UPSC Insta–DART (Daily Aptitude and Reasoning Test) 24 Aug 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
#### Quiz-summary
0 of 5 questions completed
Questions:
#### Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
#### Categories
• Not categorized 0%
• Question 1 of 5 1. Question A vessel A mixture , petrol and kerosene oil are in the ratio of 7:5 and in vessel B it is in the ratio of 8:5. P liter of mixture from vessel A and Q liter of mixture from vessel B are taken out and poured into vessel C. if vessel C contains total 300 liter mixture with 40% kerosene oil, then find the value of Q/P ? a) 12/13 b) 13/12 c) 13/15 d) 14/15 Correct Answer: (a) 13/12 Explanation: For vessel A- Petrol taken out=7P/12 liters Kerosene oil taken out=5P/12 liters For vessel B- Petrol taken out=8Q/13 liters Kerosene oil taken out=5Q/13 liters In vessel C- Kerosene oil 5P/12 +5Q/13=3002/5 On solving we get 13P+12Q=3744 —àequation(1) Petrol in vessel C 7P/12+8Q/13=3003/5 91P+96Q=28080—àequation(2) From 1 and 2 we get Q=156, P=144 Q/P=156/144 Q/P=13/12 Incorrect Answer: (a) 13/12 Explanation: For vessel A- Petrol taken out=7P/12 liters Kerosene oil taken out=5P/12 liters For vessel B- Petrol taken out=8Q/13 liters Kerosene oil taken out=5Q/13 liters In vessel C- Kerosene oil 5P/12 +5Q/13=3002/5 On solving we get 13P+12Q=3744 —àequation(1) Petrol in vessel C 7P/12+8Q/13=3003/5 91P+96Q=28080—àequation(2) From 1 and 2 we get Q=156, P=144 Q/P=156/144 Q/P=13/12
#### 1. Question
A vessel A mixture , petrol and kerosene oil are in the ratio of 7:5 and in vessel B it is in the ratio of 8:5. P liter of mixture from vessel A and Q liter of mixture from vessel B are taken out and poured into vessel C. if vessel C contains total 300 liter mixture with 40% kerosene oil, then find the value of Q/P ?
Answer: (a) 13/12
Explanation:
For vessel A-
Petrol taken out=7P/12 liters
Kerosene oil taken out=5P/12 liters
For vessel B-
Petrol taken out=8Q/13 liters
Kerosene oil taken out=5Q/13 liters
In vessel C-
Kerosene oil
5P/12 +5Q/13=300*2/5
On solving we get
13P+12Q=3744 —àequation(1)
Petrol in vessel C
7P/12+8Q/13=300*3/5
91P+96Q=28080—àequation(2)
From 1 and 2 we get Q=156, P=144
Q/P=156/144
Answer: (a) 13/12
Explanation:
For vessel A-
Petrol taken out=7P/12 liters
Kerosene oil taken out=5P/12 liters
For vessel B-
Petrol taken out=8Q/13 liters
Kerosene oil taken out=5Q/13 liters
In vessel C-
Kerosene oil
5P/12 +5Q/13=300*2/5
On solving we get
13P+12Q=3744 —àequation(1)
Petrol in vessel C
7P/12+8Q/13=300*3/5
91P+96Q=28080—àequation(2)
From 1 and 2 we get Q=156, P=144
Q/P=156/144
• Question 2 of 5 2. Question From container P containing 216 liters of mixture of milk and water , water is 12.5% of milk in a container. 72 liters of the mixture is taken out and poured into container Q in which ratio of milk to water is 3:1. If difference between total milk and total water in container Q is 120 liters, then find difference between the quantity of initial mixture in a container Q and final mixture in P? a) 16liters b) 18liters c) 12liters d) 8liters Correct Answer: (a) 16 liters Explanation: Let initially milk and water in container Q is ‘3a’ liters and ‘a’ respectively ATQ, 3a+8/972-a-1/972 =120 On solving e get a=32liters Initial quantity in container Q=32(3+1)=128 liters Required difference=(216-72)-128=16liters Incorrect Answer: (a) 16 liters Explanation: Let initially milk and water in container Q is ‘3a’ liters and ‘a’ respectively ATQ, 3a+8/972-a-1/972 =120 On solving e get a=32liters Initial quantity in container Q=32(3+1)=128 liters Required difference=(216-72)-128=16liters
#### 2. Question
From container P containing 216 liters of mixture of milk and water , water is 12.5% of milk in a container. 72 liters of the mixture is taken out and poured into container Q in which ratio of milk to water is 3:1. If difference between total milk and total water in container Q is 120 liters, then find difference between the quantity of initial mixture in a container Q and final mixture in P?
• a) 16liters
• b) 18liters
• c) 12liters
• d) 8liters
Answer: (a) 16 liters
Explanation:
Let initially milk and water in container Q is ‘3a’ liters and ‘a’ respectively
3a+8/972-a-1/972 =120
On solving e get a=32liters
Initial quantity in container Q=32*(3+1)=128 liters
Required difference=(216-72)-128=16liters
Answer: (a) 16 liters
Explanation:
Let initially milk and water in container Q is ‘3a’ liters and ‘a’ respectively
3a+8/972-a-1/972 =120
On solving e get a=32liters
Initial quantity in container Q=32*(3+1)=128 liters
Required difference=(216-72)-128=16liters
• Question 3 of 5 3. Question A container contain 96L mixture of milk and water out of which 35% of water. 20L of mixture is taken out and 10L milk and 16L water are added in remaining mixture. Find the difference between quantity of milk and water in final mixture after replacement. a) 15.4L b) 16.8L c) 19.8L d) 21.4L Correct Answer: (b) 16.8L Explanation: Milk remained after 20lit mixture is taken out =(96-20)65/100=49.4L Water remained after 20lit mixture is taken out =(96-20)35/100=26.6L Required difference=(49.4+10)-(26.6+16)=16.8liter Incorrect Answer: (b) 16.8L Explanation: Milk remained after 20lit mixture is taken out =(96-20)65/100=49.4L Water remained after 20lit mixture is taken out =(96-20)35/100=26.6L Required difference=(49.4+10)-(26.6+16)=16.8liter
#### 3. Question
A container contain 96L mixture of milk and water out of which 35% of water. 20L of mixture is taken out and 10L milk and 16L water are added in remaining mixture. Find the difference between quantity of milk and water in final mixture after replacement.
Answer: (b) 16.8L
Explanation:
Milk remained after 20lit mixture is taken out
=(96-20)*65/100=49.4L
Water remained after 20lit mixture is taken out
=(96-20)*35/100=26.6L
Required difference=(49.4+10)-(26.6+16)=16.8liter
Answer: (b) 16.8L
Explanation:
Milk remained after 20lit mixture is taken out
=(96-20)*65/100=49.4L
Water remained after 20lit mixture is taken out
=(96-20)*35/100=26.6L
Required difference=(49.4+10)-(26.6+16)=16.8liter
• Question 4 of 5 4. Question A container contains mixture of milk and water in the ratio 5:3 respectively. If 16liter milk is added in it then ratio of milk to water becomes 11:5. Find difference between initial quantity of milk and that of water. a) 10L b) 20L c) 30L d) 15L Correct Answer: (a) 10L Explanation: Let the initial quantity of milk and water be 5x and 3x liter respectively. ATQ, 5x+8/3x =11/5 25x+40=33x X=5 5x-3x=2x=25=10L Incorrect Answer: (a) 10L Explanation: Let the initial quantity of milk and water be 5x and 3x liter respectively. ATQ, 5x+8/3x =11/5 25x+40=33x X=5 5x-3x=2x=25=10L
#### 4. Question
A container contains mixture of milk and water in the ratio 5:3 respectively. If 16liter milk is added in it then ratio of milk to water becomes 11:5. Find difference between initial quantity of milk and that of water.
Answer: (a) 10L
Explanation:
Let the initial quantity of milk and water be 5x and 3x liter respectively.
5x+8/3x =11/5
25x+40=33x
5x-3x=2x=2*5=10L
Answer: (a) 10L
Explanation:
Let the initial quantity of milk and water be 5x and 3x liter respectively.
5x+8/3x =11/5
25x+40=33x
5x-3x=2x=2*5=10L
• Question 5 of 5 5. Question A container contains a mixture of two liquid P and Q in the ratio 5:3 . if 8 liter of the mixture is taken out and replaced with liquid Q, then the new ratio of liquid P to Q becomes 1:1. Find the initial quantity of mixture in the container. a) 30L b) 40L c) 20L d) 10L Correct Answer: (b) 40L Explanation: Let P:Q 5x : 3x (5x-5/8 8)/(3x-3/8 8 +8)=1/1 5x-5=3x+5 X=10/2=5 5x+3x=8x=85=40L Incorrect Answer: (b) 40L Explanation: Let P:Q 5x : 3x (5x-5/8 8)/(3x-3/8 8 +8)=1/1 5x-5=3x+5 X=10/2=5 5x+3x=8x=85=40L
#### 5. Question
A container contains a mixture of two liquid P and Q in the ratio 5:3 . if 8 liter of the mixture is taken out and replaced with liquid Q, then the new ratio of liquid P to Q becomes 1:1. Find the initial quantity of mixture in the container.
Answer: (b) 40L
Explanation:
(5x-5/8 8)/(3x-3/8 8 +8)=1/1
5x+3x=8x=8*5=40L
Answer: (b) 40L
Explanation:
(5x-5/8 8)/(3x-3/8 8 +8)=1/1
5x+3x=8x=8*5=40L
• Official Facebook Page HERE
• Follow our Twitter Account HERE