UPSC Insta–DART (Daily Aptitude and Reasoning Test) 23 Sep 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Vijay can complete a job in 70 days. Sudeep is 30% more efficient than Vijay. Surya is 20% more efficient than Vijay. If all three of them work together, then how long will they take to complete the job? a) 25 b) 22 c) 28 d) 20 Correct Answer: Option (d) Explanation: Let assume Vijay does 1 unit of work in a day. Hence the job consists of 70 units of work. Sudeep will do 1.30 unit of work in a day (30% more sufficient than Vijay). Surya will do 1.20 unit of work in a day (20% more sufficient than Vijay). All together they will do , 1+1.3+1.2 = 3.5 units of work in a day. Hence time taken by them to complete the job = 70/3.5 = 20 days. Therefore Option d is correct answer. Incorrect Answer: Option (d) Explanation: Let assume Vijay does 1 unit of work in a day. Hence the job consists of 70 units of work. Sudeep will do 1.30 unit of work in a day (30% more sufficient than Vijay). Surya will do 1.20 unit of work in a day (20% more sufficient than Vijay). All together they will do , 1+1.3+1.2 = 3.5 units of work in a day. Hence time taken by them to complete the job = 70/3.5 = 20 days. Therefore Option d is correct answer.
#### 1. Question
Vijay can complete a job in 70 days. Sudeep is 30% more efficient than Vijay. Surya is 20% more efficient than Vijay. If all three of them work together, then how long will they take to complete the job?
Answer: Option (d)
Explanation:
Let assume Vijay does 1 unit of work in a day.
Hence the job consists of 70 units of work.
Sudeep will do 1.30 unit of work in a day (30% more sufficient than Vijay).
Surya will do 1.20 unit of work in a day (20% more sufficient than Vijay).
All together they will do , 1+1.3+1.2 = 3.5 units of work in a day.
Hence time taken by them to complete the job = 70/3.5 = 20 days.
Therefore Option d is correct answer.
Answer: Option (d)
Explanation:
Let assume Vijay does 1 unit of work in a day.
Hence the job consists of 70 units of work.
Sudeep will do 1.30 unit of work in a day (30% more sufficient than Vijay).
Surya will do 1.20 unit of work in a day (20% more sufficient than Vijay).
All together they will do , 1+1.3+1.2 = 3.5 units of work in a day.
Hence time taken by them to complete the job = 70/3.5 = 20 days.
Therefore Option d is correct answer.
• Question 2 of 5 2. Question Ashok is twice as efficient as Anil. How much time will they, working together, take to complete a job which Ashok alone could have done in 10 days less than Anil? a) 8 days b) 10 days c) 5.44 days d) 6.66 days Correct Answer: Option (d) Explanation: Efficiency Ashok : Anil = 2 : 1 So for time Ashok : Anil = 1 : 2 Since Ashok alone could have done the work in 10 days less than Anil, if Ashok alone can do the work in 10 days then Anil alone can do the work in 20 days. Ashok and Anil can do the work = ab/(a+b) a= Ashok work , b=Anil work = (10×20)/(10+20) = 6.66 Together Ashok and Anil can do the work in 6.66 days. Hence Option (d) is correct answer. Incorrect Answer: Option (d) Explanation: Efficiency Ashok : Anil = 2 : 1 So for time Ashok : Anil = 1 : 2 Since Ashok alone could have done the work in 10 days less than Anil, if Ashok alone can do the work in 10 days then Anil alone can do the work in 20 days. Ashok and Anil can do the work = ab/(a+b) a= Ashok work , b=Anil work = (10×20)/(10+20) = 6.66 Together Ashok and Anil can do the work in 6.66 days. Hence Option (d) is correct answer.
#### 2. Question
Ashok is twice as efficient as Anil. How much time will they, working together, take to complete a job which Ashok alone could have done in 10 days less than Anil?
• b) 10 days
• c) 5.44 days
• d) 6.66 days
Answer: Option (d)
Explanation:
Efficiency
Ashok : Anil = 2 : 1
So for time
Ashok : Anil = 1 : 2
Since Ashok alone could have done the work in 10 days less than Anil, if Ashok alone can do the work in 10 days then Anil alone can do the work in 20 days.
Ashok and Anil can do the work = ab/(a+b) a= Ashok work , b=Anil work
= (10×20)/(10+20) = 6.66
Together Ashok and Anil can do the work in 6.66 days.
Hence Option (d) is correct answer.
Answer: Option (d)
Explanation:
Efficiency
Ashok : Anil = 2 : 1
So for time
Ashok : Anil = 1 : 2
Since Ashok alone could have done the work in 10 days less than Anil, if Ashok alone can do the work in 10 days then Anil alone can do the work in 20 days.
Ashok and Anil can do the work = ab/(a+b) a= Ashok work , b=Anil work
= (10×20)/(10+20) = 6.66
Together Ashok and Anil can do the work in 6.66 days.
Hence Option (d) is correct answer.
• Question 3 of 5 3. Question 9 boys and 12 girls perform a task in 15 days. The same task is performed by 39 boys and 72 girls in 3 days. Then what will be the time taken by 20 boys and 5 girls in performing the same task? a) 12 days b) 8 days c) 9 days d) 10 days Correct Answer: Option (d) Explanation: Let 1 boy’s 1 day’s work = x (i.e. efficiency of 1 boy = ‘x’ units/day) and 1 girl’s 1 day’s work = y (i.e. efficiency of 1 girl = ‘y’ units/day). Then, 9x + 12y = 1/15 ………………І (9 boys’ & 12 girls’ 1 day’s work) 39x + 72y = 1/3 ………….…ІІ (39 boys’ & 72 girls’ 1 day’s work). Multiplying equation І by 6 and then subtracting equation ІІ from it, we get, x = 1/225. Putting the value of x in either equation І or equation ІІ will yield y = 1/450. So, 20 boys’ and 5 girls’ 1 day’s work = 20/225 + 5/450 = 1/10. Since 1/10 part is performed in 1 day. So, 1 part is performed in 1/(1/10) day, i.e. 10 days. Incorrect Answer: Option (d) Explanation: Let 1 boy’s 1 day’s work = x (i.e. efficiency of 1 boy = ‘x’ units/day) and 1 girl’s 1 day’s work = y (i.e. efficiency of 1 girl = ‘y’ units/day). Then, 9x + 12y = 1/15 ………………І (9 boys’ & 12 girls’ 1 day’s work) 39x + 72y = 1/3 ………….…ІІ (39 boys’ & 72 girls’ 1 day’s work). Multiplying equation І by 6 and then subtracting equation ІІ from it, we get, x = 1/225. Putting the value of x in either equation І or equation ІІ will yield y = 1/450. So, 20 boys’ and 5 girls’ 1 day’s work = 20/225 + 5/450 = 1/10. Since 1/10 part is performed in 1 day. So, 1 part is performed in 1/(1/10) day, i.e. 10 days.
#### 3. Question
9 boys and 12 girls perform a task in 15 days. The same task is performed by 39 boys and 72 girls in 3 days. Then what will be the time taken by 20 boys and 5 girls in performing the same task?
• a) 12 days
• d) 10 days
Answer: Option (d)
Explanation:
Let 1 boy’s 1 day’s work = x (i.e. efficiency of 1 boy = ‘x’ units/day) and
1 girl’s 1 day’s work = y (i.e. efficiency of 1 girl = ‘y’ units/day).
Then, 9x + 12y = 1/15 ………………І
(9 boys’ & 12 girls’ 1 day’s work)
39x + 72y = 1/3 ………….…ІІ
(39 boys’ & 72 girls’ 1 day’s work).
Multiplying equation І by 6 and then subtracting equation ІІ from it, we get,
x = 1/225.
Putting the value of x in either equation І or equation ІІ will yield
y = 1/450.
So, 20 boys’ and 5 girls’ 1 day’s work
= 20/225 + 5/450
Since 1/10 part is performed in 1 day.
So, 1 part is performed in 1/(1/10) day,
i.e. 10 days.
Answer: Option (d)
Explanation:
Let 1 boy’s 1 day’s work = x (i.e. efficiency of 1 boy = ‘x’ units/day) and
1 girl’s 1 day’s work = y (i.e. efficiency of 1 girl = ‘y’ units/day).
Then, 9x + 12y = 1/15 ………………І
(9 boys’ & 12 girls’ 1 day’s work)
39x + 72y = 1/3 ………….…ІІ
(39 boys’ & 72 girls’ 1 day’s work).
Multiplying equation І by 6 and then subtracting equation ІІ from it, we get,
x = 1/225.
Putting the value of x in either equation І or equation ІІ will yield
y = 1/450.
So, 20 boys’ and 5 girls’ 1 day’s work
= 20/225 + 5/450
Since 1/10 part is performed in 1 day.
So, 1 part is performed in 1/(1/10) day,
i.e. 10 days.
• Question 4 of 5 4. Question It takes 14 persons a total of 7 hours to build a dam. If 8 persons start to build the dam at 6:00 am, and one person per hour is added beginning at 1:00 pm (on the same day), at what time will the building be completed (assume that all the persons involved in building the dam have same efficiency)? a) 4:00 pm b) 5:00 pm c) 4:40 pm d) 5:20 pm Correct Answer: Option (b) Explanation: Total amount of work = 14 persons×7 hours = 98 man-hours. From 6 am to 1 pm, 8 persons = 8 persons×7 hours = 56 man-hours. From 1 pm to 2 pm, 9 persons = 9 persons×1 hour = 9 man-hours. From 2 pm to 3 pm, 10 persons = 10 persons×1 hour = 10 man-hours. From 3 pm to 4 pm, 11 persons = 11 persons×1 hour = 11 man-hours. From 4 pm to 5 pm, 12 persons = 12 persons×1 hour = 12 man-hours. Total work = 56+9+10+11+12 = 98 man-hours. So, the work will get completed at 5:00 pm. Incorrect Answer: Option (b) Explanation: Total amount of work = 14 persons×7 hours = 98 man-hours. From 6 am to 1 pm, 8 persons = 8 persons×7 hours = 56 man-hours. From 1 pm to 2 pm, 9 persons = 9 persons×1 hour = 9 man-hours. From 2 pm to 3 pm, 10 persons = 10 persons×1 hour = 10 man-hours. From 3 pm to 4 pm, 11 persons = 11 persons×1 hour = 11 man-hours. From 4 pm to 5 pm, 12 persons = 12 persons×1 hour = 12 man-hours. Total work = 56+9+10+11+12 = 98 man-hours. So, the work will get completed at 5:00 pm.
#### 4. Question
It takes 14 persons a total of 7 hours to build a dam. If 8 persons start to build the dam at 6:00 am, and one person per hour is added beginning at 1:00 pm (on the same day), at what time will the building be completed (assume that all the persons involved in building the dam have same efficiency)?
• a) 4:00 pm
• b) 5:00 pm
• c) 4:40 pm
• d) 5:20 pm
Answer: Option (b)
Explanation:
Total amount of work = 14 persons×7 hours = 98 man-hours.
From 6 am to 1 pm, 8 persons = 8 persons×7 hours = 56 man-hours.
From 1 pm to 2 pm, 9 persons = 9 persons×1 hour = 9 man-hours.
From 2 pm to 3 pm, 10 persons = 10 persons×1 hour = 10 man-hours.
From 3 pm to 4 pm, 11 persons = 11 persons×1 hour = 11 man-hours.
From 4 pm to 5 pm, 12 persons = 12 persons×1 hour = 12 man-hours.
Total work = 56+9+10+11+12 = 98 man-hours.
So, the work will get completed at 5:00 pm.
Answer: Option (b)
Explanation:
Total amount of work = 14 persons×7 hours = 98 man-hours.
From 6 am to 1 pm, 8 persons = 8 persons×7 hours = 56 man-hours.
From 1 pm to 2 pm, 9 persons = 9 persons×1 hour = 9 man-hours.
From 2 pm to 3 pm, 10 persons = 10 persons×1 hour = 10 man-hours.
From 3 pm to 4 pm, 11 persons = 11 persons×1 hour = 11 man-hours.
From 4 pm to 5 pm, 12 persons = 12 persons×1 hour = 12 man-hours.
Total work = 56+9+10+11+12 = 98 man-hours.
So, the work will get completed at 5:00 pm.
• Question 5 of 5 5. Question A programmer made a complex program which requires x weeks to process all the input. After completion, the program runs for another x days to compile the results and thereafter prepare a handy chart for the user. How many days does the program take to give the final results? a) 7x^2 b) 8x c) 14x d) 7 Correct Answer: Option (b) Explanation: Time taken by the program to process all the inputs = x weeks = 7x days Time taken by the program to compile the results = x days. Total time taken by the program to give the final result = 7x + x = 8x days. Incorrect Answer: Option (b) Explanation: Time taken by the program to process all the inputs = x weeks = 7x days Time taken by the program to compile the results = x days. Total time taken by the program to give the final result = 7x + x = 8x days.
#### 5. Question
A programmer made a complex program which requires x weeks to process all the input. After completion, the program runs for another x days to compile the results and thereafter prepare a handy chart for the user. How many days does the program take to give the final results?
Answer: Option (b)
Explanation:
Time taken by the program to process all the inputs = x weeks = 7x days
Time taken by the program to compile the results = x days.
Total time taken by the program to give the final result = 7x + x = 8x days.
Answer: Option (b)
Explanation:
Time taken by the program to process all the inputs = x weeks = 7x days
Time taken by the program to compile the results = x days.
Total time taken by the program to give the final result = 7x + x = 8x days.
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