[Mission 2024] Insta–DART (Daily Aptitude and Reasoning Test) 18 April 2024

#### Quiz-summary

0 of 5 questions completed

Questions:

#### Information

Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

0 of 5 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

#### Categories

• Not categorized 0%

• Question 1 of 5 1. Question The average age of 60 students is 20 years. When 15 new students are admitted, the average increases by 0.4 years. What must be the average age of the new students? (a) 22 years (b) 23 years (c) 24 years (d) None of these Correct Solution: A) 22 years Let the average age of the newly admitted 15 students be x years. Therefore, total age of 15 newly admitted students = 15x Since given average age of existing 60 students = 20 Therefore, total age of the existing 60 students = 60×20 Hence, total age of the 75 students = 60×20 + 15x Since average after admission of new students increases by 0.4 years. So new average = 20.4 years è 60×20 + 15x =75×20.4 è 1200 + 15x = 1530 è 15x = 1530-1200 è 15x = 330 è x = 330/15 è x = 22 years Hence, option (a) is correct. Incorrect Solution: A) 22 years Let the average age of the newly admitted 15 students be x years. Therefore, total age of 15 newly admitted students = 15x Since given average age of existing 60 students = 20 Therefore, total age of the existing 60 students = 60×20 Hence, total age of the 75 students = 60×20 + 15x Since average after admission of new students increases by 0.4 years. So new average = 20.4 years è 60×20 + 15x =75×20.4 è 1200 + 15x = 1530 è 15x = 1530-1200 è 15x = 330 è x = 330/15 è x = 22 years Hence, option (a) is correct.

#### 1. Question

The average age of 60 students is 20 years. When 15 new students are admitted, the average increases by 0.4 years. What must be the average age of the new students?

• (a) 22 years

• (b) 23 years

• (c) 24 years

• (d) None of these

Solution: A) 22 years

Let the average age of the newly admitted 15 students be x years. Therefore, total age of 15 newly admitted students = 15x Since given average age of existing 60 students = 20 Therefore, total age of the existing 60 students = 60×20 Hence, total age of the 75 students = 60×20 + 15x Since average after admission of new students increases by 0.4 years.

So new average = 20.4 years

è 60×20 + 15x =75×20.4 è 1200 + 15x = 1530 è 15x = 1530-1200 è 15x = 330 è x = 330/15 è x = 22 years

Hence, option (a) is correct.

Solution: A) 22 years

So new average = 20.4 years

è 60×20 + 15x =75×20.4 è 1200 + 15x = 1530 è 15x = 1530-1200 è 15x = 330 è x = 330/15 è x = 22 years

Hence, option (a) is correct.

• Question 2 of 5 2. Question In a group of 1500 people, 700 can speak Hindi, 500 can speak English and 150 can speak both. Find the number of people who can speak at most one language? (a) 1250 (b) 600 (c) 1350 (d) 1050 Correct Solution: C) 1350 The number of people who can speak at most one language = Total number of people – Number of people who can speak both the languages è 1500 – 150 = 1350 Hence, option (c) is correct. Incorrect Solution: C) 1350 The number of people who can speak at most one language = Total number of people – Number of people who can speak both the languages è 1500 – 150 = 1350 Hence, option (c) is correct.

#### 2. Question

In a group of 1500 people, 700 can speak Hindi, 500 can speak English and 150 can speak both. Find the number of people who can speak at most one language?

Solution: C) 1350

The number of people who can speak at most one language = Total number of people – Number of people who can speak both the languages è 1500 – 150 = 1350

Hence, option (c) is correct.

Solution: C) 1350

The number of people who can speak at most one language = Total number of people – Number of people who can speak both the languages è 1500 – 150 = 1350

Hence, option (c) is correct.

• Question 3 of 5 3. Question If an amount doubles itself in 5 years, then in how many years will it be 8 times of the original amount, if it grows with an interest rate compounded annually? (a) 20 years (b) 15 years (c) 25 years d) 12 years Correct Solution: B) 15 years Let the initial amount be x. In 5 years the amount gets doubled, i.e. total amount=2x In the next 5 years, i.e 10 years amount gets doubled again, i.e. total amount=4x Similarly, in the next 5 years, i.e 15 years the total amount= 2 × 4x = 8x. Hence, option (b) is correct. Incorrect Solution: B) 15 years Let the initial amount be x. In 5 years the amount gets doubled, i.e. total amount=2x In the next 5 years, i.e 10 years amount gets doubled again, i.e. total amount=4x Similarly, in the next 5 years, i.e 15 years the total amount= 2 × 4x = 8x. Hence, option (b) is correct.

#### 3. Question

If an amount doubles itself in 5 years, then in how many years will it be 8 times of the original amount, if it grows with an interest rate compounded annually?

• (a) 20 years

• (b) 15 years

• (c) 25 years

• d) 12 years

Solution: B) 15 years

Let the initial amount be x.

In 5 years the amount gets doubled, i.e. total amount=2x In the next 5 years, i.e 10 years amount gets doubled again, i.e. total amount=4x Similarly, in the next 5 years, i.e 15 years the total amount= 2 × 4x = 8x.

Hence, option (b) is correct.

Solution: B) 15 years

Let the initial amount be x.

Hence, option (b) is correct.

• Question 4 of 5 4. Question In an examination if total boys and total girls appear in the ratio 11:13, then which of the following can be the total number of students appearing in the examination? (a) 246 (b) 171 (c) 240 (d) 101 Correct Solution: C) 240 Let the total number of boys be 11x and total number of girls be 13x. Therefore, total students will be 24x. Therefore, total number of students appearing in the examination must be a multiple of 24. Looking at the options, option (b) and option (d) can be directly eliminated as they are odd numbers. By looking at remaining options, it can be clearly seen that 240 is completely divisible by 24. Hence, option (c) is correct. Incorrect Solution: C) 240 Let the total number of boys be 11x and total number of girls be 13x. Therefore, total students will be 24x. Therefore, total number of students appearing in the examination must be a multiple of 24. Looking at the options, option (b) and option (d) can be directly eliminated as they are odd numbers. By looking at remaining options, it can be clearly seen that 240 is completely divisible by 24. Hence, option (c) is correct.

#### 4. Question

In an examination if total boys and total girls appear in the ratio 11:13, then which of the following can be the total number of students appearing in the examination?

Solution: C) 240

Let the total number of boys be 11x and total number of girls be 13x.

Therefore, total students will be 24x.

Therefore, total number of students appearing in the examination must be a multiple of 24.

Looking at the options, option (b) and option (d) can be directly eliminated as they are odd numbers.

By looking at remaining options, it can be clearly seen that 240 is completely divisible by 24.

Hence, option (c) is correct.

Solution: C) 240

Let the total number of boys be 11x and total number of girls be 13x.

Therefore, total students will be 24x.

Therefore, total number of students appearing in the examination must be a multiple of 24.

Looking at the options, option (b) and option (d) can be directly eliminated as they are odd numbers.

By looking at remaining options, it can be clearly seen that 240 is completely divisible by 24.

Hence, option (c) is correct.

• Question 5 of 5 5. Question P scored more than R, Y scored as much as D. L scored less than M. R scored more than Y. M scored less than D. Who scored the lowest? a) M b) Y c) L d) R Correct Solution: c) L Justification: P scored more than R: P>R Y scored as much as D: Y=D L scored less than M: M>L R scored more than Y: R>Y M scored less than D: D>M Final arrangement: P>R>Y=D>M>L Hence, L scored the lowest. Incorrect Solution: c) L Justification: P scored more than R: P>R Y scored as much as D: Y=D L scored less than M: M>L R scored more than Y: R>Y M scored less than D: D>M Final arrangement: P>R>Y=D>M>L Hence, L scored the lowest.

#### 5. Question

P scored more than R, Y scored as much as D. L scored less than M. R scored more than Y. M scored less than D. Who scored the lowest?

Solution: c) L

Justification:

P scored more than R: P>R

Y scored as much as D: Y=D

L scored less than M: M>L

R scored more than Y: R>Y

M scored less than D: D>M

Final arrangement: P>R>Y=D>M>L

Hence, L scored the lowest.

Solution: c) L

Justification:

P scored more than R: P>R

Y scored as much as D: Y=D

L scored less than M: M>L

R scored more than Y: R>Y

M scored less than D: D>M

Final arrangement: P>R>Y=D>M>L

Hence, L scored the lowest.

• Official Facebook Page HERE

• Follow our Twitter Account HERE