = 4 m/s Time = 300 ÷ 4 = 75 seconds So, option (b) is correct.

#### 5. Question

A thief is spotted by a policeman 300 m ahead and runs at 8 m/s. The policeman starts chasing immediately at 12 m/s. After how much time will the policeman catch the thief?

Answer: (b)

Solution: Initial gap = 300 m Relative speed = 12 − 8 = 4 m/s Time = 300 ÷ 4 = 75 seconds So, option (b) is correct.

Answer: (b)

Solution: Initial gap = 300 m Relative speed = 12 − 8 = 4 m/s Time = 300 ÷ 4 = 75 seconds So, option (b) is correct.

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