UPSC Insta–DART (Daily Aptitude and Reasoning Test) 04 Sep 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question A sells an item at 20% profit to B . B sells it to C at 10% profit . C sells it to D at Rs.232 profit. Difference between the cost price of D and cost price of A was Rs. 1000. How much did B pay to A for the item? a) 2880 b) 1440 c) 1200 d) 1580 Correct Answer : (a) 2880 Explanation: CP for A=x CP for D=x120/100 110/100 +232=1.32x+232 According to the question, 1.32x+232-x=1000 o.32x=768 x=2400 CP for B=2400120/100=2880 Incorrect Answer : (a) 2880 Explanation: CP for A=x CP for D=x120/100 110/100 +232=1.32x+232 According to the question, 1.32x+232-x=1000 o.32x=768 x=2400 CP for B=2400120/100=2880
#### 1. Question
A sells an item at 20% profit to B . B sells it to C at 10% profit . C sells it to D at Rs.232 profit. Difference between the cost price of D and cost price of A was Rs. 1000. How much did B pay to A for the item?
Answer : (a) 2880
Explanation:
CP for A=x
CP for D=x120/100 110/100 +232=1.32x+232
According to the question,
1.32x+232-x=1000
CP for B=2400*120/100=2880
Answer : (a) 2880
Explanation:
CP for A=x
CP for D=x120/100 110/100 +232=1.32x+232
According to the question,
1.32x+232-x=1000
CP for B=2400*120/100=2880
• Question 2 of 5 2. Question A man sells two articles at Rs. 24 each. He gains 20% on one and loses 20% on the other. In the whole transaction, there is a) Neither loss nor gain b) Profit of Rs.1 c) Profit of Rs.2 d) Loss of Rs.2 Correct Answer: (d) Loss of Rs.2 Explanation: CP first article =10024/120 =Rs.20 CP of second article=24100/80=Rs.30 Total CP=30+20=50 SP=48 Loss=50-48=Rs 2 Incorrect Answer: (d) Loss of Rs.2 Explanation: CP first article =10024/120 =Rs.20 CP of second article=24100/80=Rs.30 Total CP=30+20=50 SP=48 Loss=50-48=Rs 2
#### 2. Question
A man sells two articles at Rs. 24 each. He gains 20% on one and loses 20% on the other. In the whole transaction, there is
• a) Neither loss nor gain
• b) Profit of Rs.1
• c) Profit of Rs.2
• d) Loss of Rs.2
Answer: (d) Loss of Rs.2
Explanation:
CP first article =100*24/120 =Rs.20
CP of second article=24*100/80=Rs.30
Total CP=30+20=50
Loss=50-48=Rs 2
Answer: (d) Loss of Rs.2
Explanation:
CP first article =100*24/120 =Rs.20
CP of second article=24*100/80=Rs.30
Total CP=30+20=50
Loss=50-48=Rs 2
• Question 3 of 5 3. Question Profit percent earned when an article is sold for Rs.546 is double the percent profit earned when the same article is sold for Rs. 483. If the marked price of the article is 50% above the cost price, what is the marked price of the article? a) 630 b) 560 c) 450 d) 340 Correct Answer: (a) 630 Explanation: Profit on selling the article for Rs. 483=546-483=63 Cp of article=483-63=420 MP of article=420150/100=630 Incorrect Answer: (a) 630 Explanation: Profit on selling the article for Rs. 483=546-483=63 Cp of article=483-63=420 MP of article=420150/100=630
#### 3. Question
Profit percent earned when an article is sold for Rs.546 is double the percent profit earned when the same article is sold for Rs. 483. If the marked price of the article is 50% above the cost price, what is the marked price of the article?
Answer: (a) 630
Explanation:
Profit on selling the article for Rs. 483=546-483=63
Cp of article=483-63=420
MP of article=420*150/100=630
Answer: (a) 630
Explanation:
Profit on selling the article for Rs. 483=546-483=63
Cp of article=483-63=420
MP of article=420*150/100=630
• Question 4 of 5 4. Question The percentage profit earned by selling an article for Rs,1920 is equal to the loss percent incurred by selling it for Rs. 1280. At what price should the article be sold to gain 75% profit? a) 560 b) 850 c) 320 d) 500 Correct Answer: (a) 560 Explanation: (1920-cp)/cp=(cp-1280)/cp Cp=320 320175/100 =560 Incorrect Answer: (a) 560 Explanation: (1920-cp)/cp=(cp-1280)/cp Cp=320 320175/100 =560
#### 4. Question
The percentage profit earned by selling an article for Rs,1920 is equal to the loss percent incurred by selling it for Rs. 1280. At what price should the article be sold to gain 75% profit?
Answer: (a) 560
Explanation:
(1920-cp)/cp=(cp-1280)/cp
320*175/100 =560
Answer: (a) 560
Explanation:
(1920-cp)/cp=(cp-1280)/cp
320*175/100 =560
• Question 5 of 5 5. Question A shopkeeper marked his goods up by 60% subsequently offered a discount of 10% on marked price. What is the percentage profit that the shopkeeper makes after offering the discount? a) 35% b) 44% c) 25% d) 20% Correct Answer: (b) 44% Explanation: Let the CP of the goods=100x Marked price=100xK160/100=160x Discount=10/100 160x=16x SP=160x-16x=144x Profit =44x=44% Incorrect Answer: (b) 44% Explanation: Let the CP of the goods=100x Marked price=100xK160/100=160x Discount=10/100 160x=16x SP=160x-16x=144x Profit =44x=44%
#### 5. Question
A shopkeeper marked his goods up by 60% subsequently offered a discount of 10% on marked price. What is the percentage profit that the shopkeeper makes after offering the discount?
Answer: (b) 44%
Explanation:
Let the CP of the goods=100x
Marked price=100xK*160/100=160x
Discount=10/100 *160x=16x
SP=160x-16x=144x
Profit =44x=44%
Answer: (b) 44%
Explanation:
Let the CP of the goods=100x
Marked price=100xK*160/100=160x
Discount=10/100 *160x=16x
SP=160x-16x=144x
Profit =44x=44%
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