[Mission 2024] Insta–DART (Daily Aptitude and Reasoning Test) 11 April 2024

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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• Question 1 of 5 1. Question Study the following information carefully and answer the questions given below: A, B, C, D, E, F, G and H are sitting around a circle facing the center. D is fourth to the right of H and second to the left of B. F is fourth to the right of B. C is fourth to the right of E, who is not an immediate neighbor of B or D. A is not an immediate neighbor of D. In which of the following combinations is the third person sitting in between the first and the second persons? a) ABC b) GCD c) AHE d) EFG Correct Solution: b) GCD Justification: Inference from statement 1: Clockwise: H _ B _ D Inference from statement 2: Clockwise: F _ H _ B _ D Inference from statement 3: Clockwise: F E H _ B C D _ Inference from statement 3: Clockwise: F E H A B C D G Final arrangement: Among the given options, D is sitting between G and C. Hence, option (b) is correct. Incorrect Solution: b) GCD Justification: Inference from statement 1: Clockwise: H _ B _ D Inference from statement 2: Clockwise: F _ H _ B _ D Inference from statement 3: Clockwise: F E H _ B C D _ Inference from statement 3: Clockwise: F E H A B C D G Final arrangement: Among the given options, D is sitting between G and C. Hence, option (b) is correct.

#### 1. Question

Study the following information carefully and answer the questions given below: A, B, C, D, E, F, G and H are sitting around a circle facing the center.

D is fourth to the right of H and second to the left of B.

F is fourth to the right of B.

C is fourth to the right of E, who is not an immediate neighbor of B or D.

A is not an immediate neighbor of D.

In which of the following combinations is the third person sitting in between the first and the second persons?

Solution: b) GCD

Justification:

Inference from statement 1: Clockwise: H _ B _ D

Inference from statement 2: Clockwise: F _ H _ B _ D

Inference from statement 3: Clockwise: F E H _ B C D _

Inference from statement 3: Clockwise: F E H A B C D G

Final arrangement:

Among the given options, D is sitting between G and C.

Hence, option (b) is correct.

Solution: b) GCD

Justification:

Inference from statement 1: Clockwise: H _ B _ D

Inference from statement 2: Clockwise: F _ H _ B _ D

Inference from statement 3: Clockwise: F E H _ B C D _

Inference from statement 3: Clockwise: F E H A B C D G

Final arrangement:

Among the given options, D is sitting between G and C.

Hence, option (b) is correct.

• Question 2 of 5 2. Question Study the following information carefully and answer the questions given below: A, B, C, D, E, F, G and H are sitting around a circle facing the center. D is fourth to the right of H and second to the left of B. F is fourth to the right of B. C is fourth to the right of E, who is not an immediate neighbor of B or D. A is not an immediate neighbor of D. What is B’s position with respect to G? a) Third to the right b) Third to the left c) Fifth to the right d) Fourth to the left Correct Solution: a) Third to the right Justification: Refer the explanation for the previous question. B sits third to the right of G or fifth to the left of G. Hence, option (a) is correct. Incorrect Solution: a) Third to the right Justification: Refer the explanation for the previous question. B sits third to the right of G or fifth to the left of G. Hence, option (a) is correct.

#### 2. Question

Study the following information carefully and answer the questions given below: A, B, C, D, E, F, G and H are sitting around a circle facing the center.

D is fourth to the right of H and second to the left of B.

F is fourth to the right of B.

C is fourth to the right of E, who is not an immediate neighbor of B or D.

A is not an immediate neighbor of D.

What is B’s position with respect to G?

• a) Third to the right

• b) Third to the left

• c) Fifth to the right

• d) Fourth to the left

Solution: a) Third to the right

Justification:

Refer the explanation for the previous question.

B sits third to the right of G or fifth to the left of G.

Hence, option (a) is correct.

Solution: a) Third to the right

Justification:

Refer the explanation for the previous question.

B sits third to the right of G or fifth to the left of G.

Hence, option (a) is correct.

• Question 3 of 5 3. Question A team of 11 is to be selected from 7 batsmen and 6 bowlers available. The team must have at least 5 bowlers. In how many ways can it be done? (a) 51 (b) 48 (c) 44 (d) 63 Correct Solution: D) 63 As the team must have at least 5 bowlers, two cases are possible: Case I: Team has 5 bowlers out of 6 bowlers and 6 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 and 6 batsmen out of 7 = 6C5 7C6 = 6 7 = 42. OR Case II: Team has 6 bowlers out of 6 bowlers and 5 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 and 5 batsmen out of 7 = 6C6 7C5 = 1 21 = 21. Hence, total ways possible = 42 + 21 = 63. Hence, option (d) is correct. Incorrect Solution: D) 63 As the team must have at least 5 bowlers, two cases are possible: Case I: Team has 5 bowlers out of 6 bowlers and 6 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 and 6 batsmen out of 7 = 6C5 7C6 = 6 7 = 42. OR Case II: Team has 6 bowlers out of 6 bowlers and 5 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 and 5 batsmen out of 7 = 6C6 7C5 = 1 21 = 21. Hence, total ways possible = 42 + 21 = 63. Hence, option (d) is correct.

#### 3. Question

A team of 11 is to be selected from 7 batsmen and 6 bowlers available. The team must have at least 5 bowlers. In how many ways can it be done?

Solution: D) 63

As the team must have at least 5 bowlers, two cases are possible:

Case I: Team has 5 bowlers out of 6 bowlers and 6 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 and 6 batsmen out of 7 = 6C5 7C6 = 6 7 = 42.

Case II: Team has 6 bowlers out of 6 bowlers and 5 batsmen out of 7 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 and 5 batsmen out of 7 = 6C6 7C5 = 1 21 = 21. Hence, total ways possible = 42 + 21 = 63.

Hence, option (d) is correct.

Solution: D) 63

As the team must have at least 5 bowlers, two cases are possible:

Hence, option (d) is correct.

• Question 4 of 5 4. Question The monthly income of Ramesh and Suresh are in the ratio 4:3 and the ratio of their expenditure is 3:2. If each of them saves Rs. 6000 then by what percentage is Ramesh income more than that of Suresh income? (a) 45% (b) 33.33% (c) 60% (d) 20% Correct Solution: B) 33.33% Let the income of Ramesh and Suresh be 4x and 3x respectively And the Expenses of Ramesh and Suresh are 3y and 2y respectively. As it is given that each of them saves Rs. 6000 monthly. Therefore, Savings of Ramesh = 4x – 3y = 6000 ……(Eq 1) Saving of Suresh = 3x -2y = 6000 …….(Eq 2) Subtracting (2) from (1) gives x –y = 0, i.e. x = y …………….(Eq 3) Using (Eq 3) in (Eq 1) we get, x = 6000. So, Ramesh’s Income = 4x = 24000 Suresh’s income = 3x =18000 Net difference = 24000 – 18000 = 6000 Required percentage = 6000/18000 × 100% = 33.33% Hence, option (b) is the correct Incorrect Solution: B) 33.33% Let the income of Ramesh and Suresh be 4x and 3x respectively And the Expenses of Ramesh and Suresh are 3y and 2y respectively. As it is given that each of them saves Rs. 6000 monthly. Therefore, Savings of Ramesh = 4x – 3y = 6000 ……(Eq 1) Saving of Suresh = 3x -2y = 6000 …….(Eq 2) Subtracting (2) from (1) gives x –y = 0, i.e. x = y …………….(Eq 3) Using (Eq 3) in (Eq 1) we get, x = 6000. So, Ramesh’s Income = 4x = 24000 Suresh’s income = 3x =18000 Net difference = 24000 – 18000 = 6000 Required percentage = 6000/18000 × 100% = 33.33% Hence, option (b) is the correct

#### 4. Question

The monthly income of Ramesh and Suresh are in the ratio 4:3 and the ratio of their expenditure is 3:2. If each of them saves Rs. 6000 then by what percentage is Ramesh income more than that of Suresh income?

• (b) 33.33%

Solution: B) 33.33%

Let the income of Ramesh and Suresh be 4x and 3x respectively And the Expenses of Ramesh and Suresh are 3y and 2y respectively. As it is given that each of them saves Rs. 6000 monthly.

Therefore, Savings of Ramesh = 4x – 3y = 6000 ……(Eq 1) Saving of Suresh = 3x -2y = 6000 …….(Eq 2) Subtracting (2) from (1) gives x –y = 0, i.e. x = y …………….(Eq 3) Using (Eq 3) in (Eq 1) we get, x = 6000. So, Ramesh’s Income = 4x = 24000 Suresh’s income = 3x =18000 Net difference = 24000 – 18000 = 6000 Required percentage = 6000/18000 × 100% = 33.33% Hence, option (b) is the correct

Solution: B) 33.33%

Let the income of Ramesh and Suresh be 4x and 3x respectively And the Expenses of Ramesh and Suresh are 3y and 2y respectively. As it is given that each of them saves Rs. 6000 monthly.

• Question 5 of 5 5. Question To five liter of 20% sulfuric acid, seven and half liter of 80% sulfuric acid is added. What is the strength of the acid in the mixture now? (a) 56% (b) 52% (c) 44% (d) 40% Correct Solution: A) 56% Percentage strength of the acid in the mixture = Quantity (volume) of the acid in the mixture/Total volume × 100 = [(520/100) + (7.580/100)/(5+7.5)] 100 = (520+7.580) /(5+7.5) = 56%. Hence, option (a) is correct. Incorrect Solution: A) 56% Percentage strength of the acid in the mixture = Quantity (volume) of the acid in the mixture/Total volume × 100 = [(520/100) + (7.580/100)/(5+7.5)] 100 = (520+7.580) /(5+7.5) = 56%. Hence, option (a) is correct.

#### 5. Question

To five liter of 20% sulfuric acid, seven and half liter of 80% sulfuric acid is added. What is the strength of the acid in the mixture now?

Solution: A) 56%

Percentage strength of the acid in the mixture = Quantity (volume) of the acid in the mixture/Total volume × 100 = [(520/100) + (7.580/100)/(5+7.5)] 100 = (520+7.5*80) /(5+7.5) = 56%.

Hence, option (a) is correct.

Solution: A) 56%

Percentage strength of the acid in the mixture = Quantity (volume) of the acid in the mixture/Total volume × 100 = [(520/100) + (7.580/100)/(5+7.5)] 100 = (520+7.5*80) /(5+7.5) = 56%.

Hence, option (a) is correct.

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