[Mission 2024] Insta–DART (Daily Aptitude and Reasoning Test) 13 May 2024
Kartavya Desk Staff
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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• Question 1 of 5 1. Question If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 32 minutes, then the slower pipe alone will be able to fill the tank in? (a) 128 minutes (b) 124 minutes (c) 154 minutes (d) 168 minutes Correct Solution: A) 128minutes Let, the time is taken by pipe A = x Then, time is taken by pipe B = x/3 By substituting these values, we get: 1/x + 3/x = 1/32 x = 128 minutes Hence, option (a) is correct. Incorrect Solution: A) 128minutes Let, the time is taken by pipe A = x Then, time is taken by pipe B = x/3 By substituting these values, we get: 1/x + 3/x = 1/32 x = 128 minutes Hence, option (a) is correct.
#### 1. Question
If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 32 minutes, then the slower pipe alone will be able to fill the tank in?
• (a) 128 minutes
• (b) 124 minutes
• (c) 154 minutes
• (d) 168 minutes
Solution: A) 128minutes
Let, the time is taken by pipe A = x Then, time is taken by pipe B = x/3
By substituting these values, we get: 1/x + 3/x = 1/32 x = 128 minutes
Hence, option (a) is correct.
Solution: A) 128minutes
Let, the time is taken by pipe A = x Then, time is taken by pipe B = x/3
By substituting these values, we get: 1/x + 3/x = 1/32 x = 128 minutes
Hence, option (a) is correct.
• Question 2 of 5 2. Question Rs.1200 divided among A, B and C. A gets half of the total amount received by B and C. B gets one-third of the total amount received by A and C. Find the amount received by C ? A) Rs. 1100 B) Rs. 500 C) Rs. 1200 D) Rs. 700 Correct Answer : B) Rs. 500 Explanation: Let the amounts to be received by A, B and C be p, q and r. p + q + r = 1200 p = 1/2 (q + r) => 2p = q + r Adding ‘p’ both sides, 3p = p + q + r = 1200 => p = Rs.400 q = 1/3 (p + r) => 3q = p + r Adding ‘q’ both sides, 4q = p + q + r = 1200 => q = Rs.300 r = 1200 – (p + q) => r = Rs.500. Incorrect Answer : B) Rs. 500 Explanation: Let the amounts to be received by A, B and C be p, q and r. p + q + r = 1200 p = 1/2 (q + r) => 2p = q + r Adding ‘p’ both sides, 3p = p + q + r = 1200 => p = Rs.400 q = 1/3 (p + r) => 3q = p + r Adding ‘q’ both sides, 4q = p + q + r = 1200 => q = Rs.300 r = 1200 – (p + q) => r = Rs.500.
#### 2. Question
Rs.1200 divided among A, B and C. A gets half of the total amount received by B and C. B gets one-third of the total amount received by A and C. Find the amount received by C ?
• A) Rs. 1100
• B) Rs. 500
• C) Rs. 1200
• D) Rs. 700
Answer : B) Rs. 500
Explanation:
Let the amounts to be received by A, B and C be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding ‘p’ both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding ‘q’ both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 – (p + q) => r = Rs.500.
Answer : B) Rs. 500
Explanation:
Let the amounts to be received by A, B and C be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding ‘p’ both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding ‘q’ both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 – (p + q) => r = Rs.500.
• Question 3 of 5 3. Question A man invests Rs.5000 for 3 years at 5% p.a. compound interest reckoned yearly. Income tax at the rate of 20% on the interest earned is deducted at the end of each year. Find the amount at the end of the third year A) Rs.5624.32 B) Rs.5423 C) Rs.5634 D) Rs.5976 Correct Answer : A) Rs.5624.32 Explanation: 5% is the rate of interest. 20% of the interest amount is paid as tax. i.e 80% of the interest amount stays back. if we compute the rate of interest as 80% of 5% = 4% p.a., we will get the same value. The interest accrued for 3 years in compound interest = 3 x simple interest on principal + 3 x interest on simple interest + 1 x interest on interest on interest. = 3 x (200) + 3 x (8) + 1 x 0.32 =600 + 24 + 0.32 = 624.32 The amount at the end of 3 years = 5000 + 624.32 = 5624.32 Incorrect Answer : A) Rs.5624.32 Explanation: 5% is the rate of interest. 20% of the interest amount is paid as tax. i.e 80% of the interest amount stays back. if we compute the rate of interest as 80% of 5% = 4% p.a., we will get the same value. The interest accrued for 3 years in compound interest = 3 x simple interest on principal + 3 x interest on simple interest + 1 x interest on interest on interest. = 3 x (200) + 3 x (8) + 1 x 0.32 =600 + 24 + 0.32 = 624.32 The amount at the end of 3 years = 5000 + 624.32 = 5624.32
#### 3. Question
A man invests Rs.5000 for 3 years at 5% p.a. compound interest reckoned yearly. Income tax at the rate of 20% on the interest earned is deducted at the end of each year. Find the amount at the end of the third year
• A) Rs.5624.32
• B) Rs.5423
• C) Rs.5634
• D) Rs.5976
Answer : A) Rs.5624.32
Explanation:
5% is the rate of interest. 20% of the interest amount is paid as tax.
i.e 80% of the interest amount stays back.
if we compute the rate of interest as 80% of 5% = 4% p.a., we will get the same value.
The interest accrued for 3 years in compound interest = 3 x simple interest on principal + 3 x interest on simple interest + 1 x interest on interest on interest.
= 3 x (200) + 3 x (8) + 1 x 0.32 =600 + 24 + 0.32 = 624.32
The amount at the end of 3 years = 5000 + 624.32 = 5624.32
Answer : A) Rs.5624.32
Explanation:
5% is the rate of interest. 20% of the interest amount is paid as tax.
i.e 80% of the interest amount stays back.
if we compute the rate of interest as 80% of 5% = 4% p.a., we will get the same value.
The interest accrued for 3 years in compound interest = 3 x simple interest on principal + 3 x interest on simple interest + 1 x interest on interest on interest.
= 3 x (200) + 3 x (8) + 1 x 0.32 =600 + 24 + 0.32 = 624.32
The amount at the end of 3 years = 5000 + 624.32 = 5624.32
• Question 4 of 5 4. Question The largest measuring cylinder that can accurately fill 3 tanks of capacity 98, 182 and 266 litres each, is of capacity? A) 7 litres B) 14 litres C) 98 litres D) 42 litres Correct Answer: B) 14 litres Explanation: To know the measuring cylinder that can fill all the given capacities , they must be divisible by the required number. 98,182,266 all are divisible by 14 So 14 litres is the largest cylinder that can fill all the given cylinders. (or) The other method is take HCF of all given capacities i.e 98, 182 and 266. Incorrect Answer: B) 14 litres Explanation: To know the measuring cylinder that can fill all the given capacities , they must be divisible by the required number. 98,182,266 all are divisible by 14 So 14 litres is the largest cylinder that can fill all the given cylinders. (or) The other method is take HCF of all given capacities i.e 98, 182 and 266.
#### 4. Question
The largest measuring cylinder that can accurately fill 3 tanks of capacity 98, 182 and 266 litres each, is of capacity?
• A) 7 litres
• B) 14 litres
• C) 98 litres
• D) 42 litres
Answer: B) 14 litres
Explanation:
To know the measuring cylinder that can fill all the given capacities , they must be divisible by the required number.
98,182,266 all are divisible by 14
So 14 litres is the largest cylinder that can fill all the given cylinders.
The other method is take HCF of all given capacities i.e 98, 182 and 266.
Answer: B) 14 litres
Explanation:
To know the measuring cylinder that can fill all the given capacities , they must be divisible by the required number.
98,182,266 all are divisible by 14
So 14 litres is the largest cylinder that can fill all the given cylinders.
The other method is take HCF of all given capacities i.e 98, 182 and 266.
• Question 5 of 5 5. Question Dharam has scored 33.33% more runs than Karthik has. By how much percent less than Dharam has Karthik scored? A. 50% B. 33.33% C. 25% D. 66.66% Correct Correct Answer : C) 25% Answer Justification : Justification: Let the score of Karthik be 100. Then score of Dharam = 133.33 = 400/3 Karthik has scored ((400/3) – 100) less than that of Dharam. i.e. Karthik has scored 100/3 less than that of Dharam. By fraction; Karthik has scored (100/3)/(400/3) less than that of Dharam. Karthik has scored 1/4 less than that of Dharam. By Percentage: Karthik has scored 25% less than that of Dharam. Incorrect Correct Answer : C) 25% Answer Justification : Justification: Let the score of Karthik be 100. Then score of Dharam = 133.33 = 400/3 Karthik has scored ((400/3) – 100) less than that of Dharam. i.e. Karthik has scored 100/3 less than that of Dharam. By fraction; Karthik has scored (100/3)/(400/3) less than that of Dharam. Karthik has scored 1/4 less than that of Dharam. By Percentage: Karthik has scored 25% less than that of Dharam.
#### 5. Question
Dharam has scored 33.33% more runs than Karthik has. By how much percent less than Dharam has Karthik scored?
Correct Answer : C) 25%
Answer Justification :
Justification:
Let the score of Karthik be 100.
Then score of Dharam = 133.33 = 400/3
Karthik has scored ((400/3) – 100) less than that of Dharam.
i.e. Karthik has scored 100/3 less than that of Dharam.
By fraction; Karthik has scored (100/3)/(400/3) less than that of Dharam.
Karthik has scored 1/4 less than that of Dharam.
By Percentage: Karthik has scored 25% less than that of Dharam.
Correct Answer : C) 25%
Answer Justification :
Justification:
Let the score of Karthik be 100.
Then score of Dharam = 133.33 = 400/3
Karthik has scored ((400/3) – 100) less than that of Dharam.
i.e. Karthik has scored 100/3 less than that of Dharam.
By fraction; Karthik has scored (100/3)/(400/3) less than that of Dharam.
Karthik has scored 1/4 less than that of Dharam.
By Percentage: Karthik has scored 25% less than that of Dharam.
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