UPSC Insta–DART (Daily Aptitude and Reasoning Test) 11 Sep 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question A invested Rs. x in SI at 20% rate of interest for 8 years and B invested Rs.(x + y) in Cl at 25% rate of interest for 2 years. B invested Rs. y in SI at 30% rate of interest for 6 years. The interest obtained by B in Cl and SI is Rs.13500 and Rs.16200. find investment of A. a) 15000 b) 75000 c) 7500 d) 1500 Correct Answer: (a) 15000 Explanation: Let B invested Rs. y in SI ,y30/100 6=16200 On solving we get, y=9000 B invested (x +y) in compound interest, ,(x+9000)(1+25/100)2 –(x+9000)=13500 On solving we get x=15000 Now A investment=15000 Incorrect Answer: (a) 15000 Explanation: Let B invested Rs. y in SI ,y30/100 6=16200 On solving we get, y=9000 B invested (x +y) in compound interest, ,(x+9000)(1+25/100)2 –(x+9000)=13500 On solving we get x=15000 Now A investment=15000
#### 1. Question
A invested Rs. x in SI at 20% rate of interest for 8 years and B invested Rs.(x + y) in Cl at 25% rate of interest for 2 years. B invested Rs. y in SI at 30% rate of interest for 6 years. The interest obtained by B in Cl and SI is Rs.13500 and Rs.16200. find investment of A.
Answer: (a) 15000
Explanation:
Let B invested Rs. y in SI
,y30/100 6=16200
On solving we get, y=9000
B invested (x +y) in compound interest,
,(x+9000)(1+25/100)2 –(x+9000)=13500
On solving we get x=15000
Now A investment=15000
Answer: (a) 15000
Explanation:
Let B invested Rs. y in SI
,y30/100 6=16200
On solving we get, y=9000
B invested (x +y) in compound interest,
,(x+9000)(1+25/100)2 –(x+9000)=13500
On solving we get x=15000
Now A investment=15000
• Question 2 of 5 2. Question Priya invested (3Z+4200) in a bank earning simple interest at 10% per annum, after 2.5 years he withdraws all amount from the bank and invested in a scheme earning compound interest of Rs. 3504 at 20% per annum compounded annually , find the value of (Z+200) , if his total time period of investment is 5 years. a) 200 b) 400 c) 300 d) 600 Correct Answer: (b) 400 Explanation: (3Z+4200)+(3Z+4200)2.5 10/100 =5/4(3Z+4200) Total time period=5 years For SI 2.5 years Compound interest =2.5 years 5/4(3Z+4200) (6/56/511/10 -1)= 3504 On solving we get z=200 Z+200=200+200=400 Incorrect Answer: (b) 400 Explanation: (3Z+4200)+(3Z+4200)2.5 10/100 =5/4(3Z+4200) Total time period=5 years For SI 2.5 years Compound interest =2.5 years 5/4(3Z+4200) (6/56/511/10 -1)= 3504 On solving we get z=200 Z+200=200+200=400
#### 2. Question
Priya invested (3Z+4200) in a bank earning simple interest at 10% per annum, after 2.5 years he withdraws all amount from the bank and invested in a scheme earning compound interest of Rs. 3504 at 20% per annum compounded annually , find the value of (Z+200) , if his total time period of investment is 5 years.
Answer: (b) 400
Explanation:
(3Z+4200)+(3Z+4200)2.5 10/100 =5/4*(3Z+4200)
Total time period=5 years
For SI 2.5 years
Compound interest =2.5 years
5/4(3Z+4200) (6/56/5*11/10 -1)= 3504
On solving we get z=200
Z+200=200+200=400
Answer: (b) 400
Explanation:
(3Z+4200)+(3Z+4200)2.5 10/100 =5/4*(3Z+4200)
Total time period=5 years
For SI 2.5 years
Compound interest =2.5 years
5/4(3Z+4200) (6/56/5*11/10 -1)= 3504
On solving we get z=200
Z+200=200+200=400
• Question 3 of 5 3. Question An amount of Rs. 40000 when invested at R% simple interest for 2 years becomes Rs. 48000. What will it become in 3 years if we invested at (R+2)% ? a) 54400 b) 50000 c) 48000 d) 57000 Correct Answer: (a) 54400 Explanation: SI earned=48000-40000=8000 8000=400002R/100 On solving we get, R=10% Required amount =40000+40000123/100=54400 Incorrect Answer: (a) 54400 Explanation: SI earned=48000-40000=8000 8000=400002R/100 On solving we get, R=10% Required amount =40000+40000123/100=54400
#### 3. Question
An amount of Rs. 40000 when invested at R% simple interest for 2 years becomes Rs. 48000. What will it become in 3 years if we invested at (R+2)% ?
Answer: (a) 54400
Explanation:
SI earned=48000-40000=8000
8000=400002R/100
On solving we get, R=10%
Required amount =40000+40000123/100=54400
Answer: (a) 54400
Explanation:
SI earned=48000-40000=8000
8000=400002R/100
On solving we get, R=10%
Required amount =40000+40000123/100=54400
• Question 4 of 5 4. Question Pavan borrowed certain sum from Pratheesh for 2 years at Sl. Pavan lent this sum to Divya at the same rate for 2 years at Compound Interest. At the end of second year, Pavan received Rs 550 as compound interest but paid Rs 500 as simple interest. Find the rate of interest. a. 25% b. 20% c. 15% d. 22.5% Correct Answer: (b) Explanation: Let the sum and rate of interest be Rs P and R% respectively. Second year CI=2 years S.I. + interest of one year on first year S.I. 2- year SI=Rs.500 1-year SI=Rs.250 So interest on first year SI=550-500=50 Rate of interest=50/250=100 =20% Incorrect Answer: (b) Explanation: Let the sum and rate of interest be Rs P and R% respectively. Second year CI=2 years S.I. + interest of one year on first year S.I. 2- year SI=Rs.500 1-year SI=Rs.250 So interest on first year SI=550-500=50 Rate of interest=50/250=100 =20%
#### 4. Question
Pavan borrowed certain sum from Pratheesh for 2 years at Sl. Pavan lent this sum to Divya at the same rate for 2 years at Compound Interest. At the end of second year, Pavan received Rs 550 as compound interest but paid Rs 500 as simple interest. Find the rate of interest.
Answer: (b)
Explanation:
Let the sum and rate of interest be Rs P and R% respectively.
Second year CI=2 years S.I. + interest of one year on first year S.I.
2- year SI=Rs.500
1-year SI=Rs.250
So interest on first year SI=550-500=50
Rate of interest=50/250=*100 =20%
Answer: (b)
Explanation:
Let the sum and rate of interest be Rs P and R% respectively.
Second year CI=2 years S.I. + interest of one year on first year S.I.
2- year SI=Rs.500
1-year SI=Rs.250
So interest on first year SI=550-500=50
Rate of interest=50/250=*100 =20%
• Question 5 of 5 5. Question An amount doubles in 5 years at a SI . in what time will it become 24 times of itself at same rate? a) 55 b) 110 c) 54 d) 24 Correct Answer: (b) 110 Explanation: Rate of interest be R% and principal be Rs. P SI=2P-P=P P=PR5/100 R=20% To become 24 times=24P-P=23P 23P=P20T/100 T=110 years. Incorrect Answer: (b) 110 Explanation: Rate of interest be R% and principal be Rs. P SI=2P-P=P P=PR5/100 R=20% To become 24 times=24P-P=23P 23P=P20T/100 T=110 years.
#### 5. Question
An amount doubles in 5 years at a SI . in what time will it become 24 times of itself at same rate?
Answer: (b) 110
Explanation:
Rate of interest be R% and principal be Rs. P
P=PR5/100
To become 24 times=24P-P=23P
23P=P20T/100
T=110 years.
Answer: (b) 110
Explanation:
Rate of interest be R% and principal be Rs. P
P=PR5/100
To become 24 times=24P-P=23P
23P=P20T/100
T=110 years.
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