UPSC Insta–DART (Daily Aptitude and Reasoning Test) 23 Aug 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Vessel-A contains 160 liters of mixture of petrol and kerosene oil in the ratio 3:1 and vessel-B contains mixture of diesel, petrol and kerosene oil in the ratio 1:3:5. Mixture of both vessels are mixed in another vessel-C and quantity of petrol in vessel-C is 20 liters more than the quantity of kerosene oil in vessel-C, then find the capacity of vessel B. a) 135L b) 145L c) 150L d) 120L Correct Answer: (a) 135L Explanation: Vessel-A contains 160L mixture of petrol and kerosene Petrol : kerosene 3:1 120L : 40L Vessel-B contains Diesel : petrol : kerosene 1y : 3y : 5y ATQ, (120+1y)-(40+5y)=20 80-4y=20 60=4y 15=y Required capacity=y+3y+5y=9y=915=135liters. Incorrect Answer: (a) 135L Explanation: Vessel-A contains 160L mixture of petrol and kerosene Petrol : kerosene 3:1 120L : 40L Vessel-B contains Diesel : petrol : kerosene 1y : 3y : 5y ATQ, (120+1y)-(40+5y)=20 80-4y=20 60=4y 15=y Required capacity=y+3y+5y=9y=915=135liters.
#### 1. Question
Vessel-A contains 160 liters of mixture of petrol and kerosene oil in the ratio 3:1 and vessel-B contains mixture of diesel, petrol and kerosene oil in the ratio 1:3:5. Mixture of both vessels are mixed in another vessel-C and quantity of petrol in vessel-C is 20 liters more than the quantity of kerosene oil in vessel-C, then find the capacity of vessel B.
Answer: (a) 135L
Explanation:
Vessel-A contains 160L mixture of petrol and kerosene
Petrol : kerosene
120L : 40L
Vessel-B contains
Diesel : petrol : kerosene
1y : 3y : 5y
(120+1y)-(40+5y)=20
Required capacity=y+3y+5y=9y=9*15=135liters.
Answer: (a) 135L
Explanation:
Vessel-A contains 160L mixture of petrol and kerosene
Petrol : kerosene
120L : 40L
Vessel-B contains
Diesel : petrol : kerosene
1y : 3y : 5y
(120+1y)-(40+5y)=20
Required capacity=y+3y+5y=9y=9*15=135liters.
• Question 2 of 5 2. Question There are three vessels P,Q and R. vessel P and Q filled with mixture of milk and water in the ratio of 5:4 and 5:3 respectively.25% of mixture from vessel P taken out and mixed in vessel R, which contains 90L pure milk. If in resulting mixture milk is 250% more than water in vessel R and initial quantity of mixture in vessel Q is 40L less than that of mixture in vessel P, then find the quantity of milk in vessel Q. a) 100L b) 200L c) 250L d) 300L Correct Answer: (b) Explanation: P : Q : R Milk :water : milk: water : milk=90L 5 : 4 5 : 3 Let total mixture in vessel P =9x liters And total mixture in vessel Q= 8y liters ATQ, (9x25/100 5/9 +90)/(9x25/1004/9) =7/2 On solving we get x=40 Initial mixture in vessel P =9x=940=360 liters Mixture in vessel Q=360-40=320 Quantity of milk in vessel Q=3205/8=200L Incorrect Answer: (b) Explanation: P : Q : R Milk :water : milk: water : milk=90L 5 : 4 5 : 3 Let total mixture in vessel P =9x liters And total mixture in vessel Q= 8y liters ATQ, (9x25/100 5/9 +90)/(9x25/1004/9) =7/2 On solving we get x=40 Initial mixture in vessel P =9x=940=360 liters Mixture in vessel Q=360-40=320 Quantity of milk in vessel Q=3205/8=200L
#### 2. Question
There are three vessels P,Q and R. vessel P and Q filled with mixture of milk and water in the ratio of 5:4 and 5:3 respectively.25% of mixture from vessel P taken out and mixed in vessel R, which contains 90L pure milk. If in resulting mixture milk is 250% more than water in vessel R and initial quantity of mixture in vessel Q is 40L less than that of mixture in vessel P, then find the quantity of milk in vessel Q.
Answer: (b)
Explanation:
Milk :water : milk: water : milk=90L
5 : 4 5 : 3
Let total mixture in vessel P =9x liters
And total mixture in vessel Q= 8y liters
(9x25/100 5/9 +90)/(9x25/1004/9) =7/2
On solving we get x=40
Initial mixture in vessel P =9x=9*40=360 liters
Mixture in vessel Q=360-40=320
Quantity of milk in vessel Q=320*5/8=200L
Answer: (b)
Explanation:
Milk :water : milk: water : milk=90L
5 : 4 5 : 3
Let total mixture in vessel P =9x liters
And total mixture in vessel Q= 8y liters
(9x25/100 5/9 +90)/(9x25/1004/9) =7/2
On solving we get x=40
Initial mixture in vessel P =9x=9*40=360 liters
Mixture in vessel Q=360-40=320
Quantity of milk in vessel Q=320*5/8=200L
• Question 3 of 5 3. Question Bottle ‘A’ contains 200ml juice and bottle ‘B’ contains 220ml of water . 4xml of juice taken out from ‘A’ and mixed in ‘B’ and then 3x ml mixture from ‘B’ taken out and poured into a vacant bottle ‘C’. if the ratio of water to juice in glass C is 11:4 then find remaining Quantity of juice in bottle ‘B’ ? a) 10ml b) 30ml c) 20ml d) 64ml Correct Answer: (d) 64ml Explanation: Given, Juice taken out from bottle ‘A’ =4x ml Total mixture in bottle ‘B’ = (220+4x) ml Ratio of water/ juice in bottle B 220/4x=55/x Now the mixture taken out from bottle B and poured in glass ‘C’ =3x ml. In bottle C= water/juice=11/4 ( 3x55/55+x ) / (3xx/55x+x) =11/4 55/x=11/4 X=20ml. 4x-3xx/55+x 80-6020/75=80-16=64ml Incorrect Answer: (d) 64ml Explanation: Given, Juice taken out from bottle ‘A’ =4x ml Total mixture in bottle ‘B’ = (220+4x) ml Ratio of water/ juice in bottle B 220/4x=55/x Now the mixture taken out from bottle B and poured in glass ‘C’ =3x ml. In bottle C= water/juice=11/4 ( 3x55/55+x ) / (3xx/55x+x) =11/4 55/x=11/4 X=20ml. 4x-3xx/55+x 80-6020/75=80-16=64ml
#### 3. Question
Bottle ‘A’ contains 200ml juice and bottle ‘B’ contains 220ml of water . 4xml of juice taken out from ‘A’ and mixed in ‘B’ and then 3x ml mixture from ‘B’ taken out and poured into a vacant bottle ‘C’. if the ratio of water to juice in glass C is 11:4 then find remaining Quantity of juice in bottle ‘B’ ?
Answer: (d) 64ml
Explanation:
Juice taken out from bottle ‘A’ =4x ml
Total mixture in bottle ‘B’ = (220+4x) ml
Ratio of water/ juice in bottle B 220/4x=55/x
Now the mixture taken out from bottle B and poured in glass ‘C’ =3x ml.
In bottle C= water/juice=11/4
( 3x55/55+x ) / (3xx/55x+x) =11/4
4x-3x*x/55+x
80-60*20/75=80-16=64ml
Answer: (d) 64ml
Explanation:
Juice taken out from bottle ‘A’ =4x ml
Total mixture in bottle ‘B’ = (220+4x) ml
Ratio of water/ juice in bottle B 220/4x=55/x
Now the mixture taken out from bottle B and poured in glass ‘C’ =3x ml.
In bottle C= water/juice=11/4
( 3x55/55+x ) / (3xx/55x+x) =11/4
4x-3x*x/55+x
80-60*20/75=80-16=64ml
• Question 4 of 5 4. Question In a mixture of milk and water, the proportion of milk by weight is 60% if from the 160 gm mixture , 40gm of mixture is taken out and 12gm of pure water is added to the mixture, then find the ratio of milk and water in the new mixture. a) 6:5 b) 4:5 c) 2:3 d) 4:7 Correct Answer: (a) 6:5 Explanation: Mixture(160 gm ) Milk: water 60%:40% 3:2 96gm :64gm -12gm -16gm We get 72gm : 60gm On solving we get required ratio 6:5 Incorrect Answer: (a) 6:5 Explanation: Mixture(160 gm ) Milk: water 60%:40% 3:2 96gm :64gm -12gm -16gm We get 72gm : 60gm On solving we get required ratio 6:5
#### 4. Question
In a mixture of milk and water, the proportion of milk by weight is 60% if from the 160 gm mixture , 40gm of mixture is taken out and 12gm of pure water is added to the mixture, then find the ratio of milk and water in the new mixture.
Answer: (a) 6:5
Explanation:
Mixture(160 gm )
Milk: water
96gm :64gm
-12gm -16gm
72gm : 60gm
On solving we get required ratio
Answer: (a) 6:5
Explanation:
Mixture(160 gm )
Milk: water
96gm :64gm
-12gm -16gm
72gm : 60gm
On solving we get required ratio
• Question 5 of 5 5. Question Two vessels P and Q contain water and milk mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing 69(3/13) % water is a) 2:3 b) 2:7 c) 3:7 d) 4:3 Correct Answer: (b) 2:7 Explanation: Required ratio=2/137 :1/13 =2:7 Incorrect Answer: (b) 2:7 Explanation: Required ratio=2/137 :1/13 =2:7
#### 5. Question
Two vessels P and Q contain water and milk mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing 69(3/13) % water is
Answer: (b) 2:7
Explanation:
Required ratio=2/13*7 :1/13
Answer: (b) 2:7
Explanation:
Required ratio=2/13*7 :1/13
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