UPSC Insta–DART (Daily Aptitude and Reasoning Test) 19 Aug 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 20%. The percentage of water in the mixture is: a) 20% b) 16.66% c) 8.33% d) 25% Correct Answer: (b) 16.66% Explanation: Let CP of 1 liter milk be Rs.1 Then SP of 1 liter of mixture =Rs.1 Gain=20% CP of 1 liter mixture=Rs. (100/120)1=Rs.5/6 CP of 1 liter milk CP of 1 liter of water Ratio of milk to water=5/6 :1/6 =5:1 Hence % of water in the given mixture is=1/6100% =16.66% Incorrect Answer: (b) 16.66% Explanation: Let CP of 1 liter milk be Rs.1 Then SP of 1 liter of mixture =Rs.1 Gain=20% CP of 1 liter mixture=Rs. (100/120)1=Rs.5/6 CP of 1 liter milk CP of 1 liter of water Ratio of milk to water=5/6 :1/6 =5:1 Hence % of water in the given mixture is=1/6100% =16.66%
#### 1. Question
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 20%. The percentage of water in the mixture is:
Answer: (b) 16.66%
Explanation:
Let CP of 1 liter milk be Rs.1
Then SP of 1 liter of mixture =Rs.1
CP of 1 liter mixture=Rs. (100/120)*1=Rs.5/6
CP of 1 liter milk CP of 1 liter of water
Ratio of milk to water=5/6 :1/6 =5:1
Hence % of water in the given mixture is=1/6*100% =16.66%
Answer: (b) 16.66%
Explanation:
Let CP of 1 liter milk be Rs.1
Then SP of 1 liter of mixture =Rs.1
CP of 1 liter mixture=Rs. (100/120)*1=Rs.5/6
CP of 1 liter milk CP of 1 liter of water
Ratio of milk to water=5/6 :1/6 =5:1
Hence % of water in the given mixture is=1/6*100% =16.66%
• Question 2 of 5 2. Question One quantity of wheat at Rs.18.60 per kg is mixed with another quality at a certain rate in the ratio 8:7. If the mixture so formed be worth Rs. 20 per kg, what is the rate per kg of the second quantity of wheat? a) 21.60 b) 10.80 c) 20.60 d) 25.30 Correct Answer: (a) 21.60 Explanation: Let the rate of the second quality be Rs. X per kg. By the rule of allegation, we have: (100x-2000)/140 = 8/7 =>100x=2160 X=Rs. 21.60 Incorrect Answer: (a) 21.60 Explanation: Let the rate of the second quality be Rs. X per kg. By the rule of allegation, we have: (100x-2000)/140 = 8/7 =>100x=2160 X=Rs. 21.60
#### 2. Question
One quantity of wheat at Rs.18.60 per kg is mixed with another quality at a certain rate in the ratio 8:7. If the mixture so formed be worth Rs. 20 per kg, what is the rate per kg of the second quantity of wheat?
Answer: (a) 21.60
Explanation:
Let the rate of the second quality be Rs. X per kg.
By the rule of allegation, we have:
(100x-2000)/140 = 8/7 =>100x=2160
X=Rs. 21.60
Answer: (a) 21.60
Explanation:
Let the rate of the second quality be Rs. X per kg.
By the rule of allegation, we have:
(100x-2000)/140 = 8/7 =>100x=2160
X=Rs. 21.60
• Question 3 of 5 3. Question In a vessel contains liquid A and B in the ratio 5:3 . if 32 liters of the mixture are removed and the same quantity of liquid C is added, the ratio becomes 3:5 . what quantity does the vessel hold? a) 20liters b) 40liters c) 30liters d) 15liters Correct Answer: (a) 20liters Explanation: Let, Let the quantity of A and B be 5x and 3x liters respectively, Quantity of A removed 5/8 32= 20liters. Quantity od B removed 3/832=12liters. Now (5x-20)/3x-12+32 =3/5 On solving we get X=2.5 Quantity of vessel hold=82.5=20liters. Incorrect Answer: (a) 20liters Explanation: Let, Let the quantity of A and B be 5x and 3x liters respectively, Quantity of A removed 5/8 32= 20liters. Quantity od B removed 3/832=12liters. Now (5x-20)/3x-12+32 =3/5 On solving we get X=2.5 Quantity of vessel hold=82.5=20liters.
#### 3. Question
In a vessel contains liquid A and B in the ratio 5:3 . if 32 liters of the mixture are removed and the same quantity of liquid C is added, the ratio becomes 3:5 . what quantity does the vessel hold?
• a) 20liters
• b) 40liters
• c) 30liters
• d) 15liters
Answer: (a) 20liters
Explanation:
Let the quantity of A and B be 5x and 3x liters respectively,
Quantity of A removed
5/8 *32= 20liters.
Quantity od B removed
3/8*32=12liters.
(5x-20)/3x-12+32 =3/5
On solving we get
Quantity of vessel hold=8*2.5=20liters.
Answer: (a) 20liters
Explanation:
Let the quantity of A and B be 5x and 3x liters respectively,
Quantity of A removed
5/8 *32= 20liters.
Quantity od B removed
3/8*32=12liters.
(5x-20)/3x-12+32 =3/5
On solving we get
Quantity of vessel hold=8*2.5=20liters.
• Question 4 of 5 4. Question A bottle is full of detergent liquid . one third of it is taken out and then an equal amount of water is poured into the bottle to fill it. This operations done four times. Find the final ratio of detergent liquid to water in the bottle. a) 16:65 b) 20:74 c) 13:55 d) 10:43 Correct Answer: (a) 16: 65 Explanation: Let, Amount of detergent liquid water used in first operation=2/3 second operation=2/3 2/3=4/9 third operation=4/9 2/3=8/27 Fourth operation=8/272/3=16/81 Amount of water after fourth operation=1-16/81 =65/81 Required ratio=16/81 :65/81=16:65 Incorrect Answer: (a) 16: 65 Explanation: Let, Amount of detergent liquid water used in first operation=2/3 second operation=2/3 2/3=4/9 third operation=4/9 2/3=8/27 Fourth operation=8/272/3=16/81 Amount of water after fourth operation=1-16/81 =65/81 Required ratio=16/81 :65/81=16:65
#### 4. Question
A bottle is full of detergent liquid . one third of it is taken out and then an equal amount of water is poured into the bottle to fill it. This operations done four times. Find the final ratio of detergent liquid to water in the bottle.
Answer: (a) 16: 65
Explanation:
Amount of detergent liquid water used
in first operation=2/3
second operation=2/3 *2/3=4/9
third operation=4/9 * 2/3=8/27
Fourth operation=8/27*2/3=16/81
Amount of water after fourth operation=1-16/81 =65/81
Required ratio=16/81 :65/81=16:65
Answer: (a) 16: 65
Explanation:
Amount of detergent liquid water used
in first operation=2/3
second operation=2/3 *2/3=4/9
third operation=4/9 * 2/3=8/27
Fourth operation=8/27*2/3=16/81
Amount of water after fourth operation=1-16/81 =65/81
Required ratio=16/81 :65/81=16:65
• Question 5 of 5 5. Question In a proportion the multiplication of 1st and 4th term is 80 and that of 2nd and 3rd term is 5x, then the value of x is? a) 36 b) 16 c) 75 d) 90 Correct Answer: (b) 16 Explanation: Let, According to question in a proportion, multiplication of 1st and 4th term = multiplication of 2nd and 3rd terms 80=5x x=16 Incorrect Answer: (b) 16 Explanation: Let, According to question in a proportion, multiplication of 1st and 4th term = multiplication of 2nd and 3rd terms 80=5x x=16
#### 5. Question
In a proportion the multiplication of 1st and 4th term is 80 and that of 2nd and 3rd term is 5x, then the value of x is?
Answer: (b) 16
Explanation:
According to question in a proportion, multiplication of 1st and 4th term = multiplication of 2nd and 3rd terms
Answer: (b) 16
Explanation:
According to question in a proportion, multiplication of 1st and 4th term = multiplication of 2nd and 3rd terms
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