UPSC Insta–DART (Daily Aptitude and Reasoning Test) 27 Sep 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Ramco, Ganga and Balayya charge Rs. 200, Rs. 150 and Rs. 180 per day respectively for their work. They work at a construction site, work done by them is in the ratio of 3:2:4 respectively. What will be the average labour cost for all three workers per day for the contractor at the construction site? a) Rs. 180 b) Rs. 177 c) Rs. 200 d) Rs. 155 Correct Answer: Option (a) Explanation: Labour cost of Ramco = Rs. 200 Labour cost of Ganga = Rs. 150 Labour cost of Balayya = Rs. 180 Ratio of the work of Ramco, Ganga and Balayya = 3:2:4 So, let the work done by Ramco in one day = 3x units The work done by Ganga in one day = 2x units The work done by Balayya in one day = 4x units ∴ The average labour cost of all the three workers per day = (200×3x + 150×2x + 180×4x) / (3x + 2x + 4x) = (600x + 300x + 720x) / 9x = 1620x / 9x = Rs. 180 So, the average labour cost of all the three workers per day is Rs 180. Hence, option (a) is the correct answer Incorrect Answer: Option (a) Explanation: Labour cost of Ramco = Rs. 200 Labour cost of Ganga = Rs. 150 Labour cost of Balayya = Rs. 180 Ratio of the work of Ramco, Ganga and Balayya = 3:2:4 So, let the work done by Ramco in one day = 3x units The work done by Ganga in one day = 2x units The work done by Balayya in one day = 4x units ∴ The average labour cost of all the three workers per day = (200×3x + 150×2x + 180×4x) / (3x + 2x + 4x) = (600x + 300x + 720x) / 9x = 1620x / 9x = Rs. 180 So, the average labour cost of all the three workers per day is Rs 180. Hence, option (a) is the correct answer
#### 1. Question
Ramco, Ganga and Balayya charge Rs. 200, Rs. 150 and Rs. 180 per day respectively for their work. They work at a construction site, work done by them is in the ratio of 3:2:4 respectively. What will be the average labour cost for all three workers per day for the contractor at the construction site?
• a) Rs. 180
• b) Rs. 177
• c) Rs. 200
• d) Rs. 155
Answer: Option (a)
Explanation:
Labour cost of Ramco = Rs. 200
Labour cost of Ganga = Rs. 150
Labour cost of Balayya = Rs. 180
Ratio of the work of Ramco, Ganga and Balayya = 3:2:4
So, let the work done by Ramco in one day = 3x units
The work done by Ganga in one day = 2x units
The work done by Balayya in one day = 4x units
∴ The average labour cost of all the three workers per day = (200×3x + 150×2x + 180×4x) / (3x + 2x + 4x)
= (600x + 300x + 720x) / 9x = 1620x / 9x = Rs. 180
So, the average labour cost of all the three workers per day is Rs 180.
Hence, option (a) is the correct answer
Answer: Option (a)
Explanation:
Labour cost of Ramco = Rs. 200
Labour cost of Ganga = Rs. 150
Labour cost of Balayya = Rs. 180
Ratio of the work of Ramco, Ganga and Balayya = 3:2:4
So, let the work done by Ramco in one day = 3x units
The work done by Ganga in one day = 2x units
The work done by Balayya in one day = 4x units
∴ The average labour cost of all the three workers per day = (200×3x + 150×2x + 180×4x) / (3x + 2x + 4x)
= (600x + 300x + 720x) / 9x = 1620x / 9x = Rs. 180
So, the average labour cost of all the three workers per day is Rs 180.
Hence, option (a) is the correct answer
• Question 2 of 5 2. Question Quantity I: P alone can do a piece of work in 72 days and Q alone can do same work in 48 days, R is 50% more efficient than Q then find in how many days total work will be completed if all three work on alternate days starting with P and ending with R ? Quantity II: A alone can do a task in 48 days B is 25% less efficient than A and C can do the same task in 40 days lesser than B does. Then find in how many days all three will complete the task together? a) Quantity I ≥ Quantity II b) Quantity I < Quantity II c) Quantity I > Quantity II d) Quantity I ≤ Quantity II Correct Answer: Option (c) Explanation: Quantity I: R efficiency = 3 × (150/100) = 4.5w/d 3 days work = (P + Q + R) = 2 + 3 + 4.5 = 9.5 work Required days = 9.5 × 15 = 142.5 work Remaining work = 144 – 142.5 = 1.5 Next day by P = 1.5/2 =3/4 Total days = 15 × 3 + (3/4) = 183/4 Quantity II: A : B = 100 : 75 = 4 : 3 Total work = 4 × 48 = 192 B alone = 192/3 = 64 days C alone = 64 – 40 = 24 days C efficiency = 192/24 = 8w⁄d (A + B + C)together = 192/(4+3+8) = 192/15= 64/5 days So, Quantity I > Quantity II Hence, option (c) is the correct answer. Incorrect Answer: Option (c) Explanation: Quantity I: R efficiency = 3 × (150/100) = 4.5w/d 3 days work = (P + Q + R) = 2 + 3 + 4.5 = 9.5 work Required days = 9.5 × 15 = 142.5 work Remaining work = 144 – 142.5 = 1.5 Next day by P = 1.5/2 =3/4 Total days = 15 × 3 + (3/4) = 183/4 Quantity II: A : B = 100 : 75 = 4 : 3 Total work = 4 × 48 = 192 B alone = 192/3 = 64 days C alone = 64 – 40 = 24 days C efficiency = 192/24 = 8w⁄d (A + B + C)together = 192/(4+3+8) = 192/15= 64/5 days So, Quantity I > Quantity II Hence, option (c) is the correct answer.
#### 2. Question
Quantity I: P alone can do a piece of work in 72 days and Q alone can do same work in 48 days, R is 50% more efficient than Q then find in how many days total work will be completed if all three work on alternate days starting with P and ending with R ?
Quantity II: A alone can do a task in 48 days B is 25% less efficient than A and C can do the same task in 40 days lesser than B does. Then find in how many days all three will complete the task together?
• a) Quantity I ≥ Quantity II
• b) Quantity I < Quantity II
• c) Quantity I > Quantity II
• d) Quantity I ≤ Quantity II
Answer: Option (c)
Explanation:
Quantity I:
R efficiency = 3 × (150/100) = 4.5w/d
3 days work = (P + Q + R) = 2 + 3 + 4.5 = 9.5 work
Required days = 9.5 × 15 = 142.5 work
Remaining work = 144 – 142.5 = 1.5
Next day by P = 1.5/2 =3/4
Total days = 15 × 3 + (3/4) = 183/4
Quantity II:
A : B = 100 : 75 = 4 : 3
Total work = 4 × 48 = 192
B alone = 192/3 = 64 days
C alone = 64 – 40 = 24 days
C efficiency = 192/24 = 8w⁄d
(A + B + C)together = 192/(4+3+8) = 192/15= 64/5 days
So, Quantity I > Quantity II Hence, option (c) is the correct answer.
Answer: Option (c)
Explanation:
Quantity I:
R efficiency = 3 × (150/100) = 4.5w/d
3 days work = (P + Q + R) = 2 + 3 + 4.5 = 9.5 work
Required days = 9.5 × 15 = 142.5 work
Remaining work = 144 – 142.5 = 1.5
Next day by P = 1.5/2 =3/4
Total days = 15 × 3 + (3/4) = 183/4
Quantity II:
A : B = 100 : 75 = 4 : 3
Total work = 4 × 48 = 192
B alone = 192/3 = 64 days
C alone = 64 – 40 = 24 days
C efficiency = 192/24 = 8w⁄d
(A + B + C)together = 192/(4+3+8) = 192/15= 64/5 days
So, Quantity I > Quantity II Hence, option (c) is the correct answer.
• Question 3 of 5 3. Question Consider the following statements regarding the Financial Intelligence Unit – India (FIU-IND): FIU-IND has its headquarters in Mumbai. FIU-IND shares intelligence with law enforcement agencies but does not investigate crimes. It was formed as an independent body under the Department of Revenue. FIU-IND works to combat financial crimes under the Foreign Exchange Management Act, 1999. How many of the above statements is/are correct? a) Only one b) Only two c) Only three d) All four Correct Solution: b) Statement 1 is incorrect. FIU-IND is headquartered in New Delhi, not Mumbai. Statement 2 is correct. FIU-IND shares financial intelligence with law enforcement agencies but does not conduct investigations itself. Statement 3 is correct. FIU-IND was established in 2004 under the Department of Revenue and operates as an independent body. Statement 4 is incorrect. FIU-IND works under the Prevention of Money Laundering Act (PMLA), 2002, not the Foreign Exchange Management Act (FEMA), 1999. Incorrect Solution: b) Statement 1 is incorrect. FIU-IND is headquartered in New Delhi, not Mumbai. Statement 2 is correct. FIU-IND shares financial intelligence with law enforcement agencies but does not conduct investigations itself. Statement 3 is correct. FIU-IND was established in 2004 under the Department of Revenue and operates as an independent body. Statement 4 is incorrect. FIU-IND works under the Prevention of Money Laundering Act (PMLA), 2002, not the Foreign Exchange Management Act (FEMA), 1999.
#### 3. Question
Consider the following statements regarding the Financial Intelligence Unit – India (FIU-IND):
• FIU-IND has its headquarters in Mumbai.
• FIU-IND shares intelligence with law enforcement agencies but does not investigate crimes.
• It was formed as an independent body under the Department of Revenue.
• FIU-IND works to combat financial crimes under the Foreign Exchange Management Act, 1999.
How many of the above statements is/are correct?
• a) Only one
• b) Only two
• c) Only three
• d) All four
Solution: b)
Statement 1 is incorrect. FIU-IND is headquartered in New Delhi, not Mumbai.
Statement 2 is correct. FIU-IND shares financial intelligence with law enforcement agencies but does not conduct investigations itself.
Statement 3 is correct. FIU-IND was established in 2004 under the Department of Revenue and operates as an independent body.
Statement 4 is incorrect. FIU-IND works under the Prevention of Money Laundering Act (PMLA), 2002, not the Foreign Exchange Management Act (FEMA), 1999.
Solution: b)
Statement 1 is incorrect. FIU-IND is headquartered in New Delhi, not Mumbai.
Statement 2 is correct. FIU-IND shares financial intelligence with law enforcement agencies but does not conduct investigations itself.
Statement 3 is correct. FIU-IND was established in 2004 under the Department of Revenue and operates as an independent body.
Statement 4 is incorrect. FIU-IND works under the Prevention of Money Laundering Act (PMLA), 2002, not the Foreign Exchange Management Act (FEMA), 1999.
• Question 4 of 5 4. Question M is twice efficient as N and N can do a piece of work in 15 days. N started the work and after a few days M joined him. They completed the work in 11 days, from the starting. For how many days did they work together? a) 1 day b) 2 days c) 6 days d) 9 days Correct Answer: Option (b) Explanation: N can finish 1/15 of the work in 1 day. Then, M can finish 2/15 work in 1 day. N has started the work and will work all 11 days. Work done by N = 11/15 of the work Work done by M = 1 – (11/15) = 4/15 Number of days M has worked = (4/15) / (2/15) = 2. Thus, both M and N have worked together for 2 days. Hence, option (b) is the correct answer. Incorrect Answer: Option (b) Explanation: N can finish 1/15 of the work in 1 day. Then, M can finish 2/15 work in 1 day. N has started the work and will work all 11 days. Work done by N = 11/15 of the work Work done by M = 1 – (11/15) = 4/15 Number of days M has worked = (4/15) / (2/15) = 2. Thus, both M and N have worked together for 2 days. Hence, option (b) is the correct answer.
#### 4. Question
M is twice efficient as N and N can do a piece of work in 15 days. N started the work and after a few days M joined him. They completed the work in 11 days, from the starting. For how many days did they work together?
Answer: Option (b)
Explanation:
N can finish 1/15 of the work in 1 day.
Then, M can finish 2/15 work in 1 day.
N has started the work and will work all 11 days.
Work done by N = 11/15 of the work
Work done by M = 1 – (11/15) = 4/15
Number of days M has worked = (4/15) / (2/15) = 2.
Thus, both M and N have worked together for 2 days. Hence, option (b) is the correct answer.
Answer: Option (b)
Explanation:
N can finish 1/15 of the work in 1 day.
Then, M can finish 2/15 work in 1 day.
N has started the work and will work all 11 days.
Work done by N = 11/15 of the work
Work done by M = 1 – (11/15) = 4/15
Number of days M has worked = (4/15) / (2/15) = 2.
Thus, both M and N have worked together for 2 days. Hence, option (b) is the correct answer.
• Question 5 of 5 5. Question On nth day, n persons work, (where n = 1, 2, 3, …..) means, on first day, only one person works; on second day 2 persons work, and so on like this. If the work is completed in 25 days, how many days it takes to complete the same work by a team of 25 people, if they work regularly? a) 9 b) 13 c) 12 d) 15 Correct Answer: Option (b) Explanation: Total man days required to complete the work are 1 + 2 + 3 + 4 +………25 = (25×26)/2 = 325 man days. Now days required by 25 men to complete the work will be 325/25 = 13 days. Hence option (b) is correct answer. Incorrect Answer: Option (b) Explanation: Total man days required to complete the work are 1 + 2 + 3 + 4 +………25 = (25×26)/2 = 325 man days. Now days required by 25 men to complete the work will be 325/25 = 13 days. Hence option (b) is correct answer.
#### 5. Question
On nth day, n persons work, (where n = 1, 2, 3, …..) means, on first day, only one person works; on second day 2 persons work, and so on like this. If the work is completed in 25 days, how many days it takes to complete the same work by a team of 25 people, if they work regularly?
Answer: Option (b)
Explanation:
Total man days required to complete the work are 1 + 2 + 3 + 4 +………25 = (25×26)/2 = 325 man days.
Now days required by 25 men to complete the work will be 325/25 = 13 days.
Hence option (b) is correct answer.
Answer: Option (b)
Explanation:
Total man days required to complete the work are 1 + 2 + 3 + 4 +………25 = (25×26)/2 = 325 man days.
Now days required by 25 men to complete the work will be 325/25 = 13 days.
Hence option (b) is correct answer.
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