UPSC Insta–DART (Daily Aptitude and Reasoning Test) 16 Aug 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question *Based on the above passage, the following assumptions have been made: Consumers prioritize fashion trends over environmental concerns in most purchasing decisions. Promoting sustainable fashion alone can reverse the environmental damage caused by the fashion industry. Which of the assumptions given above is/are valid? a) 1 only b) 2 only c) Both 1 and 2 d) Neither 1 nor 2 Correct Answer: A Explanation: Assumption 1 is valid. The passage criticizes fast-changing trends and short-term aesthetics, suggesting that most consumers value trends more than sustainability. Assumption 2 is invalid. The passage does not claim that promoting sustainable fashion alone will reverse the damage. In fact, it argues for systemic change, such as slower production cycles and aligned consumer behavior. Thus, only Assumption 1 is valid → option (a) is correct. Incorrect Answer: A Explanation: Assumption 1 is valid. The passage criticizes fast-changing trends and short-term aesthetics, suggesting that most consumers value trends more than sustainability. Assumption 2 is invalid. The passage does not claim that promoting sustainable fashion alone will reverse the damage. In fact, it argues for systemic change, such as slower production cycles and aligned consumer behavior. Thus, only Assumption 1 is valid → option (a)* is correct.
#### 1. Question
*Based on the above passage, the following assumptions have been made:*
• Consumers prioritize fashion trends over environmental concerns in most purchasing decisions.
• Promoting sustainable fashion alone can reverse the environmental damage caused by the fashion industry.
Which of the assumptions given above is/are valid?
• c) Both 1 and 2
• d) Neither 1 nor 2
Answer: A
Explanation:
• Assumption 1 is valid. The passage criticizes fast-changing trends and short-term aesthetics, suggesting that most consumers value trends more than sustainability.
• Assumption 2 is invalid. The passage does not claim that promoting sustainable fashion alone will reverse the damage. In fact, it argues for systemic change, such as slower production cycles and aligned consumer behavior.
Thus, only Assumption 1 is valid → option (a) is correct.
Answer: A
Explanation:
• Assumption 1 is valid. The passage criticizes fast-changing trends and short-term aesthetics, suggesting that most consumers value trends more than sustainability.
• Assumption 2 is invalid. The passage does not claim that promoting sustainable fashion alone will reverse the damage. In fact, it argues for systemic change, such as slower production cycles and aligned consumer behavior.
Thus, only Assumption 1 is valid → option (a) is correct.
• Question 2 of 5 2. Question 12 persons are seated around a round table. What is the probability that two particular persons sit together? a) 2/11 b) 4/21 c) 8/21 d) 6/21 Correct Answer : A Explanation : In a circle of n different persons, the total number of arrangements possible = (n – 1)! n(S) = (12 – 1) = 11 ! Taking two persons as a unit, total persons = 11 Therefore no. of ways for these 11 persons to around the circular table = (11 – 1)! = 10! In any unit, 2 particular person can sit in 2! ways. Hence total number of ways that any three person can sit, =n(E) = 10! 2! Therefore P (E) = probability of three persons sitting together = n(E) / n(S) = (10! 2!)/11! = 2/11. Incorrect Answer : A Explanation : In a circle of n different persons, the total number of arrangements possible = (n – 1)! n(S) = (12 – 1) = 11 ! Taking two persons as a unit, total persons = 11 Therefore no. of ways for these 11 persons to around the circular table = (11 – 1)! = 10! In any unit, 2 particular person can sit in 2! ways. Hence total number of ways that any three person can sit, =n(E) = 10! 2! Therefore P (E) = probability of three persons sitting together = n(E) / n(S) = (10! 2!)/11! = 2/11.
#### 2. Question
12 persons are seated around a round table. What is the probability that two particular persons sit together?
Answer : A
Explanation :
In a circle of n different persons, the total number of arrangements possible = (n – 1)!
n(S) = (12 – 1) = 11 !
Taking two persons as a unit, total persons = 11
Therefore no. of ways for these 11 persons to around the circular table = (11 – 1)! = 10!
In any unit, 2 particular person can sit in 2! ways.
Hence total number of ways that any three person can sit,
=n(E) = 10! * 2!
Therefore P (E) = probability of three persons sitting together = n(E) / n(S)
= (10! * 2!)/11! = 2/11.
Answer : A
Explanation :
In a circle of n different persons, the total number of arrangements possible = (n – 1)!
n(S) = (12 – 1) = 11 !
Taking two persons as a unit, total persons = 11
Therefore no. of ways for these 11 persons to around the circular table = (11 – 1)! = 10!
In any unit, 2 particular person can sit in 2! ways.
Hence total number of ways that any three person can sit,
=n(E) = 10! * 2!
Therefore P (E) = probability of three persons sitting together = n(E) / n(S)
= (10! * 2!)/11! = 2/11.
• Question 3 of 5 3. Question Find the sum of all the 4-digit numbers that can be formed with the digits 1, 1, 2, and 3. (a) 26664 (b) 26646 (c) 26466 (d) None of these Correct Answer: D Solution: Given digits: 1, 1, 2, 3 Since 1 is repeated, total distinct permutations = 4! / 2! = 12 We calculate how many times each digit appears at each place (unit, tens, hundreds, thousands): Total positions = 12 numbers Each digit appears (12 × 1) / 4 = 3 times at each position Now compute total sum: Digit sum at each place = (3 × 1) + (3 × 1) + (3 × 2) + (3 × 3) = 3 + 3 + 6 + 9 = 21 → So, total sum = = 21 × (1000 + 100 + 10 + 1) = 21 × 1111 = 23331 Answer: (d) None of these Incorrect Answer: D Solution: Given digits: 1, 1, 2, 3 Since 1 is repeated, total distinct permutations = 4! / 2! = 12 We calculate how many times each digit appears at each place (unit, tens, hundreds, thousands): Total positions = 12 numbers Each digit appears (12 × 1) / 4 = 3 times at each position Now compute total sum: Digit sum at each place = (3 × 1) + (3 × 1) + (3 × 2) + (3 × 3) = 3 + 3 + 6 + 9 = 21 → So, total sum = = 21 × (1000 + 100 + 10 + 1) = 21 × 1111 = 23331 Answer: (d) None of these
#### 3. Question
Find the sum of all the 4-digit numbers that can be formed with the digits 1, 1, 2, and 3.
• (d) None of these
Solution:
Given digits: 1, 1, 2, 3
Since 1 is repeated, total distinct permutations = 4! / 2! = 12
We calculate how many times each digit appears at each place (unit, tens, hundreds, thousands):
• Total positions = 12 numbers
• Each digit appears (12 × 1) / 4 = 3 times at each position
Now compute total sum:
• Digit sum at each place = (3 × 1) + (3 × 1) + (3 × 2) + (3 × 3) = 3 + 3 + 6 + 9 = 21
→ So, total sum = = 21 × (1000 + 100 + 10 + 1) = 21 × 1111 = 23331
Answer: (d) None of these
Solution:
Given digits: 1, 1, 2, 3
Since 1 is repeated, total distinct permutations = 4! / 2! = 12
We calculate how many times each digit appears at each place (unit, tens, hundreds, thousands):
• Total positions = 12 numbers
• Each digit appears (12 × 1) / 4 = 3 times at each position
Now compute total sum:
• Digit sum at each place = (3 × 1) + (3 × 1) + (3 × 2) + (3 × 3) = 3 + 3 + 6 + 9 = 21
→ So, total sum = = 21 × (1000 + 100 + 10 + 1) = 21 × 1111 = 23331
Answer: (d) None of these
• Question 4 of 5 4. Question Anand went to Delhi on 5th Wednesday of April and returns to home on 5th Tuesday of June. He has to go back to Delhi to attend a meeting on International Youth Day. On which Day of the week International Youth Day falls? a) Tuesday b) Wednesday c) Thursday d) Friday Correct Answer: B Explanation: June is a 30-day month. In a 30-day month, all the seven days of week occur 4 times. (7 × 4 = 28) and two days of the week occur 5 times. These two days will be the first two or the last two days of the month. It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June. That means either 29 June is Tuesday or 30 November is Tuesday. Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August (1 + 31 + 12) = 44 => (7 × 6) + 2 Then 12th August is on Thursday. This is not given in the options. Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August (31 + 12) = 43 => (7 × 6) + 1 Thus, 12th August is on Wednesday. Incorrect Answer: B Explanation: June is a 30-day month. In a 30-day month, all the seven days of week occur 4 times. (7 × 4 = 28) and two days of the week occur 5 times. These two days will be the first two or the last two days of the month. It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June. That means either 29 June is Tuesday or 30 November is Tuesday. Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August (1 + 31 + 12) = 44 => (7 × 6) + 2 Then 12th August is on Thursday. This is not given in the options. Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August (31 + 12) = 43 => (7 × 6) + 1 Thus, 12th August is on Wednesday.
#### 4. Question
Anand went to Delhi on 5th Wednesday of April and returns to home on 5th Tuesday of June. He has to go back to Delhi to attend a meeting on International Youth Day. On which Day of the week International Youth Day falls?
• a) Tuesday
• b) Wednesday
• c) Thursday
Explanation:
June is a 30-day month.
In a 30-day month, all the seven days of week occur 4 times.
(7 × 4 = 28) and two days of the week occur 5 times.
These two days will be the first two or the last two days of the month.
It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June.
That means either 29 June is Tuesday or 30 November is Tuesday.
Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August
(1 + 31 + 12) = 44 => (7 × 6) + 2
Then 12th August is on Thursday. This is not given in the options.
Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August
(31 + 12) = 43 => (7 × 6) + 1
Thus, 12th August is on Wednesday.
Explanation:
June is a 30-day month.
In a 30-day month, all the seven days of week occur 4 times.
(7 × 4 = 28) and two days of the week occur 5 times.
These two days will be the first two or the last two days of the month.
It means if a certain day is occurring 5 times in a month, it must be on those first two or last two days. Now he returns home on the fifth Tuesday, so it has to be at the end of June.
That means either 29 June is Tuesday or 30 November is Tuesday.
Case 1: If 29 June is Tuesday, then, International Youth Day is on 12th August
(1 + 31 + 12) = 44 => (7 × 6) + 2
Then 12th August is on Thursday. This is not given in the options.
Case 2: If 30 June is Tuesday, then, International Youth Day is on 12th August
(31 + 12) = 43 => (7 × 6) + 1
Thus, 12th August is on Wednesday.
• Question 5 of 5 5. Question Consider the following statements and a question: Question: In a test, who secured the highest marks among A, B, C, D, and E? Statement I: A scored more than B and C but less than E. Statement II: D scored more than E. Statement III: C scored the least. Which one of the following is correct in respect of the Statements and the Question? (a) Only statement I and Statement II is sufficient to answer the question (b) Only statement II is sufficient to answer the question. (c) Statements I and III together are sufficient to answer the question. (d) All three statements together are sufficient to answer the question. Correct Answer: A Solution From Statement I: A > B, C; A < E ⇒ Order: B/C < A < E (Partial) From Statement II: D > E ⇒ D is higher than E So from I + II: B/C < A < E < D ⇒ D is highest → I + II are sufficient Statement III: C is lowest → no new info about top scorer Answer: (a) Statements I and II together are sufficient. Incorrect Answer: A Solution From Statement I: A > B, C; A < E ⇒ Order: B/C < A < E (Partial) From Statement II: D > E ⇒ D is higher than E So from I + II: B/C < A < E < D ⇒ D is highest → I + II are sufficient Statement III: C is lowest → no new info about top scorer Answer: (a) Statements I and II together are sufficient.
#### 5. Question
Consider the following statements and a question:
Question: In a test, who secured the highest marks among A, B, C, D, and E?
Statement I: A scored more than B and C but less than E.
Statement II: D scored more than E.
Statement III: C scored the least.
Which one of the following is correct in respect of the Statements and the Question?
• (a) Only statement I and Statement II is sufficient to answer the question
• (b) Only statement II is sufficient to answer the question.
• (c) Statements I and III together are sufficient to answer the question.
• (d) All three statements together are sufficient to answer the question.
Answer: A
Solution
From Statement I: A > B, C; A < E ⇒ Order: B/C < A < E (Partial)
From Statement II: D > E ⇒ D is higher than E
So from I + II: B/C < A < E < D ⇒ D is highest → I + II are sufficient
Statement III: C is lowest → no new info about top scorer
Answer: (a) Statements I and II together are sufficient.
Answer: A
Solution
From Statement I: A > B, C; A < E ⇒ Order: B/C < A < E (Partial)
From Statement II: D > E ⇒ D is higher than E
So from I + II: B/C < A < E < D ⇒ D is highest → I + II are sufficient
Statement III: C is lowest → no new info about top scorer
Answer: (a) Statements I and II together are sufficient.
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