[Mission 2024] Insta–DART (Daily Aptitude and Reasoning Test) 10 May 2024

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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• Question 1 of 5 1. Question How many natural numbers between 100 to 500 are multiples of 9? (a) 44 (b) 48 (c) 47 (d) 50 Correct Ans-a The series will be 108, 117, 126, ….495. Hence, Answer = [(495-108)/9]+1 =44. Option (a) is correct. Incorrect Ans-a The series will be 108, 117, 126, ….495. Hence, Answer = [(495-108)/9]+1 =44. Option (a) is correct.

#### 1. Question

How many natural numbers between 100 to 500 are multiples of 9?

The series will be 108, 117, 126, ….495.

Hence, Answer = [(495-108)/9]+1 =44. Option (a) is correct.

The series will be 108, 117, 126, ….495.

Hence, Answer = [(495-108)/9]+1 =44. Option (a) is correct.

• Question 2 of 5 2. Question The sum of the first 20 terms of an AP whose first term and third term are 25 and 35, respectively is (a) 1200 (b) 1250 (c) 1400 (d) 1450 Correct Ans-d a = 25, a + 2d= 35 means d =5. The 20th term would be a + 19d= 25 +95 = 120. The sum of the series would be given by: |20/2] x [25 + 120]= 1450. Option (d) is correct. Incorrect Ans-d a = 25, a + 2d= 35 means d =5. The 20th term would be a + 19d= 25 +95 = 120. The sum of the series would be given by: |20/2] x [25 + 120]= 1450. Option (d) is correct.

#### 2. Question

The sum of the first 20 terms of an AP whose first term and third term are 25 and 35, respectively is

a = 25, a + 2d= 35 means d =5. The 20th term would be a + 19d= 25 +95 = 120. The sum of the series would be given by: |20/2] x [25 + 120]= 1450. Option (d) is correct.

• Question 3 of 5 3. Question A number 39 is divided into three parts which are in A.P. and the sum of their squares is 515. Find the largest (a) 17 (b) 15 (c) 13 (d) 11 Correct Ans-b The three parts are 11, 13 and 15 since 112 + 132 +152 =515. Since, we want the largest number, the answer would be 15. Option (b) is correct. Incorrect Ans-b The three parts are 11, 13 and 15 since 112 + 132 +152 =515. Since, we want the largest number, the answer would be 15. Option (b) is correct.

#### 3. Question

A number 39 is divided into three parts which are in A.P. and the sum of their squares is 515. Find the largest

The three parts are 11, 13 and 15 since 112 + 132 +152 =515. Since, we want the largest number, the answer would be 15. Option (b) is correct.

• Question 4 of 5 4. Question If a clock strikes once at 12 A.M., twice at 1 A.M., thrice at 2 A.M. and so on, how many times will the clock be struck in the course of 3 days? (a) 756 (b) 828 (c) 678 (d) 1288 Correct Ans-b In a period of l day or 24 hours the clock would strike 1 +2+3+…+23 276 times. In the course-of 3 days the clock would strike 276 x 3 828. Option (b) is correct. Incorrect Ans-b In a period of l day or 24 hours the clock would strike 1 +2+3+…+23 276 times. In the course-of 3 days the clock would strike 276 x 3 828. Option (b) is correct.

#### 4. Question

If a clock strikes once at 12 A.M., twice at 1 A.M., thrice at 2 A.M. and so on, how many times will the clock be struck in the course of 3 days?

In a period of l day or 24 hours the clock would strike 1 +2+3+…+23 276 times. In the course-of 3 days the clock would strike 276 x 3 828. Option (b) is correct.

• Question 5 of 5 5. Question What will be the maximum sum of 54, 52, 50,…..? (a) 702 (b) 704 (c) 756 (d) 700 Correct Ans-c Since this is a decreasing A.P. with first term positive, the maximum sum will occur upto the point where the progression remains non-negative. 54, 52, 50, ……0 Hence, 28 terms x 27 =756. Option (c) is correct. Incorrect Ans-c Since this is a decreasing A.P. with first term positive, the maximum sum will occur upto the point where the progression remains non-negative. 54, 52, 50, ……0 Hence, 28 terms x 27 =756. Option (c) is correct.

#### 5. Question

What will be the maximum sum of 54, 52, 50,…..?

Since this is a decreasing A.P. with first term positive, the maximum sum will occur upto the point where the progression remains non-negative. 54, 52, 50, ……0

Hence, 28 terms x 27 =756. Option (c) is correct.

Since this is a decreasing A.P. with first term positive, the maximum sum will occur upto the point where the progression remains non-negative. 54, 52, 50, ……0

Hence, 28 terms x 27 =756. Option (c) is correct.

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