UPSC Insta–DART (Daily Aptitude and Reasoning Test) 14 Aug 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
#### Quiz-summary
0 of 5 questions completed
Questions:
#### Information
Best of Luck! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
#### Categories
• Not categorized 0%
• Question 1 of 5 1. Question In a class there are 60 girls and 30 boys, the total average weight of the class is 47(7/15)kg and the average weight of boys is 58kg. What will be the average weight of girls. a) 42 b) 44 c) 45 d) 46 Correct Answer: (a) 42 Explanation: 3058 + 60x =(712/15) 90 Where, x= average weight of girls 47(7/15) = 712/15 90=(boys +girls)=total number of students On solving we get x=42 approximately Hence the average weight of the girls=42kg. Incorrect Answer: (a) 42 Explanation: 3058 + 60x =(712/15) 90 Where, x= average weight of girls 47(7/15) = 712/15 90=(boys +girls)=total number of students On solving we get x=42 approximately Hence the average weight of the girls=42kg.
#### 1. Question
In a class there are 60 girls and 30 boys, the total average weight of the class is 47(7/15)kg and the average weight of boys is 58kg. What will be the average weight of girls.
Answer: (a) 42
Explanation:
3058 + 60x =(712/15) *90
Where, x= average weight of girls
47(7/15) = 712/15
90=(boys +girls)=total number of students
On solving we get x=42 approximately
Hence the average weight of the girls=42kg.
Answer: (a) 42
Explanation:
3058 + 60x =(712/15) *90
Where, x= average weight of girls
47(7/15) = 712/15
90=(boys +girls)=total number of students
On solving we get x=42 approximately
Hence the average weight of the girls=42kg.
• Question 2 of 5 2. Question The average age of all the 200 employees in an office is 58 years, where 2/5 employees are women and the ratio of average age of men to women is 5:7. The average age of female employees is. a) 60 b) 50 c) 70 d) 80 Correct Answer: (c) Explanation: Number of women=2002/5=80 Number of male=2003/5=120 According to the question, 807x + 1205x =11600 560x+600x=11600 1160x=11600 ,x=10 Average age of female employees=70 years. Incorrect Answer: (c) Explanation: Number of women=2002/5=80 Number of male=2003/5=120 According to the question, 807x + 1205x =11600 560x+600x=11600 1160x=11600 ,x=10 Average age of female employees=70 years.
#### 2. Question
The average age of all the 200 employees in an office is 58 years, where 2/5 employees are women and the ratio of average age of men to women is 5:7. The average age of female employees is.
Answer: (c)
Explanation:
Number of women=200*2/5=80
Number of male=200*3/5=120
According to the question,
807x + 1205x =11600
560x+600x=11600
1160x=11600
Average age of female employees=70 years.
Answer: (c)
Explanation:
Number of women=200*2/5=80
Number of male=200*3/5=120
According to the question,
807x + 1205x =11600
560x+600x=11600
1160x=11600
Average age of female employees=70 years.
• Question 3 of 5 3. Question There are 6 consecutive odd numbers. The difference between the square of the average of the last three numbers and that of first three numbers is 288. What is the average of largest odd number and smallest odd number? a) 29 b) 20 c) 25 d) 24 Correct Answer : (d) Explanation: Let consecutive odd numbers are, 2x+1, 2x+3, 2x+5, 2x+7, 2x+9, 2x+11 ((2x+7+2x+9+2x+11)/3 )2 – ((2x+1+2x+3+2x+5)/3 )2 =288 (2x+9)2 – (2x+3)2 = 288 Apply a2-b2=(a+ b)(a-b) formula On solving we get x=9 The consecutive odd numbers are, 19, 21,23,25,27,29 Average of small and larger odd number is (19+29)/2= 24 Incorrect Answer : (d) Explanation: Let consecutive odd numbers are, 2x+1, 2x+3, 2x+5, 2x+7, 2x+9, 2x+11 ((2x+7+2x+9+2x+11)/3 )2 – ((2x+1+2x+3+2x+5)/3 )2 =288 (2x+9)2 – (2x+3)2 = 288 Apply a2-b2=(a+ b)(a-b) formula On solving we get x=9 The consecutive odd numbers are, 19, 21,23,25,27,29 Average of small and larger odd number is (19+29)/2= 24
#### 3. Question
There are 6 consecutive odd numbers. The difference between the square of the average of the last three numbers and that of first three numbers is 288. What is the average of largest odd number and smallest odd number?
Answer : (d)
Explanation:
Let consecutive odd numbers are,
2x+1, 2x+3, 2x+5, 2x+7, 2x+9, 2x+11
((2x+7+2x+9+2x+11)/3 )2 – ((2x+1+2x+3+2x+5)/3 )2 =288
(2x+9)2 – (2x+3)2 = 288
Apply a2-b2=(a+ b)(a-b) formula
On solving we get x=9
The consecutive odd numbers are,
19, 21,23,25,27,29
Average of small and larger odd number is
(19+29)/2= 24
Answer : (d)
Explanation:
Let consecutive odd numbers are,
2x+1, 2x+3, 2x+5, 2x+7, 2x+9, 2x+11
((2x+7+2x+9+2x+11)/3 )2 – ((2x+1+2x+3+2x+5)/3 )2 =288
(2x+9)2 – (2x+3)2 = 288
Apply a2-b2=(a+ b)(a-b) formula
On solving we get x=9
The consecutive odd numbers are,
19, 21,23,25,27,29
Average of small and larger odd number is
(19+29)/2= 24
• Question 4 of 5 4. Question Present average age of P,Q and R is (8x+12) years. The present age of P and Q is (12x-30) years. The present age of Q is 25% less than present age of R and 20% more than the present age of P. What is he present age of P? a) 15 b) 90 c) 20 d) 40 Correct Answer: (a) Explanation: P+Q+R= 24x+36—-(1) P+Q=24x-60——-(2) On solving 1 and 2 , We get R=24 Q= 25% less than R=2/4(24)=18 Q=20% more than P Q=6/5(P) 185/6=P P=15 years. Incorrect Answer: (a) Explanation: P+Q+R= 24x+36—-(1) P+Q=24x-60——-(2) On solving 1 and 2 , We get R=24 Q= 25% less than R=2/4(24)=18 Q=20% more than P Q=6/5(P) 185/6=P P=15 years.
#### 4. Question
Present average age of P,Q and R is (8x+12) years. The present age of P and Q is (12x-30) years. The present age of Q is 25% less than present age of R and 20% more than the present age of P. What is he present age of P?
Answer: (a)
Explanation:
P+Q+R= 24x+36—-(1)
P+Q=24x-60——-(2)
On solving 1 and 2 ,
We get R=24
Q= 25% less than R=2/4(24)=18
Q=20% more than P
P=15 years.
Answer: (a)
Explanation:
P+Q+R= 24x+36—-(1)
P+Q=24x-60——-(2)
On solving 1 and 2 ,
We get R=24
Q= 25% less than R=2/4(24)=18
Q=20% more than P
P=15 years.
• Question 5 of 5 5. Question In an examination of 100 marks, the average marks of class is 40 students are 76. If the top 3 scorer of the class leave , the average score falls down by 1, if the other two toppers except the highest topper scored not more than 85 then what is the minimum score the topper can score? a) 95 b) 85 c) 75 d) 99 Correct Answer: (a) Explanation: Total score of 40 students=4076=3040 Total score of top 3=3040-3775= 265 To minimize the score of topmost scorer, let top two score get marks each 265-(85+85)=95 Incorrect Answer: (a) Explanation: Total score of 40 students=4076=3040 Total score of top 3=3040-3775= 265 To minimize the score of topmost scorer, let top two score get marks each 265-(85+85)=95
#### 5. Question
In an examination of 100 marks, the average marks of class is 40 students are 76. If the top 3 scorer of the class leave , the average score falls down by 1, if the other two toppers except the highest topper scored not more than 85 then what is the minimum score the topper can score?
Answer: (a)
Explanation:
Total score of 40 students=40*76=3040
Total score of top 3=3040-37*75= 265
To minimize the score of topmost scorer, let top two score get marks each
265-(85+85)=95
Answer: (a)
Explanation:
Total score of 40 students=40*76=3040
Total score of top 3=3040-37*75= 265
To minimize the score of topmost scorer, let top two score get marks each
265-(85+85)=95
• Official Facebook Page HERE
• Follow our Twitter Account HERE