UPSC Insta–DART (Daily Aptitude and Reasoning Test) 18 Sep 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question The length of the minute hand of a wall clock is 6 cm. What is the area swept by it in 15 minutes? (a) 28.3 cm² (b) 47.1 cm² (c) 56.5 cm² (d) 62.8 cm² Correct Answer: (a) Explanation: In 60 minutes, the minute hand covers 360°. In 15 minutes, it covers 90°. Area = (θ/360) × πr² = (90/360) × (22/7) × 6 × 6 = (1/4) × (22/7) × 36 = 198/7 ≈ 28.3 cm². Hence, option (a) is correct. Incorrect Answer: (a) Explanation: In 60 minutes, the minute hand covers 360°. In 15 minutes, it covers 90°. Area = (θ/360) × πr² = (90/360) × (22/7) × 6 × 6 = (1/4) × (22/7) × 36 = 198/7 ≈ 28.3 cm². Hence, option (a) is correct.

#### 1. Question

The length of the minute hand of a wall clock is 6 cm. What is the area swept by it in 15 minutes?

• (a) 28.3 cm²

• (b) 47.1 cm²

• (c) 56.5 cm²

• (d) 62.8 cm²

Answer: (a)

Explanation: In 60 minutes, the minute hand covers 360°. In 15 minutes, it covers 90°. Area = (θ/360) × πr² = (90/360) × (22/7) × 6 × 6 = (1/4) × (22/7) × 36 = 198/7 ≈ 28.3 cm². Hence, option (a) is correct.

Answer: (a)

• Question 2 of 5 2. Question Priya and Neha deliver parcels. Priya alone delivers 43 parcels in p hours. Together, Priya and Neha deliver 43 parcels in t hours. How many hours will Neha take alone to deliver 43 parcels? (a) p/(p + t) (b) t/(p + t) (c) pt/(p + t) (d) pt/(p − t) Correct Answer: (d) Explanation Let 43 be a unit. Priya’s rate = 1/p, combined rate = 1/t. Neha’s rate = 1/t − 1/p = (p − t)/(pt). Time for Neha alone = 1 ÷ [(p − t)/(pt)] = pt/(p − t) hours. Hence, option (d) is correct. Incorrect Answer: (d) Explanation Let 43 be a unit. Priya’s rate = 1/p, combined rate = 1/t. Neha’s rate = 1/t − 1/p = (p − t)/(pt). Time for Neha alone = 1 ÷ [(p − t)/(pt)] = pt/(p − t) hours. Hence, option (d) is correct.

#### 2. Question

Priya and Neha deliver parcels. Priya alone delivers 43 parcels in p hours. Together, Priya and Neha deliver 43 parcels in t hours. How many hours will Neha take alone to deliver 43 parcels?

• (a) p/(p + t)

• (b) t/(p + t)

• (c) pt/(p + t)

• (d) pt/(p − t)

Answer: (d) Explanation Let 43 be a unit. Priya’s rate = 1/p, combined rate = 1/t. Neha’s rate = 1/t − 1/p = (p − t)/(pt). Time for Neha alone = 1 ÷ [(p − t)/(pt)] = pt/(p − t) hours. Hence, option (d) is correct.

• Question 3 of 5 3. Question A, B, and C can complete a piece of work individually in 8 hours, 12 hours, and 24 hours, respectively. They work alternately—A in the 1st hour, B in the 2nd hour, C in the 3rd hour, and then repeat. How many hours are needed to finish the work? (a) 9 hours (b) 10 hours (c) 12 hours (d) 15 hours Correct Answer: (c) Explanation Work done by A, B and C in 1st three hours = 1/8 + 1/12 + 1/24 = 6/24 = 1/4. ∵ 3 hours are needed to complete 1/4th part of the work. ∴ Time taken to complete the whole work = 3 × 4 = 12 hours. Hence, option (c) is correct. Incorrect Answer: (c) Explanation Work done by A, B and C in 1st three hours = 1/8 + 1/12 + 1/24 = 6/24 = 1/4. ∵ 3 hours are needed to complete 1/4th part of the work. ∴ Time taken to complete the whole work = 3 × 4 = 12 hours. Hence, option (c) is correct.

#### 3. Question

A, B, and C can complete a piece of work individually in 8 hours, 12 hours, and 24 hours, respectively. They work alternately—A in the 1st hour, B in the 2nd hour, C in the 3rd hour, and then repeat. How many hours are needed to finish the work?

• (a) 9 hours

• (b) 10 hours

• (c) 12 hours

• (d) 15 hours

Answer: (c) Explanation Work done by A, B and C in 1st three hours = 1/8 + 1/12 + 1/24 = 6/24 = 1/4. ∵ 3 hours are needed to complete 1/4th part of the work. ∴ Time taken to complete the whole work = 3 × 4 = 12 hours. Hence, option (c) is correct.

• Question 4 of 5 4. Question A reporting system processes data for m weeks, compiles for 4m days, and then prepares charts for 3m days. How many days are required to deliver the final report? (a) 7m (b) 11m (c) 14m (d) 10m Correct Answer: (c) Explanation: Processing time = m weeks = 7m days. Compiling time = 4m days. Charting time = 3m days. Total time = 7m + 4m + 3m = 14m days. Incorrect Answer: (c) Explanation: Processing time = m weeks = 7m days. Compiling time = 4m days. Charting time = 3m days. Total time = 7m + 4m + 3m = 14m days.

#### 4. Question

A reporting system processes data for m weeks, compiles for 4m days, and then prepares charts for 3m days. How many days are required to deliver the final report?

Answer: (c) Explanation: Processing time = m weeks = 7m days. Compiling time = 4m days. Charting time = 3m days. Total time = 7m + 4m + 3m = 14m days.

• Question 5 of 5 5. Question A hot water tap can fill a tank in 7.5 minutes and a cold-water tap can fill the same tank in 12 minutes. Rakesh opens both taps together and after 2 minutes he closes the hot-water tap. Cold water tap will fill the remaining part of the tank in : (a) 6 minutes 36 seconds (b) 6 minutes 40 seconds (c) 6 minutes 48 seconds (d) 6 minutes 54 seconds Correct Answer: C Explanation: Hot water tap fills (1/7.5) = (2/15) per minute; cold-water tap fills (1/12) per minute. Work done by both in 2 minutes = 2 × [(2/15) + (1/12)] = 2 × [(8/60) + (5/60)] = 2 × (13/60) = 26/60 = 13/30. Remaining part = 1 − (13/30) = 17/30. Time by cold-water tap = (17/30)/(1/12) = (17/30) × 12 = 204/30 = 6.8 minutes = 6 minutes 48 seconds. Hence, option (c) is correct. Incorrect Answer: C Explanation: Hot water tap fills (1/7.5) = (2/15) per minute; cold-water tap fills (1/12) per minute. Work done by both in 2 minutes = 2 × [(2/15) + (1/12)] = 2 × [(8/60) + (5/60)] = 2 × (13/60) = 26/60 = 13/30. Remaining part = 1 − (13/30) = 17/30. Time by cold-water tap = (17/30)/(1/12) = (17/30) × 12 = 204/30 = 6.8 minutes = 6 minutes 48 seconds. Hence, option (c) is correct.

#### 5. Question

A hot water tap can fill a tank in 7.5 minutes and a cold-water tap can fill the same tank in 12 minutes. Rakesh opens both taps together and after 2 minutes he closes the hot-water tap. Cold water tap will fill the remaining part of the tank in :

• (a) 6 minutes 36 seconds

• (b) 6 minutes 40 seconds

• (c) 6 minutes 48 seconds

• (d) 6 minutes 54 seconds

Answer: C Explanation: Hot water tap fills (1/7.5) = (2/15) per minute; cold-water tap fills (1/12) per minute. Work done by both in 2 minutes = 2 × [(2/15) + (1/12)] = 2 × [(8/60) + (5/60)] = 2 × (13/60) = 26/60 = 13/30. Remaining part = 1 − (13/30) = 17/30. Time by cold-water tap = (17/30)/(1/12) = (17/30) × 12 = 204/30 = 6.8 minutes = 6 minutes 48 seconds. Hence, option (c) is correct.

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