UPSC Insta–DART (Daily Aptitude and Reasoning Test) 23 Sep 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question AB and CD are 2-digit numbers. Multiplying AB with CD results in a 3-digit number DEF. Adding DEF to another 3-digit number GHI results in 943. Further A, B, C, D, E, F, G, H, I are distinct digits. If E = 0, F = 6, then what is A + B + C equal to? (a) 10 (b) 11 (c) 12 (d) 13 Correct Answer: C Solution: Given that, AB and CD are 2-digit numbers. Multiplying AB with CD results in a 3-digit number DEF. Adding DEF to another 3-digit number GHI results in 943. A, B, C, D, E, F, G, H, I are distinct digits. E = 0, F = 6 Now, We need a product of the form D06. Try the pair that gives 406: AB = 29 and CD = 14. This satisfies D = 4 (units of CD) and DEF = 406 with E = 0 and F = 6. Check the sum: DEF + GHI = 943 ⇒ 406 + GHI = 943 ⇒ GHI = 537. Digits used are A=2, B=9, C=1, D=4, E=0, F=6, G=5, H=3, I=7 — all distinct. Therefore, A + B + C = 2 + 9 + 1 = 12 Hence option (c) is correct. Incorrect Answer: C Solution: Given that, AB and CD are 2-digit numbers. Multiplying AB with CD results in a 3-digit number DEF. Adding DEF to another 3-digit number GHI results in 943. A, B, C, D, E, F, G, H, I are distinct digits. E = 0, F = 6 Now, We need a product of the form D06. Try the pair that gives 406: AB = 29 and CD = 14. This satisfies D = 4 (units of CD) and DEF = 406 with E = 0 and F = 6. Check the sum: DEF + GHI = 943 ⇒ 406 + GHI = 943 ⇒ GHI = 537. Digits used are A=2, B=9, C=1, D=4, E=0, F=6, G=5, H=3, I=7 — all distinct. Therefore, A + B + C = 2 + 9 + 1 = 12 Hence option (c) is correct.

#### 1. Question

AB and CD are 2-digit numbers. Multiplying AB with CD results in a 3-digit number DEF. Adding DEF to another 3-digit number GHI results in 943. Further A, B, C, D, E, F, G, H, I are distinct digits. If E = 0, F = 6, then what is A + B + C equal to?

Given that,

AB and CD are 2-digit numbers.

Multiplying AB with CD results in a 3-digit number DEF.

Adding DEF to another 3-digit number GHI results in 943.

A, B, C, D, E, F, G, H, I are distinct digits.

E = 0, F = 6

We need a product of the form D06.

Try the pair that gives 406: AB = 29 and CD = 14.

This satisfies D = 4 (units of CD) and DEF = 406 with E = 0 and F = 6.

Check the sum:

DEF + GHI = 943 ⇒ 406 + GHI = 943 ⇒ GHI = 537.

Digits used are A=2, B=9, C=1, D=4, E=0, F=6, G=5, H=3, I=7 — all distinct.

Therefore, A + B + C = 2 + 9 + 1 = 12

Hence option (c) is correct.

Given that,

AB and CD are 2-digit numbers.

Multiplying AB with CD results in a 3-digit number DEF.

Adding DEF to another 3-digit number GHI results in 943.

A, B, C, D, E, F, G, H, I are distinct digits.

E = 0, F = 6

We need a product of the form D06.

Try the pair that gives 406: AB = 29 and CD = 14.

This satisfies D = 4 (units of CD) and DEF = 406 with E = 0 and F = 6.

Check the sum:

DEF + GHI = 943 ⇒ 406 + GHI = 943 ⇒ GHI = 537.

Digits used are A=2, B=9, C=1, D=4, E=0, F=6, G=5, H=3, I=7 — all distinct.

Therefore, A + B + C = 2 + 9 + 1 = 12

Hence option (c) is correct.

• Question 2 of 5 2. Question A 3-digit number ABC, on multiplication with D gives 42DD where A, B, C and D are different non-zero digits. What is the value of A+B+C? (a) 12 (b) 13 (c) 14 (d) 15 Correct Answer: C Solution: Given that, A 3-digit number ABC, on multiplication with D gives 42DD A, B, C and D are different non-zero digits. Now, We need a product of the form 42DD Check possible D so that 42DD divided by D gives a valid 3-digit ABC with all digits distinct and none equal to D. If D = 8, then 4288/8 = 536 A = 5, B = 3, C = 6 are distinct, none equals D If D = 6, then 4266/6 = 711 (digits repeat, not allowed) If D = 7, then 4277/7 = 611 (digits repeat, not allowed) Other D values give invalid or non-distinct cases Therefore, ABC = 536 and A + B + C = 5 + 3 + 6 = 14 Hence option (c) is correct Incorrect Answer: C Solution: Given that, A 3-digit number ABC, on multiplication with D gives 42DD A, B, C and D are different non-zero digits. Now, We need a product of the form 42DD Check possible D so that 42DD divided by D gives a valid 3-digit ABC with all digits distinct and none equal to D. If D = 8, then 4288/8 = 536 A = 5, B = 3, C = 6 are distinct, none equals D If D = 6, then 4266/6 = 711 (digits repeat, not allowed) If D = 7, then 4277/7 = 611 (digits repeat, not allowed) Other D values give invalid or non-distinct cases Therefore, ABC = 536 and A + B + C = 5 + 3 + 6 = 14 Hence option (c) is correct

#### 2. Question

A 3-digit number ABC, on multiplication with D gives 42DD where A, B, C and D are different non-zero digits. What is the value of A+B+C?

Answer: C

Solution:

Given that,

A 3-digit number ABC, on multiplication with D gives 42DD

A, B, C and D are different non-zero digits.

We need a product of the form 42DD

Check possible D so that 42DD divided by D gives a valid 3-digit ABC with all digits distinct and none equal to D.

If D = 8, then 4288/8 = 536

A = 5, B = 3, C = 6 are distinct, none equals D

If D = 6, then 4266/6 = 711 (digits repeat, not allowed)

If D = 7, then 4277/7 = 611 (digits repeat, not allowed)

Other D values give invalid or non-distinct cases

Therefore, ABC = 536 and A + B + C = 5 + 3 + 6 = 14

Hence option (c) is correct

Answer: C

Solution:

Given that,

A 3-digit number ABC, on multiplication with D gives 42DD

A, B, C and D are different non-zero digits.

We need a product of the form 42DD

Check possible D so that 42DD divided by D gives a valid 3-digit ABC with all digits distinct and none equal to D.

If D = 8, then 4288/8 = 536

A = 5, B = 3, C = 6 are distinct, none equals D

If D = 6, then 4266/6 = 711 (digits repeat, not allowed)

If D = 7, then 4277/7 = 611 (digits repeat, not allowed)

Other D values give invalid or non-distinct cases

Therefore, ABC = 536 and A + B + C = 5 + 3 + 6 = 14

Hence option (c) is correct

• Question 3 of 5 3. Question If ABC and DEF are both 3-digit numbers such that A, B, C, D, E and F are distinct non-zero digits and ABC + DEF = 1000, then what is the value of A+B+C+D+E+F? (a) 27 (b) 28 (c) 29 (d) 30 Correct Answer: B Solution: Given that, ABC and DEF are both 3-digit numbers with distinct non-zero digits and ABC + DEF = 1000 Now, taking values ABC = 124 and DEF = 876, 124 + 876 = 1000 So, A + B + C + D + E + F = 1 + 2 + 4 + 8 + 7 + 6 = 28 Hence option (b) is correct Incorrect Answer: B Solution: Given that, ABC and DEF are both 3-digit numbers with distinct non-zero digits and ABC + DEF = 1000 Now, taking values ABC = 124 and DEF = 876, 124 + 876 = 1000 So, A + B + C + D + E + F = 1 + 2 + 4 + 8 + 7 + 6 = 28 Hence option (b) is correct

#### 3. Question

If ABC and DEF are both 3-digit numbers such that A, B, C, D, E and F are distinct non-zero digits and ABC + DEF = 1000, then what is the value of A+B+C+D+E+F?

Given that,

ABC and DEF are both 3-digit numbers with distinct non-zero digits and ABC + DEF = 1000

Now, taking values ABC = 124 and DEF = 876, 124 + 876 = 1000

So, A + B + C + D + E + F = 1 + 2 + 4 + 8 + 7 + 6 = 28

Hence option (b) is correct

Given that,

ABC and DEF are both 3-digit numbers with distinct non-zero digits and ABC + DEF = 1000

Now, taking values ABC = 124 and DEF = 876, 124 + 876 = 1000

So, A + B + C + D + E + F = 1 + 2 + 4 + 8 + 7 + 6 = 28

Hence option (b) is correct

• Question 4 of 5 4. Question Number 248 is added to 3B5 and the sum obtained is 5A3, where A and B are integers. It is given that 5A3 is exactly divisible by 3. The only possible value of B is (a) 2 (b) 5 (c) 7 (d) 8 Correct Answer: A Solution: Given that, Number 248 is added to 3B5 and the sum obtained is 5A3 A and B are integers 5A3 is exactly divisible by 3 Now, Units: 5 + 8 = 13, write 3 and carry 1 Tens: B + 4 + 1 = B + 5, this equals A, and since hundreds must be 5 from 3 + 2 + 0, there is no carry here, so B + 5 < 10 Divisibility by 3: 5 + A + 3 = 8 + A must be divisible by 3, so A can be 1, 4, or 7 Since A = B + 5 and B + 5 < 10, A is in {5,6,7,8,9}. Intersection with {1,4,7} gives A = 7, hence B = 2 Thus B = 2 Hence option (a) is correct Incorrect Answer: A Solution: Given that, Number 248 is added to 3B5 and the sum obtained is 5A3 A and B are integers 5A3 is exactly divisible by 3 Now, Units: 5 + 8 = 13, write 3 and carry 1 Tens: B + 4 + 1 = B + 5, this equals A, and since hundreds must be 5 from 3 + 2 + 0, there is no carry here, so B + 5 < 10 Divisibility by 3: 5 + A + 3 = 8 + A must be divisible by 3, so A can be 1, 4, or 7 Since A = B + 5 and B + 5 < 10, A is in {5,6,7,8,9}. Intersection with {1,4,7} gives A = 7, hence B = 2 Thus B = 2 Hence option (a) is correct

#### 4. Question

Number 248 is added to 3B5 and the sum obtained is 5A3, where A and B are integers. It is given that 5A3 is exactly divisible by 3. The only possible value of B is

Given that,

Number 248 is added to 3B5 and the sum obtained is 5A3

A and B are integers

5A3 is exactly divisible by 3

Units: 5 + 8 = 13, write 3 and carry 1

Tens: B + 4 + 1 = B + 5, this equals A, and since hundreds must be 5 from 3 + 2 + 0, there is no carry here, so B + 5 < 10

Divisibility by 3: 5 + A + 3 = 8 + A must be divisible by 3, so A can be 1, 4, or 7

Since A = B + 5 and B + 5 < 10, A is in {5,6,7,8,9}. Intersection with {1,4,7} gives A = 7, hence B = 2

Thus B = 2

Hence option (a) is correct

Given that,

Number 248 is added to 3B5 and the sum obtained is 5A3

A and B are integers

5A3 is exactly divisible by 3

Units: 5 + 8 = 13, write 3 and carry 1

Tens: B + 4 + 1 = B + 5, this equals A, and since hundreds must be 5 from 3 + 2 + 0, there is no carry here, so B + 5 < 10

Divisibility by 3: 5 + A + 3 = 8 + A must be divisible by 3, so A can be 1, 4, or 7

Since A = B + 5 and B + 5 < 10, A is in {5,6,7,8,9}. Intersection with {1,4,7} gives A = 7, hence B = 2

Thus B = 2

Hence option (a) is correct

• Question 5 of 5 5. Question Fungi are among the most diverse organisms on Earth, ranging from microscopic yeasts to large mushrooms. Neither plants nor animals, they occupy a unique kingdom and play crucial ecological roles. They act as decomposers, recycling nutrients from dead organic matter, and form symbiotic relationships with plants through mycorrhizal associations, enhancing soil fertility. Humans have long depended on fungi for bread, wine, antibiotics like penicillin, and industrial enzymes. Yet, fungi can also be harmful—causing crop diseases, food spoilage, and infections in humans. The study of fungi, called mycology, reveals their dual nature: they are both life-sustaining and life-threatening. Understanding fungi is essential for medicine, agriculture, and environmental sustainability. Which one of the following statements best reflects the most logical and rational message conveyed by the author of the passage? (a) Fungi are dangerous organisms that must be eliminated from human life. (b) Fungi should be classified as plants because of their ecological role. (c) Fungi are diverse organisms with both beneficial and harmful impacts on humans and ecosystems. (d) Fungi have no significant role in agriculture or medicine. Correct Answer: (c) Explanation: Option (a) is incorrect: The passage highlights fungi’s harmful effects but equally emphasizes their benefits. Option (b) is incorrect: It explicitly notes fungi are neither plants nor animals and have their own kingdom. Option (d) is incorrect: The passage stresses fungi’s roles in antibiotics, enzymes, and agriculture. Option (c) is correct: The passage conveys the dual nature of fungi—essential to human welfare but also capable of causing harm. Incorrect Answer: (c) Explanation: Option (a) is incorrect: The passage highlights fungi’s harmful effects but equally emphasizes their benefits. Option (b) is incorrect: It explicitly notes fungi are neither plants nor animals and have their own kingdom. Option (d) is incorrect: The passage stresses fungi’s roles in antibiotics, enzymes, and agriculture. Option (c) is correct: The passage conveys the dual nature of fungi—essential to human welfare but also capable of causing harm.

#### 5. Question

Fungi are among the most diverse organisms on Earth, ranging from microscopic yeasts to large mushrooms. Neither plants nor animals, they occupy a unique kingdom and play crucial ecological roles. They act as decomposers, recycling nutrients from dead organic matter, and form symbiotic relationships with plants through mycorrhizal associations, enhancing soil fertility. Humans have long depended on fungi for bread, wine, antibiotics like penicillin, and industrial enzymes. Yet, fungi can also be harmful—causing crop diseases, food spoilage, and infections in humans. The study of fungi, called mycology, reveals their dual nature: they are both life-sustaining and life-threatening. Understanding fungi is essential for medicine, agriculture, and environmental sustainability.

Which one of the following statements best reflects the most logical and rational message conveyed by the author of the passage?

• (a) Fungi are dangerous organisms that must be eliminated from human life.

• (b) Fungi should be classified as plants because of their ecological role.

• (c) Fungi are diverse organisms with both beneficial and harmful impacts on humans and ecosystems.

• (d) Fungi have no significant role in agriculture or medicine.

Answer: (c)

Explanation: Option (a) is incorrect: The passage highlights fungi’s harmful effects but equally emphasizes their benefits. Option (b) is incorrect: It explicitly notes fungi are neither plants nor animals and have their own kingdom. Option (d) is incorrect: The passage stresses fungi’s roles in antibiotics, enzymes, and agriculture. Option (c) is correct: The passage conveys the dual nature of fungi—essential to human welfare but also capable of causing harm.

Answer: (c)

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