UPSC Insta–DART (Daily Aptitude and Reasoning Test) 2 Aug 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Four people—Arun, Meena, Karan, and Seema—each wear a different color shirt: red, green, blue, and yellow. They attend meetings in four cities: Jaipur, Bhopal, Lucknow, and Hyderabad. Clues: Meena didn’t go to Jaipur and didn’t wear red. The person wearing blue went to Lucknow. Seema went to Hyderabad. Karan wore green. The red shirt wasn’t worn in Jaipur. Who wore what colour and visited which city? (a) Arun: red in Bhopal; Meena: yellow in Jaipur; Karan: green in Lucknow; Seema: blue in Hyderabad (b) Meena: green in Bhopal; Arun: red in Lucknow; Karan: yellow in Hyderabad; Seema: blue in Jaipur (c) Arun: blue in Lucknow; Meena: yellow in Bhopal; Karan: green in Jaipur; Seema: red in Hyderabad (d) Meena: yellow in Bhopal; Arun: red in Jaipur; Karan: green in Hyderabad; Seema: blue in Lucknow Correct Answer: (c) Solution: Clue (2): Blue → Lucknow ⇒ Arun: blue, Lucknow Clue (4): Karan → green Clue (3): Seema → Hyderabad Clue (1): Meena ≠ Jaipur, ≠ red Clue (5): Red ≠ Jaipur Try option (c): Arun: blue, Lucknow Meena: yellow, Bhopal (≠ red, ≠ Jaipur) Karan: green, Jaipur Seema: red, Hyderabad All clues satisfied Incorrect Answer: (c) Solution: Clue (2): Blue → Lucknow ⇒ Arun: blue, Lucknow Clue (4): Karan → green Clue (3): Seema → Hyderabad Clue (1): Meena ≠ Jaipur, ≠ red Clue (5): Red ≠ Jaipur Try option (c): Arun: blue, Lucknow Meena: yellow, Bhopal (≠ red, ≠ Jaipur) Karan: green, Jaipur Seema: red, Hyderabad All clues satisfied
#### 1. Question
Four people—Arun, Meena, Karan, and Seema—each wear a different color shirt: red, green, blue, and yellow. They attend meetings in four cities: Jaipur, Bhopal, Lucknow, and Hyderabad.
• Meena didn’t go to Jaipur and didn’t wear red.
• The person wearing blue went to Lucknow.
• Seema went to Hyderabad.
• Karan wore green.
• The red shirt wasn’t worn in Jaipur.
Who wore what colour and visited which city?
• (a) Arun: red in Bhopal; Meena: yellow in Jaipur; Karan: green in Lucknow; Seema: blue in Hyderabad
• (b) Meena: green in Bhopal; Arun: red in Lucknow; Karan: yellow in Hyderabad; Seema: blue in Jaipur
• (c) Arun: blue in Lucknow; Meena: yellow in Bhopal; Karan: green in Jaipur; Seema: red in Hyderabad
• (d) Meena: yellow in Bhopal; Arun: red in Jaipur; Karan: green in Hyderabad; Seema: blue in Lucknow
Answer: (c)
Solution:
Clue (2): Blue → Lucknow ⇒ Arun: blue, Lucknow Clue (4): Karan → green Clue (3): Seema → Hyderabad Clue (1): Meena ≠ Jaipur, ≠ red Clue (5): Red ≠ Jaipur
Try option (c):
• Arun: blue, Lucknow
• Meena: yellow, Bhopal (≠ red, ≠ Jaipur)
• Karan: green, Jaipur
• Seema: red, Hyderabad
All clues satisfied
Answer: (c)
Solution:
Clue (2): Blue → Lucknow ⇒ Arun: blue, Lucknow Clue (4): Karan → green Clue (3): Seema → Hyderabad Clue (1): Meena ≠ Jaipur, ≠ red Clue (5): Red ≠ Jaipur
Try option (c):
• Arun: blue, Lucknow
• Meena: yellow, Bhopal (≠ red, ≠ Jaipur)
• Karan: green, Jaipur
• Seema: red, Hyderabad
All clues satisfied
• Question 2 of 5 2. Question Consider the following question and the statements: Question: What is the value of y? Statement I: 5y−3=2y+6 Statement II: y+4=3y−2 Which one of the following is correct? (a) The question can be answered by using one of the statements alone, but not by the other alone (b) The question can be answered by using either statement alone (c) The question can be answered by using both the statements together, but not by either alone (d) The question cannot be answered even by using both the statements together Correct Answer: B Solution From Statement I: 5y−3=2y+6⇒3y=9⇒y=3 From Statement II: y+4=3y−2⇒−2y=−6⇒y=3 → Both statements independently give the same value. Answer: (b) The question can be answered by using either statement alone. Incorrect Answer: B Solution From Statement I: 5y−3=2y+6⇒3y=9⇒y=3 From Statement II: y+4=3y−2⇒−2y=−6⇒y=3 → Both statements independently give the same value. Answer: (b) The question can be answered by using either statement alone.
#### 2. Question
Consider the following question and the statements:
Question: What is the value of y? Statement I: 5y−3=2y+6 Statement II: y+4=3y−2
Which one of the following is correct?
• (a) The question can be answered by using one of the statements alone, but not by the other alone
• (b) The question can be answered by using either statement alone
• (c) The question can be answered by using both the statements together, but not by either alone
• (d) The question cannot be answered even by using both the statements together
Answer: B
Solution
• From Statement I: 5y−3=2y+6⇒3y=9⇒y=3
• From Statement II: y+4=3y−2⇒−2y=−6⇒y=3
• → Both statements independently give the same value.
Answer: (b) The question can be answered by using either statement alone.
Answer: B
Solution
• From Statement I: 5y−3=2y+6⇒3y=9⇒y=3
• From Statement II: y+4=3y−2⇒−2y=−6⇒y=3
• → Both statements independently give the same value.
Answer: (b) The question can be answered by using either statement alone.
• Question 3 of 5 3. Question Consider the following question and the statements that follows: Question: What is the value of z? Statement I: 2z+5=3z−1 Statement II: 4z−3=2z+7 Which one of the following is correct? (a) The question can be answered by using one of the statements alone, but not by the other alone (b) The question can be answered by using either statement alone (c) The question can be answered by using both the statements together, but not by either alone (d) The question cannot be answered even by using both the statements together Correct Answer: D Solution From I: 2z+5=3z−1⇒z=6 From II: 4z−3=2z+7⇒2z=10⇒z=5 → Different values → contradiction. Hence, neither statement alone gives a consistent answer, and together they contradict. Incorrect Answer: D Solution From I: 2z+5=3z−1⇒z=6 From II: 4z−3=2z+7⇒2z=10⇒z=5 → Different values → contradiction. Hence, neither statement alone gives a consistent answer, and together they contradict.
#### 3. Question
Consider the following question and the statements that follows:
Question: What is the value of z? Statement I: 2z+5=3z−1 Statement II: 4z−3=2z+7
Which one of the following is correct?
• (a) The question can be answered by using one of the statements alone, but not by the other alone
• (b) The question can be answered by using either statement alone
• (c) The question can be answered by using both the statements together, but not by either alone
• (d) The question cannot be answered even by using both the statements together
Answer: D
Solution
• From I: 2z+5=3z−1⇒z=6
• From II: 4z−3=2z+7⇒2z=10⇒z=5 → Different values → contradiction. Hence, neither statement alone gives a consistent answer, and together they contradict.
Answer: D
Solution
• From I: 2z+5=3z−1⇒z=6
• From II: 4z−3=2z+7⇒2z=10⇒z=5 → Different values → contradiction. Hence, neither statement alone gives a consistent answer, and together they contradict.
• Question 4 of 5 4. Question One-fifth of a number is 10 less than one-third of the same number. What is the number? (a) 50 (b) 60 (c) 75 (d) 90 Correct Answer: C Solution: Let the number be x 1/5x=1/3x−10 Multiply both sides by 15: 3x=5x−150⇒2x=150⇒x=75 Incorrect Answer: C Solution: Let the number be x 1/5x=1/3x−10 Multiply both sides by 15: 3x=5x−150⇒2x=150⇒x=75
#### 4. Question
One-fifth of a number is 10 less than one-third of the same number. What is the number?
Answer: C
Solution: Let the number be x
1/5x=1/3x−10
Multiply both sides by 15:
3x=5x−150⇒2x=150⇒x=75
Answer: C
Solution: Let the number be x
1/5x=1/3x−10
Multiply both sides by 15:
3x=5x−150⇒2x=150⇒x=75
• Question 5 of 5 5. Question The ratio of the first to the second number is 2:5, and the ratio of the second to the third number is 5:3. If the product of the first and third numbers is 96, find the sum of the three numbers. (a) 30 (b) 36 (c) 40 (d) 42 Correct Answer: C Solution: First : Second = 2:5 Second : Third = 5:3 → Combine to get: First : Second : Third = 2 : 5 : 3 Let numbers be: 2x, 5x, 3x Product of first and third = 2x×3x=6×2=96 x2=16⇒x=4x^2 = 16 ⇒ x = 4 x2=16⇒x=4 So: First = 8 Second = 20 Third = 12 Sum = 8 + 20 + 12 = 40 Incorrect Answer: C Solution: First : Second = 2:5 Second : Third = 5:3 → Combine to get: First : Second : Third = 2 : 5 : 3 Let numbers be: 2x, 5x, 3x Product of first and third = 2x×3x=6×2=96 x2=16⇒x=4x^2 = 16 ⇒ x = 4 x2=16⇒x=4 So: First = 8 Second = 20 Third = 12 Sum = 8 + 20 + 12 = 40
#### 5. Question
The ratio of the first to the second number is 2:5, and the ratio of the second to the third number is 5:3. If the product of the first and third numbers is 96, find the sum of the three numbers.
Solution: First : Second = 2:5 Second : Third = 5:3 → Combine to get: First : Second : Third = 2 : 5 : 3
Let numbers be: 2x, 5x, 3x Product of first and third = 2x×3x=6×2=96
x2=16⇒x=4x^2 = 16 ⇒ x = 4 x2=16⇒x=4
• Second = 20
• Third = 12 Sum = 8 + 20 + 12 = 40
Solution: First : Second = 2:5 Second : Third = 5:3 → Combine to get: First : Second : Third = 2 : 5 : 3
Let numbers be: 2x, 5x, 3x Product of first and third = 2x×3x=6×2=96
x2=16⇒x=4x^2 = 16 ⇒ x = 4 x2=16⇒x=4
• Second = 20
• Third = 12 Sum = 8 + 20 + 12 = 40
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