[Mission 2024] Insta–DART (Daily Aptitude and Reasoning Test) 20- 21 March 2024
Kartavya Desk Staff
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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• Question 1 of 10 1. Question A vendor sells 50 percent of apples he had and throws away 20 percent of the remainder. Next day he sells 60 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw? (a) 20% (b) 22% (c) 24% (d) 26% Correct Correct Answer: D) 26% Explanation: Let total apples be 100 first day he throws = 5020/100 = 10 apples next day he throws = 4040/100 = 16 apples so total = 26 Incorrect Correct Answer: D) 26% Explanation: Let total apples be 100 first day he throws = 5020/100 = 10 apples next day he throws = 4040/100 = 16 apples so total = 26
#### 1. Question
A vendor sells 50 percent of apples he had and throws away 20 percent of the remainder. Next day he sells 60 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?
Correct Answer: D) 26%
Explanation:
Let total apples be 100
first day he throws = 50*20/100 = 10 apples
next day he throws = 40*40/100 = 16 apples
so total = 26
Correct Answer: D) 26%
Explanation:
Let total apples be 100
first day he throws = 50*20/100 = 10 apples
next day he throws = 40*40/100 = 16 apples
so total = 26
• Question 2 of 10 2. Question The price of rice is increased by 20 percent and a person decrease his consumption by 15 percent, so his expenditure on rice – (a) increase by 2 percent (b) increase by 4 percent (c) decrease by 2 percent (d) decrease by 4 percent Correct Correct Answer: A) increase by 2 percent Explanation: Let initial price of rice – 100 and new price of rice – 120 Suppose initial consumption is 100kg and new consumption is 85kg Initial expenditure = 10000 New expenditure = 10200 (200/10000)100 = 2 percent increase. Incorrect Correct Answer: A) increase by 2 percent Explanation: Let initial price of rice – 100 and new price of rice – 120 Suppose initial consumption is 100kg and new consumption is 85kg Initial expenditure = 10000 New expenditure = 10200 (200/10000)100 = 2 percent increase.
#### 2. Question
The price of rice is increased by 20 percent and a person decrease his consumption by 15 percent, so his expenditure on rice –
• (a) increase by 2 percent
• (b) increase by 4 percent
• (c) decrease by 2 percent
• (d) decrease by 4 percent
Correct Answer: A) increase by 2 percent
Explanation:
Let initial price of rice – 100 and new price of rice – 120
Suppose initial consumption is 100kg and new consumption is 85kg
Initial expenditure = 10000
New expenditure = 10200 (200/10000)*100 = 2 percent increase.
Correct Answer: A) increase by 2 percent
Explanation:
Let initial price of rice – 100 and new price of rice – 120
Suppose initial consumption is 100kg and new consumption is 85kg
Initial expenditure = 10000
New expenditure = 10200 (200/10000)*100 = 2 percent increase.
• Question 3 of 10 3. Question 40% of the students like Mathematics, 50% like English and 10% like both Mathematics and English. What % of the students like neither English nor Mathematics? (a) 25% (b) 10% (c) 20% (d) 60% Correct Correct Answer: C) 20% Explanation: n(M or E) = n(M) + n(E) – n(M and E) n(M or E) = 40+50-10 = 80 so % of the students who like neither English nor Mathematics = 100 – 80 = 20% Incorrect Correct Answer: C) 20% Explanation: n(M or E) = n(M) + n(E) – n(M and E) n(M or E) = 40+50-10 = 80 so % of the students who like neither English nor Mathematics = 100 – 80 = 20%
#### 3. Question
40% of the students like Mathematics, 50% like English and 10% like both Mathematics and English. What % of the students like neither English nor Mathematics?
Correct Answer: C) 20%
Explanation:
n(M or E) = n(M) + n(E) – n(M and E)
n(M or E) = 40+50-10 = 80
so % of the students who like neither English nor Mathematics
= 100 – 80 = 20%
Correct Answer: C) 20%
Explanation:
n(M or E) = n(M) + n(E) – n(M and E)
n(M or E) = 40+50-10 = 80
so % of the students who like neither English nor Mathematics
= 100 – 80 = 20%
• Question 4 of 10 4. Question The average price of 80 laptops is Rs.30000. If the highest and lowest price laptops are sold out then the average price of remaining 78 laptops is Rs.29500. The cost of the highest price laptop is Rs.80000. The cost of lowest price laptop is: A. Rs.19000 B. Rs.20000 C. Rs.29000 D. Can’t be determined Correct Correct Answer : A) 19000rs Justification: The total price 80 laptops = 80 × Rs.30000 = Rs.2400000 The total price of remaining 78 laptops = 78 × Rs.29500 = Rs.2301000 The sum of prices of the costliest laptop and cheapest laptop = 2400000 – 2301000 = Rs.99000 The price of the cheapest laptop = Rs.99000 – Price of costliest laptop 99000 – Rs.80000 19000 Incorrect Correct Answer : A) 19000rs Justification: The total price 80 laptops = 80 × Rs.30000 = Rs.2400000 The total price of remaining 78 laptops = 78 × Rs.29500 = Rs.2301000 The sum of prices of the costliest laptop and cheapest laptop = 2400000 – 2301000 = Rs.99000 The price of the cheapest laptop = Rs.99000 – Price of costliest laptop 99000 – Rs.80000 19000
#### 4. Question
The average price of 80 laptops is Rs.30000. If the highest and lowest price laptops are sold out then the average price of remaining 78 laptops is Rs.29500. The cost of the highest price laptop is Rs.80000. The cost of lowest price laptop is:
• A. Rs.19000
• B. Rs.20000
• C. Rs.29000
• D. Can’t be determined
Correct Answer : A) 19000rs
Justification:
The total price 80 laptops = 80 × Rs.30000 = Rs.2400000
The total price of remaining 78 laptops = 78 × Rs.29500 = Rs.2301000
The sum of prices of the costliest laptop and cheapest laptop = 2400000 – 2301000 = Rs.99000
The price of the cheapest laptop = Rs.99000 – Price of costliest laptop
• 99000 – Rs.80000
Correct Answer : A) 19000rs
Justification:
The total price 80 laptops = 80 × Rs.30000 = Rs.2400000
The total price of remaining 78 laptops = 78 × Rs.29500 = Rs.2301000
The sum of prices of the costliest laptop and cheapest laptop = 2400000 – 2301000 = Rs.99000
The price of the cheapest laptop = Rs.99000 – Price of costliest laptop
• 99000 – Rs.80000
• Question 5 of 10 5. Question The age of B is 50% greater than the age of A. The age of C is 20% less than the age of B. By how much percentage the age of C is greater than the age of A. A. 30% B. 25% C. 20% D. 15% Correct Correct Answer : C) 20% Justification: Let the age of A be 100 years. Age of B =50 years. The age of C is 20% less than the age of B. The age of C is 80% of the age of B. The age of C is 80% of 150 years. Age of C = 120 years. Age of C is 20 years greater than that of A. Thus, age of C is 20% greater than that of A. Incorrect Correct Answer : C) 20% Justification: Let the age of A be 100 years. Age of B =50 years. The age of C is 20% less than the age of B. The age of C is 80% of the age of B. The age of C is 80% of 150 years. Age of C = 120 years. Age of C is 20 years greater than that of A. Thus, age of C is 20% greater than that of A.
#### 5. Question
The age of B is 50% greater than the age of A. The age of C is 20% less than the age of B. By how much percentage the age of C is greater than the age of A.
Correct Answer : C) 20%
Justification:
Let the age of A be 100 years.
Age of B =50 years.
The age of C is 20% less than the age of B.
The age of C is 80% of the age of B.
The age of C is 80% of 150 years.
Age of C = 120 years.
Age of C is 20 years greater than that of A.
Thus, age of C is 20% greater than that of A.
Correct Answer : C) 20%
Justification:
Let the age of A be 100 years.
Age of B =50 years.
The age of C is 20% less than the age of B.
The age of C is 80% of the age of B.
The age of C is 80% of 150 years.
Age of C = 120 years.
Age of C is 20 years greater than that of A.
Thus, age of C is 20% greater than that of A.
• Question 6 of 10 6. Question Each edge of a cube is increased by 20% then the percentage increase in surface area of the cube is: A. 144% B. 40% C. 44% D. 72.8% Correct Correct Answer : C) 44% Justification: Let each edge of a cube be ‘a’ units The new length = 1.2a units Initial surface area = 6a2 sq. units New surface area = 6 (1.2a)2 = 6 (1.44) a2 = 1.44 (6a2) sq. units = .44 (Initial surface area) % increase in the surface area = 44% Incorrect Correct Answer : C) 44% Justification: Let each edge of a cube be ‘a’ units The new length = 1.2a units Initial surface area = 6a2 sq. units New surface area = 6 (1.2a)2 = 6 (1.44) a2 = 1.44 (6a2) sq. units = .44 (Initial surface area) % increase in the surface area = 44%
#### 6. Question
Each edge of a cube is increased by 20% then the percentage increase in surface area of the cube is:
Correct Answer : C) 44%
Justification:
Let each edge of a cube be ‘a’ units
The new length = 1.2a units
Initial surface area = 6a2 sq. units
New surface area = 6 (1.2a)2 = 6 (1.44) a2 = 1.44 (6a2) sq. units = .44 (Initial surface area)
% increase in the surface area = 44%
Correct Answer : C) 44%
Justification:
Let each edge of a cube be ‘a’ units
The new length = 1.2a units
Initial surface area = 6a2 sq. units
New surface area = 6 (1.2a)2 = 6 (1.44) a2 = 1.44 (6a2) sq. units = .44 (Initial surface area)
% increase in the surface area = 44%
• Question 7 of 10 7. Question Varuna had to do a multiplication. Instead of taking 35 as one of the multipliers, she took 53. As a result, the product went up by 540. What is the new product? A.1050 B.540 C.1440 D.1590 Correct Answer D) 1590 Solution: Let us assume that the number with which Varuna has to perform the multiplication is ‘x’. Instead of finding 35x, she calculated 53x. The difference = 53x – 35x = 18x = 540 Therefore, x = 540/18 = 30 So, the new product = 30 x 53 = 1590. Incorrect Answer D) 1590 Solution: Let us assume that the number with which Varuna has to perform the multiplication is ‘x’. Instead of finding 35x, she calculated 53x. The difference = 53x – 35x = 18x = 540 Therefore, x = 540/18 = 30 So, the new product = 30 x 53 = 1590.
#### 7. Question
Varuna had to do a multiplication. Instead of taking 35 as one of the multipliers, she took 53. As a result, the product went up by 540. What is the new product?
Answer D) 1590
Let us assume that the number with which Varuna has to perform the multiplication is ‘x’.
Instead of finding 35x, she calculated 53x.
The difference = 53x – 35x = 18x = 540
Therefore, x = 540/18 = 30
So, the new product = 30 x 53 = 1590.
Answer D) 1590
Let us assume that the number with which Varuna has to perform the multiplication is ‘x’.
Instead of finding 35x, she calculated 53x.
The difference = 53x – 35x = 18x = 540
Therefore, x = 540/18 = 30
So, the new product = 30 x 53 = 1590.
• Question 8 of 10 8. Question All the page numbers from a book are added, beginning at page 1. However, one page number was added twice by mistake. The sum obtained was 1000. Which page number was added twice? A.44 B.45 C.10 D.12 Correct Answer c) 10 Solution: If the number of pages is 44, the sum will be 4445/2 = 2245 = 990 So, the number 10 was added twice. Incorrect Answer c) 10 Solution: If the number of pages is 44, the sum will be 4445/2 = 2245 = 990 So, the number 10 was added twice.
#### 8. Question
All the page numbers from a book are added, beginning at page 1. However, one page number was added twice by mistake. The sum obtained was 1000. Which page number was added twice?
Answer c) 10
If the number of pages is 44, the sum will be 4445/2 = 2245 = 990
So, the number 10 was added twice.
Answer c) 10
If the number of pages is 44, the sum will be 4445/2 = 2245 = 990
So, the number 10 was added twice.
• Question 9 of 10 9. Question An accurate clock shows 8 o’clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o’clock in the afternoon? A.154° B.180° C.170° D.160° Correct Answer B) 1800 Solution: We know that angle traced by hour hand in 12 hrs = 360° From 8 to 2, there are 6 hours. Angle traced by the hour hand in 6 hours = 6x(360/12)=1800 Incorrect Answer B) 1800 Solution: We know that angle traced by hour hand in 12 hrs = 360° From 8 to 2, there are 6 hours. Angle traced by the hour hand in 6 hours = 6x(360/12)=1800
#### 9. Question
An accurate clock shows 8 o’clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o’clock in the afternoon?
Answer B) 1800
We know that angle traced by hour hand in 12 hrs = 360°
From 8 to 2, there are 6 hours.
Angle traced by the hour hand in 6 hours = 6x(360/12)=1800
Answer B) 1800
We know that angle traced by hour hand in 12 hrs = 360°
From 8 to 2, there are 6 hours.
Angle traced by the hour hand in 6 hours = 6x(360/12)=1800
• Question 10 of 10 10. Question Abhi and Dairya started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Dairya’s share is : A) 8400 B) 8200 C) 8100 D) 8000 Correct Answer: A) 8400 Explanation: Ratio of their shares = 22500 : 35000 = 9 : 14. Dairya’s share = Rs. (13800 14/23) = Rs. 8400. Incorrect Answer: A) 8400 Explanation: Ratio of their shares = 22500 : 35000 = 9 : 14. Dairya’s share = Rs. (13800 14/23) = Rs. 8400.
#### 10. Question
Abhi and Dairya started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Dairya’s share is :
Answer: A) 8400
Explanation:
Ratio of their shares = 22500 : 35000 = 9 : 14.
Dairya’s share = Rs. (13800 * 14/23) = Rs. 8400.
Answer: A) 8400
Explanation:
Ratio of their shares = 22500 : 35000 = 9 : 14.
Dairya’s share = Rs. (13800 * 14/23) = Rs. 8400.
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