UPSC Insta–DART (Daily Aptitude and Reasoning Test) 20 Feb 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question The LCM of two numbers is 432 and their HCF is 72.if one of the number is 144, the other number is: a) 216 b) 144 c) 92 d) 152 Correct Answer: A Solution LCMHCF = ab a = First number b = Second number 72432 = 144b b = 216 Incorrect Answer: A Solution LCMHCF = ab a = First number b = Second number 72432 = 144b b = 216
#### 1. Question
The LCM of two numbers is 432 and their HCF is 72.if one of the number is 144, the other number is:
LCMHCF = ab
a = First number
b = Second number
72432 = 144b
LCMHCF = ab
a = First number
b = Second number
72432 = 144b
• Question 2 of 5 2. Question The HCF and LCM of two numbers are 6 and 462 respectively. The numbers of such pairs will be a) 0 b) 1 c) 2 d) 3 Correct Answer: C Solution Let the numbers be 6x and 6y x and y are co prime to each other, LCM = 6xy 6xy = 462 xy = 77 Possible pairs = (1, 77) and (7, 11) Incorrect Answer: C Solution Let the numbers be 6x and 6y x and y are co prime to each other, LCM = 6xy 6xy = 462 xy = 77 Possible pairs = (1, 77) and (7, 11)
#### 2. Question
The HCF and LCM of two numbers are 6 and 462 respectively. The numbers of such pairs will be
Let the numbers be 6x and 6y
x and y are co prime to each other,
Possible pairs = (1, 77) and (7, 11)
Let the numbers be 6x and 6y
x and y are co prime to each other,
Possible pairs = (1, 77) and (7, 11)
• Question 3 of 5 3. Question The LCM of two numbers is 4 times of their HCF. The sum of LCM and HCF is 250.If one of the number is 200 then the other number is a) 50 b) 150 c) 200 d) 350 Correct Answer: A Solution LCM = 4 HCF HCF＋4HCF = 250 5HCF = 250 HCF = 50 LCM = 450 = 200 Second number =( LCMHCF)/First number = (20050)/200 = 50 Incorrect Answer: A Solution LCM = 4 HCF HCF＋4HCF = 250 5HCF = 250 HCF = 50 LCM = 450 = 200 Second number =( LCMHCF)/First number = (20050)/200 = 50
#### 3. Question
The LCM of two numbers is 4 times of their HCF. The sum of LCM and HCF is 250.If one of the number is 200 then the other number is
LCM = 4 HCF
HCF＋4HCF = 250
5HCF = 250
LCM = 4*50 = 200
Second number =( LCMHCF)/First number = (20050)/200 = 50
LCM = 4 HCF
HCF＋4HCF = 250
5HCF = 250
LCM = 4*50 = 200
Second number =( LCMHCF)/First number = (20050)/200 = 50
• Question 4 of 5 4. Question The LCM of two numbers is 7 times of their HCF. The sum of LCM and HCF is 560.If one of the numbers is 200 then the other number is? a) 343/2 b) 161/3 c) 178 d) 82 Correct Answer: A Solution LCM = 7 HCF HCF＋7HCF = 560 8HCF = 560 HCF = 70 LCM = 770 = 490 Second number = ( LCMHCF)/First number = (49070)/200 = 343/2 Incorrect Answer: A Solution LCM = 7 HCF HCF＋7HCF = 560 8HCF = 560 HCF = 70 LCM = 770 = 490 Second number = ( LCMHCF)/First number = (49070)/200 = 343/2
#### 4. Question
The LCM of two numbers is 7 times of their HCF. The sum of LCM and HCF is 560.If one of the numbers is 200 then the other number is?
LCM = 7 HCF
HCF＋7HCF = 560
8HCF = 560
LCM = 7*70 = 490
Second number = ( LCMHCF)/First number = (49070)/200 = 343/2
LCM = 7 HCF
HCF＋7HCF = 560
8HCF = 560
LCM = 7*70 = 490
Second number = ( LCMHCF)/First number = (49070)/200 = 343/2
• Question 5 of 5 5. Question The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24 is? a) 1500 b) 13824 c) 2500 d) 3600 Correct Answer: D Solution LCM of (16, 20, 24) = 222253 To make perfect square multiply by 53 Hence answer is 441515 = 3600 Incorrect Answer: D Solution LCM of (16, 20, 24) = 222253 To make perfect square multiply by 53 Hence answer is 441515 = 3600
#### 5. Question
The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24 is?
LCM of (16, 20, 24) = 22225*3
To make perfect square multiply by 5*3
Hence answer is 4415*15 = 3600
LCM of (16, 20, 24) = 22225*3
To make perfect square multiply by 5*3
Hence answer is 4415*15 = 3600
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