[Mission 2024] Insta–DART (Daily Aptitude and Reasoning Test) 8 May 2024
Kartavya Desk Staff
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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• Question 1 of 5 1. Question Let A denotes the set of quadrilaterals having two diagonals equal and bisecting each other. Let B denotes the set of quadrilaterals having diagonals bisecting each other at 90. Then, A ∩ B denotes (a) the set of parallelograms (b) the set of rhombuses (c) the set of squares (d) the set of rectangles Correct Ans: c A= diagonal equal and bisecting each other. A is square or rectangle. And B diagonal bisecting each other at 90°. So, A ∪ B = the set of square Incorrect Ans: c A= diagonal equal and bisecting each other. A is square or rectangle. And B diagonal bisecting each other at 90°. So, A ∪ B = the set of square
#### 1. Question
Let A denotes the set of quadrilaterals having two diagonals equal and bisecting each other. Let B denotes the set of quadrilaterals having diagonals bisecting each other at 90. Then, A ∩ B denotes
• (a) the set of parallelograms
• (b) the set of rhombuses
• (c) the set of squares
• (d) the set of rectangles
A= diagonal equal and bisecting each other.
A is square or rectangle. And B diagonal bisecting each other at 90°.
So, A ∪ B = the set of square
A= diagonal equal and bisecting each other.
A is square or rectangle. And B diagonal bisecting each other at 90°.
So, A ∪ B = the set of square
• Question 2 of 5 2. Question Out of 105 students taking an examination English and Mathematics, 80 students pass in English, 75 students fail students in both the subjects. How many students pass in only one subject? (a) 26 (b) 30 (c) 35 (d) 45 Correct Ans: d Number of students failing in Mathematics = 105-75 =30 Number of students tailing in English = 105-80 =25 Number of students failing in 1 subject = (25+30) – 10 = 45 Incorrect Ans: d Number of students failing in Mathematics = 105-75 =30 Number of students tailing in English = 105-80 =25 Number of students failing in 1 subject = (25+30) – 10 = 45
#### 2. Question
Out of 105 students taking an examination English and Mathematics, 80 students pass in English, 75 students fail students in both the subjects. How many students pass in only one subject?
Number of students failing in Mathematics
Number of students tailing in English
Number of students failing in 1 subject
= (25+30) – 10
Number of students failing in Mathematics
Number of students tailing in English
Number of students failing in 1 subject
= (25+30) – 10
• Question 3 of 5 3. Question If A and B are any two non-empty subsets of a set E, then what is A ∪ (A ∩ B) equal to? (a) A ∩ B (b) A ∪ B (c) A (d) B Correct Ans: C Since, A and B are non-empty subsets of E. ∴A∪(A ∩ B) = A ∪( Shaded portion) = A Incorrect Ans: C Since, A and B are non-empty subsets of E. ∴A∪(A ∩ B) = A ∪( Shaded portion) = A
#### 3. Question
If A and B are any two non-empty subsets of a set E, then what is A ∪ (A ∩ B) equal to?
Since, A and B are non-empty subsets of E.
∴A∪(A ∩ B) = A ∪( Shaded portion)
Since, A and B are non-empty subsets of E.
∴A∪(A ∩ B) = A ∪( Shaded portion)
• Question 4 of 5 4. Question If A is a non- empty subset of a set E, then what is E∪(A ∩ Ø) – (A – Ø) equal to? E ∪(A∩Ø) equal to? (a) A (b) Complement of A (c) Ø (d) E Correct Ans: c E ∪[(A ∩Ø) – ( A -Ø)] ⇒E ∪[ Ø- A ] [Because (A ∩ Ø ) = fand (A – Ø)= A] Here, A cannot be subtracted from f Incorrect Ans: c E ∪[(A ∩Ø) – ( A -Ø)] ⇒E ∪[ Ø- A ] [Because (A ∩ Ø ) = fand (A – Ø)= A] Here, A cannot be subtracted from f
#### 4. Question
If A is a non- empty subset of a set E, then what is E∪(A ∩ Ø) – (A – Ø) equal to? E ∪(A∩Ø) equal to?
• (b) Complement of A
E ∪[(A ∩Ø) – ( A -Ø)]
⇒E ∪[ Ø- A ] [Because (A ∩ Ø ) = fand (A – Ø)= A]
Here, A cannot be subtracted from f
E ∪[(A ∩Ø) – ( A -Ø)]
⇒E ∪[ Ø- A ] [Because (A ∩ Ø ) = fand (A – Ø)= A]
Here, A cannot be subtracted from f
• Question 5 of 5 5. Question Consider the following statements Set of points of a given line is a finite set. Intelligent students in a class is a set. Good books in a school library is a set. Which of the above statement(s) is/are not correct? (a) Only I (b) Both ll and III (c) Both I and II (d) I, II and III Correct Ans: d The set of points of a given line is not a finite set Here, we cannot decide, which students are intelligent Here, we cannot decide, which books are good a school library Incorrect Ans: d The set of points of a given line is not a finite set Here, we cannot decide, which students are intelligent Here, we cannot decide, which books are good a school library
#### 5. Question
Consider the following statements
• Set of points of a given line is a finite set.
• Intelligent students in a class is a set.
• Good books in a school library is a set.
Which of the above statement(s) is/are not correct?
• (a) Only I
• (b) Both ll and III
• (c) Both I and II
• (d) I, II and III
• The set of points of a given line is not a finite set
• Here, we cannot decide, which students are intelligent
• Here, we cannot decide, which books are good a school library
• The set of points of a given line is not a finite set
• Here, we cannot decide, which students are intelligent
• Here, we cannot decide, which books are good a school library
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