UPSC Insta–DART (Daily Aptitude and Reasoning Test) 26 Aug 2024

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question If we add 8 to the Numerator of the fraction and increases denominator by 50% then both becomes equal. And when the Numerator is increased by 10 and denominator is doubled then it becomes equal to the original fraction. What will be two times of that fraction? a) 5/6 b) 5/3 c) 5/7 d) 2/5 Correct Answer: (b) 5/3 Explanation: Let consider fraction as x/y AQT, (x+8)=3y/2 2x+16=3y —->(equation 1) As per the question again, (x+10)/2y =x/y On solving we get, ,x=10 ,y=12 Original fraction=x/y=10/12=5/6 Required fraction=5/62=5/3 Incorrect Answer: (b) 5/3 Explanation: Let consider fraction as x/y AQT, (x+8)=3y/2 2x+16=3y —->(equation 1) As per the question again, (x+10)/2y =x/y On solving we get, ,x=10 ,y=12 Original fraction=x/y=10/12=5/6 Required fraction=5/62=5/3

#### 1. Question

If we add 8 to the Numerator of the fraction and increases denominator by 50% then both becomes equal. And when the Numerator is increased by 10 and denominator is doubled then it becomes equal to the original fraction. What will be two times of that fraction?

Answer: (b) 5/3

Explanation:

Let consider fraction as x/y

(x+8)=3y/2

2x+16=3y —->(equation 1)

As per the question again,

(x+10)/2y =x/y

On solving we get,

Original fraction=x/y=10/12=5/6

Required fraction=5/6*2=5/3

Answer: (b) 5/3

Explanation:

Let consider fraction as x/y

(x+8)=3y/2

2x+16=3y —->(equation 1)

As per the question again,

(x+10)/2y =x/y

On solving we get,

Original fraction=x/y=10/12=5/6

Required fraction=5/6*2=5/3

• Question 2 of 5 2. Question A mixture of milk and water contains 80% of milk. x liter of mixture is taken out and replaced with water . find the value of x if final concentration of milk in the mixture is 50% and initial quantity of mixture is 320 liter. a) 120 b) 60 c) 80 d) 100 Correct Answer: (a) 120 Explanation: 4/5(320)-4/5 (x) = 1/5 (320)-1/5(x) +x Where 4/5 means 80% 1/5 means 20% On solving we get x= 120 Incorrect Answer: (a) 120 Explanation: 4/5(320)-4/5 (x) = 1/5 (320)-1/5(x) +x Where 4/5 means 80% 1/5 means 20% On solving we get x= 120

#### 2. Question

A mixture of milk and water contains 80% of milk. x liter of mixture is taken out and replaced with water . find the value of x if final concentration of milk in the mixture is 50% and initial quantity of mixture is 320 liter.

Answer: (a) 120

Explanation:

4/5(320)-4/5 (x) = 1/5 *(320)-1/5(x) +x

Where 4/5 means 80%

1/5 means 20%

On solving we get x= 120

Answer: (a) 120

Explanation:

4/5(320)-4/5 (x) = 1/5 *(320)-1/5(x) +x

Where 4/5 means 80%

1/5 means 20%

On solving we get x= 120

• Question 3 of 5 3. Question Akshay is 50% more than Bharath, Charan is 2/3rd of Akshay and Danesh is 60% more than Charan now if each of Akshay, Bharath, Charan and Danesh is increased by 20%. Then find Danesh is what percent of Bharath after the increase. a) 120% b) 130% c) 160% d) 150% Correct Answer: (c) 160% Explanation: Akshay/Bharath =3x/2x Charan=2/3 (Akshay) Charan/Akshay =2x/3x Danesh=(160/100) Charan Danesh/Charan=8x/5x After balancing the ratio we get Akshay :Bharath : Charan :Danesh 15x : 10x : 10x : 16x If all increased by 20% we get same ratio only 15:10:10:16 Danesh/Bharath =16/10 100=160% Incorrect Answer: (c) 160% Explanation: Akshay/Bharath =3x/2x Charan=2/3 (Akshay) Charan/Akshay =2x/3x Danesh=(160/100) Charan Danesh/Charan=8x/5x After balancing the ratio we get Akshay :Bharath : Charan :Danesh 15x : 10x : 10x : 16x If all increased by 20% we get same ratio only 15:10:10:16 Danesh/Bharath =16/10 100=160%

#### 3. Question

Akshay is 50% more than Bharath, Charan is 2/3rd of Akshay and Danesh is 60% more than Charan now if each of Akshay, Bharath, Charan and Danesh is increased by 20%. Then find Danesh is what percent of Bharath after the increase.

Answer: (c) 160%

Explanation:

Akshay/Bharath =3x/2x

Charan=2/3 (Akshay)

Charan/Akshay =2x/3x

Danesh=(160/100) Charan

Danesh/Charan=8x/5x

After balancing the ratio we get

Akshay :Bharath : Charan :Danesh

15x : 10x : 10x : 16x

If all increased by 20% we get same ratio only

15:10:10:16

Danesh/Bharath =16/10 *100=160%

Answer: (c) 160%

Explanation:

Akshay/Bharath =3x/2x

Charan=2/3 (Akshay)

Charan/Akshay =2x/3x

Danesh=(160/100) Charan

Danesh/Charan=8x/5x

After balancing the ratio we get

Akshay :Bharath : Charan :Danesh

15x : 10x : 10x : 16x

If all increased by 20% we get same ratio only

15:10:10:16

Danesh/Bharath =16/10 *100=160%

• Question 4 of 5 4. Question Annually income of Priya is 12.48 lakh, she spend 38(6/13)% of monthly income on food and rent, 12.5% of remaining on gym , 14(2/7) remaining on clothing and 75% of remaining invested in mutual fund . if she kept remaining amount after all expenses as cash with her then find how much cash Priya have after 1 year. a) 12000 b) 144000 c) 14400 d) 20000 Correct Answer: (b) 144000 Explanation: Annual income=1248000 Monthly income=104000 For food and rent=36(1/13)%=500/13 % 104000=40000 Remaining=64000 Gym=12.5%=1/8 (64000)=8000 Remaining=56000 14(2/7)%=clothing=1/7 56000 =8000 Remaining =48000 75%=mutual fund=3/4 (48000)=36000 Remaining=48000-36000=12000 Remaining she kept monthly =12000 Yearly she kept=1200012=144000 Incorrect Answer: (b) 144000 Explanation: Annual income=1248000 Monthly income=104000 For food and rent=36(1/13)%=500/13 % 104000=40000 Remaining=64000 Gym=12.5%=1/8 (64000)=8000 Remaining=56000 14(2/7)%=clothing=1/7 56000 =8000 Remaining =48000 75%=mutual fund=3/4 (48000)=36000 Remaining=48000-36000=12000 Remaining she kept monthly =12000 Yearly she kept=1200012=144000

#### 4. Question

Annually income of Priya is 12.48 lakh, she spend 38(6/13)% of monthly income on food and rent, 12.5% of remaining on gym , 14(2/7) remaining on clothing and 75% of remaining invested in mutual fund . if she kept remaining amount after all expenses as cash with her then find how much cash Priya have after 1 year.

Answer: (b) 144000

Explanation:

Annual income=1248000

Monthly income=104000

For food and rent=36(1/13)%=500/13 % *104000=40000

Remaining=64000

Gym=12.5%=1/8 * (64000)=8000

Remaining=56000

14(2/7)%=clothing=1/7 *56000 =8000

Remaining =48000

75%=mutual fund=3/4 * (48000)=36000

Remaining=48000-36000=12000

Remaining she kept monthly =12000

Yearly she kept=12000*12=144000

Answer: (b) 144000

Explanation:

Annual income=1248000

Monthly income=104000

For food and rent=36(1/13)%=500/13 % *104000=40000

Remaining=64000

Gym=12.5%=1/8 * (64000)=8000

Remaining=56000

14(2/7)%=clothing=1/7 *56000 =8000

Remaining =48000

75%=mutual fund=3/4 * (48000)=36000

Remaining=48000-36000=12000

Remaining she kept monthly =12000

Yearly she kept=12000*12=144000

• Question 5 of 5 5. Question Abhi got 216 marks in test which were 56 more than that of Anu marks, if Sonu got 60% of the total marks of the test which is 80 marks more that the Anu marks , what percentage of marks did Anu got? a) 40% b) 45% c) 60% d) 50% Correct Abhi got 216 marks in test which were 56 more than that of Anu marks, if Sonu got 60% of the total marks of the test which is 80 marks more that the Anu marks , what percentage of marks did Anu got? Incorrect Abhi got 216 marks in test which were 56 more than that of Anu marks, if Sonu got 60% of the total marks of the test which is 80 marks more that the Anu marks , what percentage of marks did Anu got?

#### 5. Question

Abhi got 216 marks in test which were 56 more than that of Anu marks, if Sonu got 60% of the total marks of the test which is 80 marks more that the Anu marks , what percentage of marks did Anu got?

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