UPSC Insta–DART (Daily Aptitude and Reasoning Test) 21 Nov 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question The price of wheat increased by 50%. A family reduced its consumption so that the expenditure increased by only 20%. If earlier they consumed 60 kg per month, what is the new consumption? (a) 48 kg (b) 50 kg (c) 52 kg (d) 54 kg Correct Answer: (a) Explanation: Initial price = ₹100 per kg. Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000. New expenditure = 6,000 + 20% of 6,000 = ₹7,200. New price = 100 + 50% of 100 = ₹150. So, 150 × new consumption = 7,200. New consumption = 7,200 ÷ 150 = 48 kg. Incorrect Answer: (a) Explanation: Initial price = ₹100 per kg. Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000. New expenditure = 6,000 + 20% of 6,000 = ₹7,200. New price = 100 + 50% of 100 = ₹150. So, 150 × new consumption = 7,200. New consumption = 7,200 ÷ 150 = 48 kg.

#### 1. Question

The price of wheat increased by 50%. A family reduced its consumption so that the expenditure increased by only 20%. If earlier they consumed 60 kg per month, what is the new consumption?

Answer: (a)

Explanation: Initial price = ₹100 per kg. Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000. New expenditure = 6,000 + 20% of 6,000 = ₹7,200. New price = 100 + 50% of 100 = ₹150. So, 150 × new consumption = 7,200. New consumption = 7,200 ÷ 150 = 48 kg.

Answer: (a)

• Question 2 of 5 2. Question X and Y invest in the ratio 3:4. After 9 months, X triples his capital for the last 3 months, while Y continues with the same capital for the whole year. If the total profit is ₹51,000, find Y’s share. (a) ₹21,000 (b) ₹22,500 (c) ₹24,000 (d) ₹27,000 Correct Answer: (c) Solution: Let initial capitals be X = 3k, Y = 4k. For first 9 months: • X = 3k × 9 • Y = 4k × 9 For last 3 months: • X = (9k) × 3 (tripled) • Y = 4k × 3 (unchanged) Total: • X = 27k + 27k = 54k • Y = 36k + 12k = 48k Ratio = 54 : 48 = 9 : 8 Total parts = 17 Y’s share = (8/17) × 51,000 = ₹24,000. Hence, option (c). Incorrect Answer: (c) Solution: Let initial capitals be X = 3k, Y = 4k. For first 9 months: • X = 3k × 9 • Y = 4k × 9 For last 3 months: • X = (9k) × 3 (tripled) • Y = 4k × 3 (unchanged) Total: • X = 27k + 27k = 54k • Y = 36k + 12k = 48k Ratio = 54 : 48 = 9 : 8 Total parts = 17 Y’s share = (8/17) × 51,000 = ₹24,000. Hence, option (c).

#### 2. Question

X and Y invest in the ratio 3:4. After 9 months, X triples his capital for the last 3 months, while Y continues with the same capital for the whole year. If the total profit is ₹51,000, find Y’s share.

• (a) ₹21,000

• (b) ₹22,500

• (c) ₹24,000

• (d) ₹27,000

Answer: (c)

Solution: Let initial capitals be X = 3k, Y = 4k. For first 9 months: • X = 3k × 9 • Y = 4k × 9 For last 3 months: • X = (9k) × 3 (tripled) • Y = 4k × 3 (unchanged) Total: • X = 27k + 27k = 54k • Y = 36k + 12k = 48k Ratio = 54 : 48 = 9 : 8 Total parts = 17 Y’s share = (8/17) × 51,000 = ₹24,000. Hence, option (c).

Answer: (c)

• Question 3 of 5 3. Question Two brothers buy bus tickets. The elder one has ₹8, which he realizes is 40% of the total fare for both. The younger one gives him ₹5. How much more money do they still need to buy the tickets? (a) ₹2 (b) ₹3 (c) ₹7 (d) None, they already have enough Correct Answer: (c) Solution: Let total fare = F. 40% of F = 8 ⇒ F = (8 × 100) / 40 = ₹20. Total money = 8 + 5 = ₹13. Still needed = 20 – 13 = ₹7. Incorrect Answer: (c) Solution: Let total fare = F. 40% of F = 8 ⇒ F = (8 × 100) / 40 = ₹20. Total money = 8 + 5 = ₹13. Still needed = 20 – 13 = ₹7.

#### 3. Question

Two brothers buy bus tickets. The elder one has ₹8, which he realizes is 40% of the total fare for both. The younger one gives him ₹5. How much more money do they still need to buy the tickets?

• (d) None, they already have enough

Answer: (c)

Solution: Let total fare = F. 40% of F = 8 ⇒ F = (8 × 100) / 40 = ₹20. Total money = 8 + 5 = ₹13. Still needed = 20 – 13 = ₹7.

Answer: (c)

Solution: Let total fare = F. 40% of F = 8 ⇒ F = (8 × 100) / 40 = ₹20. Total money = 8 + 5 = ₹13. Still needed = 20 – 13 = ₹7.

• Question 4 of 5 4. Question In a recruitment test, 50% candidates were male and 50% female. 40% of males and 60% of females cleared the screening test. In the final, 60% of males and 50% of females succeeded. Which of the following statements is correct? (a) Success rate is equal for men and women. (b) Success rate is higher for men. (c) Overall success rate is exactly 30%. (d) More women cleared the exam than men. Correct Answer: (d) Solution: Total = 1000. Males = 500, Females = 500. Screening: Males = 500 × 40% = 200. Females = 500 × 60% = 300. Final success: Males = 200 × 60% = 120. Females = 300 × 50% = 150. Success rates: Men = 120/500 = 24%. Women = 150/500 = 30%. Overall = (120+150)/1000 = 270/1000 = 27%. So, women’s rate is higher (30% vs 24%). Incorrect Answer: (d) Solution: Total = 1000. Males = 500, Females = 500. Screening: Males = 500 × 40% = 200. Females = 500 × 60% = 300. Final success: Males = 200 × 60% = 120. Females = 300 × 50% = 150. Success rates: Men = 120/500 = 24%. Women = 150/500 = 30%. Overall = (120+150)/1000 = 270/1000 = 27%. So, women’s rate is higher (30% vs 24%).

#### 4. Question

In a recruitment test, 50% candidates were male and 50% female. 40% of males and 60% of females cleared the screening test. In the final, 60% of males and 50% of females succeeded. Which of the following statements is correct?

• (a) Success rate is equal for men and women.

• (b) Success rate is higher for men.

• (c) Overall success rate is exactly 30%.

• (d) More women cleared the exam than men.

Answer: (d)

Solution: Total = 1000. Males = 500, Females = 500.

Screening: Males = 500 × 40% = 200. Females = 500 × 60% = 300.

Final success: Males = 200 × 60% = 120. Females = 300 × 50% = 150.

Success rates: Men = 120/500 = 24%. Women = 150/500 = 30%.

Overall = (120+150)/1000 = 270/1000 = 27%.

So, women’s rate is higher (30% vs 24%).

Answer: (d)

Solution: Total = 1000. Males = 500, Females = 500.

Screening: Males = 500 × 40% = 200. Females = 500 × 60% = 300.

Final success: Males = 200 × 60% = 120. Females = 300 × 50% = 150.

Success rates: Men = 120/500 = 24%. Women = 150/500 = 30%.

Overall = (120+150)/1000 = 270/1000 = 27%.

So, women’s rate is higher (30% vs 24%).

• Question 5 of 5 5. Question A factory has to supply 50,000 units of a spare part. It produces 2,000 units/day, but 8% are defective. After 15 days, a new machine increases production to 2,500 units/day, but now 5% are defective. In how many days will the order be fulfilled? (a) 25 (b) 28 (c) 29 (d) 30 Correct Answer: (a) Solution: First 15 days: Daily good units = 2,000 – 8% of 2,000 = 1,840. In 15 days = 15 × 1,840 = 27,600. Remaining = 50,000 – 27,600 = 22,400. After machine: Daily good = 2,500 – 5% of 2,500 = 2,375. Days required = 22,400 ÷ 2,375 = 9.43 ≈ 10 days. Total days = 15 + 10 = 25 days. Incorrect Answer: (a) Solution: First 15 days: Daily good units = 2,000 – 8% of 2,000 = 1,840. In 15 days = 15 × 1,840 = 27,600. Remaining = 50,000 – 27,600 = 22,400. After machine: Daily good = 2,500 – 5% of 2,500 = 2,375. Days required = 22,400 ÷ 2,375 = 9.43 ≈ 10 days. Total days = 15 + 10 = 25 days.

#### 5. Question

A factory has to supply 50,000 units of a spare part. It produces 2,000 units/day, but 8% are defective. After 15 days, a new machine increases production to 2,500 units/day, but now 5% are defective. In how many days will the order be fulfilled?

Answer: (a)

Solution: First 15 days: Daily good units = 2,000 – 8% of 2,000 = 1,840. In 15 days = 15 × 1,840 = 27,600.

Remaining = 50,000 – 27,600 = 22,400.

After machine: Daily good = 2,500 – 5% of 2,500 = 2,375.

Days required = 22,400 ÷ 2,375 = 9.43 ≈ 10 days.

Total days = 15 + 10 = 25 days.