UPSC Insta–DART (Daily Aptitude and Reasoning Test) 16 Sep 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question Neha has Rs. 15,000 with her and she wants to buy a mobile handset; but she finds that she has only 60% of the amount required to buy the handset. Therefore, she borrows Rs. 10,000 from a friend. Then (a) Neha still does not have enough amount to buy the handset. (b) Neha has exactly the same amount as required to buy the handset. (c) Neha has enough amount to buy the handset and she will have Rs. 500 with her after buying the handset. (d) Neha has enough amount to buy the handset and she will have Rs. 1,000 with her after buying the handset. Correct Answer: B Solution: Given that, Amount with Neha = Rs. 15,000 This is 60% of the handset price Amount borrowed = Rs. 10,000 Now, Let price of handset be H 15,000 = 60% of H H = (15,000 x 100) / 60 = Rs. 25,000 Total amount with Neha after borrowing = 15,000 + 10,000 = Rs. 25,000 Hence, Neha has exactly the same amount as required to buy the handset. Hence option (b) is correct Incorrect Answer: B Solution: Given that, Amount with Neha = Rs. 15,000 This is 60% of the handset price Amount borrowed = Rs. 10,000 Now, Let price of handset be H 15,000 = 60% of H H = (15,000 x 100) / 60 = Rs. 25,000 Total amount with Neha after borrowing = 15,000 + 10,000 = Rs. 25,000 Hence, Neha has exactly the same amount as required to buy the handset. Hence option (b) is correct

#### 1. Question

Neha has Rs. 15,000 with her and she wants to buy a mobile handset; but she finds that she has only 60% of the amount required to buy the handset. Therefore, she borrows Rs. 10,000 from a friend. Then

• (a) Neha still does not have enough amount to buy the handset.

• (b) Neha has exactly the same amount as required to buy the handset.

• (c) Neha has enough amount to buy the handset and she will have Rs. 500 with her after buying the handset.

• (d) Neha has enough amount to buy the handset and she will have Rs. 1,000 with her after buying the handset.

Given that,

Amount with Neha = Rs. 15,000 This is 60% of the handset price Amount borrowed = Rs. 10,000

Let price of handset be H 15,000 = 60% of H H = (15,000 x 100) / 60 = Rs. 25,000

Total amount with Neha after borrowing = 15,000 + 10,000 = Rs. 25,000

Hence, Neha has exactly the same amount as required to buy the handset. Hence option (b) is correct

Given that,

Amount with Neha = Rs. 15,000 This is 60% of the handset price Amount borrowed = Rs. 10,000

Let price of handset be H 15,000 = 60% of H H = (15,000 x 100) / 60 = Rs. 25,000

Total amount with Neha after borrowing = 15,000 + 10,000 = Rs. 25,000

Hence, Neha has exactly the same amount as required to buy the handset. Hence option (b) is correct

• Question 2 of 5 2. Question Consider the Question and two Statements given below: Question: Is K brother of M? Statement-1: K and M are siblings. Statement-2: K is male. (a) Statement-1 alone is sufficient to answer the Question. (b) Statement-2 alone is sufficient to answer the Question. (c) Both Statement-1 and Statement-2 are sufficient to answer the Question. (d) Both Statement-1 and Statement-2 are not sufficient to answer the Question. Correct Answer: C Solution: Given that, From Statement-1: K and M are siblings (gender of K unknown). Hence Statement-1 alone is not sufficient. Statement-2: K is male (no relation to M given). Hence Statement-2 alone is not sufficient. Combining both statements: K is male and K and M are siblings ⇒ K is the brother of M. Hence together they are sufficient. Hence option (c) is correct. Incorrect Answer: C Solution: Given that, From Statement-1: K and M are siblings (gender of K unknown). Hence Statement-1 alone is not sufficient. Statement-2: K is male (no relation to M given). Hence Statement-2 alone is not sufficient. Combining both statements: K is male and K and M are siblings ⇒ K is the brother of M. Hence together they are sufficient. Hence option (c) is correct.

#### 2. Question

Consider the Question and two Statements given below:

Question: Is K brother of M?

Statement-1: K and M are siblings. Statement-2: K is male.

• (a) Statement-1 alone is sufficient to answer the Question.

• (b) Statement-2 alone is sufficient to answer the Question.

• (c) Both Statement-1 and Statement-2 are sufficient to answer the Question.

• (d) Both Statement-1 and Statement-2 are not sufficient to answer the Question.

Answer: C

Solution:

Given that,

From Statement-1: K and M are siblings (gender of K unknown). Hence Statement-1 alone is not sufficient.

Statement-2: K is male (no relation to M given). Hence Statement-2 alone is not sufficient.

Combining both statements: K is male and K and M are siblings ⇒ K is the brother of M. Hence together they are sufficient.

Hence option (c) is correct.

Answer: C

Solution:

Given that,

From Statement-1: K and M are siblings (gender of K unknown). Hence Statement-1 alone is not sufficient.

Statement-2: K is male (no relation to M given). Hence Statement-2 alone is not sufficient.

Combining both statements: K is male and K and M are siblings ⇒ K is the brother of M. Hence together they are sufficient.

Hence option (c) is correct.

• Question 3 of 5 3. Question A principal P becomes Q in 1 year when compounded monthly with R% annual rate of interest. If the same principal P becomes Q in 1 year when compounded annually with S% annual rate of interest, then which one of the following is correct? (a) R = S (b) R > S (c) R < S (d) Cannot be determined Correct Answer: C Solution: Given that, Monthly at R%: Q = P(1 + R/1200)^12 Annually at S%: Q = P(1 + S/100) Equating: 1 + S/100 = (1 + R/1200)^12 Since (1 + a)^12 > 1 + 12a for a > 0, we get (1 + R/1200)^12 > 1 + R/100 ⇒ 1 + S/100 > 1 + R/100 ⇒ S > R Therefore R < S. Hence option (c) is correct Incorrect Answer: C Solution: Given that, Monthly at R%: Q = P(1 + R/1200)^12 Annually at S%: Q = P(1 + S/100) Equating: 1 + S/100 = (1 + R/1200)^12 Since (1 + a)^12 > 1 + 12a for a > 0, we get (1 + R/1200)^12 > 1 + R/100 ⇒ 1 + S/100 > 1 + R/100 ⇒ S > R Therefore R < S. Hence option (c) is correct

#### 3. Question

A principal P becomes Q in 1 year when compounded monthly with R% annual rate of interest. If the same principal P becomes Q in 1 year when compounded annually with S% annual rate of interest, then which one of the following is correct?

• (d) Cannot be determined

Given that,

Monthly at R%: Q = P(1 + R/1200)^12 Annually at S%: Q = P(1 + S/100)

1 + S/100 = (1 + R/1200)^12

Since (1 + a)^12 > 1 + 12a for a > 0, we get

(1 + R/1200)^12 > 1 + R/100 ⇒ 1 + S/100 > 1 + R/100 ⇒ S > R

Therefore R < S.

Hence option (c) is correct

Given that,

Monthly at R%: Q = P(1 + R/1200)^12 Annually at S%: Q = P(1 + S/100)

1 + S/100 = (1 + R/1200)^12

Since (1 + a)^12 > 1 + 12a for a > 0, we get

(1 + R/1200)^12 > 1 + R/100 ⇒ 1 + S/100 > 1 + R/100 ⇒ S > R

Therefore R < S.

Hence option (c) is correct

• Question 4 of 5 4. Question Rahul can finish a work in 40 days. Aman is 60% as efficient as Rahul. If both work together for 10 days, then Aman leaves, how many more days will Rahul take to complete the remaining work? (a) 15 (b) 24 (c) 18 (d) 12 Correct Answer: (b) Explanation: Rahul’s 1-day work = 1/40. Total work = 1 unit. Aman’s 1-day work = 60% of (1/40) = 3/200. In 1 day, together they do = 1/40 + 3/200 = (5 + 3)/200 = 8/200 = 1/25. In 10 days, they finish = 10 × 1/25 = 2/5 of the work. Remaining work = 1 − 2/5 = 3/5. Rahul alone takes = (3/5) ÷ (1/40) = (3/5) × 40 = 24 days. So correct answer = 24 days Incorrect Answer: (b) Explanation: Rahul’s 1-day work = 1/40. Total work = 1 unit. Aman’s 1-day work = 60% of (1/40) = 3/200. In 1 day, together they do = 1/40 + 3/200 = (5 + 3)/200 = 8/200 = 1/25. In 10 days, they finish = 10 × 1/25 = 2/5 of the work. Remaining work = 1 − 2/5 = 3/5. Rahul alone takes = (3/5) ÷ (1/40) = (3/5) × 40 = 24 days. So correct answer = 24 days

#### 4. Question

Rahul can finish a work in 40 days. Aman is 60% as efficient as Rahul. If both work together for 10 days, then Aman leaves, how many more days will Rahul take to complete the remaining work?

Answer: (b)

Explanation: Rahul’s 1-day work = 1/40. Total work = 1 unit. Aman’s 1-day work = 60% of (1/40) = 3/200. In 1 day, together they do = 1/40 + 3/200 = (5 + 3)/200 = 8/200 = 1/25. In 10 days, they finish = 10 × 1/25 = 2/5 of the work. Remaining work = 1 − 2/5 = 3/5. Rahul alone takes = (3/5) ÷ (1/40) = (3/5) × 40 = 24 days. So correct answer = 24 days

Answer: (b)

• Question 5 of 5 5. Question A and B can complete a work in 18 days and 24 days respectively. They start together, but after 6 days A leaves. How long will B alone take to finish the remaining work? (a) 10 days (b) 12 days (c) 14 days (d) 15 days Correct Answer: (a) Explanation: A’s 1-day work = 1/18, B’s 1-day work = 1/24. Together in 1 day = 1/18 + 1/24 = (4 + 3)/72 = 7/72. Work done in 6 days = 6 × 7/72 = 7/12. Remaining = 1 – 7/12 = 5/12. B alone does = 1/24 per day. Time = (5/12) ÷ (1/24) = (5/12) × 24 = 10 days. So, option (a) is correct. Incorrect Answer: (a) Explanation: A’s 1-day work = 1/18, B’s 1-day work = 1/24. Together in 1 day = 1/18 + 1/24 = (4 + 3)/72 = 7/72. Work done in 6 days = 6 × 7/72 = 7/12. Remaining = 1 – 7/12 = 5/12. B alone does = 1/24 per day. Time = (5/12) ÷ (1/24) = (5/12) × 24 = 10 days. So, option (a) is correct.

#### 5. Question

A and B can complete a work in 18 days and 24 days respectively. They start together, but after 6 days A leaves. How long will B alone take to finish the remaining work?

• (a) 10 days

• (b) 12 days

• (c) 14 days

• (d) 15 days

Answer: (a)

Explanation: A’s 1-day work = 1/18, B’s 1-day work = 1/24. Together in 1 day = 1/18 + 1/24 = (4 + 3)/72 = 7/72. Work done in 6 days = 6 × 7/72 = 7/12. Remaining = 1 – 7/12 = 5/12. B alone does = 1/24 per day. Time = (5/12) ÷ (1/24) = (5/12) × 24 = 10 days. So, option (a) is correct.

Answer: (a)

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