UPSC Insta–DART (Daily Aptitude and Reasoning Test) 1 Oct 2025

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

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• Question 1 of 5 1. Question How many seconds in total are there in x weeks, x hours, x minutes and x seconds? (a) 608460x (b) 608461x (c) 608401x (d) 608361x Correct Answer – B Solution: As we know: Seconds in a minute = 60 sec Seconds in an hour = 60 x 60 = 3600 sec Seconds in a week = 60 x 60 x 24 x 7 = 604800 sec Thus seconds in total are there in x weeks, x hours, x minutes and x seconds = 604800x + 3600x + 60x + 1x = 608461x Hence option (b) is correct Incorrect Answer – B Solution: As we know: Seconds in a minute = 60 sec Seconds in an hour = 60 x 60 = 3600 sec Seconds in a week = 60 x 60 x 24 x 7 = 604800 sec Thus seconds in total are there in x weeks, x hours, x minutes and x seconds = 604800x + 3600x + 60x + 1x = 608461x Hence option (b) is correct

#### 1. Question

How many seconds in total are there in x weeks, x hours, x minutes and x seconds?

• (a) 608460x

• (b) 608461x

• (c) 608401x

• (d) 608361x

Answer – B

As we know:

Seconds in a minute = 60 sec Seconds in an hour = 60 x 60 = 3600 sec Seconds in a week = 60 x 60 x 24 x 7 = 604800 sec

Thus seconds in total are there in x weeks, x hours, x minutes and x seconds =

604800x + 3600x + 60x + 1x = 608461x

Hence option (b) is correct

Answer – B

As we know:

Seconds in a minute = 60 sec Seconds in an hour = 60 x 60 = 3600 sec Seconds in a week = 60 x 60 x 24 x 7 = 604800 sec

Thus seconds in total are there in x weeks, x hours, x minutes and x seconds =

604800x + 3600x + 60x + 1x = 608461x

Hence option (b) is correct

• Question 2 of 5 2. Question A clock gains 1% of the week-time during the first week and then gains 2% of the week-time during the next one week. If the clock was set right at 12 noon on a Sunday, what will be the time that the clock will show exactly 14 days from the time it was set right? a) 5: 01 b) 5: 02 c) 5: 03 d) 5: 04 Correct Answer: B Explanation There are 168 hours in a week. In the first week the clock shows 1.01 x 168 = 169.68 hours. In the next week it shows 1.02 x 168 = 171.36 hours. Total shown in two weeks = 169.68 + 171.36 = 341.04 hours, while the true time is 336 hours. Hence the clock is 341.04 − 336 = 5.04 hours fast, i.e. 5 hours 2.4 minutes. Therefore the clock will show 12 noon plus 5.04 hours = 5: 02 P.M. Incorrect Answer: B Explanation There are 168 hours in a week. In the first week the clock shows 1.01 x 168 = 169.68 hours. In the next week it shows 1.02 x 168 = 171.36 hours. Total shown in two weeks = 169.68 + 171.36 = 341.04 hours, while the true time is 336 hours. Hence the clock is 341.04 − 336 = 5.04 hours fast, i.e. 5 hours 2.4 minutes. Therefore the clock will show 12 noon plus 5.04 hours = 5: 02 P.M.

#### 2. Question

A clock gains 1% of the week-time during the first week and then gains 2% of the week-time during the next one week. If the clock was set right at 12 noon on a Sunday, what will be the time that the clock will show exactly 14 days from the time it was set right?

Answer: B Explanation There are 168 hours in a week. In the first week the clock shows 1.01 x 168 = 169.68 hours. In the next week it shows 1.02 x 168 = 171.36 hours. Total shown in two weeks = 169.68 + 171.36 = 341.04 hours, while the true time is 336 hours. Hence the clock is 341.04 − 336 = 5.04 hours fast, i.e. 5 hours 2.4 minutes. Therefore the clock will show 12 noon plus 5.04 hours = 5: 02 P.M.

• Question 3 of 5 3. Question A work is done in 9k days by some men. If the number of men is increased by 33.33 percent, by what percentage will the time reduce? (a) 20 percent (b) 22.22 percent (c) 25 percent (d) 28 percent Correct Answer: C Solution Initial men = N1, new men = 4/3 N1 So, N19k = (4/3)N1D2 => D2 = 9k/(4/3) = 6.75k Reduction in time = 9k – 6.75k = 2.25k Percentage decrease: 2.25k/9k X 100 = 1/4 X 100 = 25 percent Incorrect Answer: C Solution Initial men = N1, new men = 4/3 N1 So, N19k = (4/3)N1D2 => D2 = 9k/(4/3) = 6.75k Reduction in time = 9k – 6.75k = 2.25k Percentage decrease: 2.25k/9k X 100 = 1/4 X 100 = 25 percent

#### 3. Question

A work is done in 9k days by some men. If the number of men is increased by 33.33 percent, by what percentage will the time reduce?

• (a) 20 percent

• (b) 22.22 percent

• (c) 25 percent

• (d) 28 percent

Answer: C Solution Initial men = N1, new men = 4/3 N1 So, N19k = (4/3)N1D2 => D2 = 9k/(4/3) = 6.75k Reduction in time = 9k – 6.75k = 2.25k Percentage decrease: 2.25k/9k X 100 = 1/4 X 100 = 25 percent

• Question 4 of 5 4. Question Ravi and Meena together paid Rs 100 for wraps and shakes. If a wrap costs Rs 13 and a shake costs Rs 7, then which one of the following statements is correct? (a) We cannot determine whether they bought more wraps or shakes. (b) They bought the same number of wraps and shakes. (c) They bought more shakes than wraps. (d) They bought more wraps than shakes. Correct Answer: (b) Solution: 13x + 7y = 100 Check multiples of 13: 13 x 5 = 65 → remaining = 35 → 7 x 5 → 5 wraps, 5 shakes → same number 13 x 6 = 78 → remaining = 22 (not a multiple of 7) 13 x 7 = 91 → remaining = 9 (not a multiple of 7) No other non-negative solution works, so numbers are equal. Incorrect Answer: (b) Solution: 13x + 7y = 100 Check multiples of 13: 13 x 5 = 65 → remaining = 35 → 7 x 5 → 5 wraps, 5 shakes → same number 13 x 6 = 78 → remaining = 22 (not a multiple of 7) 13 x 7 = 91 → remaining = 9 (not a multiple of 7) No other non-negative solution works, so numbers are equal.

#### 4. Question

Ravi and Meena together paid Rs 100 for wraps and shakes. If a wrap costs Rs 13 and a shake costs Rs 7, then which one of the following statements is correct?

• (a) We cannot determine whether they bought more wraps or shakes.

• (b) They bought the same number of wraps and shakes.

• (c) They bought more shakes than wraps.

• (d) They bought more wraps than shakes.

Answer: (b)

Solution: 13x + 7y = 100 Check multiples of 13: 13 x 5 = 65 → remaining = 35 → 7 x 5 → 5 wraps, 5 shakes → same number 13 x 6 = 78 → remaining = 22 (not a multiple of 7) 13 x 7 = 91 → remaining = 9 (not a multiple of 7) No other non-negative solution works, so numbers are equal.

Answer: (b)

• Question 5 of 5 5. Question The price of wheat increased by 50%. A family reduced its consumption so that the expenditure increased by only 20%. If earlier they consumed 60 kg per month, what is the new consumption? (a) 48 kg (b) 50 kg (c) 52 kg (d) 54 kg Correct Answer: (a) Explanation: Initial price = ₹100 per kg. Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000. New expenditure = 6,000 + 20% of 6,000 = ₹7,200. New price = 100 + 50% of 100 = ₹150. So, 150 × new consumption = 7,200. New consumption = 7,200 ÷ 150 = 48 kg. Incorrect Answer: (a) Explanation: Initial price = ₹100 per kg. Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000. New expenditure = 6,000 + 20% of 6,000 = ₹7,200. New price = 100 + 50% of 100 = ₹150. So, 150 × new consumption = 7,200. New consumption = 7,200 ÷ 150 = 48 kg.

#### 5. Question

The price of wheat increased by 50%. A family reduced its consumption so that the expenditure increased by only 20%. If earlier they consumed 60 kg per month, what is the new consumption?

Answer: (a)

Explanation: Initial price = ₹100 per kg. Initial consumption = 60 kg → Expenditure = 100 × 60 = ₹6,000. New expenditure = 6,000 + 20% of 6,000 = ₹7,200. New price = 100 + 50% of 100 = ₹150. So, 150 × new consumption = 7,200. New consumption = 7,200 ÷ 150 = 48 kg.

Answer: (a)

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