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UPSC Insta–DART (Daily Aptitude and Reasoning Test) 11 Oct 2024

Kartavya Desk Staff

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question Raju has some amount of money and he invested 60% of that amount in simple interest at the rate of 24% per annum for 2 years and he invested the remaining amount in compound interest at the rate of 10% per annum for 2 years. From the given statement in the above question which of the following can be determined. Amount invested by Raju? If the difference between the simple and compound interest received by Raju is Rs.1530, then find the amount invested in simple interest? The amount invested in simple interest is Rs.1500 more than the amounts invested in compound interest, then find the interest received from simple interest? Overall interest received by Raju? a) All 1, 2, 3 and 4 b) Only 1 c) Only 2 d) Only 2 and 3 Correct Answer: D Expanation Let the total amount invested by Raju = 5x The amount invested in simple interest=5x60/100=5x3/5 = 3x The amount invested in compound interest =5x3x=2x Interest received by Raju=3x242/100+[2x(1+10/100)2-2x] From option (1) The amount invested in simple interest=5x60/100=5x3/5=3x The amount invested in compound interest=5x3x=2x This does not satisfy the given condition. From option (2) 3x242/100-[2x(1+10/100)2-2x]=1530 1.44x-[2x1.21-2x]=1530 1.44x-2.42x+2x=1530 1.02x=1530 x=1500 The amount invested in simple interest=31500=Rs.4500 This satisfies the given condition. From option (3) The amount invested in simple interest=15003x/(3x-2x)=Rs.4500 Interest received in simple interes t= 4500242/100 =Rs.2160 This satisfies the given condition. From option (4) Interest received by Raju =3x242/100+[2x(1+10/100)2-2x] This does not satisfy the given condition. Incorrect Answer: D Expanation Let the total amount invested by Raju = 5x The amount invested in simple interest=5x60/100=5x3/5 = 3x The amount invested in compound interest =5x3x=2x Interest received by Raju=3x242/100+[2x(1+10/100)2-2x] From option (1) The amount invested in simple interest=5x60/100=5x3/5=3x The amount invested in compound interest=5x3x=2x This does not satisfy the given condition. From option (2) 3x242/100-[2x(1+10/100)2-2x]=1530 1.44x-[2x1.21-2x]=1530 1.44x-2.42x+2x=1530 1.02x=1530 x=1500 The amount invested in simple interest=31500=Rs.4500 This satisfies the given condition. From option (3) The amount invested in simple interest=15003x/(3x-2x)=Rs.4500 Interest received in simple interes t= 4500242/100 =Rs.2160 This satisfies the given condition. From option (4) Interest received by Raju =3x242/100+[2x(1+10/100)2-2x] This does not satisfy the given condition.

#### 1. Question

Raju has some amount of money and he invested 60% of that amount in simple interest at the rate of 24% per annum for 2 years and he invested the remaining amount in compound interest at the rate of 10% per annum for 2 years. From the given statement in the above question which of the following can be determined.

• Amount invested by Raju?

• If the difference between the simple and compound interest received by Raju is Rs.1530, then find the amount invested in simple interest?

• The amount invested in simple interest is Rs.1500 more than the amounts invested in compound interest, then find the interest received from simple interest?

• Overall interest received by Raju?

• a) All 1, 2, 3 and 4

• d) Only 2 and 3

Expanation

Let the total amount invested by Raju = 5x

The amount invested in simple interest=5x60/100=5x3/5 = 3x

The amount invested in compound interest =5x3x=2x

Interest received by

Raju=3x242/100+[2x*(1+10/100)2-2x]

From option (1)

The amount invested in simple interest=5x60/100=5x3/5=3x

The amount invested in compound interest=5x3x=2x This does not satisfy the given condition.

From option (2)

3x242/100-[2x*(1+10/100)2-2x]=1530

1.44x-[2x*1.21-2x]=1530

1.44x-2.42x+2x=1530

1.02x=1530

The amount invested in simple interest=31500=Rs.4500 This satisfies the given condition*.

From option (3)

The amount invested in simple interest=1500*3x/(3x-2x)=Rs.4500

Interest received in simple interes t= 4500242/100 =Rs.2160 This satisfies the given condition.

From option (4)

Interest received by Raju =3x242/100+[2x(1+10/100)2-2x] This does not satisfy the given condition.*

Expanation

Let the total amount invested by Raju = 5x

The amount invested in simple interest=5x60/100=5x3/5 = 3x

The amount invested in compound interest =5x3x=2x

Interest received by

Raju=3x242/100+[2x*(1+10/100)2-2x]

From option (1)

The amount invested in simple interest=5x60/100=5x3/5=3x

The amount invested in compound interest=5x3x=2x This does not satisfy the given condition.

From option (2)

3x242/100-[2x*(1+10/100)2-2x]=1530

1.44x-[2x*1.21-2x]=1530

1.44x-2.42x+2x=1530

1.02x=1530

The amount invested in simple interest=31500=Rs.4500 This satisfies the given condition*.

From option (3)

The amount invested in simple interest=1500*3x/(3x-2x)=Rs.4500

Interest received in simple interes t= 4500242/100 =Rs.2160 This satisfies the given condition.

From option (4)

Interest received by Raju =3x242/100+[2x(1+10/100)2-2x] This does not satisfy the given condition.*

• Question 2 of 5 2. Question Bhavana invested Rs.15000 in compound interest at the rate of x% per annum for 2 years is Rs.4837.5 If Bhavana invested Rs.25000 each in simple and compound interest at the rate of (x+9)% per annum for 2 years, then find the difference between the simple and compound interest received by Bhavana? a) Rs.1320 b) Rs.1440 c) Rs.1600 d) Rs.1080 Correct Answer: B Explanation 15000(1+x/100)2-15000=4837.5 (1+x/100)2-1=0.3225 1+x/100=1.3225 1+x/100=1.15 x=15 Required difference=[25000(1+24/100)2-25000] – 25000*(15+9)*2/100=13440-12000=Rs.1440 Incorrect Answer: B Explanation 15000(1+x/100)2-15000=4837.5 (1+x/100)2-1=0.3225 1+x/100=1.3225 1+x/100=1.15 x=15 Required difference=[25000(1+24/100)2-25000] – 25000*(15+9)*2/100=13440-12000=Rs.1440

#### 2. Question

Bhavana invested Rs.15000 in compound interest at the rate of x% per annum for 2 years is Rs.4837.5 If Bhavana invested Rs.25000 each in simple and compound interest at the rate of (x+9)% per annum for 2 years, then find the difference between the simple and compound interest received by Bhavana?

• a) Rs.1320

• b) Rs.1440

• c) Rs.1600

• d) Rs.1080

Explanation

15000*(1+x/100)2-15000=4837.5

(1+x/100)2-1=0.3225

1+x/100=1.3225

1+x/100=1.15

Required difference=[25000*(1+24/100)2-25000] –

25000*(15+9)*2/100=13440-12000=Rs.1440

Explanation

15000*(1+x/100)2-15000=4837.5

(1+x/100)2-1=0.3225

1+x/100=1.3225

1+x/100=1.15

Required difference=[25000*(1+24/100)2-25000] –

25000*(15+9)*2/100=13440-12000=Rs.1440

• Question 3 of 5 3. Question A sum of money of Rs.2600 was lent out in two parts in such a way that the simple interest on the first part at 10% per annum for 5 years is the same as the interest of the second part at 9% per annum for 6 years. The part lent out at 10% is a) Rs.1450 b) Rs.1250 c) Rs.1350 d) Rs.1150 Correct Answer: C Explanation Principle=P=2600 First part = A : 10% x 5 years=50% of first part Second part (P-A): 9% x 6 years=54% of the second part 50% of A = 54% (P-A) 50/100 x A = 54/100 x (2600-A) A/2 = (54 x 26) – (54/100 x A) A/2 + (54/100 x A) = 1404 (50/100 x A) + (54/100 x A) = 1404 (104/100)A = 1404 104A = 140400 A = 1350 Incorrect Answer: C Explanation Principle=P=2600 First part = A : 10% x 5 years=50% of first part Second part (P-A): 9% x 6 years=54% of the second part 50% of A = 54% (P-A) 50/100 x A = 54/100 x (2600-A) A/2 = (54 x 26) – (54/100 x A) A/2 + (54/100 x A) = 1404 (50/100 x A) + (54/100 x A) = 1404 (104/100)A = 1404 104A = 140400 A = 1350

#### 3. Question

A sum of money of Rs.2600 was lent out in two parts in such a way that the simple interest on the first part at 10% per annum for 5 years is the same as the interest of the second part at 9% per annum for 6 years. The part lent out at 10% is

• a) Rs.1450

• b) Rs.1250

• c) Rs.1350

• d) Rs.1150

Explanation

Principle=P=2600

First part = A : 10% x 5 years=50% of first part

Second part (P-A): 9% x 6 years=54% of the

second part

50% of A = 54% (P-A)

50/100 x A = 54/100 x (2600-A)

A/2 = (54 x 26) – (54/100 x A)

A/2 + (54/100 x A) = 1404

(50/100 x A) + (54/100 x A) = 1404

(104/100)A = 1404

104A = 140400

A = 1350

Explanation

Principle=P=2600

First part = A : 10% x 5 years=50% of first part

Second part (P-A): 9% x 6 years=54% of the

second part

50% of A = 54% (P-A)

50/100 x A = 54/100 x (2600-A)

A/2 = (54 x 26) – (54/100 x A)

A/2 + (54/100 x A) = 1404

(50/100 x A) + (54/100 x A) = 1404

(104/100)A = 1404

104A = 140400

A = 1350

• Question 4 of 5 4. Question A sum of Rs 4,000 amounts to Rs 5,008 in three years at simple interest at the rate of x% per annum. If the interest rate becomes (x + 2.6)%, then the revised maturity amount will be? a) Rs 5,330 b) Rs 5,200 c) Rs 5,320 d) Rs 5,420 Correct Answer: C Explanation Simple interest in 3 years = 5008 – 4000 =Rs.1008 1008 = 4000 × 3 × (R/100) R = 8.4% Rate of interest is 8.4% per annum. New rate of interest = 8.4 + 2.6 = 11% per annum Maturity amount in 3 years = 4000 × 3 × (11/100) + 4000 = Rs. 5320 Incorrect Answer: C Explanation Simple interest in 3 years = 5008 – 4000 =Rs.1008 1008 = 4000 × 3 × (R/100) R = 8.4% Rate of interest is 8.4% per annum. New rate of interest = 8.4 + 2.6 = 11% per annum Maturity amount in 3 years = 4000 × 3 × (11/100) + 4000 = Rs. 5320

#### 4. Question

A sum of Rs 4,000 amounts to Rs 5,008 in three years at simple interest at the rate of x% per annum. If the interest rate becomes (x + 2.6)%, then the revised maturity amount will be?

• a) Rs 5,330

• b) Rs 5,200

• c) Rs 5,320

• d) Rs 5,420

Explanation

Simple interest in 3 years = 5008 – 4000 =Rs.1008

1008 = 4000 × 3 × (R/100)

Rate of interest is 8.4% per annum.

New rate of interest = 8.4 + 2.6 = 11% per annum

Maturity amount in 3 years = 4000 × 3 × (11/100) + 4000 = Rs. 5320

Explanation

Simple interest in 3 years = 5008 – 4000 =Rs.1008

1008 = 4000 × 3 × (R/100)

Rate of interest is 8.4% per annum.

New rate of interest = 8.4 + 2.6 = 11% per annum

Maturity amount in 3 years = 4000 × 3 × (11/100) + 4000 = Rs. 5320

• Question 5 of 5 5. Question If the difference between the compound and simple interest on a sum for 3 years at the rate of 10% per annum is Rs. 77.5 then find the sum invested? a) Rs. 3500 b) Rs. 2500 c) Rs. 4000 d) Rs. 1500 Correct Answer: B Explanation Let Principle = 100% Rate = 10% Time = 3 years Simple interest = 30% of principle Compound interest = 33.1% of Principle Difference = 3.1% 3.1% = Rs 77.5 1% = Rs. 25 100% = Rs. 2500 Incorrect Answer: B Explanation Let Principle = 100% Rate = 10% Time = 3 years Simple interest = 30% of principle Compound interest = 33.1% of Principle Difference = 3.1% 3.1% = Rs 77.5 1% = Rs. 25 100% = Rs. 2500

#### 5. Question

If the difference between the compound and simple interest on a sum for 3 years at the rate of 10% per annum is Rs. 77.5 then find the sum invested?

• a) Rs. 3500

• b) Rs. 2500

• c) Rs. 4000

• d) Rs. 1500

Explanation

Let Principle = 100% Rate = 10% Time =

Simple interest = 30% of principle

Compound interest = 33.1% of Principle

Difference = 3.1%

3.1% = Rs 77.5

1% = Rs. 25

100% = Rs. 2500

Explanation

Let Principle = 100% Rate = 10% Time =

Simple interest = 30% of principle

Compound interest = 33.1% of Principle

Difference = 3.1%

3.1% = Rs 77.5

1% = Rs. 25

100% = Rs. 2500

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