UPSC Insta–DART (Daily Aptitude and Reasoning Test) 10 Nov 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question With reference to the above passage, the following assumptions have been made: I. Globalization promotes economic efficiency but poses risks to cultural diversity. II. Resistance to cultural homogenization can sometimes take divisive or exclusionary forms. III. The preservation of cultural plurality is incompatible with global integration. Which of the above assumptions is/are valid? (a) I only (b) I and II only (c) II and III only (d) All three Correct Answer: (b) Explanation: Assumption I is correct: The passage opens by acknowledging globalization’s economic and technological benefits while simultaneously highlighting its homogenizing effect — “accelerated exchange” versus “loss of distinctiveness.” Hence, assumption I is valid. Assumption II is correct: The author explicitly states that identity revivals “often manifest as aggressive assertions of cultural purity,” implying that resistance to homogenization can turn divisive. Assumption III is incorrect: The passage argues the opposite — that the challenge is to integrate globalization and pluralism, not to treat them as incompatible. Therefore, assumption III is invalid. Hence, only assumptions I and II are valid, making (b) the correct answer. Incorrect Answer: (b) Explanation: Assumption I is correct: The passage opens by acknowledging globalization’s economic and technological benefits while simultaneously highlighting its homogenizing effect — “accelerated exchange” versus “loss of distinctiveness.” Hence, assumption I is valid. Assumption II is correct: The author explicitly states that identity revivals “often manifest as aggressive assertions of cultural purity,” implying that resistance to homogenization can turn divisive. Assumption III is incorrect: The passage argues the opposite — that the challenge is to integrate globalization and pluralism, not to treat them as incompatible. Therefore, assumption III is invalid. Hence, only assumptions I and II are valid, making (b) the correct answer.

#### 1. Question

With reference to the above passage, the following assumptions have been made:

I. Globalization promotes economic efficiency but poses risks to cultural diversity. II. Resistance to cultural homogenization can sometimes take divisive or exclusionary forms. III. The preservation of cultural plurality is incompatible with global integration.

Which of the above assumptions is/are valid?

• (a) I only

• (b) I and II only

• (c) II and III only

• (d) All three

Answer: (b)

Explanation: Assumption I is correct: The passage opens by acknowledging globalization’s economic and technological benefits while simultaneously highlighting its homogenizing effect — “accelerated exchange” versus “loss of distinctiveness.” Hence, assumption I is valid. Assumption II is correct: The author explicitly states that identity revivals “often manifest as aggressive assertions of cultural purity,” implying that resistance to homogenization can turn divisive. Assumption III is incorrect: The passage argues the opposite — that the challenge is to integrate globalization and pluralism, not to treat them as incompatible. Therefore, assumption III is invalid. Hence, only assumptions I and II are valid, making (b) the correct answer.

Answer: (b)

• Question 2 of 5 2. Question There are digits 2, 3, 4, 5, 6, and 7. I. More than 800 four-digit numbers can be formed if repetition is allowed. II. More than 800 four-digit numbers can be formed if repetition is not allowed. (a) I only (b) II only (c) Both I and II (d) Neither I nor II Correct Answer: (a) Solution: I (repetition allowed): 6 choices for each of 4 places → 6⁴ = 1296 > 800 → True. II (repetition not allowed): 6 × 5 × 4 × 3 = 360 < 800 → False. Hence, (a) I only. Incorrect Answer: (a) Solution: I (repetition allowed): 6 choices for each of 4 places → 6⁴ = 1296 > 800 → True. II (repetition not allowed): 6 × 5 × 4 × 3 = 360 < 800 → False. Hence, (a) I only.

#### 2. Question

There are digits 2, 3, 4, 5, 6, and 7. I. More than 800 four-digit numbers can be formed if repetition is allowed. II. More than 800 four-digit numbers can be formed if repetition is not allowed.

• (a) I only

• (b) II only

• (c) Both I and II

• (d) Neither I nor II

Answer: (a) Solution: I (repetition allowed): 6 choices for each of 4 places → 6⁴ = 1296 > 800 → True. II (repetition not allowed): 6 × 5 × 4 × 3 = 360 < 800 → False. Hence, (a) I only.

• Question 3 of 5 3. Question A number is formed by repeating a two-digit number three times, such as 252525 or 434343. Which of the following numbers will always divide such numbers? (a) 7 (b) 13 (c) 1001001 (d) 10101 Correct Answer: (d) Solution: Let the two-digit number be xy. Actual number = 10000 × xy + 100 × xy + xy = (10000 + 100 + 1) × xy = 10101 × xy. Hence, such numbers are always divisible by 10101. Incorrect Answer: (d) Solution: Let the two-digit number be xy. Actual number = 10000 × xy + 100 × xy + xy = (10000 + 100 + 1) × xy = 10101 × xy. Hence, such numbers are always divisible by 10101.

#### 3. Question

A number is formed by repeating a two-digit number three times, such as 252525 or 434343. Which of the following numbers will always divide such numbers?

• (c) 1001001

Answer: (d) Solution: Let the two-digit number be xy. Actual number = 10000 × xy + 100 × xy + xy = (10000 + 100 + 1) × xy = 10101 × xy. Hence, such numbers are always divisible by 10101.

• Question 4 of 5 4. Question Choose the group which is different from the others: (a) 64, 125, 216, 343 (b) 8, 27, 64, 125 (c) 1, 8, 27, 81 (d) 27, 64, 125, 216 Correct Answer: (c) Solution: Each group seems to represent cubes of natural numbers, check each: (a) 4³, 5³, 6³, 7³ → all perfect cubes. (b) 2³, 3³, 4³, 5³ → all perfect cubes. (c) 1³, 2³, 3³, 81 (not a cube, 81 = 3⁴) → one term not a cube. (d) 3³, 4³, 5³, 6³ → all perfect cubes. Hence, group (c) is different because 81 is not a perfect cube. Incorrect Answer: (c) Solution: Each group seems to represent cubes of natural numbers, check each: (a) 4³, 5³, 6³, 7³ → all perfect cubes. (b) 2³, 3³, 4³, 5³ → all perfect cubes. (c) 1³, 2³, 3³, 81 (not a cube, 81 = 3⁴) → one term not a cube. (d) 3³, 4³, 5³, 6³ → all perfect cubes. Hence, group (c) is different because 81 is not a perfect cube.

#### 4. Question

Choose the group which is different from the others:

• (a) 64, 125, 216, 343

• (b) 8, 27, 64, 125

• (c) 1, 8, 27, 81

• (d) 27, 64, 125, 216

Answer: (c) Solution: Each group seems to represent cubes of natural numbers, check each: (a) 4³, 5³, 6³, 7³ → all perfect cubes. (b) 2³, 3³, 4³, 5³ → all perfect cubes. (c) 1³, 2³, 3³, 81 (not a cube, 81 = 3⁴) → one term not a cube. (d) 3³, 4³, 5³, 6³ → all perfect cubes. Hence, group (c) is different because 81 is not a perfect cube.

• Question 5 of 5 5. Question How many 3-digit natural numbers (without repetition) are there such that each digit is odd and the number is divisible by 3? (a) 20 (b) 24 (c) 30 (d) 36 Correct Answer: (b) Solution: Allowed digits are odd: {1, 3, 5, 7, 9}. A 3-digit number with no repetition is divisible by 3 iff the sum of its digits is divisible by 3. Classify by residues mod 3: 0-class: {3, 9} 1-class: {1, 7} 2-class: {5} Valid triples must be of type (0,1,2). The only way is to choose one from each class: pick one from {3,9} (2 ways), one from {1,7} (2 ways), and 5 (1 way) ⇒ 2×2×1 = 4 sets. Each set can be arranged in 3! = 6 ways ⇒ total = 4×6 = 24. Incorrect Answer: (b) Solution: Allowed digits are odd: {1, 3, 5, 7, 9}. A 3-digit number with no repetition is divisible by 3 iff the sum of its digits is divisible by 3. Classify by residues mod 3: 0-class: {3, 9} 1-class: {1, 7} 2-class: {5} Valid triples must be of type (0,1,2). The only way is to choose one from each class: pick one from {3,9} (2 ways), one from {1,7} (2 ways), and 5 (1 way) ⇒ 2×2×1 = 4 sets. Each set can be arranged in 3! = 6 ways ⇒ total = 4×6 = 24.

#### 5. Question

How many 3-digit natural numbers (without repetition) are there such that each digit is odd and the number is divisible by 3?

Answer: (b) Solution: Allowed digits are odd: {1, 3, 5, 7, 9}. A 3-digit number with no repetition is divisible by 3 iff the sum of its digits is divisible by 3. Classify by residues mod 3:

• 0-class: {3, 9}

• 1-class: {1, 7}

• 2-class: {5}

Valid triples must be of type (0,1,2). The only way is to choose one from each class: pick one from {3,9} (2 ways), one from {1,7} (2 ways), and 5 (1 way) ⇒ 2×2×1 = 4 sets. Each set can be arranged in 3! = 6 ways ⇒ total = 4×6 = 24.

Answer: (b) Solution: Allowed digits are odd: {1, 3, 5, 7, 9}. A 3-digit number with no repetition is divisible by 3 iff the sum of its digits is divisible by 3. Classify by residues mod 3:

• 0-class: {3, 9}

• 1-class: {1, 7}

• 2-class: {5}

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