UPSC Insta–DART (Daily Aptitude and Reasoning Test) 22 Sep 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Three persons A, B and C are standing in a queue not necessarily in the same order. There are 3 persons between A and B, and 6 persons between B and C. If there are 8 persons ahead of C and 10 behind A, what could be the minimum number of persons in the queue? (a) 16 (b) 17 (c) 18 (d) 19 Correct Answer: A Solution: Given that, There are 3 persons between A and B There are 6 persons between B and C There are 8 persons ahead of C There are 10 persons behind A Now, Arrange as: (+1) B (+3) A (+2) C (+7) Check: Between A and B = 3 (ok) Between B and C = 3 + 1 + 2 = 6 (ok) Ahead of C = 1 + 1 + 3 + 1 = 6, add the 2 between A and C gives 8 total ahead (ok) Behind A = 2 + 1 + 7 = 10 (ok) Total persons = 1 + 1 + 3 + 1 + 2 + 1 + 7 = 16 Hence option (a) is correct Incorrect Answer: A Solution: Given that, There are 3 persons between A and B There are 6 persons between B and C There are 8 persons ahead of C There are 10 persons behind A Now, Arrange as: (+1) B (+3) A (+2) C (+7) Check: Between A and B = 3 (ok) Between B and C = 3 + 1 + 2 = 6 (ok) Ahead of C = 1 + 1 + 3 + 1 = 6, add the 2 between A and C gives 8 total ahead (ok) Behind A = 2 + 1 + 7 = 10 (ok) Total persons = 1 + 1 + 3 + 1 + 2 + 1 + 7 = 16 Hence option (a) is correct
#### 1. Question
Three persons A, B and C are standing in a queue not necessarily in the same order. There are 3 persons between A and B, and 6 persons between B and C. If there are 8 persons ahead of C and 10 behind A, what could be the minimum number of persons in the queue?
Answer: A
Solution:
Given that,
There are 3 persons between A and B There are 6 persons between B and C There are 8 persons ahead of C There are 10 persons behind A
Arrange as: (+1) B (+3) A (+2) C (+7)
Check: Between A and B = 3 (ok) Between B and C = 3 + 1 + 2 = 6 (ok) Ahead of C = 1 + 1 + 3 + 1 = 6, add the 2 between A and C gives 8 total ahead (ok) Behind A = 2 + 1 + 7 = 10 (ok)
Total persons = 1 + 1 + 3 + 1 + 2 + 1 + 7 = 16
Hence option (a) is correct
Answer: A
Solution:
Given that,
There are 3 persons between A and B There are 6 persons between B and C There are 8 persons ahead of C There are 10 persons behind A
Arrange as: (+1) B (+3) A (+2) C (+7)
Check: Between A and B = 3 (ok) Between B and C = 3 + 1 + 2 = 6 (ok) Ahead of C = 1 + 1 + 3 + 1 = 6, add the 2 between A and C gives 8 total ahead (ok) Behind A = 2 + 1 + 7 = 10 (ok)
Total persons = 1 + 1 + 3 + 1 + 2 + 1 + 7 = 16
Hence option (a) is correct
• Question 2 of 5 2. Question Two statements S1 and S2 are given below followed by a question. S1: Ramesh and Suresh can complete a task together in 12 days. S2: Ramesh alone can complete the same task in 20 days. Question: How many days will Suresh alone take to complete the task? Which of the following is correct with respect to above? (a) S1 alone is sufficient to answer the Question. (b) S2 alone is sufficient to answer the Question. (c) Both S1 and S2 together are required to answer the Question. (d) Both S1 and S2 together are not sufficient to answer the Question. Correct Answer: (c) Explanation: From S1: Combined rate = 1/12 From S2: Ramesh’s rate = 1/20 ⇒ Suresh’s rate = 1/12 – 1/20 = (5 – 3)/60 = 1/30 So, Suresh alone takes 30 days Hence, both statements are needed. Incorrect Answer: (c) Explanation: From S1: Combined rate = 1/12 From S2: Ramesh’s rate = 1/20 ⇒ Suresh’s rate = 1/12 – 1/20 = (5 – 3)/60 = 1/30 So, Suresh alone takes 30 days Hence, both statements are needed.
#### 2. Question
Two statements S1 and S2 are given below followed by a question.
S1: Ramesh and Suresh can complete a task together in 12 days. S2: Ramesh alone can complete the same task in 20 days.
Question: How many days will Suresh alone take to complete the task?
Which of the following is correct with respect to above?
• (a) S1 alone is sufficient to answer the Question.
• (b) S2 alone is sufficient to answer the Question.
• (c) Both S1 and S2 together are required to answer the Question.
• (d) Both S1 and S2 together are not sufficient to answer the Question.
Answer: (c) Explanation: From S1: Combined rate = 1/12 From S2: Ramesh’s rate = 1/20 ⇒ Suresh’s rate = 1/12 – 1/20 = (5 – 3)/60 = 1/30 So, Suresh alone takes 30 days Hence, both statements are needed.
Answer: (c) Explanation: From S1: Combined rate = 1/12 From S2: Ramesh’s rate = 1/20 ⇒ Suresh’s rate = 1/12 – 1/20 = (5 – 3)/60 = 1/30 So, Suresh alone takes 30 days Hence, both statements are needed.
• Question 3 of 5 3. Question A two-digit number is such that when its digits are reversed, the new number is 27 less than the original. How many such numbers are possible? (a) 3 (b) 4 (c) 5 (d) 7 Correct Answer: D Solution: Let the two-digit number be 10a + b, where a is tens digit and b is units digit. Reversed number = 10b + a. Difference = (10a + b) – (10b + a) = 9(a – b). Given 9(a – b) = 27 ⇒ a – b = 3. Now check possible pairs: (3,0)=30, (4,1)=41, (5,2)=52, (6,3)=63, (7,4)=74, (8,5)=85, (9,6)=96. Total = 7 numbers. Hence, option (d) is correct. Incorrect Answer: D Solution: Let the two-digit number be 10a + b, where a is tens digit and b is units digit. Reversed number = 10b + a. Difference = (10a + b) – (10b + a) = 9(a – b). Given 9(a – b) = 27 ⇒ a – b = 3. Now check possible pairs: (3,0)=30, (4,1)=41, (5,2)=52, (6,3)=63, (7,4)=74, (8,5)=85, (9,6)=96. Total = 7 numbers. Hence, option (d) is correct.
#### 3. Question
A two-digit number is such that when its digits are reversed, the new number is 27 less than the original. How many such numbers are possible?
Answer: D
Solution: Let the two-digit number be 10a + b, where a is tens digit and b is units digit. Reversed number = 10b + a. Difference = (10a + b) – (10b + a) = 9(a – b). Given 9(a – b) = 27 ⇒ a – b = 3.
Now check possible pairs: (3,0)=30, (4,1)=41, (5,2)=52, (6,3)=63, (7,4)=74, (8,5)=85, (9,6)=96. Total = 7 numbers.
Hence, option (d) is correct.
Answer: D
Solution: Let the two-digit number be 10a + b, where a is tens digit and b is units digit. Reversed number = 10b + a. Difference = (10a + b) – (10b + a) = 9(a – b). Given 9(a – b) = 27 ⇒ a – b = 3.
Now check possible pairs: (3,0)=30, (4,1)=41, (5,2)=52, (6,3)=63, (7,4)=74, (8,5)=85, (9,6)=96. Total = 7 numbers.
Hence, option (d) is correct.
• Question 4 of 5 4. Question What is the rightmost digit preceding the zeros in the value of 1220? (a) 4 (b) 6 (c) 8 (d) 2 Correct Answer: B Solution: The value = 1220 12^20 = (3 × 4)20 = 320 × 240 The factor 240 will create zeros, so the deciding digit is from 320 Cyclicity of 3 is 4. 20 divided by 4 leaves remainder 0 So, 320 ends with 1 Therefore, the rightmost digit before zeros = 6 Hence, option B is correct Incorrect Answer: B Solution: The value = 1220 12^20 = (3 × 4)20 = 320 × 240 The factor 240 will create zeros, so the deciding digit is from 320 Cyclicity of 3 is 4. 20 divided by 4 leaves remainder 0 So, 320 ends with 1 Therefore, the rightmost digit before zeros = 6 Hence, option B is correct
#### 4. Question
What is the rightmost digit preceding the zeros in the value of 1220?
Answer: B
Solution: The value = 1220 12^20 = (3 × 4)20 = 320 × 240 The factor 240 will create zeros, so the deciding digit is from 320 Cyclicity of 3 is 4. 20 divided by 4 leaves remainder 0 So, 320 ends with 1 Therefore, the rightmost digit before zeros = 6 Hence, option B is correct
Answer: B
Solution: The value = 1220 12^20 = (3 × 4)20 = 320 × 240 The factor 240 will create zeros, so the deciding digit is from 320 Cyclicity of 3 is 4. 20 divided by 4 leaves remainder 0 So, 320 ends with 1 Therefore, the rightmost digit before zeros = 6 Hence, option B is correct
• Question 5 of 5 5. Question Let p, q and r be digits (1 to 9) with p < q < r, and pp, qq and rr be the corresponding two-digit repeated-digit numbers. Suppose pp + qq + rr = tt0, where tt0 is a three-digit number ending with zero. The number of possible ordered triples (p, q, r) is 8. The number of possible values of p is 4. Which of the above statements is/are correct? (a) 1 only (b) 2 only (c) Both 1 and 2 (d) Neither 1 nor 2 Correct Answer: A Solution: Given that, pp + qq + rr = tt0 and pp = 11p etc. Now, 11(p + q + r) = tt0, so p + q + r is 10 or 20. List the strictly increasing digit triples (p, q, r): Sum 10 gives 4 ordered triples. Sum 20 gives 4 ordered triples. Total ordered triples = 8. So Statement 1 is correct. Distinct p values across these valid triples are {1, 2, 3, 4, 5} which is 5 values, not 4. So Statement 2 is incorrect. Hence, only Statement 1 is correct. Therefore, option (a) is correct. Incorrect Answer: A Solution: Given that, pp + qq + rr = tt0 and pp = 11p etc. Now, 11(p + q + r) = tt0, so p + q + r is 10 or 20. List the strictly increasing digit triples (p, q, r): Sum 10 gives 4 ordered triples. Sum 20 gives 4 ordered triples. Total ordered triples = 8. So Statement 1 is correct. Distinct p values across these valid triples are {1, 2, 3, 4, 5} which is 5 values, not 4. So Statement 2 is incorrect. Hence, only Statement 1 is correct. Therefore, option (a) is correct.
#### 5. Question
Let p, q and r be digits (1 to 9) with p < q < r, and pp, qq and rr be the corresponding two-digit repeated-digit numbers. Suppose pp + qq + rr = tt0, where tt0 is a three-digit number ending with zero.
• The number of possible ordered triples (p, q, r) is 8.
• The number of possible values of p is 4.
Which of the above statements is/are correct?
• (a) 1 only
• (b) 2 only
• (c) Both 1 and 2
• (d) Neither 1 nor 2
Answer: A
Solution:
Given that, pp + qq + rr = tt0 and pp = 11p etc.
Now, 11(p + q + r) = tt0, so p + q + r is 10 or 20.
List the strictly increasing digit triples (p, q, r):
Sum 10 gives 4 ordered triples. Sum 20 gives 4 ordered triples. Total ordered triples = 8. So Statement 1 is correct.
Distinct p values across these valid triples are {1, 2, 3, 4, 5} which is 5 values, not 4. So Statement 2 is incorrect.
Hence, only Statement 1 is correct. Therefore, option (a) is correct.
Answer: A
Solution:
Given that, pp + qq + rr = tt0 and pp = 11p etc.
Now, 11(p + q + r) = tt0, so p + q + r is 10 or 20.
List the strictly increasing digit triples (p, q, r):
Sum 10 gives 4 ordered triples. Sum 20 gives 4 ordered triples. Total ordered triples = 8. So Statement 1 is correct.
Distinct p values across these valid triples are {1, 2, 3, 4, 5} which is 5 values, not 4. So Statement 2 is incorrect.
Hence, only Statement 1 is correct. Therefore, option (a) is correct.
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