UPSC Insta–DART (Daily Aptitude and Reasoning Test) 25 Feb 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question If the average temperature of first four days of week was 39°C and the average temperature of the week was 40ºC, then what was the average temperature of the last three days of the week? a) 63.3 b) 12.3 c) 40.3 d) 41.33 Correct Answer: D Explanation Total temperature of first four days=394=156 Total temperature of the week is=407=280 Total temperature of last three days=280-156=124 Average temperature of last three days =124/3=41.33 Incorrect Answer: D Explanation Total temperature of first four days=394=156 Total temperature of the week is=407=280 Total temperature of last three days=280-156=124 Average temperature of last three days =124/3=41.33
#### 1. Question
If the average temperature of first four days of week was 39°C and the average temperature of the week was 40ºC, then what was the average temperature of the last three days of the week?
Explanation
Total temperature of first four days=39*4=156
Total temperature of the week is=40*7=280
Total temperature of last three days=280-156=124
Average temperature of last three days =124/3=41.33
Explanation
Total temperature of first four days=39*4=156
Total temperature of the week is=40*7=280
Total temperature of last three days=280-156=124
Average temperature of last three days =124/3=41.33
• Question 2 of 5 2. Question If the difference between the average of 1st, 2nd and 2nd, 3rd is 12, then find the difference between 1st and 3rd number? a) 11 b) 19 c) 17 d) 24 Correct Answer: D Explanation Let the 1st number is a, 2nd number is b and 3rd number is c. Accrediting to the question, (a+b)/2 – (b+c)/2=12 Or, a+b-b-c=24 Or, a-c=24 So difference of first and third number is 24 Incorrect Answer: D Explanation Let the 1st number is a, 2nd number is b and 3rd number is c. Accrediting to the question, (a+b)/2 – (b+c)/2=12 Or, a+b-b-c=24 Or, a-c=24 So difference of first and third number is 24
#### 2. Question
If the difference between the average of 1st, 2nd and 2nd, 3rd is 12, then find the difference between 1st and 3rd number?
Explanation
Let the 1st number is a, 2nd number is b and 3rd number is c.
Accrediting to the question,
(a+b)/2 – (b+c)/2=12
Or, a+b-b-c=24
Or, a-c=24
So difference of first and third number is 24
Explanation
Let the 1st number is a, 2nd number is b and 3rd number is c.
Accrediting to the question,
(a+b)/2 – (b+c)/2=12
Or, a+b-b-c=24
Or, a-c=24
So difference of first and third number is 24
• Question 3 of 5 3. Question The average of 8 numbers is 14.The average of 6 of these numbers is 16.What is the average of the remaining two numbers? a) 11 b) 12 c) 8 d) 4 Correct Answer: C Explanation Sum of 8 numbers is =148=112 Sum of 6 number is=616=96 So sum of remaining two is=112-96=16 So average of remaining two is=16/2=8 Incorrect Answer: C Explanation Sum of 8 numbers is =148=112 Sum of 6 number is=616=96 So sum of remaining two is=112-96=16 So average of remaining two is=16/2=8
#### 3. Question
The average of 8 numbers is 14.The average of 6 of these numbers is 16.What is the average of the remaining two numbers?
Explanation
Sum of 8 numbers is =14*8=112
Sum of 6 number is=6*16=96
So sum of remaining two is=112-96=16
So average of remaining two is=16/2=8
Explanation
Sum of 8 numbers is =14*8=112
Sum of 6 number is=6*16=96
So sum of remaining two is=112-96=16
So average of remaining two is=16/2=8
• Question 4 of 5 4. Question The average marks of 30 students in class is 47.While checking two errors were noticed after correction, one student got 45 marks more and others 12 marks less. What is correct average? a) 22.36 b) 45.9 c) 26.3 d) 22 Correct Answer: B Explanation Total marks of 30 students is=4730=1410 After correction total marks of 30 student is=1410-45+12=1377 So new average of 50 student is =1377/30=45.9 Incorrect Answer: B Explanation Total marks of 30 students is=4730=1410 After correction total marks of 30 student is=1410-45+12=1377 So new average of 50 student is =1377/30=45.9
#### 4. Question
The average marks of 30 students in class is 47.While checking two errors were noticed after correction, one student got 45 marks more and others 12 marks less. What is correct average?
Explanation
Total marks of 30 students is=47*30=1410
After correction total marks of 30 student is=1410-45+12=1377
So new average of 50 student is =1377/30=45.9
Explanation
Total marks of 30 students is=47*30=1410
After correction total marks of 30 student is=1410-45+12=1377
So new average of 50 student is =1377/30=45.9
• Question 5 of 5 5. Question Average age of 32 students in a class is 14 years. The age of their teacher is 41 years, what is the average age of the students and teacher combined? a) 11.3 b) 14.81 c) 13.36 d) 15.17 Correct Answer: B Explanation Total age of 32 student of the class is=3214=448 Total age when teacher included is=448+41=489 So average when teacher included is=489/33=14.81 Incorrect Answer: B Explanation Total age of 32 student of the class is=3214=448 Total age when teacher included is=448+41=489 So average when teacher included is=489/33=14.81
#### 5. Question
Average age of 32 students in a class is 14 years. The age of their teacher is 41 years, what is the average age of the students and teacher combined?
Explanation
Total age of 32 student of the class is=32*14=448
Total age when teacher included is=448+41=489
So average when teacher included is=489/33=14.81
Explanation
Total age of 32 student of the class is=32*14=448
Total age when teacher included is=448+41=489
So average when teacher included is=489/33=14.81
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