UPSC Insta–DART (Daily Aptitude and Reasoning Test) 24 Jan 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question In a certain code language “EASY” is written as “5117”. In the same code language, how will “BEAM” be written as? a) 4512 b) 4567 c) 2513 d) 2514 Correct Answer: D Explanation EASY → E is the 5th alphabet in the series A is the first alphabet in the series S is the 19th alphabet, which makes it (1+9 = 10 ⇒ 1+0 = 1) Y is the 25th alphabet, which makes it (2+5 = 7) Hence, EASY = 5117 Similarly, BEAM → B is the 2nd alphabet in the series E is the 5th alphabet in the series A is the 1st alphabet in the series M is the 13th alphabet, which makes it (1+3 = 4) Hence BEAM = 2514 Incorrect Answer: D Explanation EASY → E is the 5th alphabet in the series A is the first alphabet in the series S is the 19th alphabet, which makes it (1+9 = 10 ⇒ 1+0 = 1) Y is the 25th alphabet, which makes it (2+5 = 7) Hence, EASY = 5117 Similarly, BEAM → B is the 2nd alphabet in the series E is the 5th alphabet in the series A is the 1st alphabet in the series M is the 13th alphabet, which makes it (1+3 = 4) Hence BEAM = 2514

#### 1. Question

In a certain code language “EASY” is written as “5117”. In the same code language, how will “BEAM” be written as?

Explanation

EASY → E is the 5th alphabet in the series

A is the first alphabet in the series

S is the 19th alphabet, which makes it (1+9 = 10 ⇒ 1+0 = 1)

Y is the 25th alphabet, which makes it (2+5 = 7)

Hence, EASY = 5117

Similarly,

BEAM → B is the 2nd alphabet in the series

E is the 5th alphabet in the series

A is the 1st alphabet in the series

M is the 13th alphabet, which makes it (1+3 = 4)

Hence BEAM = 2514

Explanation

EASY → E is the 5th alphabet in the series

A is the first alphabet in the series

S is the 19th alphabet, which makes it (1+9 = 10 ⇒ 1+0 = 1)

Y is the 25th alphabet, which makes it (2+5 = 7)

Hence, EASY = 5117

Similarly,

BEAM → B is the 2nd alphabet in the series

E is the 5th alphabet in the series

A is the 1st alphabet in the series

M is the 13th alphabet, which makes it (1+3 = 4)

Hence BEAM = 2514

• Question 2 of 5 2. Question “SPECIAL” is written as “65” in a certain code language what will “CONNECT” be coded as? a) 70 b) 64 c) 32 d) 74 Correct Answer: D Explanation SPECIAL → Sum of the place value of each alphabet in the alphabetical order SPECIAL = 19+16+5+3+9+1+12 = 65 So, CONNECT = 3+15+14+14+5+3+20 = 74 Incorrect Answer: D Explanation SPECIAL → Sum of the place value of each alphabet in the alphabetical order SPECIAL = 19+16+5+3+9+1+12 = 65 So, CONNECT = 3+15+14+14+5+3+20 = 74

#### 2. Question

“SPECIAL” is written as “65” in a certain code language what will “CONNECT” be coded as?

Explanation

SPECIAL → Sum of the place value of each alphabet in the alphabetical order

SPECIAL = 19+16+5+3+9+1+12 = 65

So, CONNECT = 3+15+14+14+5+3+20 = 74

Explanation

SPECIAL → Sum of the place value of each alphabet in the alphabetical order

SPECIAL = 19+16+5+3+9+1+12 = 65

So, CONNECT = 3+15+14+14+5+3+20 = 74

• Question 3 of 5 3. Question If ‘BEAUTIFUL’ is coded as ‘97’ in a code language, then what will be the code for ‘WONDERFUL’? a) 87 b) 99 c) 118 d) 121 Correct Answer: C Explanation Given code: BEAUTIFUL → 97 The alphabetical position of letter as follows Sum of these numbers = 2 + 5 + 1 + 21 + 20 + 9 + 6 + 21 + 12 = 97 So, word ‘BEAUTIFUL’ will be coded as ‘97’. Applying the similar concept in ‘WONDERFUL So, sum of these numbers = 23 + 15 + 14 + 4 + 5 + 18 + 6 + 21 + 12 = 118 So, word ‘WONDERFUL’ will be coded as ‘118’. Incorrect Answer: C Explanation Given code: BEAUTIFUL → 97 The alphabetical position of letter as follows Sum of these numbers = 2 + 5 + 1 + 21 + 20 + 9 + 6 + 21 + 12 = 97 So, word ‘BEAUTIFUL’ will be coded as ‘97’. Applying the similar concept in ‘WONDERFUL So, sum of these numbers = 23 + 15 + 14 + 4 + 5 + 18 + 6 + 21 + 12 = 118 So, word ‘WONDERFUL’ will be coded as ‘118’.

#### 3. Question

If ‘BEAUTIFUL’ is coded as ‘97’ in a code language, then what will be the code for ‘WONDERFUL’?

Explanation

Given code:

BEAUTIFUL → 97

The alphabetical position of letter as follows

Sum of these numbers = 2 + 5 + 1 + 21 + 20 + 9 + 6 + 21 + 12 = 97

So, word ‘BEAUTIFUL’ will be coded as ‘97’.

Applying the similar concept in ‘WONDERFUL

So, sum of these numbers = 23 + 15 + 14 + 4 + 5 + 18 + 6 + 21 + 12 = 118

So, word ‘WONDERFUL’ will be coded as ‘118’.

Explanation

Given code:

BEAUTIFUL → 97

The alphabetical position of letter as follows

Sum of these numbers = 2 + 5 + 1 + 21 + 20 + 9 + 6 + 21 + 12 = 97

So, word ‘BEAUTIFUL’ will be coded as ‘97’.

Applying the similar concept in ‘WONDERFUL

So, sum of these numbers = 23 + 15 + 14 + 4 + 5 + 18 + 6 + 21 + 12 = 118

So, word ‘WONDERFUL’ will be coded as ‘118’.

• Question 4 of 5 4. Question Directions for the following 2 (two) items: The digits from 0 to 9 are coded as shown below. Condition I. If a number begins and ends with zero or an even number, then the first and last digits are to be coded as A and λ (lamda) respectively. Condition II. If a number begins with one and ends with zero, then the first and last digits are to be coded as γ (gamma) and E respectively. What is the code for 379150? a) MEZ⋆θR b) ØEU⋆θZ c) λØU⋆θE d) Cannot be determined Correct Answer: B Explanation For the given number none of the above two conditions are applicable. Hence code for ‘379150’ can simply be derived from the chart given in the question. 379150 → ØE U⋆θZ Incorrect Answer: B Explanation For the given number none of the above two conditions are applicable. Hence code for ‘379150’ can simply be derived from the chart given in the question. 379150 → ØE U⋆θZ

#### 4. Question

Directions for the following 2 (two) items: The digits from 0 to 9 are coded as shown below.

• Condition I. If a number begins and ends with zero or an even number, then the first and last digits are to be coded as A and λ (lamda) respectively.

• Condition II. If a number begins with one and ends with zero, then the first and last digits are to be coded as γ (gamma) and E respectively.

What is the code for 379150?

• d) Cannot be determined

Explanation

For the given number none of the above two conditions are applicable. Hence code for ‘379150’ can simply

be derived from the chart given in the question.

379150 → ØE U⋆θZ

Explanation

For the given number none of the above two conditions are applicable. Hence code for ‘379150’ can simply

be derived from the chart given in the question.

379150 → ØE U⋆θZ

• Question 5 of 5 5. Question What will be the code for 147689020? a) ⋆MEcRUZXZ b) γME⋆RUZXE c) γMEØRUZXE d) γMEcRUZXE Correct Answer: D Explanation Here, the 2nd condition is applicable as the number begins with 1 and ends with 0. So, the first and last digits are to be coded as γ (gamma) and E respectively. Rest of the digits will be coded as per the chart given in the question. 147689020 → γMEcRUZXE Incorrect Answer: D Explanation Here, the 2nd condition is applicable as the number begins with 1 and ends with 0. So, the first and last digits are to be coded as γ (gamma) and E respectively. Rest of the digits will be coded as per the chart given in the question. 147689020 → γMEcRUZXE

#### 5. Question

What will be the code for 147689020?

• a) ⋆MEcRUZXZ

• b) γME⋆RUZXE

• c) γMEØRUZXE

• d) γMEcRUZXE

Explanation

Here, the 2nd condition is applicable as the number begins with 1 and ends with 0. So, the first and last digits are to be coded as γ (gamma) and E respectively. Rest of the digits will be coded as per the chart given in the question. 147689020 → γMEcRUZXE

Explanation

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