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[Mission 2024] Insta–DART (Daily Aptitude and Reasoning Test) 22- 23 March 2024

Kartavya Desk Staff

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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• Question 1 of 10 1. Question Abhi and Dairya started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Dairya’s share is : A) 8400 B) 8200 C) 8100 D) 8000 Correct Answer: A) 8400 Explanation: Ratio of their shares = 22500 : 35000 = 9 : 14. Dairya’s share = Rs. (13800 14/23) = Rs. 8400. Incorrect Answer: A) 8400 Explanation: Ratio of their shares = 22500 : 35000 = 9 : 14. Dairya’s share = Rs. (13800 14/23) = Rs. 8400.

#### 1. Question

Abhi and Dairya started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Dairya’s share is :

Answer: A) 8400

Explanation:

Ratio of their shares = 22500 : 35000 = 9 : 14.

Dairya’s share = Rs. (13800 * 14/23) = Rs. 8400.

Answer: A) 8400

Explanation:

Ratio of their shares = 22500 : 35000 = 9 : 14.

Dairya’s share = Rs. (13800 * 14/23) = Rs. 8400.

• Question 2 of 10 2. Question How many of the following numbers are divisible by 132? 264,396,462,792,968,2178,5184,6336 A) 4 (b) 5 (c) 6 (d) 7 Correct Answer: A) 4 Explanation: 132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also. 264 => 4,3,11(/) 396 => 4,3,11(/) 462 => 11,3 792 => 4,3,11(/) 968 => 11,4 2178 => 11,3 5184 => 3,4 6336 => 4,3,11(/) Required number of numbers=4. Incorrect Answer: A) 4 Explanation: 132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also. 264 => 4,3,11(/) 396 => 4,3,11(/) 462 => 11,3 792 => 4,3,11(/) 968 => 11,4 2178 => 11,3 5184 => 3,4 6336 => 4,3,11(/) Required number of numbers=4.

#### 2. Question

How many of the following numbers are divisible by 132?

264,396,462,792,968,2178,5184,6336

Answer: A) 4

Explanation:

132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.

264 => 4,3,11(/)

396 => 4,3,11(/)

462 => 11,3

792 => 4,3,11(/)

968 => 11,4

2178 => 11,3

5184 => 3,4

6336 => 4,3,11(/)

Required number of numbers=4.

Answer: A) 4

Explanation:

132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.

264 => 4,3,11(/)

396 => 4,3,11(/)

462 => 11,3

792 => 4,3,11(/)

968 => 11,4

2178 => 11,3

5184 => 3,4

6336 => 4,3,11(/)

Required number of numbers=4.

• Question 3 of 10 3. Question The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: A. 279 B. 283 C. 308 D. 318 Correct Answer: Option C) Explanation: Other number =(11 x 7700)/ 275= 308. Incorrect Answer: Option C) Explanation: Other number =(11 x 7700)/ 275= 308.

#### 3. Question

The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

Answer: Option C)

Explanation:

Other number =(11 x 7700)/ 275= 308.

Answer: Option C)

Explanation:

Other number =(11 x 7700)/ 275= 308.

• Question 4 of 10 4. Question The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child? (a) 4 years (b) 8 years (c) 10 years (d) 12 years Correct Correct Answer: A) 4years Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years. Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 5x = 20 x = 4. Age of the youngest child = x = 4 years. Incorrect Correct Answer: A) 4years Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years. Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 5x = 20 x = 4. Age of the youngest child = x = 4 years.

#### 4. Question

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

• (a) 4 years

• (b) 8 years

• (c) 10 years

• (d) 12 years

Correct Answer: A) 4years

Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years. Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 5x = 20 x = 4. Age of the youngest child = x = 4 years.

Correct Answer: A) 4years

Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years. Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 5x = 20 x = 4. Age of the youngest child = x = 4 years.

• Question 5 of 10 5. Question A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B’s share? (a) Rs. 500 (b) Rs. 1500 (c) Rs. 2000 (d) None of these Correct Correct Answer: C) 2000rs Explanation: Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x – 3x = 1000 x = 1000. B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000. Incorrect Correct Answer: C) 2000rs Explanation: Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x – 3x = 1000 x = 1000. B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.

#### 5. Question

A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B’s share?

• (a) Rs. 500

• (b) Rs. 1500

• (c) Rs. 2000

• (d) None of these

Correct Answer: C) 2000rs

Explanation: Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x – 3x = 1000 x = 1000. B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.

Correct Answer: C) 2000rs

Explanation: Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x – 3x = 1000 x = 1000. B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.

• Question 6 of 10 6. Question The average weight of 12 sailors in a boat decreases by 2kg when one of the sailors who weighs 80kgs is replaced by a new sailor. What is the weight of the new sailor? A. 78kgs B. 58kgs C. 68kgs D. None of the above Correct Correct Answer : D) None of the above Answer Justification : Due to the replacement of a sailor weighing 80kgs, the change in the average weight is -2kgs. Since the number of sailors remain the same i.e. 12, The total change in the weight = 12 × -2 = -24kgs. This change has happened due to the replacement. Hence, the weight of new sailor = 80 – 24 = 56kgs. Incorrect Correct Answer : D) None of the above Answer Justification : Due to the replacement of a sailor weighing 80kgs, the change in the average weight is -2kgs. Since the number of sailors remain the same i.e. 12, The total change in the weight = 12 × -2 = -24kgs. This change has happened due to the replacement. Hence, the weight of new sailor = 80 – 24 = 56kgs.

#### 6. Question

The average weight of 12 sailors in a boat decreases by 2kg when one of the sailors who weighs 80kgs is replaced by a new sailor. What is the weight of the new sailor?

• D. None of the above

Correct Answer : D) None of the above

Answer Justification :

Due to the replacement of a sailor weighing 80kgs, the change in the average weight is -2kgs.

Since the number of sailors remain the same i.e. 12,

The total change in the weight = 12 × -2 = -24kgs.

This change has happened due to the replacement.

Hence, the weight of new sailor = 80 – 24 = 56kgs.

Correct Answer : D) None of the above

Answer Justification :

Due to the replacement of a sailor weighing 80kgs, the change in the average weight is -2kgs.

Since the number of sailors remain the same i.e. 12,

The total change in the weight = 12 × -2 = -24kgs.

This change has happened due to the replacement.

Hence, the weight of new sailor = 80 – 24 = 56kgs.

• Question 7 of 10 7. Question The difference between Compound Interest and Simple Interest on a certain sum of money at 10 % per annum for 3 years is Rs. 930. Find the principal if it is known that the interest is compounded annually. (a) 31000 (b) 30000 (c) 31500 (d) 32000 Correct Correct Answer: B) 30000 The Simple after three years for 10% is 30%. The Compound Interest after three years for 10% is 1.11.11.1=1.331 Cumulative rate of compound interest = 33.1% Difference between SI and CI= 3.1% Principal = 930100/3.1= 30000 Incorrect Correct Answer: B) 30000 The Simple after three years for 10% is 30%. The Compound Interest after three years for 10% is 1.11.11.1=1.331 Cumulative rate of compound interest = 33.1% Difference between SI and CI= 3.1% Principal = 930100/3.1= 30000

#### 7. Question

The difference between Compound Interest and Simple Interest on a certain sum of money at 10 % per annum for 3 years is Rs. 930. Find the principal if it is known that the interest is compounded annually.

Correct Answer: B) 30000

The Simple after three years for 10% is 30%.

The Compound Interest after three years for 10% is 1.11.11.1=1.331

Cumulative rate of compound interest = 33.1%

Difference between SI and CI= 3.1%

Principal = 930*100/3.1= 30000

Correct Answer: B) 30000

The Simple after three years for 10% is 30%.

The Compound Interest after three years for 10% is 1.11.11.1=1.331

Cumulative rate of compound interest = 33.1%

Difference between SI and CI= 3.1%

Principal = 930*100/3.1= 30000

• Question 8 of 10 8. Question Kalmesh, Pragathi and Tabhu started a business by investing Rs X, Rs (X+400) and Rs (X-200). If after the end of year, total share of profit of Kalmesh and Tabhu is Rs 8100 out of a total profit of Rs 13,500, find the profit share of Pragathi. (a) Rs 6100 (b) Rs 5400 (c) Rs 5100 (d) Rs 6600 Correct Correct Answer: B) 5400rs Kalmesh : Pragathi : Tabhu X : (X+400) : (X-200) So (X+X-200)/(X + X+400 + X-200) 13500 = 8100 Solve, X = 1600 So ratio of profit share is 1600 : 2000 : 1400 = 8 : 10 : 7 So profit share of Pragathi = 10/25 13500 = Rs 5400. Incorrect Correct Answer: B) 5400rs Kalmesh : Pragathi : Tabhu X : (X+400) : (X-200) So (X+X-200)/(X + X+400 + X-200) 13500 = 8100 Solve, X = 1600 So ratio of profit share is 1600 : 2000 : 1400 = 8 : 10 : 7 So profit share of Pragathi = 10/25 13500 = Rs 5400.

#### 8. Question

Kalmesh, Pragathi and Tabhu started a business by investing Rs X, Rs (X+400) and Rs (X-200). If after the end of year, total share of profit of Kalmesh and Tabhu is Rs 8100 out of a total profit of Rs 13,500, find the profit share of Pragathi.

• (a) Rs 6100

• (b) Rs 5400

• (c) Rs 5100

• (d) Rs 6600

Correct Answer: B) 5400rs

Kalmesh : Pragathi : Tabhu

X : (X+400) : (X-200)

So (X+X-200)/(X + X+400 + X-200) * 13500 = 8100

Solve, X = 1600

So ratio of profit share is

1600 : 2000 : 1400 = 8 : 10 : 7

So profit share of Pragathi = 10/25 * 13500 = Rs 5400.

Correct Answer: B) 5400rs

Kalmesh : Pragathi : Tabhu

X : (X+400) : (X-200)

So (X+X-200)/(X + X+400 + X-200) * 13500 = 8100

Solve, X = 1600

So ratio of profit share is

1600 : 2000 : 1400 = 8 : 10 : 7

So profit share of Pragathi = 10/25 * 13500 = Rs 5400.

• Question 9 of 10 9. Question A bell rings every 18 minutes. A second bell rings every 24 minutes. A third bell rings every 32 minutes. If all the three bells ring at the same time at 8 o’clock in the morning, at what other time will they all ring together? (a) 12 : 40 hrs (b) 12 : 48 hrs (c) 12 : 56 hrs (d) 13 : 04 hrs Correct Correct Answer: B) 12:48 hrs Take the LCM of 18, 24 and 32 which comes out to be 288 minutes i.e. 4 hours and 48 minutes. Add to 8’o clock. The time is 12:48 hours. Incorrect Correct Answer: B) 12:48 hrs Take the LCM of 18, 24 and 32 which comes out to be 288 minutes i.e. 4 hours and 48 minutes. Add to 8’o clock. The time is 12:48 hours.

#### 9. Question

A bell rings every 18 minutes. A second bell rings every 24 minutes. A third bell rings every 32 minutes. If all the three bells ring at the same time at 8 o’clock in the morning, at what other time will they all ring together?

• (a) 12 : 40 hrs

• (b) 12 : 48 hrs

• (c) 12 : 56 hrs

• (d) 13 : 04 hrs

Correct Answer: B) 12:48 hrs

Take the LCM of 18, 24 and 32 which comes out to be 288 minutes i.e. 4 hours and 48 minutes. Add to 8’o clock. The time is 12:48 hours.

Correct Answer: B) 12:48 hrs

Take the LCM of 18, 24 and 32 which comes out to be 288 minutes i.e. 4 hours and 48 minutes. Add to 8’o clock. The time is 12:48 hours.

• Question 10 of 10 10. Question There are four routes to travel from city A to city B and six routes from city B to city C. How many routes are possible to travel from the city A to city C? (a) 24 (a) 24 (c) 10 (d) 8 Correct Correct Answer: A) 24 For every one route, you will have six routes to take. So, total number of routes is 6 X 4 = 24. Incorrect Correct Answer: A) 24 For every one route, you will have six routes to take. So, total number of routes is 6 X 4 = 24.

#### 10. Question

There are four routes to travel from city A to city B and six routes from city B to city C. How many routes are possible to travel from the city A to city C?

Correct Answer: A) 24

For every one route, you will have six routes to take. So, total number of routes is 6 X 4 = 24.

Correct Answer: A) 24

For every one route, you will have six routes to take. So, total number of routes is 6 X 4 = 24.

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