UPSC Insta–DART (Daily Aptitude and Reasoning Test) 18 Dec 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question A clock loses 1% of the week-time during the first week and then gains 2% of the week-time during the next one week. If the clock was set right at 12 noon on a Sunday, what will be the time that the clock will show exactly 14 days from the time it was set right? a) 1: 36 b) 1: 40 c) 1: 41 d) 1: 19 Correct Answer: B Explanation The clock loses 1% week-time during the first week. In a day there are 24 hours and in a week there are 7 days. Therefore, there are 7 × 24 = 168 hours in a week. If the clock loses 1% time during the first week, then it will show a time which is 1% of 168 hours less than 12 Noon at the end of the first week = 1.68 hours less. Subsequently, the clock gains 2% during the next week. The second week has 168 hours and the clock gains 2% time = 2% of 168 hours = 3.36 hours more than the actual time. As it lost 1.68 hours during the first week and then gained 3.36 hours during the next week, the net result will be a -1.68 + 3.36 = 1.68 hours net gain in time. So the clock will show a time which is 1.68 hours more than 12 noon two weeks from the time it was set right. 1.68 hours = 1 hour and 40.8 minutes, i.e. 1 : 40 P.M. Incorrect Answer: B Explanation The clock loses 1% week-time during the first week. In a day there are 24 hours and in a week there are 7 days. Therefore, there are 7 × 24 = 168 hours in a week. If the clock loses 1% time during the first week, then it will show a time which is 1% of 168 hours less than 12 Noon at the end of the first week = 1.68 hours less. Subsequently, the clock gains 2% during the next week. The second week has 168 hours and the clock gains 2% time = 2% of 168 hours = 3.36 hours more than the actual time. As it lost 1.68 hours during the first week and then gained 3.36 hours during the next week, the net result will be a -1.68 + 3.36 = 1.68 hours net gain in time. So the clock will show a time which is 1.68 hours more than 12 noon two weeks from the time it was set right. 1.68 hours = 1 hour and 40.8 minutes, i.e. 1 : 40 P.M.
#### 1. Question
A clock loses 1% of the week-time during the first week and then gains 2% of the week-time during the next one week. If the clock was set right at 12 noon on a Sunday, what will be the time that the clock will show exactly 14 days from the time it was set right?
Explanation
The clock loses 1% week-time during the first week.
In a day there are 24 hours and in a week there are 7 days. Therefore, there are 7 × 24 = 168 hours in a week.
If the clock loses 1% time during the first week, then it will show a time which is 1% of 168 hours less than 12 Noon at the end of the first week = 1.68 hours less.
Subsequently, the clock gains 2% during the next week. The second week has 168 hours and the clock gains 2% time = 2% of 168 hours = 3.36 hours more than the actual time.
As it lost 1.68 hours during the first week and then gained 3.36 hours during the next week, the net result will be a -1.68 + 3.36 = 1.68 hours net gain in time.
So the clock will show a time which is 1.68 hours more than 12 noon two weeks from the time it was set right.
1.68 hours = 1 hour and 40.8 minutes, i.e. 1 : 40 P.M.
Explanation
The clock loses 1% week-time during the first week.
In a day there are 24 hours and in a week there are 7 days. Therefore, there are 7 × 24 = 168 hours in a week.
If the clock loses 1% time during the first week, then it will show a time which is 1% of 168 hours less than 12 Noon at the end of the first week = 1.68 hours less.
Subsequently, the clock gains 2% during the next week. The second week has 168 hours and the clock gains 2% time = 2% of 168 hours = 3.36 hours more than the actual time.
As it lost 1.68 hours during the first week and then gained 3.36 hours during the next week, the net result will be a -1.68 + 3.36 = 1.68 hours net gain in time.
So the clock will show a time which is 1.68 hours more than 12 noon two weeks from the time it was set right.
1.68 hours = 1 hour and 40.8 minutes, i.e. 1 : 40 P.M.
• Question 2 of 5 2. Question At what time between 1 and 2 o’ clock will the hands of a watch make an angle of 180°? a) 35(5/11) min. past 1 b) 40 min. past 1 c) 50(4/11) min. past 1 d) 38(2/11) min. past 1 Correct Answer: D Explanation Total relative angular distance to be covered by minute hand = 7 ×30° = 210° Minute hand gains 11/2° over hour hand in 1 minute Time required to make 210° gain = (2/11)×210 = 420/11 = 38(2/11) min. past 1 So, the correct time must be 5:12 am. Incorrect Answer: D Explanation Total relative angular distance to be covered by minute hand = 7 ×30° = 210° Minute hand gains 11/2° over hour hand in 1 minute Time required to make 210° gain = (2/11)×210 = 420/11 = 38(2/11) min. past 1 So, the correct time must be 5:12 am.
#### 2. Question
At what time between 1 and 2 o’ clock will the hands of a watch make an angle of 180°?
• a) 35(5/11) min. past 1
• b) 40 min. past 1
• c) 50(4/11) min. past 1
• d) 38(2/11) min. past 1
Explanation
Total relative angular distance to be covered by minute hand = 7 ×30° = 210°
Minute hand gains 11/2° over hour hand in 1 minute
Time required to make 210° gain = (2/11)×210 = 420/11 = 38(2/11) min. past 1 So, the correct time must be 5:12 am.
Explanation
Total relative angular distance to be covered by minute hand = 7 ×30° = 210°
Minute hand gains 11/2° over hour hand in 1 minute
Time required to make 210° gain = (2/11)×210 = 420/11 = 38(2/11) min. past 1 So, the correct time must be 5:12 am.
• Question 3 of 5 3. Question Find the time between 3 and 4 will the hands of a watch point in the opposite direction? a) 49(1/11) min past 3 b) 49(3/11) min past 3 c) 49(2/11) min past 3 d) 49(4/11) min past 3 Correct Answer: A Explanation Between x and (x + 1) O’clock, the 2 hands are in opposite directions at (5x + 30)(12/11) min past x. So, between 3 and 4, 2 hands will be in opposite directions at (5 3 + 30)(12/11) = (45)(12/11) = 540/11 = 49(1/11) min past 3. Incorrect Answer: A Explanation Between x and (x + 1) O’clock, the 2 hands are in opposite directions at (5x + 30)(12/11) min past x. So, between 3 and 4, 2 hands will be in opposite directions at (5 3 + 30)(12/11) = (45)(12/11) = 540/11 = 49(1/11) min past 3.
#### 3. Question
Find the time between 3 and 4 will the hands of a watch point in the opposite direction?
• a) 49(1/11) min past 3
• b) 49(3/11) min past 3
• c) 49(2/11) min past 3
• d) 49(4/11) min past 3
Explanation
Between x and (x + 1) O’clock, the 2 hands are in opposite directions at (5x + 30)(12/11) min past x.
So, between 3 and 4, 2 hands will be in opposite directions at (5 3 + 30)(12/11)
= (45)(12/11) = 540/11 = 49(1/11) min past 3.
Explanation
Between x and (x + 1) O’clock, the 2 hands are in opposite directions at (5x + 30)(12/11) min past x.
So, between 3 and 4, 2 hands will be in opposite directions at (5 3 + 30)(12/11)
= (45)(12/11) = 540/11 = 49(1/11) min past 3.
• Question 4 of 5 4. Question At what time between 6 and 7 are the hands of a clock 8 minutes apart? a) 24 min past 6 b) 21 min past 6 c) 18min past 6 d) 20 min past 6 Correct Answer: A Explanation Between x and (x + 1) O’clock, the 2 hands will be t min apart at (5x ± t)(12/11) min past x. Between 6 and 7 O’clock, the 2 hands will be 8 min. apart at (5 6 –8) (12/11) = 264/11 =24 min past 6. Incorrect Answer: A Explanation Between x and (x + 1) O’clock, the 2 hands will be t min apart at (5x ± t)(12/11) min past x. Between 6 and 7 O’clock, the 2 hands will be 8 min. apart at (5 6 –8) (12/11) = 264/11 =24 min past 6.
#### 4. Question
At what time between 6 and 7 are the hands of a clock 8 minutes apart?
• a) 24 min past 6
• b) 21 min past 6
• c) 18min past 6
• d) 20 min past 6
Explanation
Between x and (x + 1) O’clock, the 2 hands will be t min apart at (5x ± t)(12/11) min past x.
Between 6 and 7 O’clock, the 2 hands will be 8 min. apart at (5 6 –8) (12/11) = 264/11 =24 min past 6.
Explanation
Between x and (x + 1) O’clock, the 2 hands will be t min apart at (5x ± t)(12/11) min past x.
Between 6 and 7 O’clock, the 2 hands will be 8 min. apart at (5 6 –8) (12/11) = 264/11 =24 min past 6.
• Question 5 of 5 5. Question How many times do the hands of a clock coincide in a day? a) 20 b) 21 c) 22 d) 24 Correct Answer: C Explanation The hands of a clock coincide 11 times in every 12 hours (since between 11 and 1, they coincide only once, i.e. at 12 o’ clock). The hands coincide 22 times in a day. Incorrect Answer: C Explanation The hands of a clock coincide 11 times in every 12 hours (since between 11 and 1, they coincide only once, i.e. at 12 o’ clock). The hands coincide 22 times in a day.
#### 5. Question
How many times do the hands of a clock coincide in a day?
Explanation
The hands of a clock coincide 11 times in every 12 hours (since between 11 and 1, they coincide only once, i.e. at 12 o’ clock). The hands coincide 22 times in a day.
Explanation
The hands of a clock coincide 11 times in every 12 hours (since between 11 and 1, they coincide only once, i.e. at 12 o’ clock). The hands coincide 22 times in a day.
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