UPSC Insta–DART (Daily Aptitude and Reasoning Test) 1 Nov 2025
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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• Question 1 of 5 1. Question A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes? A. 32 rolls B. 54 rolls C. 108 rolls D. 120 rolls Correct Correct Answer : D Explanation: Number of cuts made to cut a roll into 10 pieces = 9. Therefore, required number of rolls = (45 × 24)/9 = 120. Incorrect Correct Answer : D Explanation: Number of cuts made to cut a roll into 10 pieces = 9. Therefore, required number of rolls = (45 × 24)/9 = 120.
#### 1. Question
A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes?
• A. 32 rolls
• B. 54 rolls
• C. 108 rolls
• D. 120 rolls
Correct Answer : D
Explanation:
Number of cuts made to cut a roll into 10 pieces = 9. Therefore, required number of rolls = (45 × 24)/9 = 120.
Correct Answer : D
Explanation:
Number of cuts made to cut a roll into 10 pieces = 9. Therefore, required number of rolls = (45 × 24)/9 = 120.
• Question 2 of 5 2. Question The letters L, M, N, O, P, Q, R, S and T in their order are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3. What is the integer assigned to N? A. 7 B. 5 C. 4 D. 6 Correct Correct Answer : D Explanation: N= 6 P= 4 T= 9 difference between P & T is 5 i.e., T = 5 + 4 = 9 difference between N & T is 3 i.e., N = 9 – 3 = 6 So, integer assigned to N = 6 Incorrect Correct Answer : D Explanation: N= 6 P= 4 T= 9 difference between P & T is 5 i.e., T = 5 + 4 = 9 difference between N & T is 3 i.e., N = 9 – 3 = 6 So, integer assigned to N = 6
#### 2. Question
The letters L, M, N, O, P, Q, R, S and T in their order are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3. What is the integer assigned to N?
Correct Answer : D
Explanation:
difference between P & T is 5 i.e., T = 5 + 4 = 9
difference between N & T is 3 i.e., N = 9 – 3 = 6 So, integer assigned to N = 6
Correct Answer : D
Explanation:
difference between P & T is 5 i.e., T = 5 + 4 = 9
difference between N & T is 3 i.e., N = 9 – 3 = 6 So, integer assigned to N = 6
• Question 3 of 5 3. Question Ravi is 7 ranks ahead of Sumit in a class of 39. If Sumit’s rank is seventeenth from the last, what is Ravi’s rank from the start? A. 14th B. 15th C. 16th D. 17th Correct Correct Answer : C Answer Justification : Explanation: Sumit is 17th from the last and Ravi is 7 ranks ahead of sumit. So, Ravi is 24th from the last. Number of students ahead of Ravi in rank = (39 – 24) = 15. So, Ravi is 16th from the start. Incorrect Correct Answer : C Answer Justification : Explanation: Sumit is 17th from the last and Ravi is 7 ranks ahead of sumit. So, Ravi is 24th from the last. Number of students ahead of Ravi in rank = (39 – 24) = 15. So, Ravi is 16th from the start.
#### 3. Question
Ravi is 7 ranks ahead of Sumit in a class of 39. If Sumit’s rank is seventeenth from the last, what is Ravi’s rank from the start?
Correct Answer : C
Answer Justification :
Explanation:
Sumit is 17th from the last and Ravi is 7 ranks ahead of sumit. So, Ravi is 24th from the last.
Number of students ahead of Ravi in rank = (39 – 24) = 15. So, Ravi is 16th from the start.
Correct Answer : C
Answer Justification :
Explanation:
Sumit is 17th from the last and Ravi is 7 ranks ahead of sumit. So, Ravi is 24th from the last.
Number of students ahead of Ravi in rank = (39 – 24) = 15. So, Ravi is 16th from the start.
• Question 4 of 5 4. Question How many natural numbers up to 100 are not divisible by 3 or 7? A. 43 B. 57 C. 44 D. 67 Correct Correct Answer : B Explanation: Numbers divisible by 3 = 100/3 = 33 Numbers divisible by 7 = 100/7 = 14 Numbers divisible by 21 (LCM of 3 and 7) = 100/21 = 4 Total numbers divisible by 3 or 7 = 33 + 14 – 4 = 43 Total numbers which are not divisible by 3 or 7 = 100 – 43 = 57 Incorrect Correct Answer : B Explanation: Numbers divisible by 3 = 100/3 = 33 Numbers divisible by 7 = 100/7 = 14 Numbers divisible by 21 (LCM of 3 and 7) = 100/21 = 4 Total numbers divisible by 3 or 7 = 33 + 14 – 4 = 43 Total numbers which are not divisible by 3 or 7 = 100 – 43 = 57
#### 4. Question
How many natural numbers up to 100 are not divisible by 3 or 7?
Correct Answer : B
Explanation:
Numbers divisible by 3 = 100/3 = 33 Numbers divisible by 7 = 100/7 = 14
Numbers divisible by 21 (LCM of 3 and 7) = 100/21 = 4
Total numbers divisible by 3 or 7 = 33 + 14 – 4 = 43
Total numbers which are not divisible by 3 or 7 = 100 – 43 = 57
Correct Answer : B
Explanation:
Numbers divisible by 3 = 100/3 = 33 Numbers divisible by 7 = 100/7 = 14
Numbers divisible by 21 (LCM of 3 and 7) = 100/21 = 4
Total numbers divisible by 3 or 7 = 33 + 14 – 4 = 43
Total numbers which are not divisible by 3 or 7 = 100 – 43 = 57
• Question 5 of 5 5. Question In a certain code, ‘256’ means ‘red colour chalk’, ‘589’ means ‘green colour flower’ and ‘254’ means ‘white colour chalk’. The digit in the code that indicates ‘white’ is A. 2 B. 4 C. 5 D. 8 Correct Correct Answer : B Answer Justification : Explanation: ‘256’ = ‘red colour chalk’ ‘589’ = ‘green colour flower’ ‘254’ = ‘white colour chalk’ 5 and colour are common in all three. So, 5 = Colour, 2 = Chalk Incorrect Correct Answer : B Answer Justification : Explanation: ‘256’ = ‘red colour chalk’ ‘589’ = ‘green colour flower’ ‘254’ = ‘white colour chalk’ 5 and colour are common in all three. So, 5 = Colour, 2 = Chalk
#### 5. Question
In a certain code, ‘256’ means ‘red colour chalk’, ‘589’ means ‘green colour flower’ and ‘254’ means ‘white colour chalk’. The digit in the code that indicates ‘white’ is
Correct Answer : B
Answer Justification :
Explanation:
‘256’ = ‘red colour chalk’
‘589’ = ‘green colour flower’
‘254’ = ‘white colour chalk’
5 and colour are common in all three. So, 5 = Colour, 2 = Chalk
Correct Answer : B
Answer Justification :
Explanation:
‘256’ = ‘red colour chalk’
‘589’ = ‘green colour flower’
‘254’ = ‘white colour chalk’
5 and colour are common in all three. So, 5 = Colour, 2 = Chalk
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