UPSC Insta–DART (Daily Aptitude and Reasoning Test) 20 Aug 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question In what respective ratio two varieties of wheat costing Rs. 72 per kg and Rs. 120per kg be mixed. So that by selling the mixture for 108 per kg 20% profit is earned? a) 2:3 b) 4:3 c) 5:2 d) 6:5 Correct Answer: (a) 2:3 Explanation: Mixture cost price=100/120 108=90 Incorrect Answer: (a) 2:3 Explanation: Mixture cost price=100/120 108=90
#### 1. Question
In what respective ratio two varieties of wheat costing Rs. 72 per kg and Rs. 120per kg be mixed. So that by selling the mixture for 108 per kg 20% profit is earned?
Answer: (a) 2:3
Explanation:
Mixture cost price=100/120 *108=90
Answer: (a) 2:3
Explanation:
Mixture cost price=100/120 *108=90
• Question 2 of 5 2. Question What will be the ratio of diesel to petrol in the final solution formed by mixing diesel and petrol that are present in the three identical vessel in the ratio 3:2 , 4:3, and 5:2 a) 22:37 b) 22:13 c) 13:22 d) 25:16 Correct Answer: (b) 22:13 Explanation: In 1st vessel, diesel = 3x/5 and petrol= 2x/5 In 2nd vessel, diesel = 4x/7 and petrol= 3x/7 In 3rd vessel, diesel = 5x/7 and petrol= 2x/7 (3x/5 +4x/7 +5x/7) : (2x/5 +3x/7+2x/7) 66/35 :39/35 66:39 On solving we get, 22:13 Incorrect Answer: (b) 22:13 Explanation: In 1st vessel, diesel = 3x/5 and petrol= 2x/5 In 2nd vessel, diesel = 4x/7 and petrol= 3x/7 In 3rd vessel, diesel = 5x/7 and petrol= 2x/7 (3x/5 +4x/7 +5x/7) : (2x/5 +3x/7+2x/7) 66/35 :39/35 66:39 On solving we get, 22:13
#### 2. Question
What will be the ratio of diesel to petrol in the final solution formed by mixing diesel and petrol that are present in the three identical vessel in the ratio 3:2 , 4:3, and 5:2
Answer: (b) 22:13
Explanation:
In 1st vessel, diesel = 3x/5 and petrol= 2x/5
In 2nd vessel, diesel = 4x/7 and petrol= 3x/7
In 3rd vessel, diesel = 5x/7 and petrol= 2x/7
(3x/5 +4x/7 +5x/7) : (2x/5 +3x/7+2x/7)
66/35 :39/35
On solving we get, 22:13
Answer: (b) 22:13
Explanation:
In 1st vessel, diesel = 3x/5 and petrol= 2x/5
In 2nd vessel, diesel = 4x/7 and petrol= 3x/7
In 3rd vessel, diesel = 5x/7 and petrol= 2x/7
(3x/5 +4x/7 +5x/7) : (2x/5 +3x/7+2x/7)
66/35 :39/35
On solving we get, 22:13
• Question 3 of 5 3. Question A women deposits 10% her salary in mutual fund. She saves 30% of the remaining. The ratio of her expenses on medicines and groceries is 3:4, of the remaining sala rater saving. If her expense on the medicine is Rs. 4050, find her annual salary. a) 15000 b) 18000 c) 180000 d) 150000 Correct Answer: (c) 180000 Explanation: Let her monthly salary considered as 100x She invested 10% I mutual fund = 10x Remaining after mutual fund= 90x In that remaining 30% for savings=27x After savings the remain9ing amount=63x In that 63x, Expenses for medicine and groceries in the ratio=3:4, Hich is equal to For medicines=27x For groceries=36x For medicines=27x=4050 X=150 Therefore monthly salary=15000 Annual salary=1500012=180000 Incorrect Answer: (c) 180000 Explanation: Let her monthly salary considered as 100x She invested 10% I mutual fund = 10x Remaining after mutual fund= 90x In that remaining 30% for savings=27x After savings the remain9ing amount=63x In that 63x, Expenses for medicine and groceries in the ratio=3:4, Hich is equal to For medicines=27x For groceries=36x For medicines=27x=4050 X=150 Therefore monthly salary=15000 Annual salary=1500012=180000
#### 3. Question
A women deposits 10% her salary in mutual fund. She saves 30% of the remaining. The ratio of her expenses on medicines and groceries is 3:4, of the remaining sala rater saving. If her expense on the medicine is Rs. 4050, find her annual salary.
Answer: (c) 180000
Explanation:
Let her monthly salary considered as 100x
She invested 10% I mutual fund = 10x
Remaining after mutual fund= 90x
In that remaining 30% for savings=27x
After savings the remain9ing amount=63x
In that 63x,
Expenses for medicine and groceries in the ratio=3:4,
Hich is equal to
For medicines=27x
For groceries=36x
For medicines=27x=4050
Therefore monthly salary=15000
Annual salary=15000*12=180000
Answer: (c) 180000
Explanation:
Let her monthly salary considered as 100x
She invested 10% I mutual fund = 10x
Remaining after mutual fund= 90x
In that remaining 30% for savings=27x
After savings the remain9ing amount=63x
In that 63x,
Expenses for medicine and groceries in the ratio=3:4,
Hich is equal to
For medicines=27x
For groceries=36x
For medicines=27x=4050
Therefore monthly salary=15000
Annual salary=15000*12=180000
• Question 4 of 5 4. Question A container has 15 liters of alcohol. If 5 liters of alcohol is replaced by 5 liters of water and this operation is repeated two times more, then what will be the quantity of alcohol in the new mixture? a) 4.44 b) 5.4 c) 4.88 d) 5 Correct Answer: (a) 4.44 Explanation: Let the initial quantity of alcohol be ‘x’ liter and the ‘y’ liter of alcohol is replaced by water each time. Required quantity of alcohol left in the mixture =x((x-y)/x)n =15((15-5)/15)3 =4.44 liters Incorrect Answer: (a) 4.44 Explanation: Let the initial quantity of alcohol be ‘x’ liter and the ‘y’ liter of alcohol is replaced by water each time. Required quantity of alcohol left in the mixture =x((x-y)/x)n =15((15-5)/15)3 =4.44 liters
#### 4. Question
A container has 15 liters of alcohol. If 5 liters of alcohol is replaced by 5 liters of water and this operation is repeated two times more, then what will be the quantity of alcohol in the new mixture?
Answer: (a) 4.44
Explanation:
Let the initial quantity of alcohol be ‘x’ liter and the ‘y’ liter of alcohol is replaced by water each time. Required quantity of alcohol left in the mixture
=x((x-y)/x)n
=15((15-5)/15)3
=4.44 liters
Answer: (a) 4.44
Explanation:
Let the initial quantity of alcohol be ‘x’ liter and the ‘y’ liter of alcohol is replaced by water each time. Required quantity of alcohol left in the mixture
=x((x-y)/x)n
=15((15-5)/15)3
=4.44 liters
• Question 5 of 5 5. Question An alloy ‘A’ made up of copper and zinc contain 20% of copper and another alloy ‘B’ having same elements contain 15% zinc . a new alloy is made by mixing both alloys which contains 30% copper. Fins the ratio of quantity of alloy A and B in the new alloy. a) 11:2 b) 22:5 c) 11:5 d) 23:5 Correct Answer: (a) 11:2 Explanation: Let, 11/20 :1/10 On solving we get 11:2 Incorrect Answer: (a) 11:2 Explanation: Let, 11/20 :1/10 On solving we get 11:2
#### 5. Question
An alloy ‘A’ made up of copper and zinc contain 20% of copper and another alloy ‘B’ having same elements contain 15% zinc . a new alloy is made by mixing both alloys which contains 30% copper. Fins the ratio of quantity of alloy A and B in the new alloy.
Answer: (a) 11:2
Explanation:
11/20 :1/10
On solving we get
Answer: (a) 11:2
Explanation:
11/20 :1/10
On solving we get
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