UPSC Insta–DART (Daily Aptitude and Reasoning Test) 22 Aug 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question On a 150 cm track, points are marked from both ends. From the left end, first mark is at 5 cm, next 10 cm ahead, then 15 cm, etc. From the right end, same pattern starts. How many distinct points will be marked if overlapping ones are counted only once? (a) 14 (b) 15 (c) 13 (d) 17 Correct Solution: C From left: Marks at: 5, 15, 30, 50, 75, 105, 140 Next jump = 5 + 15 = 155 > 150 → stop → 7 points From right: First mark at 5 cm from right ⇒ 145 Then: 145, 135, 120, 100, 75, 45, 10 → 7 points Left: 5, 15, 30, 50, 75, 105, 140 Right: 145, 135, 120, 100, 75, 45, 10 Common point = 75 So total distinct = 7 + 7 – 1 = 13 Incorrect Solution: C From left: Marks at: 5, 15, 30, 50, 75, 105, 140 Next jump = 5 + 15 = 155 > 150 → stop → 7 points From right: First mark at 5 cm from right ⇒ 145 Then: 145, 135, 120, 100, 75, 45, 10 → 7 points Left: 5, 15, 30, 50, 75, 105, 140 Right: 145, 135, 120, 100, 75, 45, 10 Common point = 75 So total distinct = 7 + 7 – 1 = 13

#### 1. Question

On a 150 cm track, points are marked from both ends. From the left end, first mark is at 5 cm, next 10 cm ahead, then 15 cm, etc. From the right end, same pattern starts. How many distinct points will be marked if overlapping ones are counted only once?

Solution: C

From left: Marks at: 5, 15, 30, 50, 75, 105, 140 Next jump = 5 + 15 = 155 > 150 → stop → 7 points

From right: First mark at 5 cm from right ⇒ 145 Then: 145, 135, 120, 100, 75, 45, 10 → 7 points

Left: 5, 15, 30, 50, 75, 105, 140 Right: 145, 135, 120, 100, 75, 45, 10

Common point = 75

So total distinct = 7 + 7 – 1 = 13

Solution: C

From left: Marks at: 5, 15, 30, 50, 75, 105, 140 Next jump = 5 + 15 = 155 > 150 → stop → 7 points

From right: First mark at 5 cm from right ⇒ 145 Then: 145, 135, 120, 100, 75, 45, 10 → 7 points

Left: 5, 15, 30, 50, 75, 105, 140 Right: 145, 135, 120, 100, 75, 45, 10

Common point = 75

So total distinct = 7 + 7 – 1 = 13

• Question 2 of 5 2. Question A person bought 28 pens at Rs. x per pen. Later he found that with Rs. 168 more, he could have bought 4 more pens and reduced the average cost per pen by Rs. 1.50. What is the value of x? (a) Rs. 50 (b) Rs. 54 (c) Rs. 55 (d) Rs. 60 Correct Answer: (b) Solution: Total cost = 28x New cost = 28x + 168 New pens = 32 New avg = x – 1.5 ⇒ 28x + 168 = 32(x – 1.5) ⇒ 28x + 168 = 32x – 48 ⇒ 216 = 4x ⇒ x = 54 Final Answer: Rs. 54 Incorrect Answer: (b) Solution: Total cost = 28x New cost = 28x + 168 New pens = 32 New avg = x – 1.5 ⇒ 28x + 168 = 32(x – 1.5) ⇒ 28x + 168 = 32x – 48 ⇒ 216 = 4x ⇒ x = 54 Final Answer: Rs. 54

#### 2. Question

A person bought 28 pens at Rs. x per pen. Later he found that with Rs. 168 more, he could have bought 4 more pens and reduced the average cost per pen by Rs. 1.50. What is the value of x?

• (a) Rs. 50

• (b) Rs. 54

• (c) Rs. 55

• (d) Rs. 60

Answer: (b)

Solution: Total cost = 28x New cost = 28x + 168 New pens = 32 New avg = x – 1.5

⇒ 28x + 168 = 32(x – 1.5) ⇒ 28x + 168 = 32x – 48 ⇒ 216 = 4x ⇒ x = 54

Final Answer: Rs. 54

Answer: (b)

Solution: Total cost = 28x New cost = 28x + 168 New pens = 32 New avg = x – 1.5

⇒ 28x + 168 = 32(x – 1.5) ⇒ 28x + 168 = 32x – 48 ⇒ 216 = 4x ⇒ x = 54

Final Answer: Rs. 54

• Question 3 of 5 3. Question In a stadium, ticket prices for Platinum, Gold, and Silver are in the ratio 10 : 6 : 3. The spectators are in the ratio 1 : 2 : 5. If total revenue collected is ₹1,11,000, how much came from Silver ticket holders? (a) ₹42,000 (b) ₹45,000 (c) ₹48,000 (d) ₹50,000 Correct Answer – B Solution: Revenue parts: Platinum: 10×1 = 10 Gold: 6×2 = 12 Silver: 3×5 = 15 Total = 10 + 12 + 15 = 37 Silver = 15 → (15/37) × 1,11,000 = ₹45,000 Incorrect Answer – B Solution: Revenue parts: Platinum: 10×1 = 10 Gold: 6×2 = 12 Silver: 3×5 = 15 Total = 10 + 12 + 15 = 37 Silver = 15 → (15/37) × 1,11,000 = ₹45,000

#### 3. Question

In a stadium, ticket prices for Platinum, Gold, and Silver are in the ratio 10 : 6 : 3. The spectators are in the ratio 1 : 2 : 5. If total revenue collected is ₹1,11,000, how much came from Silver ticket holders?

• (a) ₹42,000

• (b) ₹45,000

• (c) ₹48,000

• (d) ₹50,000

Answer – B

Solution:

Revenue parts: Platinum: 10×1 = 10 Gold: 6×2 = 12 Silver: 3×5 = 15 Total = 10 + 12 + 15 = 37 Silver = 15 → (15/37) × 1,11,000 = ₹45,000

Answer – B

Solution:

Revenue parts: Platinum: 10×1 = 10 Gold: 6×2 = 12 Silver: 3×5 = 15 Total = 10 + 12 + 15 = 37 Silver = 15 → (15/37) × 1,11,000 = ₹45,000

• Question 4 of 5 4. Question A school employs 45 teachers and 30 support staff. The average salary of all employees is ₹40,000. Each support staff earns ₹10,000 less than a teacher. What is the monthly salary of a support staff member? (a) ₹32,000 (b) ₹33,000 (c) ₹34,000 (d) ₹35,000 Correct Answer – C Solution: Let support salary = ₹x → teacher = x + 10,000 Total salary = 45(x + 10,000) + 30x = 45x + 4,50,000 + 30x = 75x + 4,50,000 Total employees = 75 Total = ₹40,000 × 75 = ₹30,00,000 75x + 4,50,000 = 30,00,000 ⇒ 75x = 25,50,000 ⇒ x = ₹34,000 Incorrect Answer – C Solution: Let support salary = ₹x → teacher = x + 10,000 Total salary = 45(x + 10,000) + 30x = 45x + 4,50,000 + 30x = 75x + 4,50,000 Total employees = 75 Total = ₹40,000 × 75 = ₹30,00,000 75x + 4,50,000 = 30,00,000 ⇒ 75x = 25,50,000 ⇒ x = ₹34,000

#### 4. Question

A school employs 45 teachers and 30 support staff. The average salary of all employees is ₹40,000. Each support staff earns ₹10,000 less than a teacher. What is the monthly salary of a support staff member?

• (a) ₹32,000

• (b) ₹33,000

• (c) ₹34,000

• (d) ₹35,000

Answer – C

Solution: Let support salary = ₹x → teacher = x + 10,000

Total salary = 45(x + 10,000) + 30x = 45x + 4,50,000 + 30x = 75x + 4,50,000 Total employees = 75 Total = ₹40,000 × 75 = ₹30,00,000

75x + 4,50,000 = 30,00,000 ⇒ 75x = 25,50,000 ⇒ x = ₹34,000

Answer – C

Solution: Let support salary = ₹x → teacher = x + 10,000

Total salary = 45(x + 10,000) + 30x = 45x + 4,50,000 + 30x = 75x + 4,50,000 Total employees = 75 Total = ₹40,000 × 75 = ₹30,00,000

75x + 4,50,000 = 30,00,000 ⇒ 75x = 25,50,000 ⇒ x = ₹34,000

• Question 5 of 5 5. Question Raj is rowing upstream from point A to point B, a distance of 40 km. He starts at a constant speed. Ten minutes later, a rescue boat leaves point A and overtakes him in 50 minutes. Question: What is Raj’s rowing speed in still water? Statement I: The speed of the current is 2 km/h. Statement II: The rescue boat’s speed in still water is 10 km/h. Which one of the following is correct in respect of the Statements and the Question? (a) Statement I alone is sufficient to answer the Question (b) Statement II alone is sufficient to answer the Question (c) Statement I and Statement II together are required to answer the Question (d) Statement I and Statement II together are not sufficient to answer the Question Correct Answer: (c) Explanation: Let Raj’s speed = R, stream = x Effective speed = R − x; Boat’s effective = 10 − 2 = 8 Time Raj rows = 60 min (10 + 50), Boat = 50 min (R − 2)(1) = (8)(5/6) ⇒ R = 6.67 km/h Need both x and boat speed ⇒ Answer: (c) Incorrect Answer: (c) Explanation: Let Raj’s speed = R, stream = x Effective speed = R − x; Boat’s effective = 10 − 2 = 8 Time Raj rows = 60 min (10 + 50), Boat = 50 min (R − 2)(1) = (8)(5/6) ⇒ R = 6.67 km/h Need both x and boat speed ⇒ Answer: (c)

#### 5. Question

Raj is rowing upstream from point A to point B, a distance of 40 km. He starts at a constant speed. Ten minutes later, a rescue boat leaves point A and overtakes him in 50 minutes.

Question: What is Raj’s rowing speed in still water?

Statement I: The speed of the current is 2 km/h. Statement II: The rescue boat’s speed in still water is 10 km/h.

Which one of the following is correct in respect of the Statements and the Question?

• (a) Statement I alone is sufficient to answer the Question

• (b) Statement II alone is sufficient to answer the Question

• (c) Statement I and Statement II together are required to answer the Question

• (d) Statement I and Statement II together are not sufficient to answer the Question

Answer: (c) Explanation: Let Raj’s speed = R, stream = x Effective speed = R − x; Boat’s effective = 10 − 2 = 8 Time Raj rows = 60 min (10 + 50), Boat = 50 min (R − 2)(1) = (8)(5/6) ⇒ R = 6.67 km/h Need both x and boat speed ⇒ Answer: (c)

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