UPSC Insta–DART (Daily Aptitude and Reasoning Test) 02 Sep 2024
Kartavya Desk Staff
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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• Question 1 of 5 1. Question Difference between the selling price when a article is sold at 12% profit and when sold at 20% loss is Rs. 176. If the same article is marked 60% above its cost price and sold after offering a discount of 25%, then what would be its selling price? a) 660 b) 880 c) 550 d) 500 Correct Answer: (a) 660 Explanation: Let the cost price of the article=100x Then according to the question 100x 112/100 -100x 80/100 =176 112x-80x=176 On solving we get x=5.5 Then the cost price of the article=550 MP=550 160/100=880 SP=88075/100=660 Incorrect Answer: (a) 660 Explanation: Let the cost price of the article=100x Then according to the question 100x 112/100 -100x 80/100 =176 112x-80x=176 On solving we get x=5.5 Then the cost price of the article=550 MP=550 160/100=880 SP=88075/100=660
#### 1. Question
Difference between the selling price when a article is sold at 12% profit and when sold at 20% loss is Rs. 176. If the same article is marked 60% above its cost price and sold after offering a discount of 25%, then what would be its selling price?
Answer: (a) 660
Explanation:
Let the cost price of the article=100x
Then according to the question
100x 112/100 -100x 80/100 =176
112x-80x=176
On solving we get x=5.5
Then the cost price of the article=550
MP=550 *160/100=880
SP=880*75/100=660
Answer: (a) 660
Explanation:
Let the cost price of the article=100x
Then according to the question
100x 112/100 -100x 80/100 =176
112x-80x=176
On solving we get x=5.5
Then the cost price of the article=550
MP=550 *160/100=880
SP=880*75/100=660
• Question 2 of 5 2. Question A shopkeeper bought article ‘A’ for Rs. ‘x’ and marked it 20% above its cost price and sold it for Rs. 5400. Marked price of article ‘B’ is Rs. 2000 more than that of article ‘A’. while selling price of article ‘B’ is Rs. 1000 more than that of ‘A’. find the cost price of article ‘A’ if article ‘B’ is sold at a discount of 20%. a) 1000 b) 5000 c) 2000 d) 4000 Correct Answer: (b) 5000 Explanation: SP of B =5400+1000=6400 MP of B=6400/0.80=8000 MP of article A=8000-2000=6000 Cost price of article ‘A’ = 6000/1.20=5000 Incorrect Answer: (b) 5000 Explanation: SP of B =5400+1000=6400 MP of B=6400/0.80=8000 MP of article A=8000-2000=6000 Cost price of article ‘A’ = 6000/1.20=5000
#### 2. Question
A shopkeeper bought article ‘A’ for Rs. ‘x’ and marked it 20% above its cost price and sold it for Rs. 5400. Marked price of article ‘B’ is Rs. 2000 more than that of article ‘A’. while selling price of article ‘B’ is Rs. 1000 more than that of ‘A’. find the cost price of article ‘A’ if article ‘B’ is sold at a discount of 20%.
Answer: (b) 5000
Explanation:
SP of B =5400+1000=6400
MP of B=6400/0.80=8000
MP of article A=8000-2000=6000
Cost price of article ‘A’ = 6000/1.20=5000
Answer: (b) 5000
Explanation:
SP of B =5400+1000=6400
MP of B=6400/0.80=8000
MP of article A=8000-2000=6000
Cost price of article ‘A’ = 6000/1.20=5000
• Question 3 of 5 3. Question Th e profit earned on selling an article for Rs. 1960 id equal to the loss incurred on selling the same article for Rs. 1320 . what price it should be sold to earn profit a profit of 10%? a) 1804 b) 1500 c) 1600 d) 1400 Correct Answer: (a) 1804 Explanation: (1960-CP)=(CP-1320) On solving we get CP=1640 Therefor the required SP=1640110/100=1804 Rs=1804 Incorrect Answer: (a) 1804 Explanation: (1960-CP)=(CP-1320) On solving we get CP=1640 Therefor the required SP=1640110/100=1804 Rs=1804
#### 3. Question
Th e profit earned on selling an article for Rs. 1960 id equal to the loss incurred on selling the same article for Rs. 1320 . what price it should be sold to earn profit a profit of 10%?
Answer: (a) 1804
Explanation:
(1960-CP)=(CP-1320)
On solving we get CP=1640
Therefor the required SP=1640*110/100=1804
Answer: (a) 1804
Explanation:
(1960-CP)=(CP-1320)
On solving we get CP=1640
Therefor the required SP=1640*110/100=1804
• Question 4 of 5 4. Question Priya purchased an article and marked it 80% above the cost price and sold it after giving a discount of 25% for Rs. 3240. What will be the selling price of the article if discount of 15% is given? a) 3672 b) 4320 c) 5390 d) 6000 Correct Answer: (a) 3672 Explanation: CP=100x MP=180x Discount=25% SP= 75/100 180x SP=135x=3240 On solving we get x=24 CP=2400 MP=24180=4320 Now 15% discount=85/100 (4320) New SP =3672 Incorrect Answer: (a) 3672 Explanation: CP=100x MP=180x Discount=25% SP= 75/100 180x SP=135x=3240 On solving we get x=24 CP=2400 MP=24180=4320 Now 15% discount=85/100 (4320) New SP =3672
#### 4. Question
Priya purchased an article and marked it 80% above the cost price and sold it after giving a discount of 25% for Rs. 3240. What will be the selling price of the article if discount of 15% is given?
Answer: (a) 3672
Explanation:
Discount=25%
SP= 75/100 * 180x
SP=135x=3240
On solving we get
MP=24*180=4320
Now 15% discount=85/100 *(4320)
New SP =3672
Answer: (a) 3672
Explanation:
Discount=25%
SP= 75/100 * 180x
SP=135x=3240
On solving we get
MP=24*180=4320
Now 15% discount=85/100 *(4320)
New SP =3672
• Question 5 of 5 5. Question The percentage loss incurred by selling the product at Rs. 1350 is equal to one-half of the percentage profit earned by selling the same product at Rs. 3450 . at what price should the product be sold to make profit of 10%? a) 2255 b) 2050 c) 2000 d) 4000 Correct Answer: (a) 2255 Explanation: (CP-1350)100 /CP =1/2(3450-CP)100/CP On solving we get CP=2050 SP=2050 110/100=2255 Incorrect Answer: (a) 2255 Explanation: (CP-1350)100 /CP =1/2(3450-CP)100/CP On solving we get CP=2050 SP=2050 110/100=2255
#### 5. Question
The percentage loss incurred by selling the product at Rs. 1350 is equal to one-half of the percentage profit earned by selling the same product at Rs. 3450 . at what price should the product be sold to make profit of 10%?
Answer: (a) 2255
Explanation:
(CP-1350)100 /CP =1/2(3450-CP)100/CP
On solving we get
SP=2050 *110/100=2255
Answer: (a) 2255
Explanation:
(CP-1350)100 /CP =1/2(3450-CP)100/CP
On solving we get
SP=2050 *110/100=2255
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