UPSC Insta–DART (Daily Aptitude and Reasoning Test) 19 Nov 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question In 1980, Indian Republic day was celebrated on Saturday. Subhash was born on 5th September in the same year. Arvind is 5 days younger to Subhash while Arunima is 2 days elder to Arvind. Find out on which days of the week were Arvind and Arunima born? (a) Wednesday and Monday respectively (b) Saturday and Friday respectively (c) Sunday and Tuesday respectively (d) Tuesday and Sunday respectively Correct Solution: Option (a) Explanation: In 1980, Indian Republic day was celebrated on Saturday. Therefore, 26th January 1980 was Saturday. Number of odd days from 26th January to 31st January = 5 Number of odd days in: February (1980 is a leap year, therefore February has 29 days) = 1 March = 3 April = 2 May = 3 June= 2 July = 3 August = 3 September = 5 Number of odd days from 26th January to 5th September = {5 + 1 + 3 + 2 + 3 + 2 + 3 + 3 + 5}/7 = 27/7 = 6 Subhash was born on 5th September 1980. Therefore, his birthday fell on (Saturday + 6 days) = Friday Arvind is 5 days younger to Subhash. Therefore, his birthday fell on (Friday + 5 days) = Wednesday Arunima is 2 days elder to Arvind. Therefore, her birthday fell on (Wednesday – 2 days) = Monday Arvind and Arunima were born on Wednesday and Monday respectively. Incorrect Solution: Option (a) Explanation: In 1980, Indian Republic day was celebrated on Saturday. Therefore, 26th January 1980 was Saturday. Number of odd days from 26th January to 31st January = 5 Number of odd days in: February (1980 is a leap year, therefore February has 29 days) = 1 March = 3 April = 2 May = 3 June= 2 July = 3 August = 3 September = 5 Number of odd days from 26th January to 5th September = {5 + 1 + 3 + 2 + 3 + 2 + 3 + 3 + 5}/7 = 27/7 = 6 Subhash was born on 5th September 1980. Therefore, his birthday fell on (Saturday + 6 days) = Friday Arvind is 5 days younger to Subhash. Therefore, his birthday fell on (Friday + 5 days) = Wednesday Arunima is 2 days elder to Arvind. Therefore, her birthday fell on (Wednesday – 2 days) = Monday Arvind and Arunima were born on Wednesday and Monday respectively.
#### 1. Question
In 1980, Indian Republic day was celebrated on Saturday. Subhash was born on 5th September in the same year. Arvind is 5 days younger to Subhash while Arunima is 2 days elder to Arvind. Find out on which days of the week were Arvind and Arunima born?
• (a) Wednesday and Monday respectively
• (b) Saturday and Friday respectively
• (c) Sunday and Tuesday respectively
• (d) Tuesday and Sunday respectively
Solution: Option (a)
Explanation:
In 1980, Indian Republic day was celebrated on Saturday. Therefore, 26th January 1980 was Saturday.
Number of odd days from 26th January to 31st January = 5
Number of odd days in:
February (1980 is a leap year, therefore February has 29 days) = 1
August = 3
September = 5
Number of odd days from 26th January to 5th September = {5 + 1 + 3 + 2 + 3 + 2 + 3 + 3 + 5}/7 = 27/7 = 6
Subhash was born on 5th September 1980. Therefore, his birthday fell on (Saturday + 6 days) = Friday
Arvind is 5 days younger to Subhash. Therefore, his birthday fell on (Friday + 5 days) = Wednesday
Arunima is 2 days elder to Arvind. Therefore, her birthday fell on (Wednesday – 2 days) = Monday
Arvind and Arunima were born on Wednesday and Monday respectively.
Solution: Option (a)
Explanation:
In 1980, Indian Republic day was celebrated on Saturday. Therefore, 26th January 1980 was Saturday.
Number of odd days from 26th January to 31st January = 5
Number of odd days in:
February (1980 is a leap year, therefore February has 29 days) = 1
August = 3
September = 5
Number of odd days from 26th January to 5th September = {5 + 1 + 3 + 2 + 3 + 2 + 3 + 3 + 5}/7 = 27/7 = 6
Subhash was born on 5th September 1980. Therefore, his birthday fell on (Saturday + 6 days) = Friday
Arvind is 5 days younger to Subhash. Therefore, his birthday fell on (Friday + 5 days) = Wednesday
Arunima is 2 days elder to Arvind. Therefore, her birthday fell on (Wednesday – 2 days) = Monday
Arvind and Arunima were born on Wednesday and Monday respectively.
• Question 2 of 5 2. Question The 4th day of September of a particular year is Tuesday. On what date shall the last Monday of the month fall? (a) 28th (b) 29th (c) 24th (d) 31st Correct Solution: Option (c) Explanation: The first Monday is on 3rd. Last Monday will be on 21 + 3 = 24th. Remember: September has only 30 days. Incorrect Solution: Option (c) Explanation: The first Monday is on 3rd. Last Monday will be on 21 + 3 = 24th. Remember: September has only 30 days.
#### 2. Question
The 4th day of September of a particular year is Tuesday. On what date shall the last Monday of the month fall?
Solution: Option (c)
Explanation:
The first Monday is on 3rd.
Last Monday will be on 21 + 3 = 24th.
Remember: September has only 30 days.
Solution: Option (c)
Explanation:
The first Monday is on 3rd.
Last Monday will be on 21 + 3 = 24th.
Remember: September has only 30 days.
• Question 3 of 5 3. Question If 1st day of a century is Friday then what could be the 1st day of the next century. (a) Monday or Tuesday (b) Sunday or Monday (c) Tuesday or Wednesday (d) None of these Correct Solution: Option (c) Explanation: In a period of 100 years, there are 23 or 24 leap years (as for century year it might be or might not be a leap year, as 1900 was not a leap year) The number of odd days in a period of 100 years is 100 + 23 or 100 + 24 or 123/124 odd days. The number of odd days in 100 years is when 123/124 divided by 7, the remainder is 4 or 5. So next century should start with Tuesday or Wednesday. Incorrect Solution: Option (c) Explanation: In a period of 100 years, there are 23 or 24 leap years (as for century year it might be or might not be a leap year, as 1900 was not a leap year) The number of odd days in a period of 100 years is 100 + 23 or 100 + 24 or 123/124 odd days. The number of odd days in 100 years is when 123/124 divided by 7, the remainder is 4 or 5. So next century should start with Tuesday or Wednesday.
#### 3. Question
If 1st day of a century is Friday then what could be the 1st day of the next century.
• (a) Monday or Tuesday
• (b) Sunday or Monday
• (c) Tuesday or Wednesday
• (d) None of these
Solution: Option (c)
Explanation:
In a period of 100 years, there are 23 or 24 leap years (as for century year it might be or might not be a leap year, as 1900 was not a leap year)
The number of odd days in a period of 100 years is 100 + 23 or 100 + 24 or 123/124 odd days.
The number of odd days in 100 years is when 123/124 divided by 7, the remainder is 4 or 5. So next century should start with Tuesday or Wednesday.
Solution: Option (c)
Explanation:
In a period of 100 years, there are 23 or 24 leap years (as for century year it might be or might not be a leap year, as 1900 was not a leap year)
The number of odd days in a period of 100 years is 100 + 23 or 100 + 24 or 123/124 odd days.
The number of odd days in 100 years is when 123/124 divided by 7, the remainder is 4 or 5. So next century should start with Tuesday or Wednesday.
• Question 4 of 5 4. Question If you were born on 14th April 1992, which was a Sunday, then on which day of the week does your birthday fall in 1993? (a) Monday (b) Tuesday (c) Wednesday (d) Friday Correct Solution: Option (a) Explanation: 14th April 1992 to 14th April 1993 is a complete year, which has 365 days. Hence, the number of odd days from 14th April 1992 to 14th April 1993 is 1. Hence, 14th April 1993 is one day after Sunday. i.e, Monday. Incorrect Solution: Option (a) Explanation: 14th April 1992 to 14th April 1993 is a complete year, which has 365 days. Hence, the number of odd days from 14th April 1992 to 14th April 1993 is 1. Hence, 14th April 1993 is one day after Sunday. i.e, Monday.
#### 4. Question
If you were born on 14th April 1992, which was a Sunday, then on which day of the week does your birthday fall in 1993?
• (a) Monday
• (b) Tuesday
• (c) Wednesday
• (d) Friday
Solution: Option (a)
Explanation:
14th April 1992 to 14th April 1993 is a complete year, which has 365 days. Hence, the number of odd days from 14th April 1992 to 14th April 1993 is 1. Hence, 14th April 1993 is one day after Sunday. i.e, Monday.
Solution: Option (a)
Explanation:
14th April 1992 to 14th April 1993 is a complete year, which has 365 days. Hence, the number of odd days from 14th April 1992 to 14th April 1993 is 1. Hence, 14th April 1993 is one day after Sunday. i.e, Monday.
• Question 5 of 5 5. Question If every second Saturday and all the Sundays are holidays in a 30 days month beginning on Saturday, then how many working days are there in that month? (a) 15 (b) 18 (c) 23 (d) 25 Correct Solution: Option (c) Explanation: Since the month begins on Saturday, so 2nd, 9th, 16th, 23rd and 30th days are Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all. Therefore, the number of working days = 30 – 7 = 23. Incorrect Solution: Option (c) Explanation: Since the month begins on Saturday, so 2nd, 9th, 16th, 23rd and 30th days are Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all. Therefore, the number of working days = 30 – 7 = 23.
#### 5. Question
If every second Saturday and all the Sundays are holidays in a 30 days month beginning on Saturday, then how many working days are there in that month?
Solution: Option (c)
Explanation:
Since the month begins on Saturday, so 2nd, 9th, 16th, 23rd and 30th days are Sundays.
While 8th and 22nd days are second Saturdays.
Thus, there are 7 holidays in all.
Therefore, the number of working days = 30 – 7 = 23.
Solution: Option (c)
Explanation:
Since the month begins on Saturday, so 2nd, 9th, 16th, 23rd and 30th days are Sundays.
While 8th and 22nd days are second Saturdays.
Thus, there are 7 holidays in all.
Therefore, the number of working days = 30 – 7 = 23.
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